The unknown mass of water is 545.21
What is mass?
mass is a quantitative measure of inertia , a fundamental property of all matter .
mass depends on the number and kind of atoms.
It is a dimensionaless quantity.
Sol-
As per the given question
220 g of water added to 90°c
Mass of water=10°C
Tempreture of the mixture =33°C
Unknown mass
m1 (n-t)= m2(t-b)
220(90-33)=m2(33-10)
:- (we can also do multiple of cp but as both side of the cp fluid unit are same so it's not needed)
220×57=m2 (23)
m2= 220×57/23
m2 =545.21
Thus the unknown mass of water is 545.21 .
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Under a pressure of 14Nm-2, some air has
a volume of 1.5m3. Determine its volume
when its pressure is 10Nm-2. Assuming the
temperature is kept constant
Answer:
2.1 m³
Explanation:
Boyle's Law states:
The absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies if the temperature and amount of gas remain unchanged within a closed system (Wikipedia) }
We can express this relationship as
[tex]P \propto \dfrac{1}{V}[/tex]
where V is the volume under pressure P
This can be re-written as:
PV = a constant
We are given that [tex]$V = 1.5m^3$[/tex] when [tex]$P = 14N/m^2$[/tex]
So PV = 1.5 x 14 = 21 Nm
At [tex]10 N/m^2[/tex] the PV product must also be 21
So 10V' = 21 where V' = volume at [tex]\displaystyle 10 N/m^2[/tex]
Therefore V' = 21/10 = 2.1 m³
An ore cart of mass 1200 kg is rolling at a speed of 12.8 m/s across a flat surface a crane dumps 338 kg of ore into the cart from directly above it how fast does the cart move after being loaded with ore assume that frictional forces with the flat surface are negligible
Given,
The mass of the cart, M=1200 kg
The speed of the cart before the ore is dumped, u=12.8 m/s
The mass of the ore dumped on the cart, m=338 kg
From the law of conservation of momentum, the total momentum of the system of the cart and the ores before and after the ore is dumped into the cart must be equal.
Thus,
[tex]Mu=(M+m)v[/tex]Where vis the speed of the cart after the ore is dumped.
On substituting the known values in the above equation,
[tex]\begin{gathered} 1200\times12.8=(1200+338)v \\ \Rightarrow v=\frac{1200\times12.8}{1200+338} \\ =9.99\text{ m/s} \\ \approx10\text{ m/s} \end{gathered}[/tex]Thus the speed of the loaded cart will be 10 m/s
A box weighing 51.1 N is pulled horizontally until it slides uniformly over a level floor. If the applied force is 6.30 N, what is the coefficient of friction between the box and the floor?
Given data
*A box weighs is N = 51.1 N
*The applied force is F = 6.30 N
The formula for the coefficient of friction between the box and the floor is given as
[tex]\mu=\frac{F}{N}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \mu=\frac{6.30}{51.1} \\ =0.123 \end{gathered}[/tex]Hence, the coefficient of friction between the box and the floor is 0.123
A gardener mows a lawn with an old-fashioned push mower. The handle of the i mower makes a 32° angle with the surface of the lawn.
a)If a 68N force is applied along the handle of the 17kg mower, what is the force exerted by the lawn on the mower? b）If the angle between the surface of the lawn and the handle of the mower is increased, does this force increase, decrease, or stay the same? Explain.
The force exerted by the lawn on the mower is 202 N when applied 68N force along the handle.
What is force and how come it be 202 N and how it decreases?Whenever we talk of force we talk of Newton as is discovered by him and so the unit of force is Newton.Force is simply a push or pull but stating it in Newton's way it is the product of mass and acceleration.Here is given that the handle is making a 32 degree angle with the surface of the lawn.Applying 68 N force along the handle of 17 kg mower the force exerted would be 202 N , here we have to encounter the normal force.The normal force would approach the force due to gravity because there is decreased force from the handle.To know more about force visit:
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A student made the table shown to list some contact and non-contact forces .
Examples of forces
Contact force - the upward force applied by a coach on a student sitting on it .
The force applied by a student in a box to move it .
Non- contact forces
The force applied by an electromagnetic on a wire
The force which opposes of an object on a ruff surface .
Which statement best explains why the table is incorrect?
A- Normal force is a force acting at a distance.
B- The student applies a non- contact force on the box .
C- The electromagnetic and wire have to be in contact to apply the force .
D- Frictional force acts between the object and the rough surface when they are In contact.
The statement that best explains why the table is incorrect is that frictional force acts between the object and the rough surface when they are In contact ( D ).
The statements in the table that describes contact forces are correct and one of the statements that describes a non-contact force is not correct. A contact force is a force applied by one mass on another due to being in contact with each other. A non contact force is the opposite of a contact force.
The force which opposes the motion of an object on a rough surface is frictional force. Frictional force is opposing between two surfaces in contact with each other. Since the two surfaces have to be in contact with each other it falls under the description of contact force.
Therefore, the statement that best explains why the table is incorrect is that frictional force acts between the object and the rough surface when they are in contact ( D ).
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for equation solve for x given 0
x=2.61 radians
Explanation
[tex]2\cos (x)+\sqrt[]{3}=0[/tex]
Step 1
Let's isolate x
a)
[tex]\begin{gathered} 2\cos (x)+\sqrt[]{3}=0 \\ \text{subtract }\sqrt[]{3}\text{ in both sides} \\ 2\cos (x)+\sqrt[]{3}-\sqrt[]{3}=0-\sqrt[]{3} \\ 2\cos (x)=-\sqrt[]{3} \end{gathered}[/tex]
Step 2
b) now, divide both sides by 2
[tex]\begin{gathered} 2\cos (x)=-\sqrt[]{3} \\ \text{divide both sides by 2} \\ \frac{2\cos(x)}{2}=\frac{-\sqrt[]{3}}{2} \\ \cos (x)=\frac{-\sqrt[]{3}}{2} \\ \end{gathered}[/tex]Step 3
c) finally,Inverse cosine in both sides ( remember we are looking for an angle)
[tex]\begin{gathered} \cos (x)=\frac{-\sqrt[]{3}}{2} \\ \text{ Inverse cosine in both sides} \\ \cos ^{-1}(\cos (x))=\cos ^{-1}(\frac{-\sqrt[]{3}}{2}) \\ x=\cos ^{-1}(\frac{-\sqrt[]{3}}{2}) \\ x=\cos ^{-1}(-0.86) \\ x=2.61\text{ radians} \end{gathered}[/tex]therefore, the answer is
x=2.61 radians
I hope this helps you
A mosquito was accelerating from rest at a rate of 0.15 m/s'. If she flew for 12 meters, what was her final velocity?
The final velocity of the mosquito if it was accelerating from rest at a rate of 0.15 m/s² and flew for 12 meters, is 1.8 m/s
What is velocity?velocity is a term used to describe how quickly and in what direction a point is moving. A point always moves in a direction that is perpendicular to its path; in the case of a circular path, for instance, its direction is always perpendicular to a line connecting the point to the circle's centre (a radius).
The speed at which a point is moving along a path is measured by the magnitude of the velocity.
When a point moves a specific distance along its path in a predetermined amount of time, the distance travelled divided by the time required represents the point's average speed during that time. For instance, the average speed of a train travelling 100 km in two hours is 50 km/h.
The formula for final velocity is
v² - u² = 2as
where v is the final velocity,
u is initial velocity,
a the acceleration and
s the distance
Assuming initial velocity to be 0
Substituting the values
v² - (0)² = 2(0.15)(12)
v = 1.8
So, The final velocity of the mosquito if it was accelerating from rest at a rate of 0.15 m/s² and flew for 12 meters, is 1.8 m/s.
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A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-g bullet moving with a speed of 1.50 x 103 m/s. What must the baseball’s speed be if the pitcher’s claim is valid?
ANSWER
3.10 x 10⁴ m/s
EXPLANATION
Given:
• The mass of the baseball. m₂ = 0.145 g
,• The mass of the bullet, m₁ = 3.00 g
,• The speed of the bullet, v₁ = 1.50 x 10³ m/s
Find:
• The speed of the ball, v₂, if it has the same momentum as the bullet.
The momentum of an object of mass m moving at a speed v is,
[tex]p=mv[/tex]So, in this problem, if both objects have the same momentum,
[tex]m_1v_1=m_2v_2[/tex]Solving for v₂,
[tex]v_2=\frac{m_1v_1}{m_2}[/tex]Replace the known values and solve,
[tex]v_2=\frac{3.00\text{ }g\cdot1.50\times10^3\text{ }m/s}{0.145\text{ }g}\approx3.10\times10^4m/s[/tex]Hence, the speed of the baseball must be 3.10 x 10⁴ m/s.
Which of the following statements about treating PTSD is true? a. By focusing on a person’s specific traumatic memory, trauma-focused therapy has been shown to be too narrow in scope to be helpful in treating PTSD. b. The American Psychological Association has issued guidelines to replace psychotropic interventions with trauma-focused therapy. c. The American Psychological Association has issued guidelines to replace cognitive-behavioral therapy with trauma-focused therapy. d. Trauma-focused therapy is gaining support as a first-line treatment showing longer-lasting results than psychotropic medication.
A person with PTSD has trouble bouncing back after experiencing or seeing a traumatic event.
With triggers producing intense emotional and physical reactions as well as memories of the incident, the syndrome can last for months or even years.
Affected individuals may experience nightmares or unwelcome recollections of the trauma, avoid situations that trigger those memories, have heightened reactions, experience anxiety, or experience depression.
Different forms of trauma-focused psychotherapy are utilized in treatment, along with drugs to treat symptoms.
Trauma-focused therapies maintain a constant focus on the trauma and its ensuing repercussions on the patient over the course of therapy. By exposing the patient to reminders of the traumatic incident, this method aids in the correction of incorrect cognitions and the reduction of symptoms.
"Trauma-focused treatment has been demonstrated to be too limited in scope to be effective in treating PTSD since it concentrates on a person's particular traumatic memory."
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Question 11 of 16 If a reaction occurs, what will be the products of the unbalanced reaction below? Zn(s) + HCl(aq) The Activity Series of Elements A. ZnH(s) + Cl2(9) OB. No reaction will occur. O C. HZnCl(s) O D. ZnCl2(s) + H2(9)
When zinc reacts with hydrochloric acid, zinc chloride and hydrogen gas will be produced.
i.e.,
[tex]Zn(s)+\text{HCl(aq)}\rightarrow ZnCl_2(s)+H_2(g)[/tex]Hence the correct answer is option D.
A box with a mass of 45.0 kg is pushed across a horizontal surface with a force of 19.0 N. What isthe acceleration of the box in meters per second squared?
Given data:
Mass of the box;
[tex]m=45.0\text{ kg}[/tex]Force;
[tex]F=19.0\text{ N}[/tex]The force is given as,
[tex]F=ma[/tex]Here, a is the acceleration of the box.
Rearraning the above equation to get an expression for acceleration,
[tex]a=\frac{F}{m}[/tex]Substituting all known values,
[tex]\begin{gathered} a=\frac{19\text{ N}}{45\text{ kg}} \\ =0.42\text{ m/s}^2 \end{gathered}[/tex]Therefore, the acceleration of the box is 0.42 meters per second squared.
What is the difference and similarity between ∆x & ∆y
The difference between ∆x & ∆y is found say in its position. ∆x refers to the change in the position of the horizontal direction while ∆y refers to the change in the vertical direction.
The similarity between ∆x & ∆y is that both of them has to express same nature of phenomena.
What is position?
Position is described as a place where someone or something is located or has been put.
x and y has been used in all sciences to denote known and unknown variables. ∆x & ∆y deals with the changes in those variables either known or unknown.
X is usually in the horizontal position while Y is in the vertical position.
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6kg of human blood at a temperature of 65degees celcius is mixed with 4kg of human blood ata temperature of 20 degrees celcius . evaluate the final temperature of the mixture
Answer:
[tex]T_f=47^{\circ}[/tex]Explanation: Two samples of blood that have different masses and temperatures and are mixed, we have to find the final temperature of the mixture. the final temperature can be found using the following formula:
[tex]T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1)[/tex](1) Formula basically tells us that the product of mass and temperature remains constant throughout, so the addition of two products of the two separate blood samples would be equal to the product of final temperature and the total mass of the mixture. Mathematically this means that:
[tex]\mleft(m_1+m_2\mright)T_f=(m_1\cdot T_1)+(m_2T_2)[/tex]Using (1) and plugging in the corresponding values, we get the answer as follows:
[tex]\begin{gathered} T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1) \\ m_1=6\operatorname{kg} \\ m_2=4\operatorname{kg} \\ T_1=65^{\circ} \\ T_2=20^{\circ} \\ \therefore\rightarrow \\ T_f=\frac{(6kg\cdot65^{\circ}+4\operatorname{kg}\cdot20^{\circ})}{(6kg+4\operatorname{kg})}=\frac{(390+80)}{10}=\frac{470}{10}=47^{\circ} \\ \therefore\rightarrow \\ T_f=47^{\circ} \end{gathered}[/tex]Electronegativity can best be defined as a) relative measure showing how many bonds an atom will formb) a relative measure showing the degree to which electrons can be removed from an atom c) the degree to which an electron will leave an atom d) the degree to which an atom wants to gain more electrons
The electronegativity of an element is the tendency of an atom to attract electrons to itself in a chemical compound.
The electronegativity decreases down the group and increases from left to right across the period.
Therefore, electronegativity can best be defined as the degree to which an atom wants to gain more electrons. Hence, option (d) is the correct choice.
A net force of 20 Newtons acts on and object of mass 5.0 kilograms for 5.0 seconds. What is the magnitude of the impulse?
The impulse of the objects is N-s.
In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton-seconds or kilograms per second and is denoted by the symbol J.
We are given that,
The net force acted on the object = F = 20 N
The mass of the object = m = 5.0kg
The total time taken = t = 5.0s
Therefore, the impulse of the object can be calculated by the formula,
J = F × t
Where, J is the impulse on the object, F is the force on the object , t is the total time taken ,
J = 20N × 5.0sec
J = 100 N-sec
Thus , the total impulse on the object would be 100N-sec.
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This defense mechanism offers self-justifying explanations in place of the real, more threatening, unconscious reasons for one's actions. This is known as:
This defense mechanism offers self-justifying explanations in place of the real, more threatening, unconscious reasons for one's actions. This is known as Rationalization.
According to the question, rationalization is a defense mechanism, and the phrase refers to the act of justifying through the creation of numerous sorts of justifications, explanations, and reasons for any behavior.
A coherent, logically ordered system that also serves to rationalize an individual's unconscious motivation for acting is referred to as a rationalization.
One method of reorganizing a business to improve operational effectiveness and alter organizational policy is rationalization.
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Calculate the resultant displacement for the following 10km left,20 km right,30 km left.polygon method
The resultant displacement of the object is 20 km left.
What is resultant displacement?
The resultant displacement of an object is the net or sum of all the distance travelled by an object in a given direction.
The given position of the object;
first position, = 10 km leftsecond position = 20 km rightthird position = 30 km leftThe resultant displacement is calculated as follows;
D = -10 km + 20 km - 30 km
D = 20 km - 40 km
D = -20 km
Thus, the magnitude and direction of the resultant displacement of the object is 20 km and left respectively.
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Solve for the impulse imparted on the golf ball.
t = 0.001 s
F = 2000 N
Answer:
2 N s
Explanation:
Impulse = force * time
= 2000 N * .001 s = 2 N s
How much work does a 12-V battery do in pushing 2 mC of charge through a circuit containing onelight bulb?
Given data:
[tex]\begin{gathered} V=12\text{ V} \\ Q=2\text{ mC} \end{gathered}[/tex]The work done is given as,
[tex]W=QV[/tex]Putting all known values,
[tex]\begin{gathered} W=2\times10^{-3}\text{ C}\times12\text{ V} \\ =24\text{ mJ} \end{gathered}[/tex]Therefore, 24 mJ of the work is done.
ㄱ Question 18 of 25 Studying the solar system helps scientists learn about the universe. Why might a scientist use a model to represent the solar system? O A. The actual solar system is too large. B. The actual solar system is too small. C. The actual solar system is too simple. D. The actual solar system moves too slowly. SUBMIT it's A
A hockey stick 1.1 m long completes a swing in 0.15 seconds through a range of 85°. Assume a uniform angular velocity. What is the linear distance moved by the end of the stick? What is the tangential velocity of the end of the stick?
The linear distance and the tangential velocity of the end of the stick are 1.63 m and 10.9 m/s respectively.
What is rotational motion?Rotational motion is the motion of a body around a circular path, in a fixed orbit. The dynamics for rotational motion are entirely analogous to linear or translational dynamics. The equations for rotating objects are similar to the motion equations for linear motion.
Given, the length of the hockey stick, r = 1.1 m
The hockey stick completes one swing in time, t = 0.15 sec
The angle θ = 85° = 1.483 rad
The average angular velocity of the hockey stick,
ω = θ/t = 1.483rad/0.15s = 9.9 rad/s
The linear distance moved by the end of the hockey stick:
L = rθ = 1.1× 1.483 = 1.63 m
The tangential velocity of the end of the hockey stick:
v = rω = 1.1 × 9.9 = 10.9 m/s
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Julie flew 450 miles to Connecticut to visit her sister and then returned three days later. At the end of the trip, what was her displacement and distance traveled?
a. 450 miles; 0 miles
b. 900 miles; 0 miles
c. 0 miles; 900 miles
d. 450 miles, 450 miles
Submission
VIEW GRADE DETAILS
Julie travelled displacement of 0 miles distance of 900 miles. So the correct answer is option (C) 0 miles; 900 miles.
According to question, Julie travelled from Connecticut to visit her sister is 450 miles and return back to Connecticut .
Here, total journey = distance travelled by Julie = 450 + 450 = 900 miles.
Displacement is shortest distance from point one to other, but here Julie return back to her initial point. So, the displacement is zero.
Distance is the total journey travelled between two points from one point to other. Its magnitude cannot be zero. Its S.I. unit is meter.
Displacement is the shortest distance between two points. Its magnitude may be zero. Its S.I. unit is meter.
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Dots sells a total of 266 T-shirts ($2) and shorts ($4). In April, total sales were $672.How many T-shirts and shorts did Dots sell? Hint: Let S = Shorts.
Let x be the number of t-shirts and y the number of shorts they sold. Since in total they sold 266 items we have the equation:
[tex]x+y=266[/tex]Now we know that each shirt cost $2 and each short cost $4 and that the total sales were $672 then we have the equation:
[tex]2x+4y=672[/tex]Hence we have the system of equations:
[tex]\begin{gathered} x+y=266 \\ 2x+4y=672 \end{gathered}[/tex]Solving for y from the first equation we have:
[tex]y=266-x[/tex]Plugging this in to the second equation we have:
[tex]\begin{gathered} 2x+4(266-x)=672 \\ 2x+1064-4x=672 \\ -2x=672-1064 \\ -2x=-392 \\ x=\frac{-392}{-2} \\ x=196 \end{gathered}[/tex]Plugging this value in the equation for y we have:
[tex]y=266-196=70[/tex]Therefore the sold 196 shirts and 70 shorts.
Find the equation of a line passing through (8, 43.6) and (4.5, 26.3)
5x + y = 3.6 equation of a line going between (8, 43.6) and (4.5, 26.3).
Write about a vector?Having independent properties for both size and direction, a quantity or phenomenon is referred to as a vector. The representation of a quantity in mathematics or geometry is another use of the term. In nature, vectors include things like force, momentum, weight, electromagnetic fields, and velocity.
Exactly what is a unit vector?Unit vectors are those that have a magnitude that is exactly one unit. They are quite useful for a variety of reasons. The unit vectors [0,1] and [1,0] in particular can be combined to create any other vector.
The slope of the line joining points A(8,43.6) and B(4.5,26.3) is given by the equation m= y2-y1/x2-x1=26.3-43.6/4.5-8 = 5.
Consequently, the equation for the line that is required is given by y-y1 = m. (x-x1)
y- 43.6 = 5(x-8) =5x + y = 3.6.
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what is scientific knowledge
Answer: Based on evidence
Explanation: Scientific knowledge is based on evidence and is included in scientific theories: consistent and deductively complete sets of propositions around a topic of scientific interest, which describe it and give it a verifiable explanation.
You observe that 34 crests of a water wave pass you each minute. if the wavelength is 12 m, what is the speed of the wave?
ANSWER:
6.8 m/s
STEP-BY-STEP EXPLANATION:
We must calculate the frequency, knowing that per minute (60 seconds) there are 34 crests, therefore:
[tex]f=\frac{34}{60}=0.57\text{ Hz}[/tex]Therefore, the speed of the wave would be:
[tex]\begin{gathered} s=f\cdot w \\ s\text{ =speed} \\ f=\text{ frequency = 0.57 Hz} \\ w\text{ = wavelength = 12 m} \end{gathered}[/tex]Replacing:
[tex]\begin{gathered} s=0.57\cdot12 \\ s=6.8\text{ m/s} \end{gathered}[/tex]The speed of the wave is 6.8 m/s
in order to you need to apply a force of 1700N to the baseball. How much work done on baseball to hit a distance of 110m? How much power is delivered to the baseball the hitter takes 0.35s to swing the bat?
F = 1700N
Work = ?
mass = 0.14kg
distance = 110m
Work = Force * distance = 1700N * 110 m = 187,000J
Power = Work/ time = 187000J/0.35 = 534,285.7 Watts
8. Climbing a mountain, your water bottle falls and hits the ground. If it is moving at 30m/s upon impact. how far did it fall?
Answer:
45.9 m
Explanation:
FIRST:
vf = a t
30 = 9.81 (t) shows t = 3.06 s
THEN:
df = 1/2 a t^2
= 1/2 ( 9.81)(3.06)^2 = 45.9 m
Please answer 9 only. Simple answer and simple explanation is needed, thanks.
Answer:
a = -493.83 m/s²
Explanation:
The acceleration can be calculated as:
[tex]a=\frac{v_f-v_i}{t}[/tex]Where vf is the final velocity, vi is the initial velocity and t is the time.
Then, we need to convert 320 km/h to m/s as follows:
[tex]320\frac{\operatorname{km}}{h}\times\frac{1000m}{1\operatorname{km}}\times\frac{1h}{3600s}=88.89\text{ m/s}[/tex]Now, we can replace vf by 0 m/s, vi by 88.89 m/s, and t by 0.18 s to get an acceleration equal to:
[tex]\begin{gathered} a=\frac{0-88.89\text{ m/s}}{0.18s}=\frac{-88.89\text{ m/s}}{0.18s}=-493.83m/s^2 \\ \end{gathered}[/tex]Therefore, the acceleration that takes place in this time is equal to -493.83 m/s²
What’s the magnitud of the force?
F=(557N)i-(611N)j+(468N)k
Answer: 950.05 N
Explanation: