2
The table gives the melting and boiling points of four pure substances, W, X, Y and Z.
Melting point in °C
Boiling point in °C
w
-7
60
Х
660
2500
Y
180
1330
Z
115
445
Use data from the table to answer the questions.
(a) (0) Which substance is a gas at 100°C?
X AW
B X
D CY
DZ
(ii) Which substance is a liquid for the largest range of temperature?
D A W
B X
CY
DZ
liquid at 1000 °C and a gas at 2000°C?​

Answers

Answer 1

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance     Melting Point (°C)       Boiling Point (°C)

     W                       -7                                  60

     X                       660                              2500

     Y                        180                               1330

     Z                         115                                445

Let's consider that:

Below the melting point, a substance is solid.Between the melting and the boiling point, a substance is liquid.Above the boiling point, a substance is gas.

(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?​

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.


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which elements are out of order in terms of atomic mass. co,Ni or Li,be or I,xe​

Answers

Answer:

The pair co,Ni is out of order in terms of atomic mass

Explanation:

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Answers

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sorry if i am wrong heh

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Pb(NO3)2(aq)+2KCI(aq)------- PbCl2(s)+2KNO2 (aq). how many grams of PbCl2 solution will react with a 0.46L of a 0.101m KCI solution​

Answers

Answer:

6.46g of PbCl2 are produced

Explanation:

The PbCl2 will not react, is a product of the reaction. The question must be say how many grams of PbCl2 will be produced

Based on the chemical reaction:

Pb(NO3)2(aq)+2KCI(aq) → PbCl2(s)+2KNO2 (aq)

1 mole of PbCl2 is produced when 2 moles of KCl are reacting.

To solve this question we must find the moles of KCl that will react. With these moles we can find the moles of PbCl2 and the grams produced using its molar mass:

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0.46L * (0.101moles / L) = 0.04646 moles KCl

Moles PbCl2:

0.04646 moles KCl * (1mol PbCl2 / 2mol KCl) =

0.02323 moles of PbCl2 are produced

Mass -Molar mass PbCl2: 278.106g/mol-

0.02323 moles * (278.106g / mol) =

6.46g of PbCl2 are produced

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Answer:

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◕‿↼ Hey There!

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Answers

Answer:

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Explanation:

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GOT IT RIGHT ON MY ASSIGNMENT

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