Answer:
V= 1,160 m
Explanation:
formula:
V= V* T
remplazamos:
V= 116m /s * 10s
V= 1,160 m
Answer:
V= 1,160 m
Explanation:
Do you always need
more than one reactant
or more than one
product to have a
chemical reaction?
Answer:
no
Explanation:
1. Day and Night are caused by
10 points
A. The Tilt of the Earth’s Axis.
B. Earth’s Revolution around the sun
C. Earth's ellipical orbit
D. Earth's rotation on its axis.
An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
(A) work done on the object
(B) total force applied to the object
(C) weight of the object
(D)change in kinetic energy of the object
PLEASE HELP ME
Answer:
b
Explanation:
A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *
Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :
[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]
Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of acceleration?
Answer:
x = 95 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
Now we can find the acceleration
19 = 0 *a*(10)
a = 1.9 [m/s]
With the second equation we can find the distance:
[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]
where:
x = distance [m]
(19)² = (0)² + (2*1.9*x)
3.8*x = 361
x = 95 [m]
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Answer:
The answer is 1376 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 8 × 10 × 17.2
We have the final answer as
1376 JHope this helps you
Explanation:
potential energy = mgh
potential energy = 8 * 10 * 17.2
potential energy = 1376 joules
Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?
Answer:
a) A´= A
b) θ₁´ = 29º, θ₂´ = - 169º , θ₃´ = -49º
Explanation:
In this exercise you are asked to give the magnitudes and angles of the vectors from another system of
reference
a) The magnitudes
The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector
A = [tex]x_{f}[/tex]- x₀
if the vectors are measured in another reference frame
x_{f}´ = xx_{f}- U
x₀´ = x₀ -U
where U is the distance between the two reference frames
A´ = x_{f}´ - x₀´
we substitute
A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀
A´ = A
it does not change
b) Angles
The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis
θ₁ = 29º
does not change
θ₁´ = 29º
θ₂ = 191º
we measure clockwise
θ₂´ = θ₂ - 360
θ₂´ = 191 - 360
θ₂´ = - 169º
θ₃ =311º
we measure clockwise
θ₃´ = 311 -360
θ₃´ = -49º
Do larger bodies orbit smaller bodies or do smaller bodies orbit larger bodies? Provide some examples to support your answer.
Explanation:
the small bodies in the solar system include comets, asteroids, the objects in the Kuiper Belt and the Oort cloud, small planetary satellites, Triton, Pluto, Charon, and interplanetary dust. As some of these objects are believed to be minimally altered from their state in the young solar nebula from which the planets formed, they may provide insight into planet Earth and the formation and evolution of the solar system.
15. Which element will donate electrons?
nitrogen
chlorine
aluminum
sulfur
Answer if you know
If you give me a good explanation on how quantum mechanics work, you get 20 points and possibly a brainliest.
Answer:
spectra.
Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.
Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.
Explanation:
If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
1. A pumpkin with a mass of 2 kg accelerates 2 m/s/s when an unknown force is applied to it. What is the amount of the force?
Answer:
The answer is 4 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 2 × 2
We have the final answer as
4 NHope this helps you
Which of the following statements is correct.
A. A direct relationship exists between frequency and wavelength, as the frequency increase from Radio waves to Gamma rays so does the wavelength.
B. A direct relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays so does the wavelength.
C. An indirect relationship exists between frequency and wavelength, as the frequency increase
from Radio waves to Gamma rays the wavelength decrease.
D. An indirect relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays Wie wavelength increase
Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
,
what is the greatest possible magnitude of the other force?
Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
[tex]a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N[/tex]
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
In a physics lab, students take a long piece of string and cut it into two unequal pieces. One piece is used to suspend a large weight. The second piece is tied to the bottom of the weight as seen in the diagram below. Student 1 predicts that the upper string will always break first since it has to support the weight and the applied force, while Student 2 disagrees and predicts that the shorter piece of string will always break first if you pull slowly but with enough force to exceed the strength of the string.
(a) Which aspect(s) of Student 1’s reasoning, if any, are correct? Explain your answer.
(b) Which aspect(s) of Student 2’s reasoning, if any, are correct? Explain your answer.
(c) Which aspect(s) of both Student 1’s and 2’s reasoning, if any, are incorrect? Explain your answer.
(d) The experiment is performed and both students are surprised to learn that whether
the upper or lower string breaks first depends on whether you pull slowly or with a
sudden pull. Resolve the two lines of reasoning of Student 1 and Student 2 by
explaining the results of the experiment in a clear, concise paragraph.
Answer:
(a) The aspect of the upper string supporting the weight and the applied force
Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string
(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum
(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first
The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first
(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first
Explanation:
What quantities belong in cells X and Y?
X: centripetal acceleration
Y: period
X: tangential speed
Y: radius
X: radius
Y: centripetal acceleration
X: period
Y: tangential speed
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
The quantities belonging in cells X and Y is to be considered as the
X: period
Y: tangential speed
Quantities belong in cells X and Y:The equation for centripetal acceleration is
= v² / r
here, v should be the tangential velocity of the body
And the radius of curvature.
So based on this, we can say that
Column X. Tangential Speed
Column Y. radius
Learn more about cell here: https://brainly.com/question/15182235
Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)
Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it
Answer:
2
Explanation:
pressure(p)=force(f)\area(a)
The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, and the rock's horizontal displacement is 255 cm, what was the speed that you thew the rock
Answer:
12.495m/s
Explanation:
Horizontal displacement is the range of the projectile motion.
The range is expressed as;
R = 2U/g
U is the speed at which the rock is thrown (initial speed)
g is the acceleration due to gravity.
Given
R = 255cm = 2.55m
g = 9.8m/s²
Required
Speed U
Substitute the given parameters into the formula as shown;
2.55 = 2U/9.8
Cross multiply
2U = 2.55×9.8
2U = 24.99
U = 24.99/2
U = 12.495m/s
Hence the speed that you thew the rock is 12.495m/s
the gravitational field strength on mars is 3.7n/kg
Answer:
True
Explanation:
Is Time and Light both connected in anyway?
Answer:
It is not connected by any way
What is the root of all electrical systems?
1 batteries
2 electrons
3 atoms
4 non of the above
Answer:
I believe it's 2. I am not sure though.
When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
How far will you travel in 3.5 hrs if you have an average velocity of 90 km/hr
Answer:
The answer is 315 km
If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
very long
far apart
very short
close together
Answer:
If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.
A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
s the statement, "You run faster than I do," qualitative or quantitative?
Answer:
qualitative, its an expression, not specific #'s
Explanation:
It is Qualitative
What is Qualitative or Quantitative?Quantitative : Data is number based , countable or measurable
Qualitative : Data is interpretation based , descriptive and relating to language
Since , the statement given in question does not in include any kind of number or measurable quantity and its just an descriptive and relating to language . It is Qualitative
Learn more about Qualitative or Quantitative:
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#SPJ2
A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False
Answer:
the correct answer is b
Answer:
true
Explanation:
just did it on ck12 lol
Una fuerza resultante constante de módulo igual a 40 [N], actúa sobre un cuerpo que se mueve en línea recta.¿Que distancia ha recorrido ese cuerpo si su energía cinética varió en 8 [J]?
Responder:
0,2 m
Explicación:
Usando la fórmula para calcular el trabajo realizado expresada como;
Workdone = Fuerza * Distancia
Dado
Fuerza = 40N
Trabajo realizado = 8 julios
Necesario
Distancia
Sustituya los parámetros dados en la fórmula como se muestra;
Distancia = Trabajo / Fuerza
Distancia = 8/40
Distancia = 0,2 m
Por tanto, el cuerpo recorrió una distancia de 0,2 m
A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m/s. What is the average acceleration?
7.2 m/s2
0.14 m/s2
36 m/s 2
7 m/s2
Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = [tex]\frac{v -u}{t}[/tex]
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = [tex]\frac{36 - 1}{5}[/tex] = 7m/s²
Given values:
Top velocity,
v = 1 m/sBottom velocity,
u = 36 m/sTime,
t = 5 sThe acceleration is:
→ [tex]A = \frac{v -u}{t}[/tex]
By putting the values,
[tex]= \frac{36-1}{5}[/tex]
[tex]= \frac{35}{5}[/tex]
[tex]= 7 \ m/s^2[/tex]
Thus the answer above i.e., "option d" is correct.
Learn more about acceleration here:
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