5th grade math. correct answer will be marked brainliest

Answer: [tex]w\geq 20[/tex]

Step-by-step explanation:

Solve this like it's an equation

6w+30>150 (i know it is larger than or equal to)

6w>120

w>120/6

w>20

Answer:

The answer is 20

Step-by-step explanation:

6w+30≥150

6w≥150-30

6w≥120

divide both sides by 6

6w/6≥120/6

w≥20

we can say

w=20 since w is greater than or equal to

Answer:

3,454 cm³

Step-by-step explanation:

This is a cylinder so the volume formula is [tex]V=\pi r^{2} h[/tex]

The problem gives us the diameter (20 cm) and the height (11 cm). Since the formula uses the radius instead of the diameter, we have to divide the diameter by 2.

20 ÷ 2 = 10

The radius is 10 cm

Now, we plug our height and radius into the formula to find the volume.

[tex]V=\pi r^{2} h\\V=(\frac{22}{7})(10)^{2}(11)\\V=(\frac{22}{7})(100)(11)\\[/tex]

V≈3,454

Answer:

Yes lol

Step-by-step explanation:

Well the app says it helps people learn the answers but when I'm in a test i just look at letters:)

Answer:

I mean i'm the type to give a long winded answer. But i guess it depends on the context. Sometimes people ask for an explanation yk? Like most of those ppl who ask questions for History and English need a written response.

Answer:

-4, -7, -2, -5, 0, -3, 2, -1

Step-by-step explanation:

the pattern is -3, +5.

i hope this helps :)

Answer:

v = -3/2

Step-by-step explanation:

6v = -9

v = -9/6

v = -3/2

Answer:

Step-by-step explanation:

       Location    Reflect over x              Reflect over y

B      -0.75 ,1         -0.75 ,-1                           +0.75 ,1

C     1.75 ,-1          1.75,1                                 -1.75,+1

D      -2,-2           -2,+2                                  +2 ,-2

Trick question! All are rational numbers.

..................................................................................

The integral becomes:

V = ∫₀¹ ∫₀²π (1 − r²) r dθ dr

To find the volume of the solid enclosed by the surface z = 1 − x² − y² and the xy-plane, we need to integrate the function f(x, y) = 1 − x² − y² over the region in the xy-plane where z is positive.

Since the surface z = 1 − x² − y² represents a downward-opening paraboloid, we can set up the integral as follows:

V = ∬R (1 − x² − y²) dA

Here, R represents the region in the xy-plane bounded by the curve x² + y² = 1. To evaluate this integral, we can switch to polar coordinates. In polar coordinates, the region R corresponds to the interval 0 ≤ θ ≤ 2π and 0 ≤ r ≤ 1. The differential area element dA in polar coordinates is r dr dθ.

Evaluating this double integral will give us the volume of the solid enclosed by the surface and the xy-plane.

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The harmonic conjugate of u(x, y) = 2x(1 - y) is v(x, y) = 2y - y² - x² + C, where C is an arbitrary constant.

Here we want to find the harmonic conjugate of:

u(x, y) = 2x*(1 - y)

To do so, we need to use the Cauchy-Riemann equations state that for a function f(z) = u(x, y) + iv(x, y) to be analytic (holomorphic), the partial derivatives of u and v must satisfy the following conditions:

∂u/∂x = ∂v/∂y

∂u/∂y = -∂v/∂x

Let's find the harmonic conjugate by solving these equations:

Given u(x, y) = 2x(1 - y)

∂u/∂x = 2(1 - y)

∂u/∂y = -2x

Setting these derivatives equal to the respective partial derivatives of v:

∂v/∂y = 2(1 - y)

∂v/∂x = -2x

Now, integrate the first equation with respect to y, treating x as a constant:

v(x, y) = 2y - y² + f(x)

Differentiate the obtained equation with respect to x:

∂v/∂x = f'(x)

Comparing this derivative with the second equation, we have:

f'(x) = -2x

Integrating f'(x) with respect to x:

f(x) = -x² + C

where C is a constant of integration.

Now, substitute f(x) into the equation for v(x, y):

v(x, y) = 2y - y² - x² + C

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Answer:

40.2 in²

Step-by-step explanation:

h*b/2

h= 6.7

b= 12

Answer:

y

Step-by-step explanation:

y needs to provide a number

Answer:

$400

Step-by-step explanation:

Let the initial total cost be represented = $X.

Hence, for 20 family members

= $ x/20 each .......1

Now that they are 25 members

= $x/25 each.......2

Each in the original group which is equation 1 owed $4 less.

That is,

x/20 - 4 ........ 3

Now equate 2 and 3

X/20 - 4/1 = X/25

Taking the LCM of both sides

X-80/20 = X/25

Cross multiply both sides

25( x-80 ) = 20x

25x-2000 = 20x

Collecting like terms

25x-20x = 2000

5x = 2000

Divide through by 5

X = 2000/5

X = 400

The total cost for the catered meal is $400.

To check if it was correct

Put 400 into equation 1 and 2 and then minus whatever you get from each other, you will get $4

From equation 1

400/20 = $20

From equation 2

400/25 =$16

$20-$16 = $4

Thanks

Answer:

0

Step-by-step explanation:

HOPE I HELPED!

In part (a) of the problem, the task is to find the determinant of the given matrix M by showing all the steps of the calculation. In part (b), we are given three matrices A, B, and C with det A = -2.

(a) To find the determinant of matrix M, we can use various methods such as cofactor expansion or row operations. Let's use cofactor expansion along the first row:

det M = 2 * (-1)^(1+1) * det [[2 8 0] [17 24 0] [10 -13 1]]

- 2 * (-1)^(1+2) * det [[4 8 0] [1 24 0] [10 -13 1]]

Simplifying and evaluating the determinants of the 2x2 matrices, we get:

det M = 2 * (2 * 24 - 17 * (-13))

- 2 * (4 * 24 - 1 * (-13))

After performing the calculations, we find the determinant of matrix M.

(b) The given information states that det A = -2. However, no specific task or question is mentioned regarding matrices A, B, and C. Further instructions or requirements are needed to provide a specific answer or analysis based on the given information.

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The exact value of A in the general solution y = A + cx is 75

From the question, we have the following parameters that can be used in our computation:

y = A + cx

The differential equation is given as

y - xy' = 75

When y = A + cx is differentiated, we have

y' = c

So, we have

y - xc = 75

Recall that

y = A + cx

So, we have

A + cx - xc = 75

Evaluate the like terms

A = 75

Hence, the value of A in the general solution is 75

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To calculate the probability of winning a certain lottery where you must select 5 numbers out of 29 in any order, we can use the concept of combinations. The probability of winning can be determined by dividing the number of successful outcomes (winning combinations) by the total number of possible outcomes.

In this lottery, you need to select 5 numbers out of 29, and the order of selection doesn't matter. The total number of possible outcomes is given by the combination formula, which is denoted as C(29, 5) and calculated as

29! / (5! * (29-5)!).

To win, you have only one successful outcome, which is the combination of the 5 winning numbers. Therefore, the probability of winning can be calculated as 1 / C(29, 5). Evaluating this expression will give you the probability of winning the lottery with a single-ticket purchase.  

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Answer:

Multiply the volume of the cone by 3

Step-by-step explanation:

Required

Volume of a cylinder from a cone of the same dimension

The volume of a cone is:

[tex]V_1 = \frac{1}{3}\pi r^2h[/tex]

The volume of a cylinder is:

[tex]V_2 = \pi r^2h[/tex]

Recall that:

[tex]V_1 = \frac{1}{3}\pi r^2h[/tex]

Split:

[tex]V_1 = \frac{1}{3}*[\pi r^2h][/tex]

Substitute: [tex]V_2 = \pi r^2h[/tex]

[tex]V_1 = \frac{1}{3}*V_2[/tex]

Make V2 the subject

[tex]V_2 =3V_1[/tex]

This implies that, we simply multiply the volume of the cone by 3

Answer:

628 ft

Step-by-step explanation:

The volume of cylinder is, V= 628 ft³.

The amount of space occupied by a three-dimensional figure as measured in cubic units.

Given:

radius,r= 5 ft, height, h = 8 ft

Volume= πr²h

V= 3.14 * 5 *5 * 8

V= 628 ft³

Hence, the volume of cylinder is 628 ft³.

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the value of A in the function f(x) = 2x³ + Ax² + 8x - 3 is -7.

To find the value of A in the function f(x) = 2x³ + Ax² + 8x - 3, we are given that f(2) = 1. Substituting x = 2 into the function, we have:

f(2) = 2(2)³ + A(2)² + 8(2) - 3

Simplifying further:

1 = 2(8) + 4A + 16 - 3

1 = 16 + 4A + 13

Combining like terms:

1 = 29 + 4A

To isolate A, we subtract 29 from both sides:

-28 = 4A

Finally, we divide both sides by 4 to solve for A:

A = -7

Therefore, the value of A in the function f(x) = 2x³ + Ax² + 8x - 3 is -7.

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X denote the amount of time a book on two-hour reserve is actually checked out, and for the given cdf the following are the answers for the questions asked

(a) P(X ≤ 1) ≈ 0.0625

(b) P(0.5 ≤ X ≤ 1) ≈ 0.0469

(c) P(X > 1.5) ≈ 0.8594

(d) Median checkout duration ≈ 2.828

(e) Density function f(x) is defined as:

f(x) = 0 for x < 0

f(x) = x/8 for 0 ≤ x ≤ 4

f(x) = 0 for x > 4

(f) Expected value E(X) ≈ 2.667

(g) Variance V(X) ≈ 0.889, Standard Deviation σ(X) ≈ 0.943

(h) Expected charge E[h(X)] = 8

In probability theory, a cumulative distribution function (CDF) provides information about the probabilities of certain events occurring in a random variable. In this scenario, let's consider a book that is on a two-hour reserve and denote the amount of time it is checked out as X. We are given the CDF of X and we will use it to calculate various probabilities and statistics related to the checkout duration of the book.

The given CDF is as follows:

F(x) = 0 for x < 0

F(x) = x²/16 for 0 ≤ x ≤ 4

F(x) = 1 for x > 4

(a) P(X ≤ 1):

To calculate this probability, we need to find F(1) since F(x) represents the cumulative probability up to x. From the given CDF, we see that F(x) = x²/16 for 0 ≤ x ≤ 4. Substituting x = 1 into the equation, we get:

F(1) = (1²)/16 = 1/16.

(b) P(0.5 ≤ X ≤ 1):

To calculate this probability, we need to find F(1) - F(0.5) since F(x) represents the cumulative probability up to x. From the given CDF, we have F(0.5) = (0.5²)/16 = 1/64 and F(1) = (1²)/16 = 1/16. Therefore,

P(0.5 ≤ X ≤ 1) = F(1) - F(0.5) = (1/16) - (1/64) = 3/64.

(c) P(X > 1.5):

To calculate this probability, we need to find 1 - F(1.5) since F(x) represents the cumulative probability up to x. From the given CDF, we have F(1.5) = (1.5²)/16 = 9/64. Therefore,

P(X > 1.5) = 1 - F(1.5) = 1 - (9/64) = 55/64.

(d) Median checkout duration:

The median is the value that divides the distribution into two equal parts, meaning that half of the checkouts are below this value and half are above it. We need to solve the equation F(median) = 0.5. From the given CDF, we have:

F(median) = 0.5

0.5 = (median²)/16

Solving for the median, we get median = √(8) ≈ 2.828.

(e) Density function f(x):

The density function f(x) represents the derivative of the cumulative distribution function F(x). To obtain f(x), we differentiate the given CDF:

f(x) = F'(x)

For x < 0, f(x) = 0 since F(x) is constant in that range.

For 0 ≤ x ≤ 4, we have F(x) = x²/16.

Differentiating with respect to x, we get:

f(x) = d/dx (x²/16) = (2x)/16 = x/8.

For x > 4, f(x) = 0 since F(x) is constant in that range.

Therefore, the density function f(x) is:

f(x) = 0 for x < 0

f(x) = x/8 for 0 ≤ x ≤ 4

f(x) = 0 for x > 4

(f) Expected value E(X):

The expected value of a random variable X is a measure of its average value. To calculate E(X), we integrate the product of x and the density function f(x) over the entire range of X:

E(X) = ∫[x * f(x)] dx

For x < 0 and x > 4, f(x) = 0, so we only need to consider the interval 0 ≤ x ≤ 4:

E(X) = ∫[x * (x/8)] dx

= (1/8) ∫[x²] dx (integrating x²)

= (1/8) * (x³/3) + C (integrating x²)

= (1/24) * (x³) + C

Evaluating this expression from x = 0 to x = 4, we get:

E(X) = (1/24) * (4³) - (1/24) * (0³)

= 64/24

= 8/3

≈ 2.667

(g) Variance V(X) and Standard Deviation σ(X):

Variance is a measure of the spread or dispersion of a random variable. To calculate V(X), we need to calculate the second moment E(X²) and subtract the square of the expected value [E(X)]². The standard deviation σ(X) is the square root of the variance.

E(X²):

E(X²) = ∫[x² * f(x)] dx

For x < 0 and x > 4, f(x) = 0, so we only need to consider the interval 0 ≤ x ≤ 4:

E(X²) = ∫[x² * (x/8)] dx

= (1/8) ∫[x³] dx (integrating x³)

= (1/8) * (x⁴/4) + C (integrating x³)

= (1/32) * (x^4) + C

Evaluating this expression from x = 0 to x = 4, we get:

E(X²) = (1/32) * (4⁴) - (1/32) * (0⁴)

= 256/32

= 8

V(X):

V(X) = E(X²) - [E(X)]²

= 8 - (8/3)²

= 8 - 64/9

= 8 - 7.111

≈ 0.889

Standard deviation:

σ(X) = √(V(X))

= √(0.889)

≈ 0.943

(h) Expected charge E[h(X)]:

Given the function h(X) = X², we want to calculate the expected value of h(X). This can be done by finding E[h(X)] = E(X²).

From the previous calculations, we know that E(X²) = 8. Therefore, the expected charge is E[h(X)] = 8.

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Answer:

The angle that will be congruent to angle 4 is :

                             Angle 1

Step-by-step explanation:

It is given that:

angle 4 and angle 5 are complements.

Also, angle 1 and angle 5 are complements.

Congruent complementary Theorem--

It states that if two angles are complementary to the same angle, then the two angles are congruent to each other.

Here both angle 1 and angle 4 are complementary to the same angle i.e. angle 5.

Answer:16

Step-by-step explanation:

33-9=24

24/1.50=16

Answer:

Rewrite the question correctly! it's totally absurd

Answer:

one hundred thirty-two

Step-by-step explanation:

should be it if it is can i get brainliest?

option D: Horizontal scale: 1 unit = 10, Vertical scale: 1 unit = 10 is the correct answer.

To determine an appropriate horizontal scale and vertical scale for the viewing window, one must analyze the problem, the graph, and the data presented in the problem. The appropriate horizontal scale and vertical scale for the viewing window is given by option D, that is Horizontal scale: 1 unit = 10, Vertical scale: 1 unit = 10. The horizontal scale and vertical scale refer to the scale of the x-axis and y-axis of the graph. These scales are used to represent data in a graphic format that can be easily understood by readers. The horizontal scale is used to determine the value of the x-axis in the graph. The vertical scale is used to determine the value of the y-axis in the graph. The scale should be chosen based on the range of values in the graph. When the values in the graph are too small or too large, the scale must be adjusted accordingly. In this case, since the values of horizontal and vertical scale are large, the scale must be adjusted accordingly. Therefore, option D is the correct answer.

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The size of the horizontal and vertical scales should be chosen so that the graph fits in the viewing window. So, that is why the answer is "b. Horizontal scale: 1 unit = 5, Vertical scale: 1 unit = 10."

When graphing a function, it is important to choose an appropriate horizontal scale and vertical scale for the viewing window. The answer is "b. Horizontal scale: 1 unit = 5, Vertical scale: 1 unit = 10."Why is the answer (b) Horizontal scale: 1 unit = 5, Vertical scale: 1 unit = 10?The answer to this question is based on the graph. It is more appropriate to use (b) horizontal scale: 1 unit = 5, vertical scale: 1 unit = 10. In this situation, the x-axis should have a horizontal scale of 1 unit = 5 so that the x-axis can fit within the viewing window. Meanwhile, the y-axis should have a vertical scale of 1 unit = 10 so that the entire graph can fit in the viewing window.

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Answer:

The answer to this problem Is A I think

Step-by-step explanation:

Answer:

C NO TOO HOT OR TOO COLD

Step-by-step explanation:

Answer:

the answer is c

Step-by-step explanation:

Brainliest plz