7(x + y) ex2 − y2 dA, R where R is the rectangle enclosed by the lines x − y = 0, x − y = 7, x + y = 0, and x + y = 6

Answers

Answer 1

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]


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Step-by-step explanation:

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Answers

J + -2 = -22

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Answers

Answer:

The minimum balance is 68 liters

Step-by-step explanation:

Let the number of liters of petrol required be x

Given that  One litre of petrol has a mass of 737g, x liters will have a mass

= 0.737x kg

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Brainliest given to anyone who gets both answer


Helen draws a random circle,
She then measures its diameter and circumference,
She gets a circumference, C, of 405 mm correct to 3 significant figures.
She gets a diameter, d, of 130 mm correct to 2 significant figures.
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Calculate the lower bound and upper bound for Helen's value of .
Give your answers correct to 3 decimal places.

Answers

Answer:

3.115

Step-by-step explanation:

pi = 405 ÷ 130

= 3.1153846154

upper bound 3.116

lower bound 3.115

Edit : Incorrect Answer

Answer:

Lower Bound = 2.996

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Step-by-step explanation:

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Answers

Answer:

16/20=1/4

Step-by-step explanation:

James is 1/4 younger then his brother

4:5 is the ratio which  represents James' age to his brother's age 4 years from now.

What is Ratio?

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Given that James is 12 years old

James  brother is 16 years old.

We need to find the ratio which represents James' age to his brother's age 4 years from now.

After 4 years the James age is 12+4, 16 years

After 4 years the James brother age is 16+4, 20years

The ratio of James' age to his brother's age is 16/20

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Answers

Answer:

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Answer:

Your answer is given below:

Step-by-step explanation:

12+15+10+11/4

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TheExtraterestrial

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Answers

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Step-by-step explanation:

Given

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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for hogging time is 0.5 hour.

Step-by-step explanation:

speed of cycling = 30 km/h

speed of jogging = 8 km/h

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Let the time for cycling is t, so that time time for jogging is 2 - t .  

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

Answer:

Step-by-step explanation:

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The probability that a student is chosen randomly from the class does not have a sister is 0.375.

The probability that a student is chosen randomly from the class Has a brother is 0.208.

The probability that a student is chosen randomly from the class does not have a brother is 0.7916.

The probability that a student is chosen randomly from the class Has a sister is 0.625.

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Probability is the branch of mathematics, which discusses the occurrence of a random experiment.

First, we need to calculate how many total students there are.

Once we have the total we have to divide the number in the category that we want by the total number of students to calculate the probability of randomly getting a student in that category.

Total Students = 3 + 12 + 2 + 7 = 24 students

The probability that a student is chosen randomly from the class does not have a sister is;

[tex]= \dfrac{2+7}{24}\\\\=\dfrac{9}{24}\\\\=0.375[/tex]

The probability that a student is chosen randomly from the class Has a brother is;

[tex]= \dfrac{3+2}{24}\\\\=\dfrac{5}{24}\\\\= 0.208[/tex]

The probability that a student is chosen randomly from the class does not have a brother is;

[tex]= \dfrac{7+12}{24}\\\\=\dfrac{19}{24}\\\\= 0.7916[/tex]

The probability that a student is chosen randomly from the class Has a sister is;

[tex]= \dfrac{3+12}{24}\\\\=\dfrac{15}{24}\\\\= 0.625[/tex]

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Answer:

Step-by-step explanation:

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The correct answer is x = -3

The graph shows the function f(x).
Which equation represents f(x)?
Of(x) = -3
5
Of(x) = -3/x-1
3
2
Of(x) = 3-x-1
f(x)
Of(x) = -x
de
-10 -8 6 -4 -2,
2 4
6
8
10
L2
The
4
-5
1,99%
AI
[
Mark this and return
Save and Exit
Dlaxt
Submit
tiny

Answers

Answer:

C

Step-by-step explanation:

What we have to do here is to select a point from the graph

We can select the point (-8,1)

What this simply mean is that when x = -8, y = 1

Now, let us take a look at the second third option

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C

Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

256

Step-by-step explanation:

Given. :

2⁴ / 2^-4

2⁴ = 2 * 2 * 2 * 2 = 16

2^-4 = 1/2⁴ = 1 / (2 * 2 * 2 * 2) = 1 / 16

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16 * 16 /1

= 256

Answer:

Step-by-step explanation:

1/256 i believe

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Answers

Answer:

4 = 68

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7 = 112

Step-by-step explanation:

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