Answer:
The average deceleration of the car can be calculated using the formula for deceleration, which is given by the change in velocity divided by the time over which the change occurs. In this case, the initial velocity of the car is 200 m/s, the final velocity is 0 m/s, and the time over which the change occurs is 2 seconds. Therefore, the average deceleration can be calculated as follows:
Deceleration = (0 m/s - 200 m/s) / 2 s = -100 m/s^2
The negative sign indicates that the deceleration is in the opposite direction to the initial velocity of the car, which is what we would expect in this case, since the car is slowing down. Therefore, the average deceleration of the car is -100 m/s^2.
For another identical object initially at rest, no frictional force is exerted during segment 2 (between t = 2 s and t = 4 s). A rope exerts the same constant force of magnitude F T as in the previous scenario. What is the change in the object's kinetic energy during segment 2?
Based on the information provided, there is a change of 12 Jules in the kinetic energy during segment 2.
What is kinetic energy?Kinetic energy can be defined as the energy produced by the motion of a body. Due to this, the level of energy can change depending on movement. The change in the kinetic energy can be calculated by considering the initial kinetic energy and the final kinetic energy. Moreover, the energy is measured using Joules.
What is the change in the kinetic energy during the segment 2?Let's consider first the information given:
Inital velocity = 4 m/sAcceleration= 2 m/s2Final velocity = 8 m/sBased on the velocity, let's caclulate the change in the kinetic energy:
Final Kinetic energy - Initial kinetic energy
1/2 x 0.5 (8^2-4^2) = 12 Joules
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A train travelling along a straight line with constant acceleration is observed to travel consecutive distances of 1km in times of 30s and 60s respectively. Find the initial velocity of the train.
It moves at a pace of 116.7 meters per second at first. The velocity at time t = 0 is known as the initial velocity (u). It is the rate at which motion initially manifests itself.
What is the formula for calculating the starting value?
In mathematics, the initial value of a function represents the function's y-intercept. Beginning values can also be established using the constant in an equation. It helps to comprehend the y-intercept in graph functions.
Is the initial and ultimate velocities the same?
Initial and end velocities are equal. Consequently, there will be no difference at whatever value of "t." Consequently, this establishes that an object's initial velocity is its speed before being affected by acceleration a.
Briefing:
distance(s) = 1km = 1 × 1000m = 1000m
Time(t) = 60– 30 = 30s
initial velocity = u
acceleration (a) = 10m/s
using the formula
S = ut + ½at²
1000 = 30u + ½ × 10 × 30²
1000 = 30u + 5 × 900
1000 = 30u + 4500
30u = 4500 – 1000
30u = 3500
divide both sides by 30
u = 116.7m/s
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Two ice-hockey players simultaneously strike a puck with their sticks. The stick of one player exerts an eastward force on the puck of 12 N. The other player’s stick exerts a northward force of 15 N on the puck. Assuming that there is no frictional force between the puck and the ice, what is the magnitude of the net horizontal force on the puck?
The magnitude of the net horizontal force on the puck is 12 N.
What is net horizontal force acting on the puck?
The magnitude of the net horizontal force on the puck is the sum of all the forces acting on the puck along the horizontal direction.
The net horizontal force acting on the puck is obtained by applying Newton's second law of motion. Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the oobject.
Mathematically, Newton's second law of motion is given as;
F = ma
where;
m is the mass of the objecta is the acceleration of the objectThe given horizontal force on the puck include;
eastward force = 12 N
force of friction = 0 N
The net horizontal force on the puck is calculated as;
∑Fx = 0 N + 12 N
∑Fx = 12 N
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A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m as shown above. Question The magnitude of the net force on the block while it is sliding is most nearly
The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.
What is magnitude?Magnitude in physics typically refers to a size or quantity. Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. What is Frictionless plane?The Plane by which no opposite force is applied on the sliding or moving object is termed as Frictionless plane.
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Drag each tile to the correct box.
Arrange the events that are believed to have formed the hydrosphere in their order of occurrence.
1. bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor; 5. condensation of water vapor; 6. precipitation in the form of rainfall.
What is Hydrosphere?The millions of meteorites and comets that held the frozen particles that made up our planet's water brought it to us in the form of icy particles.
This frozen material was melting and boiling right away since the Earth was still incredibly hot. Water vapor increased in the Earth's atmosphere as more and more frozen particles arrived on our planet as a result of their boiling.
The water vapor began to condense as it rose higher into the atmosphere once there was enough of it present, which resulted in the formation of clouds. The first precipitation in the form of rainfall emerged from these early clouds.
Therefore, 1. bombardment of comets and meteorites 2. arrival of icy debris; 3. boiling of water due to Earth's enormous heat; 4. rising of water in the form of water vapor.
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Which of the following statements regarding the Roman use of concrete as a building material is FALSE?
O Concrete made rounded arches and curved buildings possible.
O Concrete was cheaper than cut stone.
O Concrete was more difficult to use than cut stone.
O Concrete required the use of less-skilled labor.
The Romans invented a new concrete recipe that combined pozzolana, a fine volcanic ash found in Southern Italy, with lime and water to make a strong, resistant kind of concrete.
The Roman term for concrete was opus caementicium, which meant that it was mixed with small stones. The Roman Empire's preferred building material was concrete. It has been utilized in monuments such as Rome's Pantheon, as well as wharves, breakwaters, and other harbor buildings. This is why concrete does not last as long as natural rocks. However, this is not how Roman concrete works. Theirs was made from volcanic ash, lime, and seawater, utilizing a chemical reaction that Romans may have observed in naturally cemented volcanic ash deposits known as tuff rocks.
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a 15 kg sled is pulled with a force p of 21 n, at an angle of 30 degrees above the horizontal, as shown. assuming no friction, what is the acceleration of the sled?
To find the acceleration of the sled, you can use the formula:
F = ma
where F is the applied force, m is the mass of the object, and a is the acceleration.
In this case, you know the applied force and the mass of the sled, so you can solve for the acceleration.
First, you need to find the horizontal component of the applied force. You can do this using the formula:
F_horizontal = F * cos(θ)
where F_horizontal is the horizontal component of the applied force, F is the applied force, and θ is the angle at which the force is applied.
Plugging in the given values, you get:
F_horizontal = 21 N * cos(30°) = 18.5 N
Then, you can use the formula for acceleration to solve for the acceleration of the sled:
a = F_horizontal / m = 18.5 N / 15 kg = 1.23 m/s^2
So the acceleration of the sled is approximately 1.23 m/s^2.
It's important to note that this calculation assumes that there is no friction acting on the sled. If there is friction present, the actual acceleration of the sled may be different.
a stone is released from rest at height h at the left side of a loop the loop. what is the minimum height hf ro which the stone will not fall of the track at the top of the loop
At height h, on the left side of a loop, a stone is let free from its resting position. h = v^2/(2 x g) + r must the stone be at in order to stay on the track at the top of the loop.
For a stone to not fall off the track at the top of a loop, it must be traveling fast enough to follow the track's curvature. This means that the stone must have a certain minimum speed at the top of the loop in order to complete it from resting position. The minimum speed required for the stone to complete the loop can be calculated using the equation v = sqrt(gr), where v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop. Therefore, the minimum height h for which the stone will not fall off the track at the top of the loop can be calculated using the equation h = v^2/(2*g) + r, where h is the minimum height, v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop.
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A recreational vehicle in the amusement park is traveling on a frictionless track that can make a circular loop as shown in the figure below. The vehicle is released from a point A at a height h from the base of the circular section of the track. (a) What must be the minimum height h required for the vehicle to complete the circular section of the track at point B without falling? If h= 3.50 R and R=20 m, calculate the speed, centripetal acceleration and tangential acceleration of the occupants while the vehicle is at point C (point C is in the horizontal diameter direction).
The minimum height that the block must start to make it around the loop without falling off is h = 5R/2
What is present inside the circular loop?The block slides are around the inside of a circular loop. This shows that or it means that we are dealing with critical velocity in vertical circular motion.
In the critical velocity in the vertical circular motion, the formula for the minimum velocity just at the lowest Point of the vertical circle required to get the critical velocity at the highest point is given as;
v = √(5gR)
Therefore, m will cancel out to give;
½v² = gh
Plugging in the relevant values gives;
½ × [√(5gR)]² = gh
Simplify to get;
5gR = 2gh
g will cancel out to get;
5R = 2h
h = 5R/2
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What are some good experiment ideas for quantum physics (stuff like the double slit experiment)
Some good experiment ideas for quantum physics is magic wavelength magnetometry of ultra-cold atoms.
What is an Experiment?This is referred to as a procedure which is carried out to support or refute a hypothesis. It is usually performed in the laboratory under controlled conditions and to achieve a purpose.
Quantum physics on the other hand is the study of matter and energy at the most fundamental level and also explains the properties and behaviors of very small objects, such as electrons, photons etc.
Magic wavelength magnetometry of ultra-cold atoms is characterized by the use of perturbations in the ambient magnetic field on particles such as electrons which are caused by contrasts in magnetic susceptibility and it helps in the study of quantum physics.
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I’m stuck on this question please help.
The magnitude of R for a hollow circular cross section will be less than the magnitude of q for a solid circular cross section with the same outside diameter in the given diagram.
What is Circular Hollow Section?
Circular Hollow Section member in the given circuit is loaded by a radial external lateral pressure that always acts normally to the cylindrical shell mid-surface, its direction depends on the shell deformation – the external pressure has a follower nature, remaining normal to the shell during and after deformation.
The area A of a circuit hollow cross-section, having radius R, and wall thickness t, can be found with the next formula where the inner, hollow area radius. In terms of tube diameters, the above formula is equivalent.
Therefore, The magnitude of R for a hollow circular cross section will be less than the magnitude of q for a solid circular cross section with the same outside diameter in the given diagram.
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The speedometer of a car reads 85 mph. It passes a truck in the next lane traveling at 75 mph. Which of the following statements is true?
Both measurements are scalar quantities.
Both measurements are vector quantities.
The car's measurement is a scalar, and the truck's measurement is a vector.
The car's measurement is a vector, and the truck's measurement is a scalar.
Answer: Both measurements are scalar quantities.
Explanation:
In physics, a scalar quantity is a quantity that is completely specified by its magnitude, without any reference to direction. Speed is an example of a scalar quantity, because it is a measure of how fast an object is moving, without specifying the direction in which it is moving. In this case, both the speedometer reading of 85 mph and the speed of the truck in the next lane at 75 mph are scalar quantities, because they are both measures of speed without specifying a direction.
A heavy rock and a light rock are dropped from the same height and experience no significant air resistance as they fall. Which of the following statements about these rocks are correct?O Just as they are about to reach the ground, the heavier rock has more kinetic energy than the lighter rockO The moment they were released, both rocks had the same amount of gravitational potential energy O Both rocks have the same kinetic energy when they reach the ground O The heavier rock reaches the ground before the lighter rock. .O Both rocks different acceleration as they are about to reach the ground
The correct statement about the rocks is Just as they are about to reach the ground, the heavier rock has more kinetic energy than the lighter rock.
As per the known fact, kinetic energy is the product mass, square of velocity and 0.5. Thus, it is due to the motion of object. Potential energy is the product mass, acceleration due to gravity and height. It is due to the height of object.
Also, momentum is another factor that will influence the results in situation mentioned in question. Based on this, momentum is the product of mass and velocity of the object. Considering momentum and kinetic energy, the heavier rock will have more kinetic energy.
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An electroencephalograph is recording Joseph's brain activity, and the recording is currently dominated by delta waves. Unexpectedly, there is a lour crash in the sleep lab. It is likely
There will be no change in the EEG, and Joseph's sleep will not be interrupted.
Electroencephalograph analysis:Delta waves are the slowest of all brain wave frequencies, and are typically associated with deep and restorative sleep. Since Joseph is already in this state, it is unlikely that the loud noise from the sleep lab will cause a change in his EEG or interrupt his sleep. The loud noise is more likely to cause a disturbance in lighter sleep stages, where the frequency of the brain wave is faster.
EEG recordings are also not typically affected by external noises, as the electrodes are measuring electrical activity within the brain and not sound waves. Therefore, the loud crash in the sleep lab is unlikely to cause a change in Joseph's EEG and his sleep will most likely remain uninterrupted.
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Chill the water as much as possible- then add heat and observe. List below at least three things you noticed (Make sure the energy symbols box is checked.) 1.When the water is being chilled the heat flows from the water to the ice. 2. When the water is being heated the heat flows from the fire to the water 3. When the water reaches a certain temperature heat energy begins to escape in the form of ga
1) Before the boiling point, the temperature of the water increases and it begins to boil. Boiling is the physical process by which a liquid changes to a gaseous state. It runs when the temperature of the entire liquid is equal to the boiling point of the liquid at that pressure. As the liquid continues to heat up, it absorbs heat, but without raising the temperature, it uses the heat to transform the substance from the liquid to the gaseous state, shifting the entire mass into the gaseous state. The heat that is generated in heating most of the liquid is called sensible heat, and the heat that appears during a change of state is called latent heat of boiling or vaporization.
2) Because iron is "closer" to its molecules, it can absorb more energy and, as a result, heat up faster. Instead, bricks have tiny air holes. That is, its molecules are "far away" and are not easily heated. As they conduct heat (conduction or convection), they lose energy.
3) When a piece of heated iron is placed in room temperature water, the iron gives off heat to the water (cooling) and the water receives heat (heating). Because the iron gives heat.
4) When you put a brick on top of an iron and heat it up, the iron heats up faster and starts heating the brick by conduction (because the material sticks together). In addition, the heat absorption capacity of the brick itself makes it warmer.
What is heat energy?
The term "thermal energy" is used loosely in various contexts of physics and engineering. We can refer to some well-defined physical concepts. These include the internal energy or enthalpy of matter and radiation. Heat (and thermodynamic work) defined as the mode of energy transfer. and the characteristic energies of the degrees of freedom of the system described by its microscopic particle content (where T denotes the temperature and Boltzmann constant).
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A geostationary satellite for communications seems to be in a fixed spot above the equator because it has the same angular velocity as the earth.
a, show that if it goes round once a day its angular velocity is a little over 7 * 10*-5 rad/s.
The angular velocity of a geostationary satellite is 7 × 10⁻⁵rad/s.
What are geostationary satellite?A geostationary satellite is an earth-orbiting satellite that travels in the same direction as the earth's rotation and is positioned at a height of around 36000 kilometers.
One orbit takes place at this altitude in 24 hours, which is how long it takes the earth to complete one rotation of its axis.
Time period of revolution = 24 hour = 24 × 60 × 60 second.
Hence, angular velocity of it = total circular angle/Time period
= 2π /( 24 × 60 × 60 ) rad/s
= 7 × 10⁻⁵rad/s.
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Examples of cell division: to grow larger, to repair injured tissue, reproduce through cell division.
Mitosis produces identical ____body____ cells.
Before a cell divides, it makes full copies of the DNA in its nucleus____this is called interphase_____.
Parent cell______original/old______: A cell that will divide or is dividing
Daughter cells_____copy/new_______: The 2 new cells that result from the division
Steps of the cell cycle:not equally divided in time
1.interphase
2.mitosis
3.cytokinesis
Answer:
try this
Explanation:
the cosmos just like humanity of earth its living like a mirror
WILL GIVE BRAINLY - 14 points
A quarterback throws a football at 35 m/s at a certain angle above the horizontal. If it took the ball 8.98 s to reach the top of its path, how long was it in the air?
rearest hundreth pls!!
PS
and explain if u can :,) not needed but will help u get the brainliest answer!!!!!!!!!!!!!!!!1111
Answer:
17.96 s
Explanation:
To find the total time the ball was in the air, we need to first find the time it took to reach the top of its path and then double that time to find the total time in the air.
The time it took to reach the top of its path is given by: t = v/g
Substituting in the known values and solving for t, we get: t = 35 m/s / 9.8 m/s^2 = 8.98 s
To find the total time the ball was in the air, we need to double the time it took to reach the top of its path, so the total time in the air is: 2 * 8.98 s = 17.96 s
Rounding to the nearest hundredth, the total time the ball was in the air is 17.96 s. Therefore, the answer is 17.96.
We cannot work without friction . why?
Answer:
thing will slide apart
Explanation:
Friction prevents objects from sliding apart. Everything would slide to the lowest point if there was no friction. It would be impossible to scale anything. We will be unable to write without friction.
A rectangular block of wood has dimensions 240mm×20.5cm×0.040m. calculate its volume in cm³.
Answer: 1968 cm3
Explanation: You first need to convert all of your dimensions to the same units.
240 mm = 24 cm
20.5 cm = 20.5 cm
0.04 m = 4 cm
Then volume is Length x width x height = 24 cm x 20.5 cm x 4 cm =
Three resistors R1 = 87.6 Ω, R2 = 22.0 Ω, R3 = 70.0 Ω, and two batteries e m f1 = 40.0 V, and e m f2 = 364 V are connected as shown in the diagram below.
A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.
What is Resistors?They are present in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance.
An ohm is the resistance that develops when a resistor has a one volt (V) drop across its terminals and a current of one ampere (A). The voltage across the terminal ends determines how much current flows.
There are numerous applications for resistors. Among some examples are voltage division, heat production, matching and loading circuits, gain control, and time constant setup. They have resistance ratings that span more than nine orders of magnitude and are marketed for use in various applications.
Therefore, A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.
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Derrick created a table of his observations from one trial of an investigation into whether a charged object will attract or repel an uncharged object. Which statement best explains an incorrect conclusion you might believe without repeated trials? object trial 1 negatively charged attract positively charged nothing (2 points) O negatively charged objects repel uncharged objects. O negatively charged objects are attracted to uncharged objects. O positively charged objects do not attract or repel an uncharged object. O positively and negatively charged objects react differently to uncharged objects
The correct option for the question is an option (c) positively charged objects do not attract or repel an uncharged object.
The analysis of stationary electrically charged particles is known as electrostatics. The charge attached to matter, which causes it to produce and feel magnetic and electric activity, is known as the electric charge.
Paper scraps are drawn to a plastic rod when brushed with fur, and a glass rod when rubbed with silk, demonstrating the electrical charge of both rods.
According to Coulomb's law, two particles with the same charge repel one another while those that have the opposite charge attract one another. Between two charged particles, there is a considerably stronger electric force in comparison to the gravitational force.
Hence, the positively charged objects do not attract or repel an uncharged object. The right answer is option C.
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the mean distance of an asteroid from the sun is 4.55 times that of earth from the sun. from kepler's law of periods, calculate the number of years required for the asteroid to make one revolution about the sun.
The number of years required for the asteroid to make one revolution about the sun will be 4.55 years
What is the meaning of Kepler's third law?
According to Kepler's Third Law, the planets' squared orbital periods and cubes of their semi-major axes are directly inversely related. According to Kepler's Third Law, a planet's period of orbiting the Sun grows exponentially with its orbital radius.
The sun is at the focus of elliptical planetary orbits, according to the first law. The radius vector from the sun to a planet sweeps equal regions in equal amounts of time, according to the second law.
According to Kepler's Third Law,
T^2 is directly proportional to r^3
(T1/T2)^2 = (r1/r2)^3
Time taken by earth to complete 1 revolution, T1 = 1 year
Time taken by asteroid to complete 1 revolution T2
distance of earth r1 = r
distance of asteroid r2 = 4.55r
So,
1/T2 = r/4.55r
T2 = 4.55 years
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A 6.0 kg bag of cat food is dropped from 5.0 m ledge. How much mechanical energy does
it have just before it strikes the ground?
Answer:
294
Explanation:
5x9.8x6=294
potential energy=5(9.8)(6)
Equation
PE=MGH
a load of 20kg is applied to the ends of wire 4m along and produce an extension of 0.24mm if the diameter of the wire is 2mm find the stress on the wire and strain producers
Answer:
Explanation: Force = mg as the wire is fixed at one point and the load is inserted at one end.
g=9.8m/s²
F= mg
F= 20×9.8= 19.6 newton
Strain= Δl/L
where Δl= change in length
and L= original length
Strain = 0.24×0.001 m/4m
Strain=0.00006
Stress= F/A
where A = cross sectional area
therefore A = π× (diametre/2)²
A=3.14×1²≈3.14 mm²= 0.000000314m²
Stress = 19.6/0.000000314=62420382 Pascal
An electron moving parallel to the x axis has an initial speed of 3.70 x 106 m/s at the origin. Its speed is reduced to 1.40 x 105 m/s at the point x=2.00cm, a) calculate the electric potential different between the origin and that point b) which point is at the higher potential.
a) Electric potential difference between origin and that point is - 38.9 V b) As the potential difference is negative , initial potential energy is greater than final potential energy. Hence, potential at origin will be higher.
What is electric potential difference?External work needed to bring a charge from one location to another location in an electric field is known as electric potential difference.
Given;
Initial speed of electron is 3.7 * 10^6 m/s
Final speed of electron is 1.4 * 10^5 m/s
Final position of electron Xf is 2cm
a) We know that when non conservative force acts on a system then mechanical energy is conserved;
ΔK + ΔU = 0
Kf- Ki + ΔU = 0
1/2 m Vf² + 1/2 m Vi² + q ΔV = 0 (As U= qV)
1/2m(Vf² - Vi²)= - q ΔV
ΔV = 1 *( 9.1*10^-31)/2*(-1.6*10^-19) [(1.4 * 10^5)²- (3.7 * 10^6)²]
ΔV = - 38.9 V
b) As the potential difference is negative , initial potential energy is greater than final potential energy. Hence, potential at origin will be higher.
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Air trapped inside a single-piston-cylinder exerts a pressure of 760 mmHg. If its volume is increased by 20% at a constant temperature, the pressure exerted would be equal to
he change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is 745 mmHg.
What is the change in the pressure of the air trapped in the cylinder?The change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is calculated from Boyle's law equation as follows:
The Boyle's law equation is given as follows:
P₁V₁ = P₂V₂
where;
P₁ is the initial pressure
V₁ is the initial volume
P₂ is the final pressure
V₂ is the final volume
From the data given,
P₁ = 760 mmHg
V₁ = V
P₂ = ?
V₂ = V + 0.2 V
V₂ = 1.02 V
P₂ = 760 * V / 1.02 V
P₂ = 745 mmHg
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Show that the displacement of a body moving with uniform acceleration a is given by
[tex]s = ut + 1 \div 2at {}^{2} [/tex]
where U is the is the velocity of the body at time (t)=0
Answer:
I only Know to derive so
Explanation:
We have from first equation,
V = u+at
From second equation
S=u+v/2×t
Now by placing the value of v from equation 1 into 2
or s =u+u+at/2×t
or,s= 2u+at/2×t
or,s=2ut/2+at^2/2
Therefore s=ut+1/2at^2
For the bar OC: mass=m, length=b, bar AB: mass=2m, length=2b ; for the slider A and B: mass=m. The angular velocity of OC is ω, (φ=60°?. Kinetic energy of the system T=?
The Kinetic energy of the system T = 6m * b² * ω² / 2
How do one calculate the Kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.
To find the kinetic energy of the system;
The kinetic energy of the bar OC is given by:
T_OC = 1/2 * m * b² * ω²
Note that:
m= Metre
b= Bar
ω = omega
The kinetic energy of the bar AB is given by:
T_AB = 1/2 * (2m) * (2b)² * ω²
The kinetic energy of the sliders A and B is given by:
T_A+B = 1/2 * m * v_A² + 1/2 * m * v_B²
where v_A and v_B are the velocities of sliders A and B, respectively.
To find the velocities of the sliders, we can use the relationship between the angular velocity of the bar OC and the linear velocities of the sliders:
v_A = b * ω * cos(φ)
v_B = b * ω * sin(φ)
Substituting these expressions into the equation for T_A+B, we get:
T_A+B = 1/2 * m * (b * ω * cos(φ))² + 1/2 * m * (b * ω * sin(φ))²
= 1/2 * m * b² * ω² * (cos^2(φ) + sin²(φ))
= 1/2 * m * b² * ω²
Since cos²(φ) + sin²(φ) = 1, the kinetic energy of the sliders is equal to the kinetic energy of the bar OC.
Finally, the total kinetic energy of the system is the sum of the kinetic energies of the three parts:
T = T_OC + T_AB + T_A+B
= 1/2 * m * b² * ω² + 1/2 * (2m) * (2b)^2 * ω² + 1/2 * m * b² * ω²
= (m+4m+m) * b² * ω²/ 2
= 6m * b² * ω² / 2
Therefore, the total kinetic energy of the system is given by:
T = 6m * b² * ω² / 2
Therefore, one should note that this result does not depend on the value of φ, so it is not necessary to know the value of φ in order to find the kinetic energy of the system.
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A 5.0 kg block with a speed of 3.0 m/s collides with a 10
kg block that has a speed of 2.0 m/s in the same direction.After the
collision, the 10 kg block travels in the original direction with a
speed of 2.5 m/s. (a) What is the velocity of the 5.0 kg block immediately after the collision? (b) By how much does the total kinetic
energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 10 kg block ends up with a
speed of 4.0 m/s. What then is the change in the total kinetic energy? (d) Account for the result you obtained in
(a) The first block moves at 4.0 m/s in the same direction right after colliding.
(b) the system's total kinetic energy changes by 28.75 J
(c) the system's total kinetic energy changes by -1.25 J
Given;
First block's mass, m1, is 5 kg.
u1 = 3.0 m/s is the first block's starting speed.
m2 weight of the second block is 10.0 kg.
u2 = 2.0 m/s is the second block's initial speed.
v2 = 2.5 m/s is the second block's final speed.
Immediately following the impact, the first block block's Part (A) velocity is as follows:
Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.
(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)
35= 2.5v₁ + 25
2.5v₁ = 35-25
2.5v₁ = 10
v₁ = 10/2.5
v₁ = 4
2.5 m/s in the same direction for v1.
Change in the system's overall kinetic energy, part (B):
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)
ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).
ΔK = 71.25 J - 42.5 J
ΔK = 28.75 J
Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s
Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)
35 = 2.5v₁ + 40
2.5v₁ = -5
2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)
K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).
ΔK = 41.25 - 42.5 J
ΔK = -1.25 J
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