100 points will award brainliest crown
Draw the image of EFG under the dilation with scale factor 3/2 and center of dilation (0, 0). Label the image E' F' G'

Answer:

d-7 divided by 2 or over 2

Answer:

C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection

Step-by-step explanation:

A. isn't correct because all four sides aren't congruent, only the pair of opposite sides are congruent. Sense only opposite side are congruent you can only reflect the opposite sides onto each other and not diagonally meaning B. and D. are incorrect leaving C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection as the correct answer

Answer:

-2F=7x

Step-by-step explanation:

F*-2= -2F       3x*3x=9x

-2F=9x-2x

-2F=7x

My answer needs to be 32-25=7

Step-by-step explanation:

solution

here,

1 dollar = rs 72.45

or, 1/72.45 dollars= rs 1

or, rs 1 = 1/72.45 dollars

now,

rs 1449= 1449/72.45 dollars

or,rs1449= 20 dollars

therefore, 20 dollars can be exchanged for rs 1449

Answer:

A = (0,1)

B = (1,-1)

C = (-1,-1)

Step-by-step explanation:

If this helped leave a brainliest

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

Answer:

A

Step-by-step explanation:

:)

hope it helps

Using the t-distribution, it is found that since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

At the null hypothesis, it is tested if the average box of cereal does not contain more than 368 grams, that is:

[tex]H_0: \mu \leq 368[/tex]

At the alternative hypothesis, it is tested if it contains, that is:

[tex]H_1: \mu > 368[/tex]

We have the standard deviation for the sample, hence, the t-distribution is used to solve this question.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are: [tex]\overline{x} = 372.5, \mu = 368, s = 15, n = 25[/tex].

Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{372.5 - 368}{\frac{15}{\sqrt{25}}}[/tex]

[tex]t = 1.5[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, with 25 -1 = 24 df, is of [tex]t^{\ast} = 1.71[/tex].

Since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

You can learn more about the use of the t-distribution to test an hypothesis at https://brainly.com/question/13873630

Answer:

6 (20 + c) > 16

Step-by-step explanation:

the sum of the number and 20 is 20 + c. so you multiply that equation by 6 giving you 6 (20 + c)

Answer:

  g(x) = 4x² -x +64

Step-by-step explanation:

The integral of f(x) will be continuous. This means the value must be the same for x = 4- as for x = 4+.

For some constant c1, the integral in the region x ≤ 4 is ...

  ∫f(x)dx = (4x² -x +c1) +C = g(x) +C

The integral in the region x ≥ 4 is given as ...

  ∫f(x)dx = 31x +C

Evaluated at x=4, we must get the same value from either expression:

  4(4²) -4 +c1 +C = 31(4) +C

  60 +c1 = 124

  c1 = 64

__

In order to make the integral continuous at x=4, we must have ...

  g(x) = 4x² -x +64

Answer:

11, 12, 13

Step-by-step explanation:

let's put the first number of the three as a:

a; a+1; a+2

The sum of the first and the twice second is 35 means:

a + 2(a+1) = 35

a + 2a + 2 = 35

3a = 33

a=11

now that we know a, we just need to add 1 and 2 as they are consecutive:

11, 12, 13

Answer:

50(64+36) this would be your answer

50 x (64+36)

Step-by-step explanation:

According to PEMDAS, you will have to solve 64 + 36 first, so you need to put them in the parenthesis. Next, simply multiply by 50.

Answer:

y=-3/2 x + 6Step-by-step explanation:

Answer:

Ez 1+1=3 Duh

Step-by-step explanation:

Answer:

m=1352

Step-by-step explanation:

(118.64-24)/0.07=m

Answer:

8

Step-by-step explanation:

The triangles are the same, except one is dilated.

So the hypotenuse of one is 5, and the other is 10. The triangle is dilated to double the other's size. so 4*2 = 8

I have no idea what i just wrote, but the answer is correct.

Answer:

2,3,4,5,6 is the domain

4,6,8,10,12 is the range

Step-by-step explanation:

Answer:

The domain is {2,3,4,5,6} and the range is {4,6,8,10,12}.

Step-by-step explanation:

Answer:

22.53-9.99=12.54

12.54 divided by 6 = 2.09

Each pencil costs $2.09

Step-by-step explanation:

Answer:

-12.5

Step-by-step explanation:

-7x+8+11x=-42

-7x+11x=-42-8

4x=-50

x=-12.5

Hope this helped! :)

Hey There!

Question:-

[tex] \sf \: - 7x+8+11x= - 42[/tex]

We need to find the value of x.

Solution:-

[tex]\sf \longmapsto - 7x + 8 + 11x = - 42[/tex]

Combine Like terms:-

[tex]\sf \longmapsto \: ( - 7x+11x)+(8)= - 42[/tex]

On Simplification :-

[tex]\sf \longmapsto \: 4x +8 = - 42[/tex]

Subtract 8 from both sides:-

[tex]\sf \longmapsto \: 4x+8 - 8= - 42 - 8[/tex]

On Simplification:-

[tex]\sf \longmapsto \: 4x + 0 = - 42 - 8[/tex]

Note that (-) and (-) equals to (+).

[tex]\sf \longmapsto \: 4x = - 50[/tex]

Divide both sides by 4:-

[tex]\sf \longmapsto \: \dfrac{4x}{4} = \dfrac{ - 50}{4} [/tex]

On Simplification:-

[tex]\sf \longmapsto \: \dfrac{ \cancel2x}{ \cancel2} = \dfrac{ \cancel{- 50}}{ \cancel4} [/tex]

[tex]\sf \longmapsto \: x = \dfrac{ - 25}{2} [/tex]

Or in Decimal :-

[tex]\sf \longmapsto \: x = -12.5[/tex]

______________________________________

Henceforth, the value of x is :-

[tex]\boxed{\huge \red{x = - \dfrac{25}{2}}} [/tex]

In Decimal:-

[tex] \boxed{\huge\red{ x = -12.5}}[/tex]

________________________________

Please let me know if you have any questions.

~MisterBrian

Answer:

1 is acute

2 is a right triangle

3 is obtuse

Step-by-step explanation:

A 90 degree angle will be written as a box in the corner. Any angle less than 90 is acute, and any angle more than 90 is obtuse.

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    y-(x-4)=0  

STEP

1

:

Equation of a Straight Line

1.1     Solve   y-x+4  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  y-x+4  = 0 and calculate its properties

Step-by-step explanation:

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

[tex]\%Percentage = \frac{450}{500}[/tex]

Divide 450 by 500

[tex]\%Percentage = 0.9[/tex]

Express as percentage

[tex]\%Percentage = 90\%[/tex]

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

https://brainly.com/question/2776232

Answer:

[tex]y=-1[/tex]

Step-by-step explanation:

[tex]y-14=6(x-2.5)[/tex]

[tex]y-14=6(0-2.5)[/tex]

[tex]y-14=6(-2.5)[/tex]

[tex]y-14=-15[/tex]

[tex]y=-1[/tex]