Answer:
[tex]\frac{1}{2}mR^2\omega^2[/tex]
Explanation:
The rotational kinetic energy of an object is given by [tex]KE_r=\frac{1}{2}I\omega^2[/tex], where [tex]I[/tex] is the object's moment of inertia/rotational inertia and [tex]\omega[/tex] is the object's angular speed.
What we're given:
The object's moment of inertia: [tex]I=MR^2[/tex] The object's radius, mass, and angular speed: [tex]R, m, \omega[/tex], respectivelySince no numerical value is given for any of these, it is implied the desired answer will be an equation in terms of the variables given.
Substituting [tex]I=MR^2[/tex]:
[tex]KE_r=\boxed{\frac{1}{2}mR^2\omega^2}[/tex]
The number of proton is equal to the number of _____ in an atom
Answer:
THE NUMBER OF PROTON IS EQUAL TO THE NUMBER OF ATOMIC NUMBER(Z) IN AN ATOM
Explanation:
PLZ MARK ME BRAINLIEST
Answer:
Explanation:
The number of proton is equal to the number of electron in an atom.
A 1.2 kg mass is suspended from the ceiling by a string. A second horizontal string holds the mass at rest next to the wall. The angle between the string and the ceiling is 65o. What is the tension force in the horizontal rope
Answer:
The tension in the horizontal string is 25.2 N.
Explanation:
mass, m = 1.2 kg
Angle, A = 65 degree
The tension in the string is T.
So, T cos A = m g
T x cos 65 = 1.2 x 9.8
T x 0.4226 = 11.76
T = 27.83 N
Tension in the horizontal string, T' = T sin A = 27.83 x sin 65 = 25.22 N
Answer:
Explanation:
See the figure attached . T₁ and T₂ are tension in the inclined and horizontal string .
The vertical component of T₁ will balance weight and horizontal component will balance the tension T₂.
T₁ sin 65 = mg and T₁ cos 65 = T₂
Dividing ,
Tan 65 = mg / T₂
T₂ = mg / tan 65
= 1.2 x 9.8 / 2.1445
= 5.5 N
Isotopes of the same element always have the same
(2 points)
O atomic mass number
O A-number
O Z-number
O neutrinos
Answer:
Z-number
Explanation:
The Z number is the number of protons in an atom, and this does not change when an isotope is created. I got it right on the test.
one of the lady spartans was falling to the ground after dunking the winning basket. At the end of her fall, she was falling 4 m/s. If she was 60kg, how much potential energy did she have at the top of her jump?
Answer:
15 is the correct answer I.t.
You push on a box with a force of 300 N directly north. Another person pushes the box with a
force of 600 N directly east. What is the resultant force?
Answer:
[tex]resultant \\ \: F = \sqrt{ {300}^{2} + {600}^{2} } \\ = \sqrt{450000} \\ = 670.82 \: newtons[/tex]
What is the essential concept of the photon theory of light?
Answer:
Cause it gives us internet
Two identical particles each of mass M and charge Q are placed a certain distance apart. If they are in equilibrium
under mutual gravitational and electric force then calculate the order of Q/M in SI units.
Answer:
Q / m = 8.61 10⁻¹¹ C / kg
Explanation:
For this exercise we use the gravitational force of attraction
[tex]F_g = G \frac{m_1m_2}{r^2}[/tex]
the electric force
[tex]F_e = k \frac{q1q2}{r^2}[/tex]
indicate that the two forces are equal
G m₁ m₂ / r² = k q₁ q₂ / r²
they also say that the two masses are equal and the two charges are equal
G m² = k Q²
Q / m = [tex]\sqrt{\frac{G}{k} }[/tex]
we calculate
Q / m = [tex]\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }[/tex]
Q / m = [tex]\sqrt{ 0.7419 \ 10 ^{-20}}[/tex]
Q / m = 0.861 10⁻¹⁰
Q / m = 8.61 10⁻¹¹ C / kg
. If the static and kinetic friction between the tire and the inclined plane are 0.2 (static) and 0.15 (kinetic), calculate the maximum inclination angle so that the tire rolls without slipping
Answer:
81.47°
Explanation:
The forward force on the tire is the horizontal component of its weight along the incline mgcosФ. The frictional force along the incline is μmgsinΦ where mgsinΦ is the vertical component of the tire's weight along the incline.
Since the tire rolls without slipping, then
mgcosФ = μmgsinΦ where μ = coefficient of kinetic friction = 0.15 (since the tire is in motion) and Φ is the angle of the incline.
So, mgcosФ = μmgsinΦ
mgcosФ/mgsinΦ = μ
μ = cosФ/sinΦ
μ = 1/tanФ
tanФ = 1/μ
Φ = tan⁻¹(1/μ)
substituting into the equation, we have
Φ = tan⁻¹(1/0.15)
Φ = tan⁻¹(6.667)
Φ = 81.47°
For a galvanic cell to generate an electric current flowing from anode to cathode, what must be true
Complete question:
For a galvanic cell to generate an electric current flowing from anode to cathode, what must be true?
(a) Electrons flow from the anode to the cathode
(b) Electrons flow from the more negatively charged electrode to the more positively charged electrode
(c) Electrons flow from higher potential energy to lower potential energy
(d) All of the above are true.
Answer:
(d) All of the above are true.
Explanation:
A galvanic or Voltaic cell is a primary type of electrochemical cell that is used to generate electrical energy from the chemical reactions that take place in it.
It consists of a positive electrode (cathode) and a negative electrode (anode) for the movement of charges.
(a) Electrons flow from the anode to the cathode. TRUE
Anode is the negative electrode and for electron current, electrons flow from negative electrode to positive electrode.
(b) Electrons flow from the more negatively charged electrode to the more positively charged electrode. TRUE
Based on electron current flow.
(c) Electrons flow from higher potential energy to lower potential energy. TRUE
The driving force of the electron flow is the potential difference. Electrons must flow from higher potential to lower potential.
All the options are correct, so we select option "D"
different between pressure and force
Force is mass into acceleration
and pressure is force applied per unit area.
The cliff divers at Acapulco, Mexico, jump off a cliff m above the ocean. Ignoring air resistance, how fast are the divers going when they hit the water
Answer:
22.87 m/s
Explanation:
Since the value of the height at which the divers jump off the cliff is not given,
Assuming that the height of the cliff above the ocean at which the divers jump = 26.7 m
Then;
The speed of the divers when they hit the ocean water can be determined by using the formula:
[tex]v^2 = 2gh \\ \\ v= \sqrt{2gh} \\ \\ v = \sqrt{2 \times 9.8 \times (26.7)} \\ \\ v \simeq 22.87 \ m /s[/tex]
An oscillating LC circuit consisting of a 1.0 nF capacitor and a 3.0 mH coil has a maximum voltage of 3.0 V. What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil
Answer:
[tex]E=4.5*10^-^9J[/tex]
Explanation:
From the question we are told that:
Capacitor [tex]C=1.0nf[/tex]
Induction [tex]I=3.0mH[/tex]
Voltage [tex]V=3.0[/tex]
Generally the equation for Max charge on Capacitor is mathematically given by
[tex]Q_{max}=C*V[/tex]
[tex]Q_{max}=1*10^{-9}*3[/tex]
[tex]Q_{max}=3*10^{-9}C[/tex]
Generally the equation for Energy in magnetic field of the coil is mathematically given by
Since
Energy stored in capacitor = Energy in magnetic field of the coil
Therefore
[tex]E = (1/2)* C * V^2[/tex]
[tex]E= 0.5 * 1*10^{-9} *3^2[/tex]
[tex]E=4.5*10^-^9J[/tex]
Instead of changing the the frequency you can change the tension to produce the next higher harmonic. What percentage of the tension would produce the next higher harmonic?
Answer:
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
Explanation:
This is a string resonance exercise, the wavelengths in a string held at the ends is
λ = 2L₀ / n
where n is an integer
the speed of the wave is
v = λ f
f = v /λ
the speed of the wave is given by the characteristics of the medium (string)
v = [tex]\sqrt{\frac{T}{\mu } }[/tex]
we substitute
f = [tex]\frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }[/tex]
to obtain the following harmonic we change n → n + 1
f’ = [tex]\frac{n+1}{2L_o} \ \sqrt{\frac{T_o}{\mu } }[/tex]
In this case, it tells us to change the tension to obtain the same frequency.
f ’= \frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }
how the two frequencies are equal
[tex]\frac{n+1}{2L_o} \sqrt{\frac{T_o}{ \mu } } = \frac{n}{2L_o} \sqrt{\frac{T}{\mu } }[/tex]
(n + 1) [tex]\sqrt{T_o}[/tex] = n [tex]\sqrt{T}[/tex]
[tex]\frac{T}{T_o} = ( \frac{n+1}{n} )^2[/tex]
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
this is the relationship of the voltages to obtain the following harmonic,
Explain how you would have to change the experimental set-up (electric field strength, drift chamber length, and/or buf
Answer:
Please find the complete question in the attached file.
Explanation:
In this statement, the weak electromagnetic field that has been used when with the range of resistance to start measuring the mobility of even an ion with both the counter-charge utilization as well as the DC is the potential for using so that we can always obtain a desired electrical field and modify the drift chamber lengthy and gas pressures buffered.
Question
1 point
An object of mass 8.0 kg is falling vertically through the air. The drag force acting on the object is 60N. What is the best estimate of the acceleration of
the object?
Answer:
here's the pdf for it
IB QuestionbankExplanation:
What is the path of an electron moving perpendicular to a uniform magnetic field?
Explanation:
this is your answer I hope it is helpful please mark me brainly
The solid metallic sphere is replaced with a hollow insulating shell of radius a. A charge Q is spread uniformly over the hollow spherical shell. What is the electric field strength inside the hollow shell at r
Answer:
Zero
Explanation:
It is given that the charge is uniformly spread at the surface of hollow spherical shells.
There is no charge with in the hollo shell. hence, with zero charge the electric field intensity is also zero.
Thus,
Magnitude of the electric field strength inside the hollow shell at r is zero
What is the wavelength of a wave with a frequency of 262 Hz and a speed of
343 m/s
Answer:
time perion=1/frequency
so here time period =1/262
let wavelength be x
speed of sound=wave length/time period
342=x/1/262
342=262x
342/262=x
1.30=x
therefore wavelength=1.30 metre
Explanation:
Help pleaseeeeee!!! I really need it today :)
Answer:
i'd say 1kg-----5m-----5kg but im not to sure
Explanation:
As you can see from the Group 1 stars, the cooler or hotter a star is, the brighter it will be. Group 2 and Group 3 stars do not follow this pattern. Hence, there must be something besides temperature that can affect how bright a star is. Describe your own hypothesis about these stars (Group 2 and Group 3). Why would their brightness not be strictly related to their temperature
Answer:
brightness that we observe from a star is related to the energy produced and the distance to the Earth
Explanation:
In stars, the color that we observe is directly related to the temperature of the star by the y of the Wien displacement.
λ_{max} T = 2,898 10³
the brightness that we observe from a star is related to the energy produced and the distance to the Earth
Last stage of a medium mass star
White Dwarf Stage
This ring is called a planetary nebula. when the last of the helium atoms in the core are fused into carbon atoms, the medium size star begins to die. Gravity causes the last of the star's matter to collapse inward and compact. This is the white dwarf stage.The accepted speed of sound at atmospheric pressure and 0 *C is 331.5 m/s. The speed of sound increases 0.607 m/s for every *C. Calculate the speed of sound at the temperature of your room and compare your measured value to the accepted value.
Complete Question
The accepted speed of sound at atmospheric pressure and 0 *C is 331.5 m/s. The speed of sound increases 0.607 m/s for every *C. Calculate the speed of sound at the temperature of your room(70F) and compare your measured value to the accepted value.
Answer:
[tex]V_{Tc}=344.314m/s[/tex]
Explanation:
From the question we are told that:
Speed of sound at Temperature [tex]0 \textdegree[/tex] [tex]V_0=331.5m/s[/tex]
Rate of Speed increase [tex]\triangle V_{infty}=0.607[/tex]
Generally the equation for Temperature in Celsius is mathematically given by
[tex]Tc=\frac{100}{180}(T_f-32)[/tex]
[tex]Tc=0.56*38[/tex]
[tex]Tc=21.11 textdegree C[/tex]
Therefore speed at Tc
[tex]V_{Tc}=V_0+(Tc)( V_{infty})[/tex]
[tex]V_{Tc}=331.5+(21.11)(0.607)[/tex]
[tex]V_{Tc}=344.314m/s[/tex]
Jack drops a stone from rest off of the top of a bridge that is 21.0 m above the ground. After the stone falls 7.0 m, Jill throws a second stone straight down. Both rocks hit the water at the exact same time. What was the initial velocity of Jill's rock
Answer:
v = 19 m/s
Explanation:
Since both rocks hit the water at the same time, and we know the total height of the bridge, we can get the time that it takes to the first rock to travel this height, due it is said that it was dropped, using the following kinematic equation:[tex]\Delta h = \frac{1}{2} * g * t^{2} (1)[/tex]
Replacing by the givens (Δh =21 m and g = 9.8 m/s2), and solving for t we get:[tex]t = \sqrt{\frac{2*21m}{9.8m/s2}} = 2.1 s (2)[/tex]
Now we need the time traveled by the first rock when it fell 7 m, that when the second rock was thrown, because the difference between the total time and this one will be the flight time for the second rock.We can use the same equation (1) replacing Δh by 7 m, and solving for t, in (2) as follows:[tex]t = \sqrt{\frac{2*7m}{9.8m/s2}} = 1.2 s (3)[/tex]
So, the total flight time for the second rock it was just the difference between (2) and (3):[tex]t_{2} = t_{tot} - t_{1} = 2.1 s - 1.2 s = 0.9 s (4)[/tex]
Since we know the total distance traveled, and the time of flight, we can use the same kinematic equation than in (1) but now taking into account the initial speed for the second rock, as follows:[tex]\Delta h = v_{o}* t_{2} + \frac{1}{2}* g*t_{2} ^{2} (5)[/tex] Since we know the value of Δh = 21 m and t₂ =0.9s, replacing in (5) and solving for v₀, we get:[tex]v_{o} =\frac{(\Delta h -\frac{1}{2}*g*t^{2})}{t_{2} } = \frac{(21m-(\frac{1}{2}*9.8m/s2*(0.9s)^{2}) ) }{(0.9m)} = 19.0 m/s (6)[/tex]
which was the initial velocity of Jill's rock taking as positive the down ward direction.After You Read
Mini Glossary
atomic number: the number of protons in an atom of
an element
mass number: the sum of the number of protons and
neutrons in an atom
average atomic mass: the average mass of the element's
isotopes, weighted according to the abundance of each isotope
nuclear decay: a process that occurs when an unstable atomic
nucleus changes into another more stable nucleus by
emitting radiation
ion: an atom that is no longer neutral because it has gained or
lost electrons
radioactive: spontaneously emits radiation
isotope: an atom of the same element that has a different
number of neutrons
1. Review the terms and their definitions in the Mini Glossary. Write a sentence that
explains how to determine the number of neutrons in an isotope that has 6 protons and
a mass number of 13.
Answer:
protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
Explanation:
mass number: the sum of the number of protons and
neutrons in an atom
this is key as it explains that protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
Which of the following is the best definition of a physical change?
A. A change in a substance where a new substance is formed
B. A change in a substance in which bonds are broken
C. A change in a substance with no new substances being formed
D. A change in a substance in which mass is conserved
Answer:
The answer is C. A change in a substance with no new substances being formed
Explanation:
I did the quiz.
The best definition of physical change is a change in a substance, with no new substances being formed. Hence, option C is correct.
What is a Physical Change?A chemical substance's form, not its chemical composition, can change due to physical changes. In most cases, compounds cannot be separated into chemical components or simpler compounds; instead, mixtures are separated into their constituent compounds through physical changes.
Whenever something changes physically but not chemically, we say that something has changed physically. This is in contrast to the idea of a chemical change, which occurs when a substance's composition changes or when one or more compounds join or fragment to generate new substances. In general, physical means can be employed to undo a physical alteration. For instance, by letting the water evaporate, salt that has been dissolved in it can be reclaimed.
Therefore, this concludes that option C is correct.
To know more about Physical change:
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Which of the following terms describes a process that absorbs 672 J from
the surroundings?
O A. Thermal conduction
B. Thermal insulation
C. Exothermic
D. Endothermic
Answer:
Endothermic
Explanation:
Took the test :^)
The endothermic process that absorbs 672 J from the surroundings.
What is endothermic process?In thermochemistry, an endothermic process is any process with an increase in the enthalpy H (or internal energy U) of the system.[1] In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system. It may be a chemical process, such as dissolving ammonium nitrate (NH4NO3) in water (H2O), or a physical process, such as the melting of ice cubes.
The term was coined by Marcellin Berthelot from the Greek roots endo-, derived from the word "endon" meaning "within", and the root "therm" , meaning "hot" or "warm" in the sense that a process depends on absorbing heat if it is to proceed. The opposite of an endothermic process is an exothermic process, one that releases or "gives out" energy, usually in the form of heat and sometimes as electrical energy. Thus in each term (endothermic and exothermic) the prefix refers to where heat (or electrical energy) goes as the process occurs.
So Endothermic reaction is where heat energy is high inside the substance and reduces the thermal energy outside the substance (outside the substance the temperature drops and the temperature increases inside the substance.)
Learn more about endothermic process
https://brainly.com/question/20569774
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What is the speed of a car that traveled total of 75 km in 2 hours? *
Answer:
speed=distance covered/time taken
=75/2
=37.5 km/hr
Explanation:
average speed = distance move/ time taken
= 75km/2h
= 37.5km/h
Sally travels by car from one city to another. She drives for 30 min at 80 km/hr, 12.0 min at 105 km/hr, and 45 min at 40.0 km/hr. What was the total distance traveled?
Given :
Sally travels by car from one city to another. She drives for 30 min at 80 km/hr, 12.0 min at 105 km/hr, and 45 min at 40.0 km/hr.
To Find :
The total distance traveled.
Solution :
Total distance traveled is given as sum :
Distance = sum of product of speed and time
D = (v₁ × t₁) + (v₂ × t₂) + (v₃ × t₃)
Putting all given value in this we get :
[tex]D = 80\times \dfrac{30}{60} + 105 \times \dfrac{12}{60} + 40\times \dfrac{45}{60}\\\\D = 91\ km[/tex]
Hence, this is the required solution.
Calculate the heat energy required to convert 4kg of ice at -25℃, to stem, at 100℃, given the specific heat capacity of water is 4200J/(kg℃), , the specific heat capacity of ice is 2100J/(kg℃), the specific latent heat of vaporization of water is 2300 000J/kg.
Answer:
1,840,000 J
Explanation:
The energy required for a particular change in state is given by the specific latent heat. Specific latent heat is the amount of energy required to change the state of 1 ... of ice into 1 kg of water at its melting point of 0°C. The same amount of energy ... stored or released as the temperature of a system changes can be calculated.
Dos cargas puntuales iguales y negativas, q1=q2=-24micro C se localizan en x=0 y y=38m y x=0 y y=-7m, respectivamente. Calcula la magnitud de la fuerza electrica total en N que ejercen estas dos cargas sobre una tercera, tambien puntual, Q=26micro C en y=0 y x=16m
Answer:
F_net = 9.87 10⁻⁴ N
Explanation:
Let's use that force is a vector magnitude
∑ F = F₁₃ + F₂₃
De bold arfe vectros. The force is the electric force, we use that charges of the same sign repel and when the charges are of a different sign they attract
the charges q1 and q2 are negative and the charge q3 is positive with the positions y1 = 38 m, y2 = -7m, y3 = 16 m
∑ F = F₁₃ - F₂₃
F_net = [tex]k \frac{q_1q_3}{r_{13}^2 } - k \frac{q_2q_3}{r_{23}^2 }[/tex]
in this case q₁ = q₂ = q
F_net = k q q₃ ( )
let's look for the distance
r₂₃ = y₂ - y₃
r₂₃ = -7 -16
r₂₃ = - 23 m
r₁₃ = 38 - 16
r₁₃ = 22 m
let's calculate
F_net = 9 10⁹ 24 26 10⁻¹² ( )
F_net = 5.616 ( 1.758 10⁻⁴ )
F_net = 9.87 10⁻⁴ N