A cough syrup contains red dye #40, with a concentration of 4.68 x 10-3 M.a.If you dilute the cough syrup by adding 175 mL of water to a 250. mL sample of the cough syrup, what will be the final concentration?

How do I do this?

Answers

Answer 1

Answer:

[tex]M_2=2.75x10^{-3}M[/tex]

Explanation:

Hello.

In this case, since a dilution process is a process by which the concentration of a solution decreases due to the increase of volume by usually adding water, it is important to take into account that the moles remain unchanged:

[tex]n_1=n_2[/tex]

Whereas in terms of molarity (M=n/V) can be written as:

[tex]M_1V_1=M_2V_2[/tex]

In such a way, since the initial concentration is 4.68e-3 M and the volume of such solution is 250. mL, the final volume results from mixing 250 mL of this solution with 175 mL, that is, to a volume of 425 mL. Thus, the concentration turns out:

[tex]M_2=\frac{M_1V_1}{V_2} =\frac{4.68x10^{-3}M*250.mL}{425.mL} \\\\M_2=2.75x10^{-3}M[/tex]

Best regards.

Answer 2

If you dilute the cough syrup by adding 175 mL of water to a 250 mL sample of the cough syrup, the final concentration would be 0.00275 M

Using a simple dilution equation:

number of moles before dilution = number of moles after dilution

Recall that: number of moles = molarity x volume (MV)

Thus:

  M1V1 = M2V2

In this case, M1 = 4.68 x 10-3 M, M2 = ? V1 = 250 mL, and V2 = 425 mL

M2 = 4.68 x 10^-3 x 250/425

                  = 0.00275 M

                    = 0.00275 M

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Answers

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Answer:

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Question answered

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Answers

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Took the test and got it correct. :)

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apex

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Lithium actually requires more than sodium.

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Answers

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Zinc is an important trace element for human beings. Zinc is used for making brass, an alloy of copper and zinc.Zinc is used as the anode  in dry cells.

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