1) The Specific Heat Capacity at 25°C of Gold is 0.129 / (g°C)

a) What is the molar Specific Heat Capacity of Gold in J/(mol °C)​

Answer:

in my opinion I think the answer the be "A"

Answer:

Ka=[H+][A−]/[HA]

which solution has the lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq) :

Higher value of Ka indicates greater ionization thus more protons in solution, higher H+ concentration in solution means lower pH value.

Since HF have higher Ka have, thus HF solution will have lower pH.

The measurement is when the solution has the lower pH so HF should have higher ka.

In the given solution, it contains the  lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq).

Here higher value of Ka represents the high ionization so there should be more protons in the solutions. and, the higher h+ concentration have the lower pH value.

So in the case when HF has higher Ka, due to this, HF solution will have lower pH.

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Answer:

true

Explanation:

This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially

D. Radioactive material can leave the patient’s body through saliva, sweat, and urine.

I took the test n got it right ¯\_(ツ)_/¯

Answer:

(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder.

Explanation:

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Answer:

Learning the rock cycle and understanding the processes involved helps all of us. This is how soil forms, through the breakdown of rocks. We need soil to survive—imagine trying to grow vegetables without it. This is an immediate connection to the food chain

Answer:

Temperature usually increases when water condenses. What behavior of water is most directly responsible for this phenomenon? The release of heat by the formation of hydrogen bonds. Hydrogen bonds stabilize and keep the of ice farther apart than the water molecules of liquid water.

Answer:

See Explanation

Explanation:

The unbalanced reaction equation is;

CO2(g) + LiOH(aq) + Li2CO3(aq) + H2O(l)

The balanced chemical reaction equation;

CO2(g) + 2LiOH(aq) + Li2CO3(aq) + H2O(l)

The molar mass of each compound is the sum of the relative atomic masses of the atoms of the elements that compose the compounds.

For CO2

12 + 16(2) = 12 + 32 = 44 g/mol

For LiOH

7 + 16 + 1 = 24 g/mol

For Li2CO3

2(7) + 12 + 3(16) = 74 g/mol

For H2O

2(1) + 16 = 18 g/mol

From the balanced chemical reaction equation, the mole ratio is 1:2:1:1. This is obtained from the stoichiometric coefficient of each reactant in the balanced chemical reaction equation.

From the question;

1 mole of CO2 occupies 22.4 L

x moles of CO2 occupies 825 L

x = 1 mole * 825 L/22.4 L

x = 36.8 moles

From the reaction equation;

1 mole of CO2 produces 1 mole of water

36.8 moles of CO2 produces 36.8 moles of water

Mass of 36.8 moles of water = 36.8 moles * 18 g/mol

= 662 g of water

The answer must have three significant figures because that is the same number of significant figures to which values were given in the question.

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].

That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]

or

[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

Answer:

1.15 M

Explanation:

Step 1: Given data

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

Answer: Al₂O₃

Explanation:

Answer:

SnSO₄

Explanation:

Tin(II) sulfate is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence.

Answer:

please give me brainlist and follow

Explanation:

SnSO₄

Answer:

Explanation:

So we know q = mc[tex]\Delta[/tex]T.

q = 55.7 J

c = 0.129j/g°C

and [tex]\Delta[/tex]T = 314-274 = 40°C.

and m is mass which can solve since we got every other variable. We will get m = 10.8g.

Answer:

68

Explanation:

Answer:

A ) New rocks floating to the surface of the crust.

TRUST

Answer: Keq= [CO2]^6[H2O]^6/ [O2]^6

Explanation:

The correct equilibrium constant expression for this equation C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g) will be

keq = 6[co2] 6[h2o] / [c6h1206] 6[o].

All reactions tend towards the state of chemical equilibrium. It is the point at which both the forward process and the reverse process are taking place at the same rate.

Since the forward and reverse rates are equal, hence the concentrations of the reactants and products will be constant at the equilibrium state. Here, it is important to remember that even though the concentrations are constant at equilibrium.

The double half-arrow sign we use for writing the reversible reaction equations. It is represented as ⇌ a sign of equilibrium.

therefore, the correct equilibrium constant expression will be C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g)

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Answer:

answer is C

Explanation:

encourage the release of carbon dioxide from the stems

Answer:

a. Br2(I)+2 KI(aq)》2KBr(aq)+I2

[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]

0.15N × 50mL = 0.2N × (Vbase)

75mL = Volum of base

37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

0.2 × V1 = 0.150 × 50

0.2V1 = 7.5

V1 = 7.5/0.2

V1 = 37.5mL

Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.

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Answer:

Extending DNA strands to match samples

Answer:

0.99 μmol/L

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 20 mL

Concentration of stock solution (C₁) = 18.8 μmol/L

Volume of diluted solution (V₂) = 380 mL

Concentration of diluted solution (C₂) =?

The concentration of the diluted solution can be obtained as follow:

C₁V₁ = C₂V₂

18.8 × 20 = C₂ × 380

376 = C₂ × 380

Divide both side by 380

C₂ = 376 / 380

C₂ = 0.99 μmol/L

Therefore, the concentration of the diluted solution the chemist is working on is 0.99 μmol/L

Answer:

167.217g/mol

Explanation:

Formula mass is defined as the mass in grams that a mole of a molecule weighs. To solve the formula mass of ZrF₄ we require the molar mass of Zr and of F (Molar mass Zr: 91.225g/mol; F: 18.998g/mol)

In this molecule, there is 1 mole of Zr and 4 moles of F. The formula mass is:

Zr = 1*91.225g/mol = 91.225g/mol

F = 4*18.998g/mol = 75.992g/mol

Formula mass: 91.225g/mol + 75.992g/mol

The oldest form where an image is transferred from one surface to another is printmaking, Screen frame commonly made of covered tightly with wood, technique makes use of woven mesh to support an ink blocking stencil is Silkscreen printing and A tool that usually made of vinyl or rubber blade is called Squeegee.

Art is a technique in which we use different kinds of things like paintings, printings, drawings and do exhibition for the decoration purpose.

Hence C, A, A and B is the correct answers of the given questions.

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la tierra nuestro planeta es el único del sistema solar que sabe que mantiene vida: vida que es increíblemente diversa,

Answer:

Plant A

Explanation:

Answer:

0. 070g

Mass of 1 Si atom =28.08/6.022*1023

So mass 1.5 *1021*4.6629*10-23

Answer:

[tex]\boxed {\boxed {\sf 0.070 \ g \ Si}}[/tex]

Explanation:

We are given a value of atoms and asked to find the mass. We can complete this in 2 steps.

1. Convert Atoms to Moles

First, we have to convert atoms to moles. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this case, the particles are silicon atoms. We can set up a proportion.

[tex]\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]

Multiply by the value of atoms given.

[tex]1.5 \times 10^{21} \ atom \ Si *\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]

Flip the ratio. This allows the atoms of silicon units to cancel and leave the moles of silicon.

[tex]1.5 \times 10^{21} \ atom \ Si *\frac {1 \ mol \ Si } {6.022 \times 10^{23} \ atom \ Si}[/tex]

[tex]1.5 \times 10^{21}*\frac {1 \ mol \ Si } {6.022 \times 10^{23} }[/tex]

[tex]\frac {1.5 \times 10^{21} \ mol \ Si } {6.022 \times 10^{23} }[/tex]

[tex]0.002490866822 \ mol \ Si[/tex]

2. Convert Moles to Grams

Next, we convert the moles to grams. We use the molar mass, which is found on the Periodic Table. This value is the number of grams in 1 mole of a substance. Look for silicon (Si).

Use this value as a ratio.

[tex]\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

Multiply by the number of moles we calculated.

[tex]0.002490866822 \ mol \ Si *\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

The moles of silicon units cancel, so we are left with grams.

[tex]0.002490866822 *\frac {28.085 \ g \ Si}{1}[/tex]

[tex]0.002490866822 *{28.085 \ g \ Si}[/tex]

[tex]0.06995599469 \ g \ Si[/tex]

3. Round

Finally we must round our answer. The original value has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

[tex]0.069\underline95599469 \ g Si[/tex]

The 9 tells us to round the other 9 to a 0, then the 6 to a 7.

[tex]0.070 \ g \ Si[/tex]

The mass of 1.5 × 10²¹ silicon atoms is 0.070 grams of silicon.