100. 00 - 0.22 what is the answer show your work

a) The cumulative distribution function for X is F(x) = 1 – exp(-x²)

is = 1 – exp(-x²)

b) P(X ≤ 2) = 0.865

c) Generate a uniformly distributed random number u between 0 and 1.

a) We have given a probability density function f(x) = 2x exp(-x²), x ≥ 0

To find the cumulative distribution function (CDF), we integrate the probability density function (PDF) from negative infinity to x as follows;

∫f(x)dx = ∫2x exp(-x²)dx

Using u =

-x², du/dx = -2x

dx = -du/2∫2x exp(-x²)dx

= -∫exp(u)du

= -exp(u) + C

= -exp(-x²) + C

We know that, F(x) = ∫f(x)dx.

From the above calculation, the CDF of X is given by;

F(x) = 1 – exp(-x²)

b)

We are to calculate P(X ≤ 2)

We know that F(2) = 1 – exp(-2²)

= 0.865

Therefore, P(X ≤ 2) = 0.865

c)

The inversion method is a way of generating random values of a random variable X using the inverse of the cumulative distribution function of X, denoted as F⁻¹(u),

where u is a uniformly distributed random number between 0 and 1.

The steps for generating a random value of X using the inversion method are:

Generate a uniformly distributed random number u between 0 and 1.

Find the inverse of the cumulative distribution function, F⁻¹(u).

This gives us the value of X.

d)

R command for one random value of X by using the inversion method```{r}

# setting seed to be 100 sets. seed(100)

# defining the inverse CDFF_inv = function(u) q norm(u, lower.tail=FALSE)

# generating a random value of Uu = run if(1)

# calculating the corresponding value of Xx = F_inv(u)```

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The exact area of the surface obtained by rotating the curve y = √(1 + eˣ) about the x-axis over the interval 0 ≤ x ≤ 7, we would need to use numerical methods to approximate the value of the integral since it does not have a simple closed-form solution.

To find the exact area of the surface obtained by rotating the curve y = √(1 + eˣ) about the x-axis, we can use the formula for the surface area of a solid of revolution.

The formula for the surface area of a curve y = f(x) rotated about the x-axis over the interval [a, b] is given by:

A = 2π∫[a, b] y * sqrt(1 + (dy/dx)²) dx

In this case, the given curve is y = √(1 + eˣ) and the interval of interest is 0 ≤ x ≤ 7. To calculate the area, we need to find the derivative dy/dx and substitute it into the formula.

Let's start by finding the derivative of y = √(1 + eˣ) with respect to x. Applying the chain rule, we have:

dy/dx = (1/2)(1 + eˣ)^(-1/2) * eˣ

Now, we can substitute y and dy/dx into the surface area formula:

A = 2π∫[0, 7] √(1 + eˣ) * sqrt(1 + [(1/2)(1 + eˣ)^(-1/2) * eˣ]²) dx

Simplifying the expression inside the integral, we have:

A = 2π∫[0, 7] √(1 + eˣ) * sqrt(1 + (eˣ/2)(1 + eˣ)^(-1)) dx

Now, we need to evaluate this integral over the interval [0, 7] to find the exact area of the surface.

Unfortunately, the integral for this particular curve does not have a simple closed-form solution. Therefore, to find the exact area, we would need to rely on numerical methods, such as numerical integration techniques or computer algorithms, to approximate the value of the integral.

Using these numerical methods, we can calculate an accurate estimate of the surface area by dividing the interval [0, 7] into smaller subintervals and applying techniques like the trapezoidal rule or Simpson's rule. The more subintervals we use, the more accurate the approximation will be.

In summary, to find the exact area of the surface obtained by rotating the curve y = √(1 + eˣ) about the x-axis over the interval 0 ≤ x ≤ 7, we would need to use numerical methods to approximate the value of the integral since it does not have a simple closed-form solution.

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Answer:220

Step-by-step explanation:

LET X BE THE LENGTH OF RECTANGLE AND FOR UPPER PORTION OF DIA GRAM BASE OF RIGHT ANGLE TRIANGLE SO X=20

LET Y BE WIDTH OF RECTANGLE SO Y=8

LET P BE THE PERPENDICULAR OF THE RIGHT TRIANGLE SO P=6

THEN

AREA OF RECTANGLE=LENGTH*WIDTH

SO AREA OF RECTANGLE BECOMES=(20)(8)=160

AND AREA OF RIGHT ANGLE TRIANGLE BECOMES=1/2(BASE*(PERPENDICULAR)

SO =1/2(20)(6)=60

SO THE TOTAL AREA OF THE DIAGRAM=AREA OF RIGHT ANGLE TRIANGLE+AREA OF RECTANGLE=160+60=220

x - 8 = 68

x - 8 + 8 = 68 + 8

x = 76

hope this helped

f(z) = z^2 + 1 has an antiderivative on the domain G = C \ {i, -i}.

(b) Hence, we cannot determine whether f(z) = z^2 + 1 has an antiderivative on the domain G = {z in C | Re(z) > 0} based on the Cauchy-Goursat theorem alone.

(a) To determine whether f(z) = z^2 + 1 has an antiderivative on the domain G = C \ {i, -i}, we can check if f(z) satisfies the Cauchy-Riemann equations on G.

The Cauchy-Riemann equations state that for a function f(z) = u(x, y) + iv(x, y) to have a derivative at a point, its real and imaginary parts must satisfy the partial derivative conditions:

∂u/∂x = ∂v/∂y and ∂u/∂y = -∂v/∂x.

For f(z) = z^2 + 1, we have u(x, y) = x^2 - y^2 + 1 and v(x, y) = 2xy.

Calculating the partial derivatives, we find:

∂u/∂x = 2x, ∂v/∂y = 2x,

∂u/∂y = -2y, ∂v/∂x = 2y.

Since ∂u/∂x = ∂v/∂y and ∂u/∂y = -∂v/∂x hold for all (x, y) in the domain G, f(z) satisfies the Cauchy-Riemann equations on G. Hence, f(z) has an antiderivative on G = C \ {i, -i}.

(b) Now, let's consider the domain G = {z in C | Re(z) > 0}. To determine if f(z) = z^2 + 1 has an antiderivative on G, we can utilize the Cauchy-Goursat theorem, which states that a function has an antiderivative on a simply connected domain if and only if its line integral around every closed curve in the domain is zero.

For f(z) = z^2 + 1, we can calculate its line integral over a closed curve C in G. However, since G is not simply connected (it has a "hole" at Re(z) = 0), the Cauchy-Goursat theorem does not apply, and we cannot conclude whether f(z) has an antiderivative on G based on this theorem.

To provide a definitive answer, further analysis or techniques such as the residue theorem may be required.

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Step-by-step explanation:

0.45 kilograms. you decide the mass value by 1000.

The degree of the extension [K: F] ≤ p.

Suppose K = F_p(t) has transcendence degree n over F_p.

Then K is an algebraic extension of F_p(t^p).

(a) We need to find a polynomial of degree p in F[x] for which t is a root.

In F_p, we have t^p - t ≡ 0 (mod p).

So, we can write t^p ≡ t (mod p).

Since F_p[t] is a polynomial ring over F_p, we have t^p - t ∈ F_p[t] is an irreducible polynomial.

Hence the degree of the extension [K: F] ≤ p.

Suppose K = F_p(t) has transcendence degree n over F_p.

Then K is an algebraic extension of F_p(t^p).

The minimal polynomial of t over F_p(t^p) is x^p - t^p. Thus, [K: F_p(t^p)] ≤ p.

Since K/F_p is an algebraic extension, we have [K: F_p] = [K: F_p(t^p)][F_p(t^p): F_p].

Thus, [K: F_p] ≤ p².

Therefore, [K: F] ≤ p².

(b) We need to show that the automorphism δ of K defined by δ (t) = t + 1 fixes F.

Let f(x) be the polynomial obtained in part (a). Since f(t) = 0, we have f(t + 1) = 0. This implies δ (t) = t + 1 is a root of f(x) also.

Hence, f(x) is divisible by x - (t + 1). We can writef(x) = (x - (t + 1))g(x)for some g(x) ∈ K[x].

Since [K: F] ≤ p², we have deg(g) ≤ p.

Substituting x = t into the above equation yields 0 = f(t) = (t - (t + 1))g(t) = -g(t).

Therefore, f(x) = (x - (t + 1))g(x) = (x - t - 1)(a_{p-1}x^{p-1} + a_{p-2}x^{p-2} + ··· + a_1 x + a_0)where a_{p-1}, a_{p-2}, ..., a_1, a_0 ∈ F_p are uniquely determined.

(c) To show that K is a Galois extension of F and determine the Galois group Gal(K/F), we need to check that K is a splitting field over F.

That is, we need to show that every element of F_p(t^p) has a root in K.Since K = F_p(t)(t^p - t) = F_p(t)(w), it suffices to show that w has a root in K.

Note that w = t^p - t = t(t^{p-1} - 1).

Since t is a root of f(x) = x^p - x ∈ F_p[t], we have t^p - t = 0 in K. Thus, w = 0 in K.

Therefore, K is a splitting field over F_p(t^p).Since [K : F_p(t^p)] ≤ p, the extension K/F_p(t^p) is separable.

Therefore, the extension K/F_p is also separable. Hence, K/F_p is a Galois extension. The degree of the extension is [K: F_p] = p².

The Galois group is isomorphic to a subgroup of S_p. Since F_p is a finite field of p elements, it contains a subfield isomorphic to Z_p. This subfield is fixed by any automorphism of K that fixes F_p.

Since F_p(t^p) is generated by F_p and t^p, any automorphism of K that fixes F_p(t^p) is uniquely determined by its effect on t.

Since there are p choices for δ(t), the Galois group has order p. It follows that the Galois group is isomorphic to Z_p.

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The coordinates of the midpoint of the line segment GH with endpoints G(-3, 2) and H(3, -2) are (0, 0). The correct option is (C).

To determine the coordinates of the midpoint of the line segment GH with endpoints G(-3, 2) and H(3, -2), we can use the midpoint formula.

The midpoint formula states that the coordinates of the midpoint (M) are given by the average of the x-coordinates and the average of the y-coordinates of the endpoints.

Midpoint (M) = ((x1 + x2) / 2, (y1 + y2) / 2)

For GH, plugging in the coordinates, we have:

Midpoint (M) = ((-3 + 3) / 2, (2 + -2) / 2)

Midpoint (M) = (0, 0)

Therefore, the coordinates of the midpoint of GH are (0, 0), which corresponds to option c. (0, 0).

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:] i honestly have no clue my self

Answer:

x= 12.942

Law of sines :)

Answer:

सैम ने 9 पाउंड आटा बनाया

Step-by-step explanation:

The value of m∠C is 85°.

Given that, △ABC ∼ △EFG. Also, m∠A = 39° and m∠F = 56°. We need to find m∠C.

Let us first write down the formula for the similarity of triangles.  The two triangles are similar if their corresponding angles are congruent.

In other words, we can write: `∠A ≅ ∠E`, `∠B ≅ ∠F`, and `∠C ≅ ∠G`.

Now, in △ABC, we have: ∠A + ∠B + ∠C = 180° (Interior angle property of a triangle)

Also, in △EFG, we have: ∠E + ∠F + ∠G = 180°(Interior angle property of a triangle)

We know that ∠A ≅ ∠E and ∠B ≅ ∠F.

Substituting these values, we get:

39° + ∠B + ∠C = 180° (From △ABC)56° + ∠B + ∠G = 180° (From △EFG)

Simplifying, we get ∠B + ∠C = 141°...(Eq 1)

∠B + ∠G = 124°....  (Eq 2)

Now, let's subtract Eq 2 from Eq 1.

We get∠C − ∠G = 17°               

Substituting values from Eq 2:

∠C − 68° = 17° ∠C = 85°

Therefore, m∠C is 85°.

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The solution to the Cauchy problem is x(t) = e^t and y(t) = te^t.

The Cauchy problem can be solved by finding the solution to the given system of differential equations.

In more detail, we have the following system of differential equations:

dx/dt = x - y

dy/dt = x + y

To solve this system, we can use the method of separation of variables. Starting with the first equation, we separate the variables:

dx/(x - y) = dt

Integrating both sides, we have:

ln|x - y| = t + C1

Exponentiating both sides, we get:

|x - y| = e^(t + C1)

Taking the absolute value, we have two cases:

(x - y) = e^(t + C1)

(x - y) = -e^(t + C1)

Simplifying, we obtain:

x - y = Ce^t, where C = e^(C1)

x - y = -Ce^t, where C = -e^(C1)

Next, we consider the second equation of the system. We differentiate both sides:

dy/dt = x + y

Substituting the expressions for x - y from the first equation, we have:

dy/dt = (Ce^t) + y

This is a linear first-order ordinary differential equation. We can solve it using an integrating factor. The integrating factor is e^t, so we multiply both sides by e^t:

e^t(dy/dt) - e^ty = Ce^t

We recognize the left side as the derivative of (ye^t) with respect to t:

d(ye^t)/dt = Ce^t

Integrating both sides, we have:

ye^t = Ce^t + C2

Simplifying, we obtain:

y = Ce^t + C2e^(-t), where C2 is the constant of integration

Using the initial conditions x(0) = 1 and y(0) = 0, we can find the values of the constants C and C2:

1 - 0 = C + C2

C = 1 - C2

Substituting this back into the equation for y, we have:

y = (1 - C2)e^t + C2e^(-t)

Therefore, the solution to the Cauchy problem is x(t) = e^t and y(t) = te^t.

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Answer:

polynomial of degree 10

Step-by-step explanation:

The degree of the polynomial is the sum of the exponents, that is

[tex]w^{7}[/tex]y³ → has degree 7 + 3 = 10

Answer:

12

Step-by-step explanation:

Through 12 years  he would have painted 72 paintings and since he hasn't sold two of them he has only sold 70.

Answer:

the first one

Step-by-step explanation:

the first one

Answer:

7. -4/5

8. 1

9. 0

10. 3/4

11. undefined/nonlinear

12. -9/4

13. parallel

To find the change-of-coordinates matrix from basis B to the standard basis, we need to express the standard basis vectors as linear combinations of the vectors in B. Then, to write t^2 as a linear combination of the polynomials in B, we can use the change-of-coordinates matrix to transform t^2 into the coordinates with respect to B.

To find the change-of-coordinates matrix from basis B to the standard basis, we express the standard basis vectors as linear combinations of the vectors in B. Let's denote the standard basis vectors as e1, e2, and e3. We can write:

e1 = 1(1 - 7t^2) + 0(-6 + t + 43t^2) + 0(1 + 6t)

e2 = 0(1 - 7t^2) + 1(-6 + t + 43t^2) + 0(1 + 6t)

e3 = 0(1 - 7t^2) + 0(-6 + t + 43t^2) + 1(1 + 6t)

The coefficients in these equations give us the entries of the change-of-coordinates matrix.

To write t^2 as a linear combination of the polynomials in B, we can use the change-of-coordinates matrix. Let [t^2]_B represent the coordinates of t^2 with respect to B. Then, [t^2]_B = C[t^2]_std, where C is the change-of-coordinates matrix. We can solve this equation to find [t^2]_B.

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Answer:

9√2

Step-by-step explanation:

To do this, we need to use the Pythagoras' Theorem. Which is a^2+b^2=c^2

In this case, we need to solve for C. So, we do 9^2 (A) +9^2 (B), assuming a and b are the same. So we end up with 81+81=c^2. Now, we find the square root of 162. Around 13 or 9√2

Answer:

I don't know thank answer sorry I just really need points you can report me if you want but I REALLY need some

Use the rslash() function in R Studio to generate a random sample of size 100 from the Slash distribution.

To generate a random sample of size 100 from the Slash distribution without using extra packages in R Studio, you can use the inverse transform method. The Slash distribution is a continuous probability distribution with a density function given by f(x) = 1 / (π(1 + x^2)).

First, generate a random sample of size 100 from a uniform distribution on the interval [0, 1]. Then, transform the uniform random numbers using the inverse cumulative distribution function (CDF) of the Slash distribution, which is given by F^(-1)(x) = tan(π(x - 0.5)). This will map the uniform random numbers to the corresponding values from the Slash distribution.

In R Studio, you can use the following code to generate the random sample:

# Set seed for reproducibility

set.seed(42)

# Generate uniform random sample

uniform_sample <- runif(100)

# Transform uniform random sample to Slash distribution

slash_sample <- tan(pi * (uniform_sample - 0.5))

The slash_sample variable will contain the generated random sample of size 100 from the Slash distribution.

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Answer:

Step-by-step explanation:

Answer: B

Step-by-step explanation:

I know I’m late :(

Answer:

a). -8    b). 4/19

Step-by-step explanation:

F(x)= x²+9x       g(x)=1/x.

g(-1) = 1/ - 1

= -1

f(-1) = x²+9x

= -1² + 9(-1)

= 1 - 9

= -8

G(f(1/2))

f(1/2) = x²+9x

= 1/2² + 9(1/2)

= 1/4 + 9/2

= 19/4

g (19/4) = 1/x

= 1/19/4

= 4/19

Answer:

1). -8    2). 4/19

Step-by-step explanation:

F(x)= x²+9x       g(x)=1/x.

g(-1) = 1/ - 1

= -1

f(-1) = x²+9x

= -1² + 9(-1)

= 1 - 9

= -8

G(f(1/2))

f(1/2) = x²+9x

= 1/2² + 9(1/2)

= 1/4 + 9/2

= 19/4

g (19/4) = 1/x

= 1/19/4

= 4/19

Answer:

x-intercept = 2

y-intercept = 6

Step-by-step explanation:

x-intercept:  6x = 12;  x = 2

y-intercept:  2y = 12;  y = 6

Answer:

40 cm²

Step-by-step explanation:

A = 1/2bh

A = 1/2 (8) (10)

A = (4) (10)

A = 40

Answer:

I am not sure rdbugs h h on grh g ih fv vy f byv7iplovh v v6c78

The equation that represents the sentence "28 is the quotient of a number and 4" is 28 = n/4.

In the given sentence, "28 is the quotient of a number and 4," we can break down the sentence into mathematical terms. The term "quotient" refers to the result of division, and "a number" can be represented by the variable "n." The divisor is 4.

1) Define the variable.

Let's assign the variable "n" to represent "a number."

2) Write the equation.

Since the sentence states that "28 is the quotient of a number and 4," we can write this as an equation: 28 = n/4.

The equation 28 = n/4 represents the fact that the number 28 is the result of dividing "a number" (n) by 4. The left side of the equation represents 28, and the right side represents "a number" divided by 4.

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Answer:

x = 3/2

Step-by-step explanation:

Simplify this equation by dividing all three terms by 1/4:

2x - 1 = 2, or

2x  = 3

Then x = 3/2