A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid

Answers

Answer 1

A 0.100 M oxalic acid, HO₂CCO₂H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid is 1.94.

Oxalic acid is a dicarboxylic acid with the chemical formula HO₂CCO₂H, with a pKa1 of 1.25 and a pKa2 of 4.14. A titration is a process in which a solution of known concentration is added to a solution of unknown concentration until the equivalence point is reached.

The goal of a titration is to determine the concentration of the unknown solution. A 0.100 M oxalic acid solution is titrated with 0.100 M KOH. The pH is calculated when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid. Here is how to calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH:

Step 1: Calculate the moles of oxalic acid

moles of oxalic acid = concentration x volume

moles of oxalic acid = 0.100 M x 0.025 L

moles of oxalic acid = 0.0025 mol

Step 2: Calculate the moles of NaOH

moles of NaOH = concentration x volume

moles of NaOH = 0.100 M x 0.035 L

moles of NaOH = 0.0035 mol

Step 3: Determine which species is in excess

0.0025 mol of oxalic acid reacts with 0.0025 mol of KOH

0.0010 mol of oxalic acid reacts with 0.0035 mol of KOH

0.0010 mol of oxalic acid is consumed in the reaction

The excess moles of NaOH = 0.0035 - 0.0010 = 0.0025 mol

Step 4: Calculate the concentration of the remaining OH- ions

Concentration of OH- ions = moles of OH- ions / volume

Concentration of OH- ions = 0.0025 mol / 0.060 L

Concentration of OH- ions = 0.0417 M

Step 5: Calculate the concentration of H+ ions

Ka1 = [H+][C₂O₄₂-]/[HC₂O₄-]

5.4 x 10^-2 = x^2 / (0.100 - x)

Assuming that x is much smaller than 0.100, x = [H+] = 0.115 M

Step 6: Calculate the pH

pH = -log[H+]

pH = -log(0.115)

pH = 1.94

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Related Questions

A man's speed is 50 m/s and his mass is 120 kg. What is his kinetic energy just before running back up? |
kg*m/s

Answers

Answer:

150,000 Joules

Explanation:

KE= 1/2 *mv^2

1/2 * 120 *50^2

60*2500

150,000 Joules

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In water, the titanium(III) ion, [Ti(H2O)6]^3+, has a broad absorption band centered at about 500 nm. What color light is absorbed by the ion?

Answers

When light is incident on the ion, wavelengths around 500 nm will be absorbed, and the remaining wavelengths will be transmitted or reflected. This provides insight into the electronic structure of the titanium(III) ion and its interaction with light.

The titanium(III) ion, [Ti(H2O)6]3+ in water, absorbs light that is centred around 500 nm. The colour of light absorbed by the ion can be inferred from the visible spectrum of electromagnetic radiation, which ranges from about 400 to 700 nm. Wavelengths around 400-450 nm appear violet, 450-495 nm blue, 495-570 nm green, 570-590 nm yellow, 590-620 nm orange, and 620-700 nm red. Since the titanium(III) ion absorbs light around 500 nm, we can infer that it absorbs light in the green portion of the visible spectrum. Therefore, the titanium(III) ion appears to be a green color.

The absorption of light by compounds can provide insight into the colour of the compound. When light is incident on a compound, certain wavelengths are absorbed, and the remaining wavelengths are transmitted or reflected. The absorbed wavelengths of light depend on the electronic structure of the compound. In the case of the titanium(III) ion, [Ti(H2O)6]3+, it is observed that light centered around 500 nm is absorbed. This means that the electronic structure of the ion allows it to absorb light in the green portion of the visible spectrum. Since the visible spectrum ranges from approximately 400 to 700 nm, it can be inferred that the titanium(III) ion appears to be green in colour. Therefore, when light is incident on the ion, wavelengths around 500 nm will be absorbed, and the remaining wavelengths will be transmitted or reflected. This provides insight into the electronic structure of the titanium(III) ion and its interaction with light.

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A 295-g aluminum engine part at an initial temperature of 13.00 degrees Celsius absorbs 75.0 kJ of heat. What is the final temperature (in degrees Celsius) of the part? (c of Al = 0.900 J/g
K)

Answers

The final temperature of the aluminum engine part is approximately 284.19 degrees Celsius.

To determine the final temperature of the aluminum engine part, we can use the equation:

q = m × c × ΔT

Where:

q is the heat absorbed (in J)

m is the mass of the aluminum part (in g)

c is the specific heat capacity of aluminum (in J/g·K)

ΔT is the change in temperature (in K)

First, let's convert the mass of the aluminum part from grams to kilograms:

295 g = 0.295 kg

We are given the heat absorbed as 75.0 kJ, which is equal to 75,000 J.

Now, let's rearrange the equation to solve for ΔT:

ΔT = q / (m × c)

Substituting the values:

ΔT = 75,000 J / (0.295 kg × 0.900 J/g·K)

Calculating ΔT:

ΔT = 271.19 K

To find the final temperature, we need to add the change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

Final temperature = 13.00°C + 271.19 K

Converting back to Celsius:

Final temperature = 284.19°C

Therefore, the aluminum engine part's ultimate temperature is approximately 284.19 degrees Celsius.

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what is the identity of a metal that has a mass of 27g and a volume of 10 cm3

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The density of the metal is 2.7 g/cm³, which can be used to identify the metal since different elements have different densities.

The given mass of the metal is 27g and its volume is 10 cm³.

The identity of the metal can be found out by using the formula of density, which is Density = Mass/Volume.

Density is a physical property of matter that is the amount of mass per unit volume. By rearranging the formula of density, we can determine the identity of the metal by finding its density which is given by mass divided by volume.

Identity of a metal that has a mass of 27g and a volume of 10 cm³ can be determined by using the formula of density which is Density = Mass/Volume.  

Here is the solution:Given,Mass of the metal = 27gVolume of the metal = 10 cm³

Density of the metal is given by the formula:Density = Mass/Volume

Substituting the given values in the formula:Density = 27g/10 cm³ = 2.7 g/cm³

The periodic table can be used to match the density with known elements and thus determine the identity of the metal.

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carbon dioxide is considered to be a greenhouse gas because it _______.

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Carbon dioxide is considered to be a greenhouse gas because it absorbs and emits infrared radiation.

Greenhouse gases like carbon dioxide trap heat in the atmosphere, leading to the warming of the Earth's surface and atmosphere.Carbon dioxide is a greenhouse gas, meaning that it can absorb and emit infrared radiation. Carbon dioxide and other greenhouse gases in the atmosphere act as a type of insulation, trapping heat and keeping the Earth's surface and atmosphere warm.A greenhouse gas is a gas that can absorb and emit infrared radiation. The greenhouse effect occurs when certain gases, such as carbon dioxide and water vapor, trap heat in the Earth's atmosphere. As more greenhouse gases are released into the atmosphere, the Earth's temperature increases, leading to climate change.

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Which of the following is an indicator that a chemical reaction occurred?
A precipitate is formed
The state of matter changed
It was melted
The identity of the substance did not change​

Answers

Answer:

the state of matter changed

Explanation:

Answer:

A) A precipitate is formed

Explanation:

occurs in aqueous solution when two ions bond together to form an insoluble salt, which is known as the precipitate.

What is the process of splitting into two cells called?

Answers

That is Mitosis...Hope that helps

Which of the following statements is true about a galvanic cell that has an E value of 1.00V? 1. The reaction is spontaneous. II. At equilibrium K = 1. III. It has a negative AGO. a. I only b. II only C. III only d. I and II e. I and III 21. What species is produced by a beta emission by magnesium-27? a. 22Mg b. Mg c. 15A1 d. 23A e. None

Answers

The correct statement which are true about a galvanic cell that has an E value of 1.00V are The reaction is spontaneous and It has a negative ΔG°. Hence, the correct option is e. The species produced by a beta emission by magnesium-27 is no specific isotope or element. Hence, the correct option is e.

A galvanic cell with an E value of 1.00V indicates that the cell reaction is spontaneous. The E value represents the cell potential, and a positive E value indicates that the reaction will proceed spontaneously in the forward direction.

At equilibrium, the cell potential would be zero (E = 0), but the given cell has an E value of 1.00V. Therefore, statement II is incorrect. The equilibrium constant (K) is not necessarily equal to 1 in a galvanic cell.

The ΔG° (standard Gibbs free energy change) is related to the E value of the cell by the equation: ΔG° = -nFΔE°, where n is the number of moles of electrons transferred and F is the Faraday constant. Since the E value is positive (1.00V), the ΔG° will be negative, indicating that the cell reaction is thermodynamically favorable. Therefore, statement III is true.

Therefore, the correct answer is e. I and III.

The beta emission by magnesium-27 (27Mg) would result in the production of an electron (β- particle). Therefore, the correct answer is e. None. No specific isotope or element is produced by the beta emission of magnesium-27.

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Consider the reaction:
NH3 (g) + HCl (g) → NH4Cl (s)
Given the following table of thermodynamic data,
Substance NH3 (g) -46.19 192.5
HCl (g) -92.30 186.69
NH4Cl (s) -314.4 94.6
determine the temperature (in °C) above which the reaction is nonspontaneous.
a. 618.1
b. 345.0
c. This reaction is spontaneous at all temperatures.
d. 1235
e. 432.8

Answers

The correct option is a. 618.1

Given data: Substances : NH3 (g) -46.19 192.5 HCl (g) -92.30 186.69 NH4Cl (s) -314.4 94.6

We are to determine the temperature (in °C) above which the reaction is nonspontaneous.

We can determine this by calculating ΔG for the reaction.

The equation to calculate ΔG is as follows:ΔG° = ΣG°(Products) - ΣG°(Reactants) ,    

From the given data, we can write:ΔG° = G°(NH4Cl) - [G°(NH3) + G°(HCl)]

Substituting the values:ΔG° = (-314.4) - [(-46.19) + (-92.30)]ΔG° = (-314.4) + 138.49ΔG° = -175.91 kJ/mol

Now we can use the equation:ΔG = ΔH - TΔS

At non-spontaneous reaction, ΔG = 0.

We can re-arrange the equation and solve for T to get the temperature at which the reaction is non-spontaneous.

T = ΔH / ΔS = (-175.91 kJ/mol) / (-192.5 J/mol-K) = 911.9 K = 638.7 °C

Therefore, the temperature above which the reaction is nonspontaneous is 638.7 °C (approx.)

Hence, the correct option is a. 618.1.

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Which indicator would show a pH change from 6 to 7? A. Red litmus indicator B. Methyl red indicator C. Phenol red indicator D. Blue litmus indicator

Please legitimate answers only

Answers

Answer:

The correct answer is Choice C.

(Phenol red indicator.)

Explanation:

Phenol red indicator is an organic dye that acts as an acid-base reaction indicator in the pH range of 6.8 to 8.4.

In acidic solutions, the color is purple, and in simple solutions, the color is red.

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Answer:

phenol red indicator

Explanation:

Did Dalton believe that atoms could be created or destroyed? Explain

Answers

Dalton proposed his atomic theory in 1804. ... Atoms cannot be subdivided, created, or destroyed. Atoms of different elements can combine in simple whole number ratios to form chemical compounds. In chemical reactions, atoms are combined, separated, or rearranged.

☁️ Answer ☁️

Yes.

"In so doing, he became the first scientist to explain the behavior of atoms in terms of the measurement of weight. He also uncovered the fact that atoms couldn't be created or destroyed. Dalton's theory additionally examined the compositions of compounds, explaining that the tiny particles (atoms) in a compound were compound atoms"

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Have a nice day noona/hyung.

A chemical substance that is extremely stable and takes years to break down into a less toxic form would be considered to be?

Answers

A chemical substance that is extremely stable and takes years to break down into a less toxic form would be considered to be persistent. Persistence refers to the ability of a substance to resist degradation or breakdown over time.

Persistent chemicals have a long environmental or biological half-life, meaning it takes a significant amount of time for them to degrade or transform into less harmful substances.

Persistence can have negative implications because these substances can persist in the environment, accumulate in living organisms, and potentially cause adverse effects.

Examples of persistent substances include certain synthetic chemicals like some pesticides, certain industrial pollutants, and some persistent organic pollutants (POPs) such as polychlorinated biphenyls (PCBs) and certain chlorinated pesticides.

The persistence of a chemical is an important factor to consider when assessing its potential environmental and health impacts.

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The heat or Q, for a chemical reactions is - 1034J , this chemical reaction is
A)Exothermic
B)Endothermic
C)Endoscopic
D)Extroverted

Answers

i think the answer is C

Write balanced half-reactions for the following redox reaction: Cr2O72−(aq)+14H+(aq)+3Zn(s)→2Cr3+(aq)+7H2O(1)+3Zn2+ (aq) reduction:___ oxidation: ___

Answers

Balanced half-reactions for the given redox reaction are Reduction: Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l), Oxidation: Zn(s) → Zn2+(aq) + 2 e-. As the reaction proceeds, Zn is oxidized and Cr2O72- is reduced. It is a redox reaction because it involves both oxidation and reduction.

In the half-reaction of oxidation, zinc atoms donate two electrons to become zinc ions. Therefore, oxidation occurs at the anode, which produces electrons that flow into the external circuit. In the reduction half-reaction, Cr2O72- accepts six electrons and seven hydrogen ions to become Cr3+ and water. Therefore, reduction occurs at the cathode, which consumes the electrons produced by the anode. Therefore, the overall balanced redox reaction is Cr2O72-(aq) + 14 H+(aq) + 3 Zn(s) → 2 Cr3+(aq) + 7 H2O(l) + 3 Zn2+(aq). The reaction can be explained as follows: zinc atoms donate two electrons to each hydrogen ion present in the acidic solution to form hydrogen gas, which causes slow corrosion of the zinc electrode. The dichromate ion acts as the oxidizing agent by accepting electrons from the zinc electrode to form zinc ions.

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On a certain hot day the atmospheric pressure was 1 atm and the temperature was 37°C. On this day 1 L sample of atmospheric gases was collected and analyzed. It was found to contain among other gases 9.38 x 10-3 mol of O2 gas, 2.46 x 10-8 mol of H2 gas and 1.79 x 10-4 mol of water vapor. If you put these amounts of the three gases in a sealed 1L tank at 1 atm and 37°C, will the combustion of hydrogen gas be spontaneous at these conditions?

Answers

Answer:

Yes, the combustion of hydrogen is spontaneous from the given conditions.

Explanation:

Let look at the reaction:

[tex]2H_2_{(g)} + O_2_{(g)} \to 2H_2O_{(g)}[/tex]

[tex]K_p = \dfrac{[P(H_2O)]^2}{[P(H_2)^2\times P(O_2)]} ----- (1)[/tex]

The total pressure of the tank = 1 atm

[tex]\mathtt{Pressure \ of \ the \ gas = moles \ fraction \of \ gas \times total \ pressure}[/tex]

Thus, pressure of [tex]O_2[/tex] gas = [tex]\dfrac{9.38 \times 10^{-3} }{(9.38 \times 10^{-3} + 2.46 \times 10^{-8} + 1.79 \times 10^{-4}} \times 1 atm[/tex]

[tex]P(O_2) = 0.9813 atm[/tex]

Pressure of [tex]H_2O[/tex] gas =[tex]\dfrac{1.78 \times 10^{-4}}{9.38 \times 10^{-3} + 2.46 \times 1)^{-8} + 1.78 \times 10^{-4}} \times 1 \ atm[/tex]

Pressure of H_2 gas = [tex]2.573 \times 10^{-6} \ atm[/tex]

From equation (1);

[tex]K_p = \dfrac{(0.0187)^2}{(2.573 \times 10^{-6})^2 \times (0.913) } \\ \\ K_p = 5.383 \times 10^7[/tex]

So, applying the equation:

[tex]\Delta G^0 = -RT In K_p \\ \\ = -8.314 \times (300)K \times IN(5.383 \times 10^7) \\ \\ = -45880.109 J \\ \\ = -45.800 \ kJ\\ \\[/tex]

Thus;

[tex]\Delta G^0 < 0[/tex]

Thus, Yes the combustion of hydrogen is spontaneous from the above conditions. From thermodynamics, we realize that assuming ∆G is negative, the reaction is spontaneous. Again we understand that ∆G=∆H-T∆S. However, for combustion, water will definitely be formed.

Finally, we can conclude that;

∆H is negative;

∆S is positive; &

∆G is also negative.

Thus, from above, we conclude combustion of hydrogen is spontaneous.

The combustion of hydrogen gas with the oxygen gas for the formation of the water vapor is a spontaneous reaction.

How do we know reaction is spontaneous?

To know about the condition that the given reaction is spontaneous or not we will use the below equation and must get the negative value:

ΔG° = -RTlnKp, where

R = universal gas constant

T = temperature

Kp = partial pressure constant

Firstly we have to calculate the value of Kp.

Given chemical reaction is:

2H₂(g) + O₂(g) → 2H₂O(g)

Value of Kp for the given reaction is:

Kp = [p(H₂O)]² / [p(H₂)]².[p(O₂)]

Partial pressure will be calculated as:

p = mole fraction × total pressure

Given that total pressure of gas = 1atm

p(H₂O) = (1.79×10⁻⁴ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 0.0187

p(H₂) = (2.46×10⁻⁸ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 2.573 × 10⁻⁶

p(O₂) = (9.38×10⁻³ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 0.913

Putting all these values on the equation of Kp, we get

Kp = (0.0187)² / (2.573 × 10⁻⁶)²(0.913) = 5.383 × 10⁷

Now putting values in the first equation we get,

ΔG° = -(8.314)(300)ln(5.383 × 10⁷)

ΔG° = -45,800 kJ

Hence, given reaction is spontaneous.

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Explain how scientists study the Earth’s interior. PLEASE HELP :))))!

Answers

Answer:

Scientists study Earth's interior by studying

seismic waves. Seismic waves are waves of energy that travel

through Earth.

Explanation:

calculate the concentrations of all species in a 1.40 m nach3coo (sodium acetate) solution. the ionization constant for acetic acid is a=1.8×10−5 .
(Na+) = ...... M
(OH-) = ...... M
(H2O+) = ...... M
(CH3COOH-) = ...... M
(CH3COOH) = ..... M

Answers

The concentrations of the species in the 1.40 M NaCH₃COO solution are (Na⁺) = 1.40 M, (OH⁻) = 0 M, (H₂O⁺) = 0 M, (CH₃COOH⁻) = 0.00502 M, and (CH₃COOH) = 0.00502 M.

To calculate the concentrations of the species in a 1.40 M NaCH₃COO (sodium acetate) solution, we need to consider the dissociation of sodium acetate and the ionization of acetic acid.

The dissociation of sodium acetate (NaCH₃COO) can be represented as follows

NaCH₃COO → Na⁺ + CH₃COO⁻

Since sodium acetate fully dissociates in water, the concentration of Na⁺ will be the same as the initial concentration of sodium acetate: 1.40 M.

The ionization of acetic acid (CH₃COOH) can be represented as follows

CH₃COOH ⇌ H⁺ + CH₃COO⁻

The ionization constant for acetic acid (Ka) is given as 1.8×10⁻⁵

Let's denote the initial concentration of acetic acid as x M. At equilibrium, the concentration of H⁺ and CH₃COO⁻ will also be x M.

Using the ionization constant expression for acetic acid, we can write

Ka = [H⁺][CH₃COO⁻] / [CH₃COOH]

1.8×10⁻⁵ = x * x / (1.40 - x)

Since the value of x is expected to be small compared to 1.40, we can approximate the denominator as 1.40.

1.8×10⁻⁵ = x² / 1.40

Rearranging the equation

x² = 1.8×10⁻⁵ × 1.40

x² = 2.52 × 10⁻⁵

Taking the square root of both sides

x = √(2.52×10⁻⁵)

x ≈ 0.00502 M (rounded to four decimal places)

Now we can calculate the concentrations of the species

(Na⁺) = 1.40 M (same as the initial concentration of sodium acetate)

(OH⁻) = 0 M (since sodium acetate and acetic acid do not provide OH⁻ ions)

(H₂O⁺) = 0 M (water does not provide H⁺ ions)

(CH₃COOH⁻) = 0.00502 M

(CH₃COOH) = 0.00502 M

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convert 2.41 x 10^2 m to cm
answer choices
2.41cm
2.41 x 10^4cm
2.41 x 10^-2cm
2.41 x 10^-6cm

Answers

Answer:

2.41*10² m equals 2.41*10⁴ cm

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

So: [tex]x=\frac{c*b}{a}[/tex]

In this case the rule of three can be applied as follows: if 1 m equals 100 cm, 2.41*10² m equals how many cm?

[tex]cm=\frac{2.41*10^{2} m*100 cm}{1 m}[/tex]

cm= 24100 = 2.41*10⁴

2.41*10² m equals 2.41*10⁴ cm

There are many organ systems that make up the human body. Although most of these systems, such as the skeletal and muscular systems, are almost the same in males and females, one is very different. The male and female reproductive systems are made up of different organs, with different functions. The male reproductive system contains the _________, which _________. A. ovaries; produce eggs B. bladder; stores urine C. kidney; filters the blood D. testes; produce sperm

Answers

Answer: The male reproductive system contains the TESTES; which PRODUCE SPERM. The correct option is D

Explanation:

There are different organ systems in the human body which functions together to bring about the normal healthy status of an individual. To list but a few, these systems include:

--> skeletal and muscular system

--> Endocrine System,

--> Nervous System, and

--> REPRODUCTIVE SYSTEM

The reproductive system is made up of the male and the female reproductive system which are very different as it's consists of different organs with different functions.

The male reproductive system consists of:

--> scrotum

--> Testes

--> prostate gland

--> seminal vesicles

--> penis.

The SPERM (spermatozoa) are produced in the seminiferous tubules of the TESTES and mature as they pass through the long and convoluted epididymis, where they are stored. Therefore option D is the correct answer.

Consider the reaction below. If you start with 4.00 moles of C3H8 (propane) and 4.00 moles of O2, how many moles of propane would be consumed? C3Hg(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) O 3.20 4.00 O 20.0 O 2.00 O 0.800

Answers

The moles of propane consumed in the reaction is approximately 4.00 moles. Option B is correct.

The balanced equation for the reaction is;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

According to the stoichiometry of the reaction, for every 1 mole of C₃H₈, 5 moles of O₂ are required for complete combustion.

Given that you start with 4.00 moles of C₃H₈ and 4.00 moles of O₂, we need to determine the limiting reactant to determine the moles of propane consumed.

For C₃H₈:

moles of C₃H₈ = 4.00 moles (given)

For O₂;

moles of O₂ = 4.00 moles (given)

To determine the limiting reactant, we need to compare the mole ratios of the reactants to the stoichiometry of the balanced equation.

For C₃H₈;

moles of C₃H₈ used = 4.00 moles

For O₂;

moles of O₂ required = 5 moles of O₂ per 1 mole of C₃H₈

moles of O₂ required = 5 × 4.00 moles = 20.00 moles

Comparing the moles of C₃H₈ used (4.00 moles) and the moles of O₂ required (20.00 moles), we can see that the moles of C₃H₈ used are less than the moles of O₂ required. This means that C₃H₈ is the limiting reactant.

Therefore, the moles of propane is 4.00 moles.

Hence, B. is the correct option.

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--The given question is incomplete, the complete question is

"Consider the reaction below. If you start with 4.00 moles of C₃H₈ (propane) and 4.00 moles of O₂, how many moles of propane would be consumed? C₃Hg(g) + 5 O₂(g) + 3 CO₂(g) + 4H₂O(g) A) 3.20 B) 4.00 C) 20.0 D) 2.00 E) 0.800."--

which statement about a chemical reaction supports the claim that mass is conserved?(1 point)

Answers

The statement that supports the claim that mass is conserved in a chemical reaction is the law of conservation of mass, which states that the total mass of the reactants is equal to the total mass of the products.

According to the law of conservation of mass, which is a fundamental principle in chemistry, mass is conserved in a chemical reaction. This means that the total mass of the substances involved in the reaction remains constant before and after the reaction takes place. In other words, no mass is gained or lost during a chemical reaction. The atoms in the reactants rearrange themselves to form new substances, but the total number of atoms remains the same. Therefore, the mass of the reactants is equal to the mass of the products. This principle has been experimentally verified and is a cornerstone of chemical reactions.


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in the lab there is an unmarked glass cylinder. half full with water weighs 11.6 kg. filled only a third with water weighs 10 kg. how much does the empty cylinder weight?

Answers

To determine the weight of an empty cylinder, we will consider the given information below:Half full of water cylinder weighs 11.6 kgFilled with a third of water, the cylinder weighs 10 kg.The glass cylinder is unmarked.Let's assume that the empty cylinder weighs x kg.

Since water was used to fill the cylinder, we know that the density of water is 1 g/cm³ or 1 kg/L.To find the volume of water needed to fill half of the cylinder, we will subtract the weight of the empty cylinder from the weight of the half-filled cylinder. Thus, volume of water filled in the cylinder is 11.6 kg - x kg. Since the cylinder is half-full, we will multiply the volume of water by 2, then divide by the total volume of the cylinder. Thus, we have:[tex]\frac{2\cdot(11.6kg-x kg)}{Volume}[/tex]Similarly, we can find the volume of water needed to fill a third of the cylinder using the formula above. Thus, we have:[tex]\frac{3\cdot(10kg-x kg)}{Volume}[/tex]Since the density of water is 1 kg/L, we know that the volume of water is equal to the weight of the water. Equating the two expressions, we have:2(11.6 - x) = 3(10 - x)Solving for x, we have x = 2.8 kg. Therefore, the empty cylinder weighs 2.8 kg.Answer: The empty cylinder weighs 2.8 kg.

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How many liters of HCI at STP are produced from 150.0 g of chlorine gas?

Answers

Answer:

As we know that

At STP

1 mole of any gas occupies 22.4L  

so

15.7L / 22.4L/mole = 0.7moles Cl2  

0.7moles x 6.022x10^23molecules/mole = 4.22x10^23molecules

hope it helps

What do elements and compounds have in common? And how do they differ?

I will mark brainliest for the best answer.

WARNING: DON'T PUT LINKS I WILL REPORT YOU!

Answers

elements and compounds might appear different, yet they share many similarities, like being made up of atoms and having bonds linking their atoms together. Elements and compounds also share the qualities of being both pure and homogeneous substances. Substances can be categorised as either elements or compounds. Both of these are made up of atoms, the only difference is an element is made of one type of atom whereas compounds are made of two or more different types of atoms.

Which is the only subatomic particle that can freely move on or off an atom?

Answers

I think this question is talking about electrons (since they flow freely in the electron cloud of an atom).

Helpppp meeeeee plssss

Answers

Answer:

A

Explanation:

the answer is A because when your working cooperative people are helping you and non cooperative is where people are working against you by them selves

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Answers

Answer:

Thank youuuuu bestie, you really pulling through

Answer:

yessss

Explanation:

A base is a compound that contains the ____ radical.

Answers

Answer:

hydroxyl (OH)

Explanation:

hydroxyl (OH)

A student determines the value of the equilibrium constant to be 8.47×10-37 for the following reaction. H2S(g) + 2H2O(l)3H2(g) + SO2(g) Based on this value of Keq: G° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 2.46 moles of H2S(g) at standard conditions at 298K. G°rxn = kJ

Answers

The free energy change (ΔG°) for the reaction of 2.46 moles of H2S(g) at standard conditions and 298K is approximately 252 kJ.G° for this reaction is expected to be less than zero.

The equilibrium constant (Keq) for a reaction is related to the standard Gibbs free energy change (ΔG°) through the equation:

ΔG° = -RTln(Keq)

Where:

ΔG° is the standard Gibbs free energy change

R is the gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin (298 K)

ln is the natural logarithm

Given that Keq = 8.47×10^(-37), we can calculate the standard Gibbs free energy change (ΔG°) using the equation above:

ΔG° = - (8.314 J/(mol·K)) * (298 K) * ln(8.47×10^(-37))

Calculating this value gives us:

ΔG° = - (8.314 J/(mol·K)) * (298 K) * (-87.24)

ΔG° ≈ 2.52 × 10^5 J/mol

Converting the units to kilojoules (kJ/mol), we get:

ΔG° ≈ 252 kJ/mol

The free energy change (ΔG°) for the reaction of 2.46 moles of H2S(g) at standard conditions and 298K is approximately 252 kJ. Since the value of ΔG° is positive, it indicates that the reaction is not spontaneous and requires an input of energy to proceed.

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A solution of 12M HCl is diluted so that it goes from 550mL to a total volume of 1000mL. What is the new concentration of the solution?

Answers

Answer:

6.6M

Explanation:

C=concentration

V=Volume

C1V1=C2V2

rearrange formula to find C2

(C1V1)/V2= C2

(12M x 550mL)/1000mL= C2

6600M*mL*/1000*mL* =C2 (cancel units)

6.6M=C2

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