A mass 25kg is attached to a spring which is held stretched a distance 120 cm by a force F=300N (Fig. 7-28), and then released. The spring compresses, pulling the mass. Assuming there is no friction, determine the speed of the mass m when the spring returns: (a) to its normal length (x = 0). (b)find the spring constant k?

Answer:

Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.

Given in the question mass and acceleration of balloon, force is given as

F = m*a

m = 2 kg

a = 4 m/s²

F = 2 kg×4 m/s²

F = 8 N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

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Answer:

thats a force

Explanation:

Answer:

force

Explanation:

the definition of a push or pull is force

Answer:

0

Explanation:

The neighbors displacement is 0 as displacement is how far the person is from their starting location. If they walk 2 miles away and then head back those 2 miles back to their house; 2-2=0

Answer:

True

Explanation:

Answer:

A team may contact the ball a total of three (3) times before it is sent over the net.

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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Answer:

Momentum = 239.59 kg·m/s

Explanation:

Mass x Velocity = Momentum

Answer:

The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)

Explanation:

Answer:

Answer is below ….

Explanation:

The Bernoulli equation is a crucial statement that connects a fluid's pressure, height, and velocity at a single point in its flow. In an idealised system, the connection between these fluid conditions along a streamline always equals the same constant along that streamline.

Water from a reservoir runs through enormous tubes called penstocks before reaching a turbine at the end of a hydroelectric dam. The gravitational potential energy drops as the water flows down the pipe according to Bernoulli's equation, yet in many configurations, the water departs at the same speed.

Bernoulli's equation is a more broad and mathematical version of Bernoulli's principle that includes variations in gravitational potential energy. We'll derive this equation in the following part, but first, let's look at Bernoulli's equation to get a sense of what it says and how one may use it.

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(hope this helps can I pls have brainlist (crown)☺️)

Answer:

B) New

During a new Moon phase, the side of the Moon facing Earth isn't reflecting any sunlight from the Sun.

Answer:

√40m/sec

Explanation:

As we know Kinetic energy = 1/2 mv^2

700 = 1/2 x 35 x v^2

1400/35 = v^2

√40 = v

So v, √40m/sec

Hope this helps you.

Answer: 80.5 miles

Explanation:

3.5 x 23 = 80.5

Answer:

no picture attached

Explanation:

Without:

With safety:

Answer:

112 [kJ]

Explanation:

1) related formula is: A=F*S, where A - required work [J], F - force [N], S - distance [m].

2) according to the formula above: A=140*800=112000[J]=112 [kJ]

Answer:

112000 J

Explanation:

800N x 140m

Answer:

where in the world is the image????..

La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.

Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido

Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N

Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N

Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N

Pero ;

Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud

volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud

volumen = 0.081 N / 1000 * 10

Volumen = 8.1 * 10 ^ -6 m ^ 3

Densidad = masa / volumen

Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3

= 7,8 * 10 ^ 3 kg / m ^ 3

Más información: https://brainly.com/question/12108425

Answer:

Infrared energy

Explanation:

Answer:

A) infrared energy

Explanation:

Answer:

Answer should be (B)

Explanation:

If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still. a moving object continues to move at the same speed and in the same direction.

ALSO: forces acting upon an object are balanced, then the object will maintain its state of motion. To maintain the state of motion is to keep the current speed and direction. But if the forces are not balanced, the object will change its state of motion.

Answer:

1.89*10⁶J

Explanation:

because 4500kg * 42m*10m/s² is 1890000J

Answer:

Why are Saturn's rings so noticeable? They are made of lots of fresh, bright icy particles from a recent breakup.

Explanation:

Answer:

A + B = B - A

The above equation must hold for the sum and difference to be zero.

How can one of the vectors not be zero?????

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

Answer:

12N

Explanation:

By Newton second law force is the product of the mass of the object times it's acceleration. That makes it [tex]2\cdot 6 kg \cdot m/s^2 = 12 N[/tex]

Answer:

typhoon forms when winds blow into areas of the ocean where the water is warm. These winds collect moisture and rise, while colder air moves in below. This creates pressure, which causes the winds to move very quickly. The winds rotate, or spin, around a center called an eye.

Answer: Yes,

If you need any other thing let me know, I'll still be on

Explanation:

The change in position of an object is known as motion. Force is external that causes a body to change its position

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Answer:

In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

The rotational inertia of the system is determined by summing all the masses together and multiply with the radius.

I(t) = Σmr²

Where;

I(t) = Inertia of the 2 spheres + inertia of the bug

I(t) = (M + M)L²  + (3M)L²

I(t) = 2ML² + 3ML²

I(t) = 5ML²

Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Complete question is below:

There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.

Learn more about rotational inertia here: https://brainly.com/question/14001220