Answer:
The empirical formula of the chemical compound is C₆H₁₂SO₂
Explanation:
To determine the empirical formula, the mass of each element in the compound is first determined from their respective compounds formed after combustion analysis.
Mass of element = mass of compound × molar mass of element / molar mass of compound
Carbon: 53.694 g x (12g/mol / 44.0 g/mol) = 14.643 mg of C in 30.141 mg sample Hydrogen: 21.980 mg x ( 2.00 / 18.00) = 2.442 mg of H in 30.141 mg sample
Sulfur: 13.05 mg x (32.00/ 64.00) = 6.525 mg of S in 30.199 mg in sample
The percentage mass composition of the elements in the compound is then determined:
Carbon: 14.643 mg / 30.141 mg = 48.58%
Hydrogen: 2.442 mg / 30.141 mg = 8.10%
Sulfur: 6.525 mg / 30.199 mg = 21.60 %
Oxygen: 100% - (48.58% + 8.10% +21.60%) = 21.72%
Number of moles of each element is then determined:
Number of moles = percentage mass/molar mass
Carbon: 48.58/12 = 4.07
Hydrogen: 8.10/1 = 8.10
Sulfur: 21.60/32 = 0.68
Oxygen: 21.72/16 = 1.36
Dividing with the smallest amount to obtain a whole number mole ratio
Carbon: 4.07 ÷ 0.68 = 6
Hydrogen: 8.10 ÷ 0.68 = 12
Sulfur: 0.68 ÷ 0.68 = 1
Oxygen: 1.36 ÷ 0.68 = 2
Therefore, the empirical formula of the chemical compound is C₆H₁₂SO₂
if irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?
A. 460
B. 690
C. 75,000
D. 230
E. 34,500
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Answer:
Option D. 230 J
Explanation:
We'll begin by calculating the temperature change of the iron. This can be obtained as follow:
Initial temperature (T₁) = 50 °C
Final temperature (T₂) = 75 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 75 – 50
ΔT = 25 °C
Thus, the temperature change of the iron is 25 °C.
Finally, we shall determine the amount of heat energy used. This can be obtained as follow:
Mass (M) = 20 g
Change in temperature (ΔT) = 25 °C
Specific heat capacity (C) = 0.46 J/gºC
Heat (Q) =?
Q = MCΔT
Q = 20 × 0.46 × 25
Q = 230 J
Thus, the amount of heat used was 230 J
How many atoms in total are there in 7.35 mol of magnesium oxide (MgO)
molecules?
Answer:
4.42 x 10^24
Explanation:
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picture ⬆️
Answer: A Molecular Approach, 2/e. Mole ratio. 2 mol C4H10 : 13 mol O2 : 8 mol CO2 : 10 mol H2O. ❖ 2 molecules of C4H10 react ... of aluminum and 73.15 g of sulfur are combined to form aluminum sulfide according to the equation:.
Explanation:
In this lab you will need to prepare solutions using dilutions. Starting with the stock 0.300 M NaOH solution, how would you prepare a 0.100 M NaOH solution (using 0.300 M NaCl as the diluent)
Answer:
1/3 dilution : 1 volume of stock solution + 2 volumes of diluent
Explanation:
Concentrated solution = 0.300 NaOH
Diluted solution = 0.100 NaOH
The dilution factor is : 0.100/0.300 = 1/3
Thus, we have to dilute three times the stock solution. For this, we take 1 volume of stock solution and then we add 2 volumes of diluent. As result, we will have 1 volume of stock solution in a total of 3 volumes. For example, we take 1 mL of 0.300 NaOH and then we add 2 mL of diluent (0.300 NaCl). The final concentration after dilution will be:
Cd = 0.300 M x 1 mL/3 mL = 0.100 M
A car starts out when the air temperature is 298 K and the absolute (total) air pressure in the tires is 500 kPa. After driving a while, the temperature of the air in the tires increases to 315 K. What is the pressure in the tires at that point, assuming their volume does not change
Answer: The pressure in the tires at that point is 528.52 kPa.
Explanation:
Given: [tex]T_{1}[/tex] = 500 K, [tex]P_{1}[/tex] = 500 kPa
[tex]T_{2}[/tex] = 315 K, [tex]P_{2}[/tex] = ?
According to Gay-Lussac's law, at constant volume the pressure of a gas is directly proportional to temperature.
Formula used to calculate the pressure is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{500 kPa}{298 K} = \frac{P_{2}}{315 K}\\P_{2} = 528.52 kPa[/tex]
Thus, we can conclude that the pressure in the tires at that point is 528.52 kPa.
help please hurry lots of points
whic process does not occur in the organelle illustrated above?
Answer:
it isnt possible to answer this without you providing the "organelle illustrated above".
Explanation:
please provide the "organelle illustrated above".
which of these is inorganic 1) leaf 2) earthworms 3) minerals 4) bacteria
Answer:
Bacteria
Explanation:
A chlorine atom becomes stable by having 8 valence electrons by
A losing one electron
B gaining one electron
C gaining 3 electrons
D losing seven electrons
a student adds 0.5 moles of solute to enough water to form 500 ml of solution what is the concentration of the solution he made
Answer: The concentration of solution made by the student is 1 M.
Explanation:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.
The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Moles of solute = 0.5 moles
Volume of solution = 500 mL
Plugging values in equation 1:
[tex]\text{Molarity of solution}=\frac{0.5\times 1000}{500}\\\\\text{Molarity of solution}=1M[/tex]
Hence, the concentration of solution made by the student is 1 M.
1. What happens when like charges are brought closer to each other?
What do all fossil fuels have in common?
O A. They are all liquids.
OB. They all contain crude oil.
O C. They all produce nitrogen as a combustion product.
O D. They are all nonrenewable energy sources.
Answer:
Your answer would be D, they are all non-renewable energy sources. Hope this helps!
Answer:
D. They are all nonrenewable energy sources.
Cobalt has an atomic number of 27 and atomic mass of 59. How many neutrons does cobalt have? 
A. 32
B. 31
C. 30
D. 33
Answer:
32
Explanation:
59-27
Why did the model of the atom change?
A. New materials became available to build better models.
B. The structure of atoms changed over time.
C. Scientists did not like the original model.
D. Experiments provided new evidence about the atom.
If in Part II, you mixed (carefully measured) 25.0 mL of 0.81 M NaOH with 65.0 mL of 0.33 M HCl, which of the two reagents is the limiting reagent for heat of reaction
Answer:
NaOH is the limiting reactant.
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write out the chemical reaction between NaOH and HCl:
[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]
Thus, since they react in a 1:1 mole ratio; we can now calculate the moles of each substance by using their volumes and molarities:
[tex]n_{NaOH}=0.0250L*0.81mol/L=0.02025molNaOH\\\\n_{HCl}=0.0650L*0.33mol/L=0.02145molHCl[/tex]
Now, since NaOH is in a fewer proportion, we infer just 0.02025 moles of HCl are consumed so that 0.0012 moles of this acid remain unreacted; in such a way, we infer that the NaOH is the limiting reactant for this reaction.
Regards!
100 grams of iron (Fe) reacts with sulfuric acid (H2SO4) in the following equation.
Fe + H2SO4 Fe2(SO4)3 + H2
36. The number of grams of iron (III ) sulfate [Fe2(SO4)3] that will be produced is __ grams.
a
275
b
357
b
b357
Answer:
2Fe +3 H2SO4 Fe2(SO4)3 + 3H2
2*56g. 3*98g➔400g. +6g
we have
2*56 g of Fe gives 400g of iron (III ) sulfate
now
100g of Fe gives=400/112*100=357g of iron (III ) sulfate
[tex]\:[/tex]
B is your answer.!
If an aqueous solution of ___________ is added to a mixture of barium nitrate and silver nitrate, the barium ion will precipitate, but the silver ion would remain in solution.
Answer:
sodium fluoride
Explanation:
When we add sodium fluoride to a solution of a given mixture, we get barium fluoride from Ba, which would be an insoluble salt, and silver fluoride from Ag, which would be a soluble salt.
The solubility rule will be used to determine the barium salt that forms as a precipitate and leaves Ag+ salt in the solution.
From the following equations, we will see that the precipitate is formed in Ba but Ag remains dissolved in the solution.
[tex]Ba(NO_3)_2{(aq)} + 2NaF_{(aq)} \to BaF_{2(s)} +2NaNo_{3(aq)}[/tex]
[tex]AgNo_{3(aq)} +NaF_{(aq)} \to AgF_{(aq)} + NaNO_{(aq)}[/tex]
if every atom of an oxygen has 8 protons in its nucleus what is the atomic number of oxygen
Answer:
8
Explanation: # of protons = atomic #
How many moles of Aluminum are in 54.0 grams of Aluminum (Al)
Answer:
2 moles!
Explanation:
Hi i hope this helped! I researched it and 2 moles was what came up first.
Josh decided his glass of iced tea needed to be sweeter. He found two types of sugar he could use in the kitchen. There was a bowl of loose crystals of sugar and a bowl of sugar cubes. Which one will dissolve faster in the iced tea
Answer:
Therefore, it can be said that sugar molecules whether in crystal or cube form do not dissolve in ice tea.
Explanation:
Sugar molecules easily dissolve in warm or hot tea. However, in iced tea sugar does not dissolve it does not matter whether you use sugar cubes or sugar crystals.
This happens because of the entropy. The entropy of warm water is high as it has fast-moving molecules, whereas the entropy of ice water is negligible. hence, sugar molecules do not dissolve in ice tea.
Therefore, it can be said that sugar molecules whether in crystal or cube form do not dissolve in ice tea.
What is a definition for ergonomics?
A 50.00 g sample of a compound containing only carbon, hydrogen, and oxygen was partially analyzed. The sample contained 24.66 g carbon, and 3.43g of hydrogen. The molecular weight of the compound was determined to be 146.0 amu. Determine emperical the molecular formula of the compound
Answer:
1. Empirical formula => C₂H₃O
2. Molecular formula => C₆H₉O₃
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 50 g
Mass of Carbon = 24.66 g
Mass of Hydrogen = 3.43 g
Molecular weight of compound = 146.0 amu
Empirical formula =?
Molecular formula =?
Next, we shall determine the mass of oxygen in the compound. This can be obtained as follow:
Mass of compound = 50 g
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O =?
Mass of O = mass of compound – ( mass of C + mass of H)
= 50 – (24.66 + 3.43)
= 50 – 28.09
= 21.91 g
1. Determination of the empirical formula.
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O = 21.91 g
Divide by their molar mass
C = 24.66 / 12 = 2.055
H = 3.43 / 1 = 3.43
O = 21.91 / 16 = 1.369
Divide by the smallest
C = 2.055 / 1.369 = 2
H = 3.43 / 1.369 = 3
O = 1.369 / 1.369 = 1
Therefore, the empirical formula of the compound is C₂H₃O
2. Determination of the molecular formula.
Molecular weight of compound = 146.0 amu
Empirical formula => C₂H₃O
Molecular formula =?
Molecular formula = [C₂H₃O]ₙ = molecular weight
Thus,
[C₂H₃O]ₙ = 146
[(12×2) + (3×1) + 16]n = 146
[24 + 3 + 16]n = 146
43n = 146
Divide both side by 43
n = 146 / 43
n = 3
Molecular formula = [C₂H₃O]ₙ
Molecular formula = [C₂H₃O]₃
Molecular formula = C₆H₉O₃
In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equatorial position and the alcohol in the ________ position.
Answer:
Axial position
Explanation:
In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equatorial position and the alcohol in the axial position.
The reason for this is that, axial bonds are parallel to each other. If substituents are larger than hydrogen, they experience a greater steric crowding in axial compared to the equatorial position. Therefore, many substituted cyclohexane compounds prefer a conformation in which the larger substituents are in equatorial position.
How many molecules are in 1.75 moles of Caco3?
1.75 molecules
3.440 x 1023 molecules
1.054 x 1024 molecules
O 2.907 x 10-24 molecules
Answer:
1.054 x 10²⁴ molecules
Explanation:
In order to convert moles of any given substance into a number of molecules, we need to use Avogadro's number, which states the number of molecules -or atoms, in the case of elements- present in one mol:
In one mol there are 6.023x10²³ molecules.We now convert 1.75 moles into molecules:
1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ moleculesRISD-QSA-SCI-CHEM-Units 7-12 Question: 1-1
A sample of 0.0255 mol potassium hydroxide, KOH, was dissolved in water to yield 10.0 mL of solution. What is the molarity of the solution?
Answer:
0.02.55M
Explanation:
Concentration = moles/ volume(L)
10mL= 0.01L
Concentration (M)= 0.0255 mol / 0.01L
Concentration (M)= 0..255M
solution of alcohol and water
[tex]\huge\mathsf{\red{\underline{\underline{Answer}}}}[/tex]
[tex]{\green{\dashrightarrow}}[/tex]When you mix the rubbing alcohol with water, the latter's molecules make hydrogen bonds with the water molecules. The alcohol dissolves in the water to form a homogenous solution, so you cannot distinguish the alcohol and the water anymore.
5. There is no water cycle where it is cold.
O true
O false
Answer:
False
Explanation:
There is a water cycle wherever there is water. If it is cold, the water cycle will just be very slow.
What is the wavelength of a light of frequency 7.21 x 1014 Hz?
O A. 237 nm
B. 721 nm
C. 416 nm
O D. 628 nm
The wavelength of the light having a frequency of 7.21×10¹⁴ Hz is 416 nm (Option C)
How do I determine the wavelength of light?Wavelength and frequency are related to the velocity of a wave according to the following formula:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above formula, the wavelength of the light can be obatined. Details below.
From the question given above, the following data were obtained:
Frequency (f) = 7.21×10¹⁴ HzVelocity of light (v) = 3×10⁸ m/sWavelength (λ) = ?Velocity (v) = wavelength (λ) × frequency (f)
3×10⁸ = wavelength × 7.21×10¹⁴
Divide both sides by 7.21×10¹⁴
Wavelength = 3×10⁸ / 7.21×10¹⁴
Wavelength = 416×10⁻⁹ m
Multiply by 10⁹ to express in nm
Wavelength = 416×10⁻⁹ × 10⁹
Wavelength = 416 nm
Thus, we can conclude that the wavelength is 416 nm (Option C)
Learn more about wavelength:
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El osmio es un metal sólido que tiene una densidad
de 22 600 kg/m?, ¿qué volumen ocuparán 100 g de
este metal?
Answer:
4.42x10⁻⁶ m³
Explanation:
Primero convertimos 100 gramos a kilogramos:
100 g / 1000 = 0.100 kgAhora se puede calcular el volumen que ocuparán 0.100 kg de osmio, usando la densidad dada por el problema:
Densidad = masa / Volumen22600 kg/m³ = 0.100 kg / volumenvolumen = 4.42x10⁻⁶ m³La respuesta es 4.42x10⁻⁶ m³.
Which part of the atom does gamma radiation depend on?
nucleus
protons
energy levels
electrons
Answer:Gamma radiation is the product of radioactive atoms. Depending upon the ratio of neutrons to protons within its nucleus, an isotope of a particular element may be stable or unstable.
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