A 200 ω resistor, a 0.850 h inductor, and a 5.75 μf capacitor are connected in series across a voltage source that has voltage amplitude 29.0 v and an angular frequency of 260 rad/s.

a. What is v at t= 22.0 ms ?
b. What is vR at t= 22.0 ms ?
c. What is vL at t= 22.0 ms ?
d. What is vC at t= 22.0 ms ?

Answers

Answer 1

The root mean square voltage Vrms of the circuit is 15.49 V.

The voltage of the resistor vR is 10.4 V.

The voltage of the inductor vL is 11.49 V.

The voltage of the capacitor vC is 0.035 V.

RMS voltage of the circuit is calculated as follows:

Vrms = -V₀ sin ωt = -29 * sin (260* 22* 10⁻³) = 29 * 0.534 = 15.49 V

XI = ωL = 260* 0.85 = 221 ohms

Xc = 1/ωc = 1/(260 * 5.75* 10⁻³) = 10³/1495 = 0.67 ohm

Z = √[R² +(XI - Xc)²] = √[200² + (221 - 0.67)²] = √[200² + 220.33²]

= √[ 40000 + 48545.30] = 297.56 ohm

Current flowing in the circuit is

Irms = Vrms/Z = 15.49 / 297.56 = 0.052 A

vR = Irms * R = 0.052 * 200 = 10.4 V

vL = Irms * L =  0.052 * 221 = 11.49 V

vC = Irms * C = 0.052 * 0.67 = 0.035 V

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From the question,

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Answer:

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Explanation:

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Answer:

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Answer:

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PLEASE HELP! A 0.423 kg object carries a +11.5 uc
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Answers

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Acellus

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[tex]\Large {{ \sf {Question :}}} [/tex]

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[tex]\Large {{ \sf {Given :}}} [/tex]

Initial Velocity (u) - 5 m/sFinal Velocity (v) - 15 m/sTime (t) - 10 sec

[tex]\Large {{ \sf {Formulae :}}} [/tex]

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