Answer:
9.9 × 10^-16N
Explanation:
Given that a 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth.
Calculating the gravitational field strength.
g = Gm/R^2
Where G = 6.67408 × 10-11 m3 kg-1 s-2
g =(6.67408 × 10-11 × 2070)/5.37 × 10^5
g = 1.38069×10^-7 / 2.88369^11
g = 4.788×10^-19 m/s
Force F = mg
Substitute g into the formula
F = 2070 × 4.79×10^-19
F = 9.9 × 10^-16N
This is a whole quiz please answer ill make as many points as i can. Btw this is pickleball
Question 1 10 pts
The ___________________ rule says the ball must bounce one on each side before either team may start volleying the ball in the air.
Group of answer choices
Double Bounce
Volley Bounce
Bounce
Two Bounce
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Question 2 10 pts
The player standing in the _____________ service court is always the firsts server.
Group of answer choices
right
left
No answer text provided.
No answer text provided.
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Question 3 10 pts
Each game is played to ___________ points, won by _________.
Group of answer choices
11, 2
21,1
15,1
12,2
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Question 4 10 pts
According to one of the inventors, the game was officially named after a family dog, Pickles, who would chase the ball and run off with it.
Group of answer choices
True
False
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Question 5 10 pts
Pickleball is played on a court the size of a Badminton court with what looks like an oversized ping pong paddle and a __________ball.
Group of answer choices
whiffle
tennis
paddle
boccee
Flag this Question
Question 6 10 pts
In Pickleball, there are two non-volley lines, which create an area called the _______ .
Group of answer choices
Kitchen
Ally
Drop Zone
Dead Area
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Question 7 10 pts
Only the receiving team can score a point by winning a rally.
Group of answer choices
True
False
Flag this Question
Question 8 10 pts
Pickleball combines elements of Badminton, Tennis and ____________.
Group of answer choices
Ping Pong
volleyball
Bocce
Four Square
Flag this Question
Question 9 10 pts
Players may not hit the ball while standing in the kitchen unless the ball has already bounced on their side.
Group of answer choices
True
False
Flag this Question
Question 10 10 pts
Before serving, the server must call the score.
Group of answer choices
True
False
Answer:
1- bounce rule
2- left
3-11,2
4-true
5- whiffle ball
6- kitchen
7-false
8- ping pong
9- true
10- true
Explanation:
I'm pre5sure they are all right. brainliest please
Answer: I had the same quiz too I’m only doing so the other guy can get brainliest
Explanation:Kfkfkfjgjggj
Jack is buying a subscription to a magazine club. The function c=45+3.75m
c
=
45
+
3
.
75
m
describes the cost of the yearly subscription, c
c
, in terms of the number of magazines, m
m
, he orders.
What is the appropriate domain for the function?
the set of integers
the set of whole numbers
the set of all real numbers
the set of rational numbers
Answer:
the set of all real numbers
Explanation:
Given the cost of the magazine expressed as:
c=45+3.75m where:
c describes the cost of the yearly subscription.
m is the amount of order.
You must understand that domain are the values of the input variable m that will make the function exist.
The value of m that will produce a positive output since we can only have a positive value of the cost. According to the option, we can say that the domain is on the set of all real numbers (some are negative but all positive real numbers)
A rectangular loop with an area of 2 m2 is placed perpendicular to a uniform magnetic field of 1 Tesla. The field’s magnitude is increased to 6 Tesla in 4 seconds. The magnitude of the induced emf is equal to:
Answer:
Induced emf = 0
Explanation:
An emf can be induced due to the change in magnetic field. It can be given by :
[tex]\epsilon=\dfrac{d\phi}{dt}\\\\\because \phi=BA\cos\theta\\\\\epsilon=\dfrac{d(BA\cos\theta)}{dt}\\\\\epsilon=A\cos\theta\dfrac{dB}{dt}[/tex]
As the loop is placed perpendicular to a uniform magnetic field of 1 Tesla. It means that [tex]\theta=90^{\circ}[/tex] and cos(90) = 0. Hence, the induced emf is equal to 0.
A car accelerates from rest to a certain velocity in a certain time. Assume that there is no friction, and that the engine power is constant. Consider the following scenarios independently. How long would it take to reach double the velocity (also from rest)
Answer:
it will take half of the initial time to reach double the velocity
Explanation:
Given that a car accelerates from rest to a certain velocity in a certain time.
Since the car accelerate from rest, the initial velocity U = 0
Using the first equation of motion,
V = U + at
V = at
Assume that there is no friction, and that the engine power is constant. Consider the following scenarios independently. How long would it take to reach double the velocity (also from rest)
That is V = 2V
Using the same formula ,
2( at ) = at
2T = t
T = t/2
Therefore, it will take half of the initial time to reach double the velocity
A net force of 275 N accelerates a 18.0 kg mass. What is the resulting acceleration? (5 points)
Answer:
The answer is 15.28 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
where
m is the mass
f is the force
We have
[tex]a = \frac{275}{18} \\ = 15.277777...[/tex]
We have the final answer as
15.28 m/s²Hope this helps you
Calculate the maximum energy that a 3-MeV alpha particle can transfer to an electron in a single collision.
Answer:
The maximum energy that can be transferred to an electron in a single collision of alpha particle is 1.63 keV
Explanation:
let mass of electron, Me = 1
let mass of proton, Mp = 1836Me = 1836
let mass of alpha particle, Ma = 4Mp = 7344
The maximum energy that can be transferred to an electron in a single collision is given by;
[tex]Q_{max} = \frac{4mME}{(M+m)^2}\\\\Q_\alpha_{max} = \frac{4(1)(7344)(3\ MeV)}{(1+7344)^2} = 0.00163 \ MeV = 1.63 \ KeV[/tex]
Therefore, the maximum energy that can be transferred to an electron in a single collision of alpha particle is 1.63 keV
Newton’s third law says that every time there is an interaction force, there is also a force that is ______________________ in size and acts in the ____________________________ direction .
Answer:
equal, opposite
Explanation:
Newton’s third law says that every time there is an interaction force, there is also a force that is equal in size and acts in the opposite direction .
MULTIPLE CHOICE QUESTION
What is the acceleration of the object?
(Remember a = Fnet/m and acceleration needs a
direction)
8 m/s/s
0.125 m/s/s to the right
8 m/s/s to the left
8 m/s/s to the right
Which object? More information is needed to answer this question
A 1500 kg car traveling at 35 m/s hits its brakes and comes to rest in 5 seconds. Calculate the force applied by the brakes. (hint: solve for a first) Show all steps!!
Answer:
We are given:
m = 1500 kg
initial velocity (u) = 35 m/s
final velocity (v) = 0 m/s
time (t) = 5 seconds
acceleration = a m/s/s
Force (f) = F newtons
Solving for acceleration:
Using the first equation of motion:
v = u + at
replacing the variables
0 = 35 + a(5)
a = -35/5
a = -7 m/s/s
Force applied by the brakes:
From newton's second law of motion:
F = ma
replacing the variables
F = (1500)(-7)
F = -10500 N
Therefore, the force applied by the brakes is -10500 N, we have a negative sign since the force is being applied opposite to the direction of motion
List some of the most common injuries that can occur from sports. Please hurry!
Suppose a rocket-propelled motorcycle is fi red from rest horizontally across a canyon 1.00 km wide. (a) What minimum constant acceleration in the x-direction must be provided by the engines so the cycle crosses safely if the opposite side is 0.750 km lower than the starting point? (b) At what speed does the motorcycle land if it maintains this constant horizontal component of acceleration? Neglect air drag, but remember that gravity is still acting in the negative y-direction.
8. Using Newton's second law, solve the following problems using
GFFS.
a. A force of 35N is applied to a 25kg object, what is its
acceleration??
b. What force is required to accelerate a 14kg object at 4.5
m/s2?
c. Calculate the mass of an object that accelerated at a rate of
2.7 m/s2 by a force of 18N.
Answer:
a) 1.4 m/s2
b) 63N
c) 6.66kg
A ball is dropped from a 19m high cliff. The acceleration on the ball was 9.8m/s². What was the ball's final velocity before hitting the ground?
Answer:
19.3 m/s
Explanation:
Take down to be positive. Given:
Δy = 19 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (19 m)
v = 19.3 m/s
What is the main difference between the atoms in a solid versus atoms in a 1 point
liquid?
Answer:
Atoms in a solid are close and tightly packed.They vibrate about fixed positions .They are arranged in a regular LATTICE.They cannot be compressed nor can they change shape.They have strong forces of attraction between them so they cannot move in order to move they have to gain ENERGY. Whereas the atoms in a liquid are not that close compared to the ones in solid.They take the shape of the container but their volume remains fixed.They have weak forces of attraction between atoms and have more energy which enables them to move.
Explanation:
Consider a wire of length L =0.30 m that runs north-south on a horizontal surface. There is a current I = 0.50 A flowing north in tie wire. The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or, in SI units. 0.5 x 10^—4 and points north and 38 degrees down from the horizontal, toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field?
Answer:
The size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.
Explanation:
To determine the size of the magnetic force on the wire due to the Earth's magnetic field,
The magnetic force is given by the formula
F = ILB sinθ
Where F is the magnetic force on the wire
I is the electric current in Amperes (A)
L is is the length of wire in meters (m)
B is the magnetic field in Tesla (T)
and θ is the angle between current and magnetic field
From the question,
L = 0.30 m
I = 0.50 A
B = 0.50 gauss = 0.5 × 10⁻⁴ T (NOTE: 1 Gauss = 10⁻⁴ Tesla)
θ = 38°
Now, putting the values into the equation
F = ILB sinθ
F = 0.50 × 0.30 × 0.5 × 10⁻⁴ sin38°
F = 7.5 × 10⁻⁶ (0.61566)
F = 4.62 × 10⁻⁶ N
Hence, the size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.
What is the average velocity of a boy moving from initial position of 4 m to a final position of 8 min 20 s. Show steps of solving:
please please heeeeelp
9514 1404 393
Answer:
0.2 m/s
Explanation:
The average velocity is the change in position divided by the change in time:
(8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s
The boy's average velocity is 0.2 m/s.
explain why a wrecking ball can destroy a building, but a yo-yo cant. Use the term kinetic energy in your explanation.
The kinetic energy of a body determines it's level of impact on the object in which it comes in contact with. Hence, the much larger kinetic energy exhibited by a wrecking ball compared to a yo-yo means that is has a much larger impact on a building than a yo-yo.
Kinetic Energy = 0.5mv²The kinetic energy of a body is a factor of it's velocity and mass as they are directly proportional.
The wrecking ball has a very large mass which is thousands of times larger than that of a yo-yo. Also, the velocity at which a wrecking ball is launched is higher than the velocity of a yo-yo.
This means that the kinetic energy of a wrecking ball is much higher than that of yo-yo. Hence, having much greater impact on a building compared to a yo-yo.
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The number of
• in the atom of an element determines its chemical properties.
Answer:
Yes, the number of electrons determines the chemical properties of the atom.
Explanation:
Question 3 of 10
A 0.057 kg tennis ball and a tennis racket collide. The racket has an initial
momentum of -1.75 kg-m/s and a final momentum of -1.25 kg-m/s. The ball
has an initial momentum of 0.00684 kg-m/s. If you assume the collision is
elastic, what is the final velocity of the ball?
A. -0.50 m/s
B. -52.48 m/s
C. -2.99 m/s
d
D. -8.65 m/s
If we assume the collision to be elastic the final velocity of the ball will be -8.65 m/s, therefore the correct option is D.
What is elastic collision?It is a type of Collison for which the momentum, as well as the kinetic energy after and before the collision, is constant. there is no loss of energy in a perfectly elastic collision.
By using the law of conservation of momentum
momentum before collision = momentum after the collision
the initial momentum of rocket +initial momentum, of ball = final momentum of rocket + final momentum of the ball
By substituting the respective values
-1.75 + 0.00684 = -1.25 + m*v
-1.75 + 0.00684 = -1.25 + 0.057*v
v = -8.65 m/s
Thus, the final velocity of the ball is -8.65 m/s
Learn more about elastic collision
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Can someone please answer this
Answer:
-) It is less than 8 [N]
See the explanation below.
Explanation:
To solve this problem we must analyze each of the answers, and in this way, we will come to the right solution. The most important thing is to keep in mind that the body is moving to the left.
-) It is equal to 8 [N]
This answer is not possible, since if the Force F was equal to 8 [N] the body would be in equilibrium and the body would not move.
-) It is equal to 10 [N]
This answer is not possible, since if Force F is greater than 8 [N] the body would move to the right.
-) It is greater than 10 [N]
This answer is not possible, since if Force F is greater than 8 [N] the body would move to the right.
-) It is less than 8 [N]
This is the correct option, as the force of 8 [N] will move the body to the left.
A 100 kg disc with radius 1.6 m is spinning horizontally at 25 rad/s. You place a 20 kg brick quickly and gently on the disc so that it sticks to the edge of the disc. Determine the final angular speed of the disc-brick system.
Answer:
20.83rad/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the mass of the disc and Brick respectively
u1 and u2 are the linear velocities respectively
v is their final velocity of the block-disc system
Given
m1 = 100kg
m2 = 20kg
u1 = wr =25×1.6
u1 = 40m/s
u2 = 0m/s (brick is stationary)
Substitute and the final linear velocity v
100(40)+20(0) = (100+20)v
4000 = 120v
v = 4000/120
v = 33.3m/s
From the formula;
v = wr
w = v/r
w= 33.3/1.6
w = 20.83rad/s.
Hence the final angular speed of the disc-brick system is 20.83rad/s
Help please!!!!!!!!!!!!!
Answer:
The second choice
Explanation:
I think the answer is the second choice because if the surface is smooth, there is less friction. With a boat, it is easier to pull it on water than on the sand, because water has less friction, and thus, the answer is the second choice because rough surfaces have more friction.
Hopefully the explanation and answer helps!
A body is pulling a load of 50N with a string inclined at an angle of 30 degrees to the horizontal.
If the tension is 108N, calculate the force tending to lift the load off the ground.
Answer:
answer: 105 sin 30 = 52.5
A coin is rolling across a table at 0.23 m/s. It rolls off the table and lands 0.15 meters away from the edge of the table. How high is the table? Show all your work.
Answer:
The table is 2.08 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If we know the range d = 0.15 m and the speed v = 0.23 m/s, we can solve the above equation for h:
[tex]\displaystyle h=\frac{d^2\cdot g}{2v^2}[/tex]
[tex]\displaystyle h=\frac{0.15^2\cdot 9.8}{2\cdot 0.23^2}[/tex]
[tex]\boxed{h=2.08\ m}[/tex]
The table is 2.08 m high
If the breaking strength of the string is 120 N, what is the minimum angle the string can make with the horizontal
Complete Question
A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string, If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?
Answer:
The value is [tex]\theta = 4.41^o[/tex]
Explanation:
From the question we are told that
The mass of the rock is [tex]m_r = 940 \ g = 0.94 \ kg[/tex]
The length of the string is [tex]l = 1.30 \ m[/tex]
The breaking strength(i.e the maximum tension) on the string is [tex]T = 120 \ N[/tex]
Gnerally the vertical component of the tension experienced by the string is mathematically represented as
[tex]T_v = T sin(\theta)[/tex]
Generally this vertical component of tension is equivalent to the weight of the rock
So
[tex]Tsin (\theta) = mg[/tex]
=> [tex]\theta = sin^{-1} [\frac{mg}{ T} ][/tex]
=> [tex]\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ][/tex]
=> [tex]\theta = 4.41^o[/tex]
Nora notices water droplets on the grass in the morning. It did not rain during the night. Which statement is true about this change of state?
Mass was added to the water particles, resulting in deposition.
Energy was added to the water particles, resulting in evaporation.
Mass was removed from the water particles, resulting in sublimation.
Energy was removed from the water particles, resulting in condensation.
Answer:
Mass was added to the water particles, resulting in deposition.
Explanation:
Answer: The energy was removed from the water particles resulting in condensation
Explanation Think about when you leave a cup of ice of and after a while you see water droplets thats what happened to the grass in the morning and thats called condensation.
A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen when the spectacles hit the ground? Neglect the air resistance.
Answer:
[tex]h_p = 30.46\ m[/tex]
Explanation:
Free Fall Motion
A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.
The speed vf of the object when a time t has passed is given by:
[tex]v_f=g\cdot t[/tex]
Where [tex]g = 9.8 m/s^2[/tex]
Similarly, the distance y the object has traveled is calculated as follows:
[tex]\displaystyle y=\frac{g\cdot t^2}{2}[/tex]
If we know the height h from which the object was dropped, we can solve the above equation for t:
[tex]\displaystyle t=\sqrt{\frac{2\cdot y}{g}}[/tex]
The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:
[tex]\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec[/tex]
The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:
[tex]t_2=2.56 - 2 = 0.56\ sec[/tex]
Therefore, it has traveled down a distance:
[tex]\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m[/tex]
Thus, the height of the pen is:
[tex]h_p = 32 - 1.54\Rightarrow h_p=30.46\ m[/tex]
The pen is 30.52 m above the ground.
Given that the height of the stadium is h = 32m
The initial velocity of the glasses will be 0.
[tex]h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s[/tex]is the time taken for the glasses to hit the ground.
Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:
[tex]t^{'}=2.55-2\\t^{'}=0.55s[/tex]in the air
distance traveled by the pen:
[tex]d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m[/tex]
So the pen is [tex]h-d=32-1.48=30.52m[/tex] above the ground.
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PLEASE PLEASE HELP PICTURE INCLUDED
Answer:
an electro magnet is technology contain at least one permanent magnet
What is the freezing point (in degrees Celcius) of 4.62 kg of water if it contains 236.5 g of C a B r 2
Answer:
The new freezing point of water is -0.476°C.
Explanation:
Given that,
Mass of water = 4.62 kg
Mass of CaBr₂ = 236.5 g
We need to calculate the molality of solution
Using formula of molality
[tex]m=\dfrac{mass\ of\ CaBr_{2}}{molar\ mass\ of\ CaBr_{2}\times mass\ of\ water}[/tex]
Put the value into the formula
[tex]m=\dfrac{236.5}{200\times4.62}[/tex]
[tex]m=0.256\ mol/kg[/tex]
[tex]m=0.256\ m[/tex]
We need to calculate the depression in freezing point of water
Using formula of freezing point
[tex]\Delta T=m\times k[/tex]
Where, k = depression constant
m = molality of solution
Put the value into the formula
[tex]\Delta T=0.256\times1.86[/tex]
[tex]\Delta T=0.476^{\circ}C[/tex]
We know that,
The standard freezing point of water is 0°C
We need to find the new freezing point of water
Using formula for freezing point of water
Freezing point of 4.62 kg of water = freezing point of water-depression in freezing point of water
[tex]\Delta T'=0-\Delta T[/tex]
Put the value into the formula
[tex]\Delta T'=0-0.476[/tex]
Hence, The new freezing point of water is -0.476°C.
WHat is the correct definnition for recovery heart rate ?
Answer:
when your heart rate is not high than normal or lower than normally
Explanation:
Recovery heart rate is when your heart recovers from a certain heart rate eg high heart rate or even low heart rate this means you heart is now functioning normally .
Answer:
Number of beats per minute the heart drops after exercise.