A house has well-insulated walls. It contains a volume of 105 m3 of air at 305 K.
Consider heating it at constant pressure. Calculate the energy required to increase the temperature of this diatomic ideal gas by 0.7

Answer:

A

Explanation:

a pex

I don't know

because I don't know

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

[tex]I=I_o cos^2\theta[/tex]

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

[tex]I' = \frac{I_o}{2}[/tex]

The intensity of light passing from the second polarizer is

[tex]I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}[/tex]

The intensity of light passing from the third polarizer is

[tex]I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}[/tex]

Answer:

Kindly check explanation

Explanation:

The trampling and violation of human rights individuals, groups and corporate organizations is really alarming ad as such, the government who are charged to protect the right and interest of its citizen. In other to curtail the trending issues of human right violation, it is imperative if sensitization programmes could be organiz d in other to keep people informed of the various ways in which people's right may be trampled upon. With these education, the ignorance can be expunged leaving only those who genuinely decides to relate and threaten the right of his fellow country person.

The laws on human right violation should be reviewed and capital punishment metted on violators in other to send a strong warning to those who still nurture the intention.

Answer:

Formula

P = I x V

Information

V = 230

A = 3

P = x

Calculation

x = 230 x 3

x = 690 W

Explanation:

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If a person wants to calculate the length of time it takes for a ball to fall from a height of 20m, the correct equation that they should use is:

D. Δt= √2Δd/a

The free fall formula should be used to obtain the length of time that it takes for a ball to fall from a given height. This formula also factors the height or distance from which the fall occurred and this is denoted by the letter d. The small letter 'a' is denotative of acceleration due to gravity and this is a constant pegged at -9.98 m/s².

So, the change in height is obtained and multiplied by two. This is further divided by the acceleration and the square root of the derived answer translates to the time taken for the ball to fall from the height of 20m. Of all the options listed, option D represents the correct equation.

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Answer:

A B C

Explanation:just took the test

Answer:

Komal could have mixed up the labels on the vials.

Someone might have jiggled the table and made the water surface tension bubble spill over.

The water could actually have been saltwater instead of pure water.

Explanation:

...........................

Answer:

24 m

Explanation:

By applying the law of conservation of energy.

K.E = P.E

[tex]\dfrac{1}{2}kx^2 = mgh[/tex]

By rearrangement;

[tex]\dfrac{k}{m} = \dfrac{2*g*h}{x^2}[/tex]

where;

k = spring constant

m = mass of pebble

h = height reached

x = stretched length

[tex]\dfrac{k}{m} = \dfrac{2*9.8*6}{(20 \times 10^{-2})^2}[/tex]

[tex]\dfrac{k}{m} =0.2940 \times 10^4[/tex]

Since the drag force is negligible;

[tex]\dfrac{1}{2}kx^2 = mgh[/tex]

[tex]h = \dfrac{k}{m}\dfrac{x^2}{g}[/tex]

[tex]h = \dfrac{1}{2}\times 0.2940 \times 10^4 \times \dfrac{(40\times 10^{-2})^2}{9.8}[/tex]

h = 24 m

Answer:

[tex]\mu_w=86\%[/tex]

Explanation:

From the question we are told that:

Velocity on Dry road [tex]V_d=10m/s[/tex]

Radius Dry [tex]r_d=4.8[/tex]

Radius wet [tex]r_w=11.8[/tex]

Generally the equation for coefficient of static friction on the dry day is mathematically given by

[tex]\mu mg=\frac{mv^2}{r_d}[/tex]

[tex]\mu g=\frac{v^2}{r_d}[/tex]

[tex]\mu_d 9.8=\frac{10^2}{4.8}[/tex]

[tex]\mu_d=2.125[/tex]

Generally the equation for the relationship between Radius & coefficient of static friction is mathematically given by

[tex]\frac{\mu_d}{\mu_w}=\frac{r_d}{r_w}[/tex]

[tex]\frac{\mu_w}{2.125}=\frac{4.8}{11.8}[/tex]

[tex]\mu_w=0.86[/tex]

Therefore

[tex]\mu_w=86\%[/tex]

Answer:

120 Newton

Explanation:

Given the following data;

Mass = 12 kg

Angle = 4°

We know that acceleration due to gravity is equal to 10 m/s

To find the minimum force to stop the block from sliding;

Force = mgCos(d)

Where;

m is the mass of an object.

g is the acceleration due to gravity.

d is the angle of inclination (theta).

Substituting into the formula we have;

F = 12*10*Cos(4°)

F = 120 * 0.9976

F = 119.71 ≈ 120 Newton

by an echo meter

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Answer:

Anytime it feels the force of gravity.

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and can occupy space. Therefore, it acts in such a way as to bring objects together i.e causing the objects to fall down towards the Earth.

This ultimately implies that, an object is in free fall anytime it feels the force of gravity i.e regardless of how fast the object moves or the direction it moves, the only force acting on the object is the force of gravity (g).

For example, when you throw any object up, it will naturally fall down due to the gravitational force between the Earth and the object.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

On planet Earth, the acceleration due to gravity that all physical objects experience is 9.8 meters per seconds square.

Answer:

3 years

Explanation:

Find the circumference of each orbit in AU.

2xπx1=6.283185307

2xπx3=18.84955592

Divide them.

18.84955592/6.283185307=3

3 years

Answer:

The frictional force required for the car to travel is 8,365.01 N

Explanation:

Given;

mass of the car, m = 1600 kg

radius of the curved road, r = 71 m

banking angle, θ = 15⁰

velocity of the car, v = 86 km/h = 86/3.6 = 23.89 m/s

The two forces acting on the are:

1.  the parallel force to the banked plane

2. the centripetal force pushing the car up the banked plane

To keep the car traveling at 86 km/h;

frictional force + parallel force to the plane = centripetal force pushing the car up the banked plane

The parallel force to the banked plane:

F = mgsinθ

F = 1600 x 9.8 x sin(15⁰)

F = 4,057.98 N

The centripetal force pushing the car up the banked plane:

[tex]F_c= (\frac{mv^2}{r} )cos(\theta)\\\\F_c = (\frac{1600 \times 23.89^2}{71} )cos(15^0)\\\\F_c = 12,422.99 \ N[/tex]

The frictional force required for the car to travel:

[tex]F_k = F_c - F\\\\F_k = 12,422.99 \ N - 4,057.98 \ N\\\\F_k = 8,365.01 \ N[/tex]

Therefore, the frictional force required for the car to travel is 8,365.01 N

2.5 watt

Explanation:

we know

power = work done /time

work done gainst gravity is = mgh

as mg = weight = force = 5 N

and height = 2 m

so work done = mgh = 5*2 = 10N

therefore ,

Power = 10/4 = 2.5 watt

Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

acceleration of the truck, [tex]a_t[/tex] = 12.7 m/s²

mass of the truck, [tex]m_t[/tex] = 2490 kg

mass of the car, [tex]m_c[/tex] = 890 kg

let the acceleration of the car at the moment they collided = [tex]a_c[/tex]

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

[tex]F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2[/tex]

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

acceleration of the truck, = 12.7 m/s²

mass of the truck, = 2490 kg

mass of the car, = 890 kg

let the acceleration of the car at the moment they collided =

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

Answer:

c

Explanation:

in food and batteries chemical energy is stored :) hope this helped

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

Answer:

V = 2.58 m/s

Explanation:

Below is the calculation:

Given the weight of Erica = 37 kg

The weight of Danny = 45 kg

Danny's speed to move upward = 4.7 m/s

Use below formula to find the answer.

m1 * u1 = (m1+m2) * V

V = m1*u1 / (m1+m2)

Here, m1 = 45

u1 = 4.7

m1 = 45

m2 = 37

Now plug the values in formula:

V = m1*u1 / (m1+m2)

V = (45*4.7)/(45+37)

V = 2.58 m/s

The color orange has a wavelength of 590 nm. The energy of an orange photon is approximately 0.337 eV.

The correct answer is option E.

To calculate the energy of a photon, we can use the equation:

E = (hc) / λ

where E is the energy of the photon, h is the Planck's constant (6.626 x [tex]10^-^3^4[/tex]J·s or 6.626 x[tex]10^-^1^9^[/tex] eV·s), c is the speed of light (3.00 x [tex]10^8[/tex] m/s), and λ is the wavelength of the light.

Given that the wavelength of orange light is 590 nm (or 590 x [tex]10^-^9[/tex]m), we can substitute the values into the equation:

E = [(6.626 x[tex]10^-^1^9^[/tex] eV·s) x (3.00 x [tex]10^8[/tex] m/s)] / (590 x[tex]10^-^9[/tex]m)

E = (1.9878 x [tex]10^-^1^0[/tex]eV·m) / (590 x [tex]10^-^9[/tex] m)

E = 3.3695 x [tex]10^-^1[/tex] eV

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The question probable may be:

The color orange has a wavelength of 590 nm. What is the energy of an orange photon? (h = 6.626 x [tex]10^-^1^9^[/tex], 1 eV = 1.6 x[tex]10^-^1^9^[/tex]J)

A) 2.81 eV

B) 3.89 eV

C) 2.10 eV

D) 2.78 eV

E)  0.337 eV

Answer:

Soil erosion is the act of removing the top layer of the soil either by rain wind or human activities

Answer:

l erosion is a gradual process that occurs when the impact of water or wind detaches and removes soil particles, causing the soil to deteriorate. ... The impact of soil erosion on water quality becomes significant, particularly as soil surface runoff. Sediment production and soil erosion are closely related.

Explanation:

Answer:

Potential energy. Releasing it, the potential energy would convert into motion, kinetic energy.

Potential energy is when an object has some sort of potential eg. for motion such as in this example.

Answer:

A. Potential energy

Explanation:

Potential energy can be thought of as stored energy, which has the potential of becoming kinetic energy once it has been released.

Answer:

here is ur answer...

Explanation:

gravity .......is ur answer

and the value of D is DE³S NU + s

An attractive force that exist between all object with mass attract another objects the magnitude of the force is directly proportional..

Hope this help!

Explanation:

i) center of gravity (or mass)

ii) m = W/g = (160 N)/(9.8 m/s^2)

= 16.3 kg

Answer:

time is 32 s and speed is 304.3 m/s

Explanation:

Height, h = 146 m

speed, u = 14 m/s

Angle, A = 43 degree

Let it hits the ground after time t.

Use second equation of motion

[tex]h = u t +0.5 at^2\\\\- 146 =14 sin 43 t - 4.9 t^2\\\\4.9 t^2 - 9.5 t - 146 =0 \\\\t =\frac{9.5\pm\sqrt {90.25 + 2861.6}}{9.8}\\\\t=\frac{9.5\pm 54.3}{9.8}\\\\t = 32.05 s, - 22.4 s[/tex]

Time cannot be negative so the time is t = 32 s .

The vertical velocity at the time of strike is  

v' =  u sin A - g t

v' = 14 sin 43 - 9.8 x 32 = 9.5 - 313.6 = - 304.1 m/s

horizontal velocity

v'' = 14 cos 43 =10.3 m/s

The resultant velocity at the time of strike is

[tex]v=\sqrt{v'^2 + v''^2}\\\\v = \sqrt{304.1^2 +10.3^2 }\\\\v = 304.3 m/s[/tex]  

Answer:

12

Explanation:

I'm a beginner so am not sureeeeee

Answer:

NO CLUE

Explanation:

GOOD LUCK THOUGH