1/(x+6)+(×+1)/x=13/(x+6)

Answer:

20%

Step-by-step explanation:

Answer:

20%

Step-by-step explanation:

19.99 - 3.998(20%) = 15.992 which when rounded is 15.99

Answer:

DO you go to a connexus school? I do and i have this same project im trying to find answers to!

Step-by-step explanation:

For the first box the volume, surface area, and cost of materials are 180 cubic inches, 258 square inches, and $12.9, for the second box 192 cubic inches, 224.4 square inches, and $11.22 for the third box 235.61 cubic inches, 227.76 square inches, and $11.38.

It is defined as a three-dimensional space enclosed by an object or thing.

For the first cereal box:

Volume = L×W×H

Here L = 7.5 in, W = 2 in, and H = 12 in

Volume = 7.5×2×12 = 180 cubic inches

Surface area = 2(L×B+B×H+H×L)

= 2(7.5×2+2×12+12×7.5)

= 2(15+24+90)

= 258 square inches

Cost for this cereal box = 258×0.05 = $12.9

For the second cereal box:

[tex]\rm Volume = \frac{1}{3} bh[/tex]

b is the area and h, is the height of the pyramid.

b = 8×6 = 48 square inches, h = 12 inches

[tex]\rm Volume = \frac{1}{3} \times48\times12[/tex]

Volume = 192 cubic inches

[tex]\rm Surface \ area = b+\frac{1}{2} ps[/tex]

p is the perimeter of the base = 2(8+6) = 28 in

Slant height s = 12.6 in

[tex]\rm Surface \ area = 48+\frac{1}{2} (28)(12.6)[/tex] = 224.4 square inches

Cost of this cereal box = 224.2×0.05 = $11.22

For the third box:

Volume = πr²h

r = 2.5 in and h = 12 in

Volume = π(2.5)²(12) = 235.61 cubic inches

Surface area = 2πr(h+r) = 2π(2.5)(12+2.5) = 227.76 square inches

Cost of this cereal box = 227.76×0.05 = $11.38

Thus, for the first box the volume, surface area, and cost of materials are 180 cubic inches, 258 square inches, and $12.9, for the second box 192 cubic inches, 224.4 square inches, and $11.22 for the third box 235.61 cubic inches, 227.76 square inches, and $11.38.

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Answer:

80

Step-by-step explanation:

the answer is 80 because 8×10=80

Answer:

116

Step-by-step explanation:

Area of whole thing is 196 and area of grass is 80 so you do 196-80 to get 116.

Answer:

B

Step-by-step explanation:

bdeehvdvjwjkwkwwjehheeh

If you dont know the anwser its always B

Answer:

4 is a percent of 15 is 0.6

Step-by-step explanation:

if you out 15/0.6 as a fraction you will get 4

Answer:

4%

Step-by-step explanation:

STEP 1: Put the numbers into a fraction

0.6/15

STEP 2: Divide

0.6/15 = 0.04

STEP 3: Move decimal point two places to the right

0.04 -> 4

Answer: 4%

Answer: 3,3

Step-by-step explanation:

After considering the given data we conclude that one tailed test can be utilised for this claim.

To test the claim about the proportion of students involved in extracurricular activities, we would employ a one-tailed test.
A one-tailed test is applied when the alternative hypothesis is directional, which projects the it predicts the direction of the difference between the sample proportion and the claimed proportion. For the given case, the alternative hypothesis will be that the proportion of attending students involved in at least one extracurricular activity is greater than 70%.
Hence, we would use a one-tailed test to test this claim.
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The Poisson distribution with a parameter λ = 1 accurately models the production stoppages, where on average, the company experiences one stoppage per month with a relatively small amount of variability.

The  scenario describes a company's production stoppages, which can be modeled using a Poisson distribution with a parameter (mean) of λ = 1. In a Poisson distribution, the mean, variance, and standard deviation are all equal.

The mean (μ) represents the average number of stoppages per month, which in this case is 1. This means that, on average, the company experiences one production stoppage per month.

The variance (σ^2) also has a value of 1 in a Poisson distribution. It measures the spread or variability of the data around the mean. In this case, the variance of 1 indicates that there is some fluctuation in the number of stoppages, but it is relatively small.

The standard deviation (σ) is equal to the square root of the variance, which is also 1 in this scenario. It represents the average amount of deviation from the mean. A standard deviation of 1 suggests that most of the observations will be within one unit of the mean.

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The main difference between Hexagon and Quadrilateral is that the Hexagon is a polygon with six sides and Quadrilateral is a polygon with four sides. In geometry, a hexagon (from Greek ἕξ hex, "six" and γωνία, gonía, "corner, angle") is a six sided polygon or 6-gon.

Answer:

54 students

Step-by-step explanation:

if 7 of 331 students did not go on buses then 331 - 7 = 324 went on buses.

324 divided by 6 = 54 students

The method that begins with a matrix or table describing the characteristics of a target population is quota sampling.

Quota sampling is a non-probability sampling method in which the researcher first creates a matrix or table describing the characteristics of the target population. Once the matrix is created, the researcher then selects a certain number of people from each category in the matrix until the desired sample size is reached.

For example, if the researcher is interested in studying the political views of college students, they might create a matrix with the following categories:

Gender: Male, Female

Age: 18-21, 22-25, 26-30

Political affiliation: Democrat, Republican, Independent

Once the matrix is created, the researcher might then select 100 students from each category, for a total sample size of 300.

Quota sampling is a quick and easy way to obtain a sample of a population. However, it is not a probability sampling method, which means that the sample may not be representative of the population. This is because the researcher is not randomly selecting participants from the population. Instead, they are selecting participants based on their characteristics.

As a result, quota sampling can lead to bias in the results of a study. For example, if the researcher selects more students from one political affiliation than another, the results of the study may be biased in favor of that political affiliation.

Overall, quota sampling is a useful tool for researchers who need to obtain a sample of a population quickly and easily. However, it is important to be aware of the limitations of this method and to take steps to minimize bias in the results of the study.

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Answer:

-5x-16

Step-by-step explanation:

Combine like terms

Step-by-step explanation:

If you want to multiply a parenthesis by a number, you simply distribute the number to all the terms in the parenthesis.

So, if you want to multiply the parenthesis

(3x−7) by 5, you need to multiply by 5

both 3x and −7.

We have that 5⋅(3x)=5⋅(3⋅x)=(5⋅3)⋅x=15x and −7⋅5=−35

So, 5(3x−7)=15x−35

Answer:

.9 g/cm^3

Step-by-step explanation:

density formula is mass divided by volume.

d=m/v

d=18g/20cm^3

d=0.9

Answer:

2d) d = 60°

3a) x = 50°

Step-by-step explanation:

2d) both of the diagonals pass through the centre of the circle and divide the rectangle into 4 triangles,then it means that;

30 + d = 90°

d = 90 - 30

d = 60°

3a) since O is the centre of the circle, and we can see that the 2 chords directly above and below the centre are parallel to each other, it means that angle x = 50° since the two sides projecting from the centre to form x° and 50° are equal and in essence used to form isosceles triangle.

Answer:

7

Step-by-step explanation:

njshhtb jahhhdvjsjjbvgshh shhkakhgsv jjjjgfe

Answer: javier is taller

Step-by-step explanation:

68inches=5' 8"

(a) The basis for the null-space N(T) is any vector Y that equals -1

(b) The basis for the range R(T) is the set {-10/23, -20/23}.

The basis for the null-space N(T) of the linear operator T, we need to solve the equation T(Y) = 0. Let's express this equation and find its solutions

1 - 23T(Y) = X + 4Y - 22 × 3.0 + 2Y - X + 4Y + 32

Simplifying the equation, we get:

-23T(Y) = 10Y + 10

Dividing both sides by -23, we have:

T(Y) = (-10/23)Y - (10/23)

To find the null-space, we set T(Y) equal to zero:

(-10/23)Y - (10/23) = 0

Simplifying further, we get:

(-10/23)Y = (10/23)

Multiplying both sides by -23/10, we obtain:

Y = -1

Therefore, any vector Y that equals -1 will satisfy the equation T(Y) = 0.

Now, let's find the basis for the range R(T) of the linear operator T. The range is the set of all possible values that T(Y) can take. To find this, we need to consider all possible values for Y and calculate T(Y) for each value.

Let's choose two arbitrary values for Y and calculate T(Y):

For Y = 0

T(0) = -10/23 × 0 - 10/23

T(0) = -10/23

For Y = 1

T(1) = -10/23 × 1 - 10/23

T(1) = -20/23

Therefore, the range R(T) consists of the values -10/23 and -20/23.

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Answer:

I'm pretty sure no because a square always has 4 right angles and all sides are the same length

the parallelogram could possibly be a rectangle tho

I could be completely wrong but I hope this helps

Answer: 1/12

Step-by-step explanation:

Answer:

11/20

Step-by-step explanation:

55% = 55/100

55/100 = 11/20

(a) The area under the curve is 154 square units.

(b) The exact area of the region between the curve y= f(x) and the x-axis is (118 / 3) square units.

(a) The given function is f(x) = 25 - x² .

We need to estimate the area under the graph between x = - 3 and x = 5 by dividing the interval [-3, 5] into 4 subintervals each of the same length by using left-hand and midpoint approximation and sketch the 4 rectangles that approximates the area under the curve.

The width of each rectangle is given by Δx, where Δx = (b - a) / n = (5 - (-3)) / 4 = 2.

The height of each rectangle is determined by either left-hand approximation or midpoint approximation.

1. Left-hand approximation: In the left-hand approximation method, the height of each rectangle is taken from the left endpoint of each subinterval. We have:

Left endpoint of the 1st subinterval is x₁ = -3 Left endpoint of the 2nd subinterval is x₂ = -1 Left endpoint of the 3rd subinterval is x₃ = 1 Left endpoint of the 4th subinterval is x₄ = 3

Thus, the heights of the four rectangles are: f(x₁) = f(-3) = 16f(x₂) = f(-1) = 24f(x₃) = f(1) = 24f(x₄) = f(3) = 16

We sketch the four rectangles as follows:

The total area of the four rectangles is the sum of the individual areas of the rectangles.

We have: Area ≈ [f(-3) + f(-1) + f(1) + f(3)] Δx= [16 + 24 + 24 + 16] × 2= 80 square units.2.

Midpoint approximation: In the midpoint approximation method, the height of each rectangle is taken from the midpoint of each subinterval.

We have: Midpoint of the 1st subinterval is x₁* = -2 Midpoint of the 2nd subinterval is x₂* = 0 Midpoint of the 3rd subinterval is x₃* = 2 Midpoint of the 4th subinterval is x₄* = 4

Thus, the heights of the four rectangles are: f(x₁*) = f(-2) = 21f(x₂*) = f(0) = 25f(x₃*) = f(2) = 21f(x₄*) = f(4) = 9

We sketch the four rectangles as follows:

The total area of the four rectangles is the sum of the individual areas of the rectangles.

We have:

Area ≈ [f(-2) + f(0) + f(2) + f(4)] Δx= [21 + 25 + 21 + 9] × 2= 154 square units.

(b) The exact area of the region between the curve y = f(x) and the x-axis on the interval [-3, 5] is given by the limit of a Riemann sum as the number of subintervals n approaches infinity.

We have:

Area = ∫[(-3, 5)] f(x) dx= ∫[-3, 5] (25 - x²) dx

= [25x - (x³ / 3)]|[-3, 5]

= [125 - (125 / 3)] - [-75 + (27 / 3)]

= (100 / 3) + (18 / 3)

= (118 / 3) square units.

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The P-value of a one-tailed test is generally smaller than that of a two-tailed test when testing the same null hypothesis and using the same level of significance.

The P-value of a one-tailed test is generally smaller than that of a two-tailed test when testing the same null hypothesis and using the same level of significance. This is because a one-tailed test focuses on a specific direction of the hypothesis, while a two-tailed test considers both directions.

In a one-tailed test, the null hypothesis is rejected only if the test statistic falls in the critical region in one direction. For example, if the null hypothesis is that a mean is less than or equal to a certain value, the critical region will be in the lower tail of the distribution. Therefore, the probability of obtaining a test statistic in the critical region is smaller compared to a two-tailed test, where the critical region is split between both tails of the distribution.

As a result, the P-value of a one-tailed test is smaller than that of a two-tailed test, given the same null hypothesis and level of significance. However, it's important to note that the choice between a one-tailed or two-tailed test should be based on the specific research question, rather than the desire for a smaller P-value.

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Answer:

38.5

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

The number of degrees of freedom for treatment are 4.

Degrees of freedom is a statistical term that refers to the number of values in a calculation that are free to vary. It is a common concept in statistical inference. In general, degrees of freedom represent the number of observations in a statistical analysis that are free to vary.To find the degrees of freedom for treatment, the formula is (k - 1), where k is the number of treatment groups. In this case, there were 5 treatment groups, so the degrees of freedom for treatment would be (5 - 1) = 4.

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Ill-conditioned means that the problem or system being considered is sensitive to small changes in the input or data, leading to unstable or inaccurate results.

When solving a least squares problem using the normal equations, ill-conditioning refers to situations where the matrix involved is nearly singular or has a high condition number.

This means that small perturbations or errors in the data can result in large changes in the computed solution.

In the context of QR factorization, if the normal equations for a least squares problem are ill-conditioned, it implies that the matrix being decomposed using QR factorization is close to being singular or has a high condition number. QR factorization can help in such cases by providing a more stable and accurate solution compared to directly solving the normal equations.

QR factorization decomposes a matrix into the product of an orthogonal matrix Q and an upper triangular matrix R. This factorization can help mitigate the effects of ill-conditioning by providing a numerically stable way to solve the least squares problem.

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