a circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. a field of 1.2 t is directed along the positive z-direction, which is upward.

Answers

Answer 1

After solving the equation the the positive z-direction is 36.88 volts are the EMF is the correct answer.

Due to that,

Radius: 15 cm = 0.15 meters

The formula for the area of a circle can be used to calculate the area of the circular loop.

A = π r²

A = π × 0.15²

A = 0.0708 m²

B = 1.2T magnetic field in the positive z direction

B = 1.2 •k T.

If loop is deleted from the field during the specified time period

∆t = 2.3ms = 2.3×10^-3s

The stated average EMF is what we are looking for, and it is

ε = —∆Φ/∆t

There is no further flow.

Φf = 0

When the magnetic flux is expressed as

I = BACosΘ

where =0 since both the magnetic field and the area are pointing in the same direction.

I=BA Cos0

Φi = BA

Φi = 1.2 × 0.0708

Φi = 0.0848 Vs

Then, ε = —∆Φ/∆t

ε = —(Φf — Φi) / ∆t

ε = —(0-0.0848) / (2.3×10^-3)

ε = 0.0848 / (2.3×10^-3)

ε = 36.88 V

36.88 volts are the EMF.

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What are the "Fundamentals of Economics?

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Answer:

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Explanation:

Answer found from:

https://www.investopedia.com/terms/f/fundamentals.asp#:~:text=In%20business%20and%20economics%2C%20fundamentals,value%20on%20securities%20or%20businesses.

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Answers

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Explain how the fountain pen is filled up with ink​

Answers

Answer:

It is because of air pressure

Explanation:

Filling a fountain pen with ink involves various methods, but the most common approach uses a piston or converter mechanism.

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D is the correct answer

A ball with a weight of 70 N hangs from a string that is coiled around a 3 kg pulley with a radius of 0.4 m. Both the ball and the pulley are initially at rest. The rotational inertia of the pulley is 0.5mr2 and the ball is released from rest. Calculate the ball's velocity after it falls a distance of 2 meters.

Answers

Answer:

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Explanation:

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we substitute

          M g h = ½ M v² + ½ (½ m r²)  (v/r) ²

          ½ v² (M + [tex]\frac{1}{2}[/tex] m) = M g h

          v² = [tex]2gh \ \frac{M}{M + \frac{m}{2} }[/tex]

let's calculate

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Answer:

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Answers

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Answers

Answer:

m = 0.01 kg

Explanation:

Given that,

Momentum of the marble, p = 0.15 kg-m/s

Speed of the marble, v = 15 m/s

We need to find its mass. We know that,

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Where

m is the mass

[tex]m=\dfrac{p}{v}\\\\m=\dfrac{0.15}{15}\\\\m=0.01\ kg[/tex]

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Answers

Answer:

The answer is D.250N.

Explanation:

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