A crowd of people stood on both sides of the street to view a 4th of July Parade.
The length of the parade was 3 miles long and 15 feet deep on each side of the street.
If 5 people can fit into a 25 ft^2 area.
Estimate the size of the crowd.
(1mile = 5280ft)

Answers

Answer 1

Given :

Length of parade , [tex]L = 3\ miles=3\times 5280\ miles = 15840\ miles[/tex] .

Breadth of parade , [tex]B=2\times 15=30\ ft[/tex] .

5 people can fit into a [tex]25\ ft^2[/tex] area.

1 mile = 5280 ft .

To Find :

The size of the crowd.

Solution :

Area of parade ,

[tex]A=15840\times 30\ ft^2\\\\A=475200\ ft^2[/tex]

Also , 5 people can fit in [tex]25\ ft^2[/tex] area .

So , number of people fit in A is :

[tex]n = \dfrac{475200\times 5}{25}\\\\n=95040[/tex]

Therefore , 95040 can fit in the parade .

Hence , this the required solution .


Related Questions

Find the lengths of the sides of the triangle PQR. P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) a. |PQ| = b. |QR| = c. |RP| =

Answers

Given :

Three points ,  P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

[tex]L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}[/tex]

Length of PQ :

[tex]PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3[/tex]

Length of QR :

[tex]QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5}[/tex] :

Length of RP :

[tex]RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6[/tex]

Hence , this is the required solution .

F(x) = 3x - 7 and g(x) = -2x - 6. Find (f o g)(4)

Answers

Answer:

(f o g)(4) = - 49

Step-by-step explanation:

F(x) = 3x - 7

g(x) = -2x - 6

To find (f o g)(4) we must first find (f o g)(x)

To find (f o g)(x) substitute g(x) into f(x) that's for every x in f (x) replace it with

g (x).

We have

(f o g)(x) = 3( - 2x - 6) - 7

= - 6x - 18 - 7

We have

(f o g)(x) = - 6x - 25

To find (f o g)(4), substitute the value of x that's 4 into (f o g)(x)

We have

(f o g)(4) = - 6(4) - 25

= - 24 - 25

We have the final answer as

(f o g)(4) = - 49

Hope this helps you

How to simplify this problem: (4c^4)^3

Answers

Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

64c^12

Chang Industries has bonds outstanding with a par value of $210,400 and a carrying value of $218,600. If the company calls these bonds at a price of $214,000, the gain or loss on retirement is:

Answers

Answer:

The loss is $4600.

Step-by-step explanation:

The par value of the bonds = $210400

The carrying value of the bonds or the actual value of bonds = $218600

The company calls the bonds at the price = $214000

Now have to find the gain or loss from the given information. Thus, below is the calculation to find the gain or loss.  

Loss or gain on retirement = $214,000 - $218,600 = -$4,600

Thus the loss on retirement is $4600.

4a-2b+40 when a=2 and b=7

Answers

Answer:

34

Step-by-step explanation:

4(2)-2(7)+40

8-14+40

-6+40=34

4a-2b+40

4x2-2x7+40

8-14+40

-6+40

34 is the answer.

10 The table below shows the results of a swimming race.
Time (sec)
Name
Paula
47.983
Marci
50
Kelli
47.972
Susan
47.21
Carla
46
10
Brenda
46.97
Which of the following gives the first four finishers in order from 1st to 4th place
F Brenda, Carla, Marci, Paula
G Carla, Brenda, Marci, Susan
H Carla, Marci, Brenda, Susan
J Susan Marci Brenda. Carla

Answers

Answer:

G. Carla, Brenda, Marci, Susan

Step-by-step explanation:

The time given for all participants are in decimals except for that of Marci and Carla which are given in the form of mixed fractions.

Convert the mixed fractions into decimals, then compare the figures together to do the ranking.

Marci = [tex] 46\frac{49}{50} = \frac{2,349}{50} = 46.98 [/tex]

Carla = [tex] 46\frac{9}{10} = \frac{469}{10} = 46.9 [/tex]

The first four finishers from the 1st to the 4th are:

1. Carla - 46.9

2. Brenda - 46.97

3. Marci - 46.98

4. Susan - 47.21

Simplify. 863x14y9−−−−−−√ Assume x and y are nonnegative.

Answers

Answer:

24x^7 y^4 √7y

Step-by-step explanation:

The value of expression would be 24x⁷y⁴√7y  which is determined by simplification of the given expression  8 √63x¹⁴y⁹.

What is the algebraic expression?

Algebraic expressions are mathematical statements with a minimum of two terms containing variables or numbers.

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

We have been the given expression as :

8 √63x¹⁴y⁹

We can simplify as:

⇒ 8 √63x¹⁴y⁹

The square root of a number is a number that can be multiplied by itself and gives the actual number.

⇒ 8 √[3×3×7( x⁷)²x (y⁴)² y]

Assume x and y are nonnegative.

⇒ 24x⁷y⁴√7y

Hence, the value of expression would be 24x⁷y⁴√7y.

Learn more about the algebraic expression here :

brainly.com/question/21751419

#SPJ2

Katie has a collection of nickels dimes and quarters with a total value of $4.60. there are 6 more dimes than nickels and 8 more quarters than nickels. How many of each coins does she have?

Answers

Answer:

920

Step-by-step explanation:

$4.60×6-8

$4.60×2dimes

=920

For which values of the parameter B the following system admits a unique solution [ 1 b 1-b 2 2 0 2–2B 4 0] [x y z] = [1 2 0]

Answers

Answer: β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det [tex]\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right][/tex] ≠ 0

Determinant of a 3x3 matrix is calculated by:

det [tex]\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right][/tex]

[tex]8(1-\beta)-[2(2-2\beta)(1-\beta)][/tex]

[tex]8-8\beta-4+8\beta-4\beta^{2}[/tex]

[tex]-4\beta^{2}+4\neq 0[/tex]

[tex]\beta^{2}\neq 1[/tex]

[tex]\beta \neq \sqrt{1}[/tex]

β ≠ ±1

For the system to have only one solution, β ≠ 1 or β ≠ -1.

ABSOLUTE VALUE! What is the absolute value of -7?

Answers

Answer:

7

Step-by-step explanation:

For any real number x, if x > 0 then |x| = x and if x < 0 then |x| = -x. In this case, x < 0 so |-7| = -(-7) = 7.

Answer:

answer is 7

Step-by-step explanation:

if its a negative, its always the positive of that number....if that makes sense

Find the least common multiple of 15, 2, and 10.

Answers

Answer:

LCM = 30

Step-by-step explanation:

15 = 3×5

2 = 2¹

10 = 2×5

LCM = 2×3×5 = 30

Help me with this please i don't understand

Answers

Answer:

84 cm²

Step-by-step explanation:

Surface are of the net = sum of the area of each section

Area of the 2 right triangles:

base (b) = 4cm, height (h) = 3 cm

Area = 2(½*b*h) = 2(½*4*3) = 4*3 = 12 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 4 cm

Area = L*W = 6*4 = 24 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 5 cm

Area = L*W = 6*5 = 30 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 3 cm

Area = L*W = 6*3 = 18 cm²

Surface area of the net = 12 + 24 + 30 + 18 = 84 cm²

evaluate h^2-3h+2 for h= -3

Answers

Answer:

2

Step-by-step explanation:

1. Start by substituting 3 for every h, so it looks like 3^2-3(3)+2

2. Do the exponent first 9-3(3)+2

3. Multiply 3(3) to get 9-9+2

4. Subtract 9-9, 0+2

5. Add 0 and 2 to get 2

Jerome is an accounts payable clerk that when printing check used 1/4 of a box of check stock. How many checks did Jerome use for if 1000 checks are able to printed out of each box?

Answers

He used 250 checks.

find the average of 2m,20cm and 95cm give your answer in cm​

Answers

Answer:

The average is:

105 cm

Step-by-step explanation:

1 m = 100cm

2m = 2*100 = 200cm

then:

(200 + 20 + 95)/3 = 315/3 = 105cm

What is the solution to the equation 1/4x+2= -5/8x-5?

Answers

Answer:

x=( -8)

Step-by-step explanation:

hope it helps.^-^

Sanna has 38 homework problems to finish she finishes the 14 problems in 25 minutes. How long will it take her to finish the rest of the assignment, if she continues at the same pace?

Answers

Answer:

45

Step-by-step explanation:

Kyle wants to buy a new laptop that has an original price of $540. The store is having a sale, so the laptop is 10 percent off, which amounts to a discount of $54. If sales tax is 8 percent on the final price of the laptop, how much tax will he need to pay?

Answers

Answer:

A. 38.88

Step-by-step explanation:

$540-54 is 486

486(0.08) or 486(8%) is 38.88

Answer:

$38.88

I took the test, trust me

Find the absolute value and solve the problem
|-23| + |-15|

Answers

Answer:

38

Step-by-step explanation:

|-23| + |-15|

First find the absolute values, which are the non negative values

23 +15

Then add

38

The answer is

23+15=38

Solve the formula h=54t+12at2 h = 54 t + 1 2 a t 2 for a.

Answers

Hope this helps!!!!!

The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).
2sin2x+sinx=1

Answers

Answer:

[tex]\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}[/tex]

Step-by-step explanation:

Given the quadratic equation as:

[tex]2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0[/tex]

Let us put [tex]sinx=y[/tex] for simplicity of the equation:

Now, the equation becomes:

[tex]2y^2+y-1=0[/tex]

Now, let us try to solve the quadratic equation:

[tex]\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1[/tex]

So, the solution to the given trigonometric quadratic equation is:

[tex]sinx = \dfrac{1}{2}[/tex]

and

[tex]sinx=-1[/tex]

Let us try to find the values of [tex]x[/tex] in the interval [tex][0, 2\pi)[/tex].

[tex]sin\theta[/tex] can have a value equal to [tex]\frac{1}{2}[/tex] in 1st and 2nd quadrant.

So, [tex]x[/tex] can be

[tex]30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}[/tex]

For [tex]sinx=-1[/tex],

[tex]x = 270^\circ\ or\ \dfrac{3 \pi}{2}[/tex]

So, the answer is:

[tex]\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}[/tex]

Which fraction has a repeating decimal as its decimal expantion

Answers

are there supposed to be answers on am i just stupid

Find the derivative F(x)=(5x+3)(2x^2+1)

Answers

Answer:

10x^3 + 6x^2 + 5x + 3

Step-by-step explanation:

F(x)=(5x+3)(2x^2+1)

= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1

= 10x^3 + 5x + 6x^2 + 3

= 10x^3 + 6x^2 + 5x + 3

What is the length of an arc given that the measure of the central angle is 30 degree and the radius is 7 cm?

Answers

La longitud del arco (s) en una circunferencia, conociendo el radio (r) y el ángulo (θ) que forman los dos radios, es:

s = r∙θ

Con el ángulo en radianes

F V7 w7 :

The angle of elevation of a ladder leaning against a wall is 60 degrees and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is ___ m.

Answers

Answer:

8

Step-by-step explanation:

3u+5u=64
What is the simplify of this
What does u

Answers

Answer:

u = 8

Step-by-step explanation:

3u + 5u = 64

8u = 64

8u/8 = 64/8

u = 8

if an area can be washed at a rate of 4,900 cm2/ minute, how many square inches can be washed per hour?

Answers

Answer : 4.5 × 10⁴ square inches can be washed per hour.

Step-by-step explanation :

As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.

Given conversions are:

1 cm = 0.39 in    and    1 hr = 60 min

As, 1 cm² = (0.39)² in²    and    1 min = 1/60 hr

So, [tex]1cm^2/min=(0.39)^2\times 60in^2/hr[/tex]

[tex]1cm^2/min=9.126in^2/hr[/tex]

Now we have to determine the square inches can be washed per hour.

As, [tex]1cm^2/min=9.126in^2/hr[/tex]

So, [tex]4900cm^2/min=\frac{4900cm^2/min}{1cm^2/min}\times 9.126in^2/hr=44717.4in^2/hr=4.5\times 10^4in^2/hr[/tex]

Therefore, 4.5 × 10⁴ square inches can be washed per hour.

Which phrase best describes f(x), graphed on the coordinate plane below?

Answers

answer.next time out the graph

Step-by-step explanation:

Answer:

It's A, an odd function

||x−4|-2|<3 PLEASE ANSWER!!!

Answers

Answer:

-1<x<9

(I think you notated it wrong, it should be |x-4|-2<3)

Solve |f−6| = |f+8| Can someone please help me with this question? I'm stuck.

Answers

Answer:

no solution

Step-by-step explanation:

|f-6| = |f+8|

solve absolute values

f-6 = f+8

add 6 to 8

f = f+14

subtract f from f

0=14

not true; no solution

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