1. Un arquitecto construirá una casa de interés social en un área rectangular de 52 m². El
frente será el ancho de la casa y el largo será dos veces el ancho.
a.
Traza una figura geométrica que represente el terreno
b.
¿Cuál es la variable con la que representarías el ancho?

Answers

Answer 1

Answer:

Definamos:

A = Ancho

L = Largo.

Sabemos que el área es rectangular, y para un rectángulo de ancho A y largo L, el área es:

Área = A*L.

Y sabemos que L = 2*A.

a) Una imagen se encuentra abajo.

b) Como podemos escribir la variable L en términos de la variable A, podemos escribir:

Área = A*L = A*(2*A) = 2*A^2

Entonces la variable que usamos es el ancho.  

Ahora podemos resolver el problema:

52m^2 = 2*A^2

52m^2/2 = 26m^2 = A^2

A = √(26m^2) = 5.1 m

Entonces el largo es:

L = 2*A = 2*5.1m = 10.2 m

1. Un Arquitecto Construir Una Casa De Inters Social En Un Rea Rectangular De 52 M. Elfrente Ser El Ancho

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

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Answers

A 33 pound bag of grass seed has = 2 pounds less than 5 smaller bags of seed

= 33 pounds = 2 pounds less than 5 smaller bags

Let the weight of smaller bag of seed be ' x ' . Then ,

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Answers

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Answers

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Answers

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