A hydraulic car jack needs to be designed so it can lift a 2903.57 lb car assuming that a person can exert a force of 24.41 lbs. If the piston the person is pushing on had a radius of 3.26 cm, what should the diameter of the piston be that is used to raise the car?

Answers

Answer 1

Answer:

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Let [tex]F_{1}[/tex] = 2903.57 lb, [tex]F_{2}[/tex] = 24.41 lbs, [tex]r_{2}[/tex] = 3.26 cm = 0.0326 m.

[tex]A_{2}[/tex] = [tex]\pi r^{2}[/tex]

    = [tex]\frac{22}{7}[/tex] x [tex](0.0326)^{2}[/tex]

    = 0.00334 [tex]m^{2}[/tex]

So that:

[tex]\frac{2903.57}{A_{1} }[/tex] = [tex]\frac{24.41}{0.00334}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{2903.57*0.00334}{24.41}[/tex]

    = 0.3973

[tex]A_{1}[/tex] = 0.4 [tex]m^{2}[/tex]

The radius of the piston can be determined by:

[tex]A_{1}[/tex] = [tex]\pi r^{2}[/tex]

0.3973 = [tex]\frac{22}{7}[/tex] x [tex]r^{2}[/tex]

[tex]r^{2}[/tex] = [tex]\frac{0.3973*7}{22}[/tex]

   = 0.1264

r = [tex]\sqrt{0.1264}[/tex]

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).


Related Questions

A 1150 kg car is on a 8.70° hill.
Using X-Y axes tilted down the
plane, what is the y-component
of the weight?

Answers

Answer:

Explanation:

y-component = - mgcos(8.7)

= - (1150)(9.81)cos(8.7)

= - 11151.69378

= - 11151.69 N

The weight of the y-component is 11140.33N.

How to find the weight of the y-component?

To find the weight of the y-component:

Given,

Car weight = 1150 kg

Anfle = 8.70 degree

weight = mg = 1150 * 9.8

= 11270 N

Y-component =  mg cos∅

= 11270 * cos(8.70)

= 11140.33N

The aspect that pushes proper or left is referred to as the x-factor, and the element that pushes up or down is known as the y-component.

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HELP ASAP!!!

Which graph shows the change in velocity of an object in free fall?

Answers

Answer:

the graph that show Change in velocity is no A

The graph that showing the velocity with respect to time for a free falling body is figure C where, the downward velocity will be higher due to the acceleration due to gravity.

What is velocity?

Velocity of a moving body is the measure of the distance covered per unit time. Thus, it is the ratio of distance to the time. Velocity is expressed in the units of Km/h, m/s. miles/h, ft./s etc.

The rate of change of velocity is called acceleration. The acceleration by the force of a gravitational field is called acceleration due to gravity g having the value 9.8 m/s².

The velocity - time graph shows a diagonal relation for a free falling body. A free falling body is initially at rest and falls downward with the negative velocity with the acceleration due to gravity. Therefore, figure B shows the change in velocity of a free falling body.

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Select all correct answers....Covalent compounds​

Answers

I know for sure that the third one is correct

Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 myf=5.00 m above the ground. On his first try, Robin looses the arrow at v0=35.0 m/sv0=35.0 m/s at an angle of θ=30.0°θ=30.0° above the horizontal. The arrow has an initial height of y0=1.50 m,y0=1.50 m, and its tip is x=60.0 mx=60.0 m away from the target orange. Treating the arrow as a point projectile and neglecting air resistance, what is the height of the arrow once it has reached the horizontal position xx of the orange? Use g=9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity.

Answers

Answer:

h' = 55.3 m

Explanation:

First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:

s = vt

where,

s = horizontal distance between arrow and orange = 60 m

v = initial horizontal speed of the arrow = v₀ Cos θ

θ = launch angle = 30°

v₀ = launch speed = 35 m/s

Therefore,

60 m = (35 m/s)Cos 30° t

t = 60 m/30.31 m/s

t = 1.98 s

Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:

h = Vi t + (1/2)gt²

where,

Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°

Vi = 17.5 m/s

Therefore,

h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²

h = 34.6 m + 19.2 m

h = 53.8 m

since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:

h' = h + y

h' = 53.8 m + 1.5 m

h' = 55.3 m

1. When asteroids collided some of the broken materials fall into Earth's orbit. What do
astronomers call the debris when it hits planet Earth?
(2 Points)
meteors
meteoroids
meteorites
metabots

Answers

i believe it is meteoroids

Before they meet Earth -- meteoroids

While they're falling -- meteors

After they hit the ground -- meteorites

The chemical equation below shows that hydrogen and oxygen chemically react to form water.



Which of these is true?

A.

Water is a pure substance and has the same properties as oxygen.


B.

Water is a pure substance and has the same properties as hydrogen.


C.

Hydrogen and oxygen are pure substances that have identical properties to each other.


D.

Hydrogen, oxygen, and water are pure substances that each have different properties.

Answers

Answer:

D

Explanation:

Hydrogen, oxygen, and water are pure substances that each have different properties.

Although the 3 of them are pure substances, but they nonetheless have different properties. These properties could either be their physical properties, or their chemical properties. This is particularly so because since Oxygen and Hydrogen the major components in water have different properties, it is only right if their product, water, has different properties also.

Answer:

D

Explanation:

got it right on study island

The flywheel of an engine has moment of inertia 1.9 kg m2 about its rotation axis. What constant torque is required to bring it up to an angular speed of 537 rev/min in 6.78 s, starting from rest, in N-m

Answers

Answer:

τ = 15.76 N-m

Explanation:

For rigid bodies, the net external torque acting on a rotating body, is equal to the product of the moment of inertia about its rotation axis, times the angular acceleration of the body, as follows:

        [tex]\tau = I * \alpha (1)[/tex]

Since I is a given of the question, we need to find out the angular acceleration.By definition, the angular acceleration is the rate of change of the angular velocity with respect to time:α = Δω/Δt = (ωf-ω₀) / (tfi-t₀)Since ω₀ = 0, and choosing t₀ =0, as tfi is a given, we need just to find out ωf.We have this value  in rev/min, so we need first to convert it to rad/sec, as follows:

       [tex]537 rev/min * (1min/60 sec)*(2*\pi *rad/rev) = 17.9 * \pi rad/sec (2)[/tex]

Replacing in the definition of α, we have:α = 17.9*π rad/sec / 6.78 s = 8.29 rad/sec²Replacing I and α in (1), we finally get:

       τ = 15.76 N-m.

giving brainliest to first one who gets this right

Answers

a. Nitrogen, Oxygen,and Carbon Dioxide

hope im right but I dont really know

In the Bohr model of the hydrogen atom, an electron in the 1st excited state moves at a speed of 2.19 106 m/s in a circular path having a radius of 5.29 10-11 m. What is the effective current associated with this orbiting electron?

Answers

Answer:

I = 1.05x10⁻³ A

Explanation:

By definition, an electric current is the rate of charge flow at a given time:

[tex] I = \frac{q}{t} [/tex]

Where:

q: is the electrons charge = 1.602x10⁻¹⁹ C

t: is the time

In a circular motion, the time is given by:

[tex] t = T = \frac{2\pi}{\omega} = \frac{2\pi}{v/r} = \frac{2\pi r}{v} [/tex]

Where:

ω: is the angular speed = v/r

v: is the speed = 2.19x10⁶ m/s

r: is the radius = 5.29x10⁻¹¹ m

[tex] t = \frac{2\pi r}{v} = \frac{2\pi 5.29 \cdot 10^{-11} m}{2.19 \cdot 10^{6} m/s} = 1.52 \cdot 10^{-16} s [/tex]

Now, the effective current is:

[tex] I = \frac{q}{t} = \frac{1.602 \cdot 10^{-19} C}{ 1.52 \cdot 10^{-16} s} = 1.05 \cdot 10^{-3} A [/tex]  

Therefore, the effective current associated with this orbiting electron is 1.05x10⁻³ A.

I hope it helps you!                                

why is it more painful to walk on gravel with your shoes off then on (3 marks please)

Answers

Answer:

Because shoes protect our feet from some of the most harmful platforms

Gravel has some small pebbles on it sometimes (or other sharp objects)

Gravel is pretty hard.

Mr Jones launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how far south does the arrow travel. (Step 2, you need the previous questions answer to answer correctly

a. 118.4 m south
b 1936 m south
C 2 m south
d 640 m south​

Answers

Answer:c

Explanation:its the answer because its the answer

The particle accelerator at CERN can accelerate an electron through a potential

difference of 80 kilovolts. Calculate

(a) The kinetic energy (in keV) of the electron​

Answers

Answer:

K.E = 1.28 × 10^-17 KeV

Explanation:

Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.

To Calculate the kinetic energy (in keV) of the electron​, let us first find the electron charge which is 1.60 × 10^-19C

The kinetic energy = work done

K.E = e × kV

Substitute e and the voltage into the formula

K.E = 1.60 × 10^-19 × 80

K.E = 1.28 × 10^-17 KeV

Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV

What is the wavelength of light falling on double slits separated by 2.00 μm if the third-order maximum is at an angle of 60.0∘?

Answers

Answer:

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Explanation:

In order to solve this problem we will use the grating equation:

mλ = d Sin θ

where,

m = order = 3

λ = wavelength of light = ?

d = slit separation = 2 μm = 2 x 10⁻⁶ m

θ = angle = 60°

Therefore,

(3)λ = (2 x 10⁻⁶ m)Sin 60°

λ = 1.732 x 10⁻⁶ m/3

λ = 5.773 x 10⁻⁷ m = 577.3 nm

a car accelerates at a constant rate from 15 m/s to 25 m/s while it travels a distance of 125 m. How long does it take to achieve this speed?

Answers

T=Vf-Vi/s
25m/s -15m/s/ 125m
10m/s /125m
=0.08s
I hope it’s correct !

The time taken by the car to achieve the final speed is 6.25 seconds.

What is the equation of motion?

The equations of motion can be defined as the equation that represents the relationship between the time, velocity, acceleration, and displacement of a moving object.

The mathematical expressions for the equations of motions can be written as:

[tex]v= u+at\\S=ut+(1/2)at^2\\v^2-u^2=2aS[/tex]

Given, the initial speed of the car, u = 15 m/s

The final speed of the given car, v = 25m/s

The distance covered by car, S = 125 m

From the third equation of motion: v² = u²+ 2aS

(25)² = (15)² + 2×a× 125

a = 1.6 m/s²

From the first equation of motion we can find the time to achieve the final speed:

v = u+ at

25 = 15 + (1.6) × t

t = 6.25 sec

Therefore, 6.25 seconds will be taken by the car to catch the final speed.

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Which of the following requires the expenditure of more​ work? ​

a. Lifting a 110 newton​ [N] weight a height of 3 meters​ [m].
b. Exerting a force of 60 ​pounds-force ​[lbf​] on a sofa to slide it 30 feet​ [ft] across a room.

Answers

Answer:

The correct answer is option B

Explanation:

Step one:

given data

a. force F= 110N

distance s= 3meters

we know that work= Force* distance

work= 110*3

Work= 330Joules

Step two:

data

Force= 60 pounds

distance= 30 ft

convert pounds to Newton

1 pound= 4.44822N

60 pounds= 60*4.44822

=266.9N

convert ft to meteres

1 ft = 0.3048meter

30ft= 0.3048*30

=9.144N

we know that work= Force* distance

work= 266.9N*9.144N

Work= 2440.53Joules

Friction that occurs in gases and liquids is called

Answers

The answer is fluid friction

Which statement best describes energy and matter in a closed system? (2 po
O Energy and matter flow into and out of the system.
Energy can flow into and out of the system but matter cannot.
Energy and matter are contained within a closed system.
O There is no energy in a closed system; there is matter.

Answers

Answer:

Energy can flow into and out of the system but matter cannot.

Explanation:

In a closed system, energy can flow in and out of the system but matter cannot.

A closed system prevents double way flow of matter. A closed system conserves matter.

For an isolated system, energy and matter cannot flow out of the system.

For open systems, energy and matter can flow out of the system.

Such systems are used for certain thermodynamics experiment.

If a 46 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by _____ J.a. 1400 J b. 10,000 J. c. 1000 J. d. 100 J

Answers

Answer:

B. 10000 J

Explanation:

The possible answers are not related to the statement at all. The correct statement is:

If a 100 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by:

From definitions of work and gravitational potential, we get the following formula to calculate the change experimented in the person's potential energy after walking up two floors in the Physics building:

[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (1)

Where:

[tex]\Delta U_{g}[/tex] - Change in the gravitational potential energy, measured in joules.

[tex]m[/tex] - Mass of the person, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta z[/tex] - Change in height, measured in meters.

If we know that [tex]m = 46\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 10\,m[/tex], then the change in the gravitational potential energy is:

[tex]\Delta U_{g} = (100\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (10\,m)[/tex]

[tex]\Delta U_{g} = 9807\,J[/tex]

The choice that best approximates this answer is B.

Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question)
a 2 seconds
b. 1 second
c.4 seconds
d 19.6​

Answers

Answer:c

Explanation:

A 45 kg object has a momentum of 225 kg-m/s northward. What is the object's velocity?
A. 180 m/s
B. 5.0 m/s
C. 10,125 m/s
D. 0.20 m/s

Answers

The answer is 5.0 m/s

9. What distance is a book from the floor if the book contains 196 Joules of potential energy and has a mass of 5 kg?​

Answers

Answer:

the book is 4 meters from the floor

Explanation:

Use the formula for potential energy:

U = m g h

196 J = 5kg 9.8m/s^2 h

h = 196 / (5*9.8 ) m

h = 4 m

At an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s. What is the angle of the shock cone

Answers

Answer:

55 degrees

Explanation:

Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.

From the question above, we can get the below parameters

Object speed (V) = 1500 km/h

Sound speed ( v) = 342 m/s

Convert km/h to m/s

(1500 × 1000)/3600

Jet speed V = 416.67 m/s

Let's first calculate the mash number M.

M = V/v

M = 416.67 / 342

M = 1.2183

Formula for the angle of the shock cone is reciprocal of mash number. That is,

Sin Ø = 1 / M

Sin Ø = 1 / 1.2183

Sin Ø = 0.8208

Ø = sin^-1(0.8208)

Ø = 55 degree

Therefore, the angle of the shock cone is approximately 55 degrees

A ball of mass 0.600 kg is carefully balanced on a shelf that is 2.20 m above the ground. What is its gravitational potential energy?

Answers

Answer:

Explanation:

Gravitational potential energy = mass x height of object x g

g is gravitational acceleration .

Gravitational potential energy of the ball = .600 x 2.20 x 9.8

= 12.936 J .

12.9 J .

Why are the coral reefs suffering? (site 2) explain

Answers

Answer:

bcuz ov yo fat mamma

Explanation:

Answer:

Water pollution

Explanation:

What is the acceleration of gravity, in m/s2, on the surface (or outer limit) of Venus? The mass of Venus is 4.87 1024 kg and its radius is 6.05 106 m.

Answers

Answer:

8.9 m/[tex]s^{2}[/tex]

Explanation:

From Newton's law of universal gravitation,

F = [tex]\frac{GMm}{R^{2} }[/tex] .............. 1

and from Newton's second law of motion,

F = mg ........... 2

Equating the two expression,

mg = [tex]\frac{GMm}{R^{2} }[/tex]

g = [tex]\frac{GM}{R^{2} }[/tex]

Given that: mass of Venus = 4.87 x [tex]10^{24}[/tex] Kg, radius = 6.05 x [tex]10^{6}[/tex] and G = 6.67 x [tex]10^{-11}[/tex] N[tex]m^{2} Kg^{-2}[/tex]

Thus;

g = [tex]\frac{6.67*10^{-11}*4.87*10^{24} }{(6.05*10^{6} )^{2} }[/tex]

  = [tex]\frac{3.24829*10^{14} }{3.66025*10^{13} }[/tex]

 = 8.87450

g = 8.9 m/[tex]s^{2}[/tex]

the acceleration of gravity on the surface of Venus is 8.9 m/[tex]s^{2}[/tex].

a pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?

Answers

Answer:

500 g

Explanation:

m = Mass of water

c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]

[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]

Q = Heat added = 40000 cal

Heat is given by

[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]

The mass of water is 500 g.

What is the force used when a 7 kg bowling ball is rolled with an acceleration of 3 m /s2? Use the formula to find the force in Newtons (N): F = 7 kg × 3 m/s2

Answers

Answer:

21 Newtons

Explanation:

Force= mass * acceleration

Force= 7 kg * 3 m/s^2

Force= 21 Newtons

which state can you infer that average home prices are the highest? Florida California Texas New York

Answers

Answer:

California

Explanation:

just took the test

The state you can infer where average home prices are the highest is California. Option B. This is further explained below.

What is an average home price?

Generally, an average home price refers to a cumulative average to the house or home pricing in a state.

In conclusion, California has the highest average home prices highest in America.

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what are the formulae of momentun and their time of use​

Answers

Answer:

???????????????????????????

pls help quick. the number line shows the starting and ending velocities for ball 1 what's the change in velocity of ball 1 calculate the value mathematically and check using the number line​

Answers

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

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