Answer:
v=2
Step-by-step explanation:
6(5-8v)+12=-54
6(5-8v)=-66
(6(5-8v))/6=-66/6
5-8v=-11
-8v=-11-5
-8v=-16
Round 17.68694 to the nearest tenth
Answer:
17.7
Step-by-step explanation:
The tenths place is the very first value after the decimal. The number 17.68694 rounds up to 17.7, because .68 is closer to .7 than it is to .6.
why does the graph of a proportional relationship must pass through the origin (0,0)
Answer:
Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.
The graph of a proportional relationship must pass through the origin (0,0). Because of the value of k, the ordered pair (0, 0) satisfies this equation.
What is a graph?
The relation between lines and points is described by a graph, which is a mathematical description of a network. A graph is made up of some points and connecting lines. It doesn't matter how long the lines are or where the points are located. A node is specified for each element in a graph.
A ray is used to describe any proportional relationship using an equation of the form y = kx. The ordered pair (0, 0) satisfies this equation regardless of the value of k, hence the ray or line must traverse the origin.
Thus, the graph of a proportional relationship must pass through the origin (0,0). Because of the value of k, the ordered pair (0, 0) satisfies this equation.
Learn more about the graph here,
https://brainly.com/question/17267403
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Do these ratios make a proportion? 4:10 and 6:15
I NEED THIS ASAP!!! Thanks!
To see if these ratios make a proportion let us first change them into fractions
= 4:10 = 4/10 = 4 ÷ 2 / 10 ÷ 2 = 2/5
= 6:15 = 6/15 = 6 ÷ 3 / 15 ÷ 3 = 2/5
= Since both these ratios are getting simplified into a same fraction , they are proportional .
Therefore , 4 : 10 :: 6 : 15 ( 4 : 10 is proportional to 6 : 15 )
Soft drinks are often sold in six-packs of 12-ounce cans and in 2-liter bottles. A liter is about 33.8 fluid ounces.
Which is the greater volume: a six-pack or 2 liters?
A store offers a 2-liter bottle of soft drink for $1.31 and a six-pack of 12-ounce cans for $1.37. Which is the better value (based on price per ounce)?
Answer:
List some of the given data:
1 L = 33.8 oz.
A) Which one has more volume?
In a six-pack, each can has 12 oz.
Then in total, this is:
6*12oz = 72oz.
In one liter we have 33.8 oz.
Then in two liters, we have two times that:
2L = 2*33.8 oz = 67.7 oz.
Then the sixpack has more volume.
B) Which one has more value?
Here we must divide the volume by the price:
Six-pack:
Volume = 72 oz.
Price = $1.37
Ratio = 72oz/$1.37 = 52.55 oz/$.
2L bottle:
Volume = 67.7 oz
Price = $1.31
Ratio = 67.7oz/$1.31 = 51.68 oz/$.
You can see that the ratio is larger in the case of the six-pack, this means that you get more ounces for each dollar.
Choose h and k such that the system has (a) no solution, (b) a unique solution, and (c) many solutions.
x1 +hx2 = 3
5x1 + 15x2 = k
a. Select the correct answer below and fill in the answer box(es) to complete your choice. (Type an integer or simplified fraction.)
A. The system has no solutions only when k nothing and h is any real number.
B. The system has no solutions only when h nothing and k nothing.
C. The system has no solutions only when h nothing and k is any real number.
D. The system has no solutions only when h nothing and k nothing.
E. The system has no solutions only when h nothing and k nothing.
F. The system has no solutions only when k nothing and h is any real number.
G. The system has no solutions only when h nothing and k nothing.
H. The system has no solutions only when h nothing and k is any real number.
b. Select the correct answer below and fill in the answer box(es) to complete your choice. (Type an integer or simplified fraction.)
A. The system has a unique solution only when h and k
B. The system has a unique solution only when h =-and k is any real number.
C. The system has a unique solution only when k | and h is any real number.
D. The system has a unique solution only when h-U and k = 1
Answer:
a) C) The system has no solutions only when h=3 and k is any real number.
b) D) The system has a unique solution when [tex]h=(-\infty,3)U(3,\infty)[/tex] and k is any real number.
c) The system has may solutions when h=3 and k=15
Step-by-step explanation:
a) In order to determine when the system will have no solution, we can start by solving the equation by substitution. We can solve the first equation for x1:
[tex]x_{1}+hx_{2}=3[/tex]
so
[tex]x_{1}=3-hx_{2}[/tex]
Next we can substitute this into the second equation so we get:
[tex]5(3-hx_{2})+15x_{2}=k[/tex]
We distribute the 5 into the first parenthesis so we get:
[tex]15-5hx_{2}+15x_{2}=k[/tex]
and group like terms:
[tex]-5hx_{2}+15x_{2}=k-15[/tex]
we factor x2 so we get:
[tex]x_{2}(-5h+15)=k-15[/tex]
and solve for x2:
[tex]x_{2}=\frac{k-15}{-5h+15}[/tex]
this final answer is important because it tells us what value the system of equations is not valid for. That answer will not ve vallid if the denominator is zero, so we can set the denominator equal to zero and solve for h, so we get:
[tex]-5h+15= 0[/tex]
and solve for h:
[tex]-5h= -15[/tex]
[tex]h=\frac{-15}{-5}[/tex]
[tex]h= 3[/tex]
so it doesn't really matter what value k gets since all that matters is that the denominator of the answer isn't zero.
b)
For part b we need to know when the system of equations will have infinitely many answers. Generally, this will happen when both equations are basically the same, so we need to make sure to simplify the second equation so it looks like the first equation, compare them and determine the respective coefficients.
So we take the second equation and factor it:
[tex]5x_{1}+15x_{2}=k[/tex]
we start by factoring a 5 from the left side of the equation so we get:
[tex]5(x_{1}+3x_{2})=k[/tex]
Next, we divide both sides of the equation into 5 so we get:
[tex]x_{1}+3x_{2}=\frac{k}{5}[/tex]
we now compare it to the first equation:
[tex]x_{1}+hx_{2}=3[/tex]
[tex]x_{1}+3x_{2}=\frac{k}{5}[/tex]
In this case, every coefficient of the two equations must be the same for us to get infinitely many answers, so we can see that h=3 and [tex]\frac{k}{5}=3[/tex]
when taking the second condition and solving for k we get that:
[tex]k=3(5)[/tex]
so
k=15
Anything else than the specific combination h=3 and k=15 will give us unique solutions, so for b, the answer is:
D) The system has a unique solution when and k is any real number.
c)
We have already solved part c on the previous part of the problem, so the answer is:
The system has many solutions when h=3 and k=15
What is the smallest value that x^(2)+6 can have?
Answer:
-56.9034
Step-by-step explanation:
Part b at the airport to walk from the car to the waiting area by the gate was
Answer:
24
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
Translate the sentence into an equation.
Twice the difference of a number and 2 equals 6.
Use the variable b for the unknown number.
Answer:
b + 2 = 6
Step-by-step explanation:
This may not be the right answer, but its what I think it is.
make a table and graph the solutions of each equation y=3x+1
Answer:
i can't graph it but i'll give you the points to graph
Step-by-step explanation:
(-2, -5) (-1,-2) (0,1) (1,4) (2,7)
start at the point in bold
salome tiene 4 veces la edad de esmeralda.si ambas edades suman 75 años¿que edad tiene cada una?
Is it -56/65????????????????
Answer:
[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]
Good job!
Step-by-step explanation:
[tex] \cos (u + v) = \cos u \cos v - \sin u \sin v [/tex]
[tex] \sin u = -\dfrac{3}{5} [/tex]; u is in QIII.
That makes [tex] \cos u = -\dfrac{4}{5} [/tex]
[tex] \sin v = -\dfrac{12}{13} [/tex]; v is in QIV.
That makes [tex] \cos v = \dfrac{5}{13} [/tex]
[tex] \cos (u + v) = (-\dfrac{4}{5})(\dfrac{5}{13}) - (-\dfrac{3}{5})(-\dfrac{12}{13}) [/tex]
[tex] \cos (u + v) = -\dfrac{20}{65} - \dfrac{36}{65} [/tex]
[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]
You are correct.
Answer:
Step-by-step explanation:
-0.8615
ayuda nose ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Round 555 to nearest 10
Answer: 600
Step-by-step explanation: 555
The five in the tens place is equal to 5
To round to the nearest tens place the number has to be 5 or more than 5
Let f and g be the functions defined by f(t) = 2t2 and g(t) = t3 + 4t.
1) Determine f'(t) and g′(t).
2) Let p(t) = 2t2 (t3 + 4t) and observe that p(t) = f(t) ⋅ g(t). Re-write the formula for p by distributing the 2t2 term. Then, compute p′(t) using the sum and constant multiple rules.
3) p′(t) = f′(t) ⋅ g′(t).
A. True
B. False
4) Let q(t) = t3 + 4t2/2t2 and observe that q(t) = g(t)/f(t). Rewrite the formula for q by dividing each term in the numerator by the denominator and simplify to write q as a sum of constant multiples of powers of t. Then, compute q′(t) using the sum and constant multiple rules.
5) q′(t) = g′(t)/f'(t).
A. True
B. False
Answer:
1) [tex]f'(t)=4t,\ g'(t)=3t^2+4[/tex]
2) [tex]p(t) =2t^5+8t^3[/tex]
[tex]p'(t)=10t^4+24t^2[/tex]
3) False
4)[tex]q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]
[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]
5) False
Step-by-step explanation:
Given that:
[tex]f(t) = 2t^2[/tex] and [tex]g(t) = t^3 + 4t[/tex]
Formula:
[tex]1. \dfrac{d}{dx}x^n=nx^{n-1}[/tex]
[tex]2. \dfrac{d}{dx}C.f(x)=C.f'(x)\ \{\text{C is a constant}\}[/tex]
1) Using above formula:
[tex]f'(t)=2\times 2 t^{2-1}=4t[/tex]
[tex]g'(t)=3t^{3-1}+4\times 1 t^{1-1}=3t^2+4[/tex]
2) [tex]p(t) =2t^2(t^3+4t)[/tex]
Rewriting the formula by distributing the [tex]2t^2[/tex] term:
[tex]p(t) =2t^2.t^3+2t^2.4t=2t^5+8t^3[/tex]
[tex]p'(t) = 10t^4+24t^2[/tex]
3) By using answers of part (1):
[tex]f'(t).g'(t)=12t^3+16t[/tex]
[tex]p'(t) = 10t^4+24t^2[/tex]
Therefore it is False that [tex]p'(t) = f'(t).g'(t)[/tex]
4) [tex]q(t)=\dfrac{t^3+4t}{2t^2}[/tex]
Writing by distributing:
[tex]q(t)=\dfrac{t^3}{2t^2}+\dfrac{4t}{2t^2}\\\Rightarrow q(t) =\dfrac{t}{2}+\dfrac{2}{t}\\\Rightarrow q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]
Using the formula:
[tex]q'(t)=\dfrac{1}{2}t^{1-1}+2\dfrac{-1}{t^2}\\\Rightarrow q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]
(5)By using answers in part (1):
[tex]\dfrac{g'(t)}{f'(t)}=\dfrac{3t^2+4}{4t}=\dfrac{3}{4}t+\dfrac{1}t[/tex]
[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]
Therefore, it is False that:
[tex]q'(t)=\dfrac{g'(t)}{f'(t)}[/tex]
ONE OF THE COLDEST TEMPERTURES EVER RECORDED WAS -128F IN ANTARCTICA. ONE OF THE WARMEST TEMPERATURES EVER RECORDED WAS 134 DEGREES FAHRENHEIT IN DEATH VALLET CALIFORNIA. HOW MANY DEGRESS DIFFERENCE ARE THERE BETWEEN THE COLDEST AND WARMEST RECORDED OUTSIDE TEMPERTURE
Answer:
271 degrees
Step-by-step explanation:
143-(-128)=143+128=271 degrees
486 inches 162 inches 4 1/2 yards ?
Answer:
486 inches is 13.5 yards and 162 inches is 4.5 yards please mark brainlist thank you
What are the coefficients of this expression 7a+23b +2c + 16
Answer:
Step-by-step explanation:
A coefficient is basically the number infront of a variable or term.
E.g. the coefficient in 7x is 7
The coefficient in 23y is 23
The coefficient in 43a is 43.
So for your question: 7a + 23b + 2c + 16,
The coefficients are 7, 23 and 2
If possible, express each of the following as the sum of a perfect square and a prime number. Give all possible answers and explain how you found them. . 21 28. 52. 68 . 13 . 20
Answer:
4^2 + 5 = 21, 5^2 + 3 = 28, 7^2 + 3 = 52, 3^2 + 43 = 52, 7^2 + 19 = 68, 3^2 + 11 = 20, 1^2+19 = 20. I can't find a prime number and a perfect square that sums to 13.
Explanation:
these are primarily derived by finding the closest perfect square to a number and finding the difference to make the sum work, or finding the simplest prime number that will reduce the number which is a multiple of a perfect square.
f(X)=3x+7, find f(10)
Answer:
37
Step-by-step explanation:
Sorry if this is wong I haven't done these in awhile, but this is how I got it.
f(X)=3x+7
f(10)=3(10) +7
f(10)=30 +7
f(10)=37
Answer:
f(10)=37
Step-by-step explanation:
f(x)=3x+7
(for f(10) we sub 10 for x)
f(10)=3×10+7
=30+7
=37
Let xy=6 and x2 + y2 = 23 what is the value of (x+y)??
Answer:
I'll assume that x2 = x^2 and y2 = y^2 and the answer is sqrt{35}.
Step-by-step explanation:
This problem invovles completing the square, so if I square (x+y), I get
x^2+2xy+y^2, and since xy = 6, 2xy = 12, 23+12 = 35, and your answer is sqrt{35}.
What is the inverse of f(x) =1/3x+2
There are 24 marbles in a jar. 3 marbles are added to the jar when the class is good. How many times can the class be rewarded to get 100 marbles
Write the equation of each line described in slope-intercept form (y = mx + b) with a slope of -6 and x-intercept of 4. (4,0)
Answer:
ill give u the answer if u do 73 divided by 2628
Step-by-step explanation:
Which situation can be represented by this inequality?
3 + 2.0 > 8x
Select one:
The cost of 2 candy bars plus a $3 bag of chips is greater than 8 candy bars.
The cost of 2 candy bars with a discount of $3 is greater than 8 candy bars.
o The cost of a $3 bag of chips plus 2 candy bars is at least as much as 8 candy bars.
The cost of a $3 bag of chips plus 2 candy bars is less than 8 candy bars.
Answer: D
Step-by-step explanation:
Help fast fast!!! I'm begging
Answer:
28
Step-by-step explanation:
Hope this helps
Look at the incomplete multiplication problem below.
638 times 56 = 3828. 3828 + question mark = blank
What value is missing?
31,500
31,900
35,280
35,728
Answer:
B
Step-by-step explanation:
Can you guys help me to find the measure of each angle tysm.
Answer:
∠EBF = 51°
∠DBE = 17°
∠ABF = 141°
∠EBA = 90°
∠DBC = 107°
∠DBF = 68°
Step-by-step explanation:
Hope this helps
Answer:
1.
a. m<EBF = 90 - 39 = 51
b. m<EBA = 90
c. m<DBE = 90 - 73 = 17
d. m<DBC = 90 + 17 = 107
e. m<ABF = 90 + 51 = 141
f. m<DBF = 17 + 51 = 68
2.
<ABD, <DBE, <EBF, <FBC, <DBF
3.
<ABF, <DBC
4.
<ABE, <EBC
What is the pattern in the numbers 1,8,27,64
Answer:
3
Step-by-step explanation:
he pattern is continued by adding 3 to the last number each time, like this: 1, 8, 27, 64, 125, 216, 343, 512, 729
Linear combination of matrices .
Multiplying a matrix by a scalar is equivalent to multiplying each entry in the matrix by that scalar:
[tex]A=\begin{bmatrix}0&-3\\-5&5\end{bmatrix}\implies3A=\begin{bmatrix}0&-9\\-15&15\end{bmatrix}[/tex]
[tex]B=\begin{bmatrix}-2&-6\\2&5\end{bmatrix}\implies-6B=\begin{bmatrix}12&36\\-12&-30\end{bmatrix}[/tex]
Now combine them:
[tex]3A-6B=3A+(-6B)=\begin{bmatrix}0+12&-9+36\\-15+(-12)&15+(-30)\end{bmatrix}=\begin{bmatrix}12&27\\-27&-15\end{bmatrix}[/tex]
prime factorization of 60 error
Answer:
2*2*3*5
Step-by-step explanation: