A circular tabletop has an approximate circumference of 47.1 inches. What is its diameter?

Answers

Answer 1

Answer: 14.99

Step-by-step explanation:C=2πr

d=2r

Solving ford

d=C

π=47.1

π≈14.9924


Related Questions

12.
Find the value of x. If necessary, round to the nearest tenth.


A. 7.0 in.

B. 9.9 in.

C. 14.0 in.

D. 11.9 in.

Answers

Answer:

9.9 inches

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh  where b is the length of the base and h is the length of the height

49 = 1/2 x*x

Multiply each side by 2

2*49 = x^2

98 = x^2

Take the square root of each side

sqrt(98) = sqrt(x^2)

9.899494937 =x

Rounding to the nearest tenth

9.9 =x

find any 4 rational number between -1/2 and -1/3

Answers

Given:

The two numbers are [tex]-\dfrac{1}{2}[/tex] and [tex]-\dfrac{1}{3}[/tex].

To find:

The 4 rational numbers between the given numbers.

Solution:

We have,

[tex]-\dfrac{1}{2}[/tex] and [tex]-\dfrac{1}{3}[/tex]

First we need to make common denominators. So multiply and divide the first fraction by 3 and second fraction by 2.

[tex]-\dfrac{1\times 3}{2\times 3}=-\dfrac{3}{6}[/tex]

[tex]-\dfrac{1\times 2}{3\times 2}=-\dfrac{2}{6}[/tex]

We need to find 4 rational numbers between the given numbers. So, multiply and divide both fractions by five, (4+1=5).

[tex]-\dfrac{3\times 5}{6\times 5}=-\dfrac{15}{30}[/tex]

[tex]-\dfrac{2\times 5}{6\times 5}=-\dfrac{10}{30}[/tex]

Now, the four numbers between -15 to -10 are -14, -13, -12, -11.

[tex]-15<-14<-13<-12<-11<-10[/tex]

[tex]-\dfrac{15}{30}<-\dfrac{14}{30}<-\dfrac{13}{30}<-\dfrac{12}{30}<-\dfrac{11}{30}<-\dfrac{10}{30}[/tex]

[tex]-\dfrac{1}{2}<-\dfrac{14}{30}<-\dfrac{13}{30}<-\dfrac{12}{30}<-\dfrac{11}{30}<-\dfrac{1}{3}[/tex]

Therefore, the 4 rational number between the given numbers are [tex]-\dfrac{14}{30},\ -\dfrac{13}{30},\ -\dfrac{12}{30}\ -\dfrac{11}{30}[/tex].

Please help me-
The graphs below have the same shape. What is the equation of the blue
graph?

Answers

Answer:

[tex]\text{C. }g(x)=(x-5)^2[/tex]

Step-by-step explanation:

The function [tex]y=(x-c)^2[/tex] has a phase shift of [tex]c[/tex] to the parent function [tex]y=x^2[/tex]. Since [tex]g(x)[/tex] has moved to the right 5 units from the parent function [tex]f(x)=x^2[/tex], we're looking for a value of [tex]c=5[/tex].

Therefore, we have:

[tex]g(x)=\boxed{(x-5)^2}[/tex]

An account pays 9% per year simple interest. In year 1, the amount in the
account is $750. How much is in the account in year 6?

Answers

Answer:

$405

Step-by-step explanation:

SI=PTR/100

=9*1*750/100

=$ 67.50

In 6 yrs= 67.50*6

=$405

Answer:

The answer is $1087.50

I got it wrong because someoneeeeeee didnt give the right answer (2 people to be exact)

someone please help me ASAP!

Answers

it would be (-5,-1) yw

Answer:

(-7,-1)

Step-by-step explanation:

bcoz coordinates of a is (-6,-2) and x=-6 we use the x-1 to find the new x which is

-6-1=-7

and to find y you should use y-3 and replace y with 2 which will be

2-3=-1

and y =-1

so the new coordinates are -7 for x-axis and -1for y-axis

help me please please

Answers

Answer:

A

Step-by-step explanation:

For a number to be written in scientific notation, you need to have it in the form:

a x 10^n

Where a is between 1 and 10(not including 10), and n is an integer. We can notice that in option A, 0.1(a) is not between one and ten, so it is not in scientific notation.

I really need this help

Answers

Answer:

area: 454.2 sq.cm

perimeter: 77.7 cm

Step-by-step explanation:

to find area, find the area of all the separate shapes and add them together:

semi-circle:

radius is 12 cm

area = [tex]\frac{\pi (12)^2\\}{2}[/tex] = 226.2 sq.cm

separate the trapezoid into two right triangles and a rectangle.

area for triangles:

[tex]\frac{1}{2}[/tex](5)(12) = 30

30 x 2 = 60 sq.cm (since there are two triangles)

area for rectangle:

12 x 14 = 168 sq.cm

area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm

for perimeter, just add the length of the exterior sides together.

we have some unknown sides, such as the semicircle and the sides of the trapezoid

we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem

[tex]5^2 + 12^2 = c^2[/tex]

[tex]25 + 144 = c^2[/tex]

[tex]169 = c^2[/tex]

[tex]\sqrt{169} =\sqrt{c^2}[/tex]

c = 13 cm

to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half

[tex]\frac{2\pi12}{2}[/tex] = 37.7 cm

now add it all up:

14 + 13 + 13 +37.7 = 77.7

What is the nth term rule of the linear sequence -5,-7,-9,-11,-13

Answers

Answer:

-7

Step-by-step explanation:

cause I took the test and got it right in my first try

Your rule for the sequence is -2n-3. Substitute any value for n and you will get the input. Hopefully this helps

pls tell plssssssssssssssssssssssssssss
:(

Answers

Answer:

x = 6 and y = 0

Step-by-step explanation:

x + 2y = 6

x = 6 - 2y                          equation(i)

substitute the value of x

x + 2y = 6

6 - 2y - 2y = 6

-4y = 6 - 6

y = 0/-4

y = 0

substitute the value of x in equation (i)

x = 6 - 2y

x = 6 - 2*0

x = 6-0

x = 6

What is the answer for this question?

Answers

Answer:

a/e

~~~~~~~~~~

[tex]\frac{(18) ab (20)cd}{ (15) bc (24) de}[/tex]

[tex]\frac{(3) ab (4)cd}{ (3) bc (4) de}\\[/tex]

[tex]\frac{ ab cd}{ bc de}\\[/tex]

[tex]\frac{ a }{ e}\\[/tex]

Step-by-step explanation:

Kaj and some friends are going to the movies. At the theater, they sell a bag of
popcorn for $4.75 and a drink for $3.75. How much would it cost if they bought 6
bags of popcorn and 3 drinks? How much would it cost if they bought p bags of
popcorn and d drinks?
Total cost, 6 bags of popcorn and 3 drinks:
Total cost, p bags of popcorn and d drinks:

Answers

Answer:

Total cost of 6 bags of popcorn and 3 drinks: [tex]\$39.75[/tex]

Total cost of [tex]p[/tex] bags of popcorn and [tex]d[/tex] drinks: [tex]4.75p+3.75d[/tex]

Step-by-step explanation:

Information given:

One bag of popcorn is $4.75One drink is $3.75

Therefore, the total cost of 6 bags of popcorn and 3 drinks must be [tex]6\cdot 4.75+3\cdot 3.75=\boxed{\$39.75}[/tex]

The cost of [tex]p[/tex] bags of popcorn and [tex]d[/tex] drinks is then [tex]\boxed{4.75p+3.75d}[/tex]

HELP WITH THIS SOMEONE!!!

Answers

Answer:

to blury

Step-by-step explanation:

prove that 9^3/2 -3 *5^0 -(1/81)^-1/2 = 15


Pls help, correct answer, I’ll mark as brainliest

Answers

Answer:

[tex]9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}=15[/tex]

Step-by-step explanation:

The given expression is :

[tex]9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}=15[/tex]

We need to prove that LHS is equal to RHS.

Taking LHS,

[tex]=9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}[/tex]

[tex]=(3)^{2\times\dfrac{3}{2}}-3-(\dfrac{1}{9})^{2\times \dfrac{-1}{2}}\\\\=27-3-9\\\\=15\\\\=RHS[/tex]

Hence, LHS = RHS.

Find the volume and surface area of the cone (to the nearest tenth)

Answers

Answer:

Surface area of cone = 286.55 cm² (Approx.)

Volume of cone = 263.89 cm³ (Approx.)

Step-by-step explanation:

Given:

Height of cone = 7 cm

Diameter of cone = 12 cm

Find:

Surface area of cone

Volume of cone

Computation:

Radius of cone = 12 / 2 = 6 cm

Surface area of cone = πr(l +r)

Surface area of cone = (3.14)(6)[(√7² + 6²) + 6]

Surface area of cone = 18.84[15.21]

Surface area of cone = 286.55 cm² (Approx.)

Volume of cone = (1/3)(π)(r²)(h)

Volume of cone = (1/3)(3.14)(6²)(7)

Volume of cone = (1/3)(3.14)(36)(7)

Volume of cone = 263.89 cm³ (Approx.)

can someone please help

Answers

Answer:

I think its Your Values, but try and a get a second opinion

A 15 foot ladder leans against a building and reaches a window 12 feet above the ground. What is the measure of the angle, to the nearest degree, that the ladder forms with the ground?

Answers

Answer:

paki sagot naman po para my isagot ako sa module ko

Answer:

it should be 37°

Step-by-step explanation:

cos=adj/hypo

cis-1(12/15)

=36.8

=37

help me find this answer​

Answers

Answer:

37.6 cm

Step-by-step explanation:

5.6m = 560cm

3.8m = 380cm

560/50 = 11.2 cm

380/50 = 7.6 cm

11.2 + 11.2 + 7.6 + 7.6 = 37.6 cm

area of a triangle: sine formula just please help i’m stuck and i don’t know what to do this was due yesterday

Answers

Answer:

269.0

Step-by-step explanation:

Trigonmetric area formula: 0.5 * a* b* sin(C)

a = 46

b=19

c = 38 degrees

0.5 * 46 * 19 * sin(38)

Pulg it into a calculator and you get 269.0441

Then round to the nearest tenth to get 269.0

Blue
A bowl contains:
• 3 red erasers
• 4 blue erasers
.6 green erasers
• 7 pink erasers
An eraser will be drawn from
the bowl and replaced 50 times.
What is a reasonable prediction
for the number of times a green
eraser will be drawn?

Answers

Answer:

i think it will be chose 3 times

Step-by-step explanation:

im not sure thats my pridiction

Answer:

0.4

Step-by-step explanation:

what is 3x² - 6x over x-2 simplified?

Answers

Answer:

3x

Step-by-step explanation:

3x^2 - 6x / x - 2

3x(x - 2) / x-2

cancels out

3x


3x^2-6x/x-2
3x(x-2)/x-2

=3x

Complete the equation for the relationship between the weight and number of months

Answers

Y=5.5x because I know

Each unit in the coordinate plane corresponds to 1 mile. Find the distance from the school to Cherry Street. Round your answer to the nearest tenth.

Answers

Answer:

[tex]11.2[/tex]

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] is equal to [tex]\sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex].

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is [tex]\sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}[/tex]

Write an algebraic expression for the phrase. 4 times the sum of q and p

Answers

4(q+p)
4 times the sum of q and p

which set of values could be the side lengths of a 30-60-90 triangle

Answers

Answer:

D. 6, 6[tex]\sqrt{3}[/tex], 12

Step-by-step explanation:

the Pythagorean Theorem states that [tex]a^{2} +b^{2} =c^{2}[/tex]

so,

[tex]6^{2} =36\\(6\sqrt{3}) ^{2} =108\\12^{2} =144\\36+108=144[/tex]

PLEASE HELP ME PLEASSEEE!!

Answers

Answer:

Step-by-step explanation:

The balloon was released at 10 yards, and it landed at 16 yards. The maximum  height the balloon reached was 27 yards. To find how high the balloon is per yard we do 27 ÷ 3 = 9

so on the table we do:

x-axis      y-axis

10        |     0

11         |     9

12        |     18

13        |     27

14        |     18

15        |     9

16        |     0

BNATT73ZGEZZU63F
free reedem code​

Answers

Thanks! But what is it for??

Answer:

Thanks I got my free thing from this code that points out where to redeem it

Step-by-step explanation:

Please help what’s the answer ??

Answers

Answer:

x = 8

In all the boxes, you will first subtract 8 with 2, which will be 6. Then you will add them.

6 + 6 + 6 = 18

7th grade girl!

*(urgent, please help! )*

Answers

For all the angles, you will have to solve for x

A: 162 = 3x

162/3 = x

54 = x

M: 120 + 2x = 180

2x = 180 - 120

2x = 60

x = 60/2

x = 30

W: 150 = 30x

150/30 = x

5 = x

S: 20 + 2x = 90

2x = 90 - 20

x = 70/2

x = 35

Q : 45 + 5x = 90

5x = 90 - 45

x = 45/5

x = 9

P: not too sure if its 150,

150 + (x+5) = 180

x+5 = 180- 150

x = 30 - 5

x = 25

now you will put all the x values in order. ( i think thats what you supposed to do)

it will be: 5, 9, 25, 30, 35, 54

hope this helps♡♡♡

On the distant planet Cowabunga, the weights of cows have a normal distribution with a mean of 483 pounds and a standard deviation of 70 pounds. The cow transport truck holds 5 cows and can hold a maximum weight of 2840. If 5 cows are randomly selected from the very large herd to go on the truck, what is the probability their total weight will be over the maximum allowed of 2840

Answers

Answer: 0.0033

Step-by-step explanation:

Let x be a random variable that denotes the weights of cows.

Given: [tex]\mu = 483,\ \sigma=70[/tex]

maximum weight can be hold= 2840 pounds.

Mean weight = [tex]\frac{2840}{5}[/tex] = 568 pounds

The probability their total weight will be over the maximum allowed of 2840

= [tex]P(X>2840)[/tex]

[tex]P(\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{568-483}{\dfrac{70}{\sqrt{5}}})\\\\=P(z>2.715)\\\\=1-P(z<2.715)\\\\=1-0.9967=0.0033[/tex]

Hence, the required probability = 0.0033

Solve the inequality.
3x + 6 <21

Answers

Answer:

3x + 6 < 21

subtract 6 on both sides

3x < 15

reduce by dividing with 3

x < 5

remember to handle inequalities just like equations

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