A person is hauling their taco stand and it takes 3,500 Joules of work to stop the taco stand. What force was exerted on the taco stand if it took 1.5 meters to stop the motion?

Answer:

It allows you to walk faster.

Explanation:  

It is the same force that allows you to accelerate forward when you run. Your planted foot can grip the ground and push backward, which causes the ground to push forward on your foot. We call this grip type of friction, where the surfaces are prevented from slipping across each other, a static frictional force.

If the density of the baseball is within the acceptable density range of 0.70 g/cm³ and 0.80 g/cm³, then your response would be Yes and vice-versa.

Density can be defined as a ratio of mass to the volume of an object such as a baseball. Mathematically, the density of a baseball can be calculated by using this formula:

Density = Mass/Volume

Since the necessary parameters weren't provided in the question, I would give an insight on how to answer the question. You should substitute the mass and volume of the given baseball into the above formula and then solve.

Furthermore, if the density of the baseball is within the acceptable density range of 0.70 g/cm³ and 0.80 g/cm³, then your response would be Yes. However, if the density of the baseball is above or below the acceptable density range, then your response would be No.

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Los Angeles lies on the Pacific plate, San Francisco lies on the North American plate, and the meeting point of the two cities is mathematically given as

T = 120 x 105 years

Generally, the equation for Distance is mathematically given as

D = Rate x Time

Therefore

T = D/R

T = (600 x 105) / 5

T = 120 x 105 years

In conclusion, the meeting point of the two plates will be

T = 120 x 105 years

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Answer:

hope this helps and if you have any questions please feel free to ask me any time

Statement :- We assume the orthagonal sequence [tex]{{\{\phi\}}_{1}^{\infty}}[/tex] in Hilbert space, now [tex]{\forall \sf \:v\in \mathbb{V}}[/tex], the Fourier coefficients are given by:

[tex]{\quad \qquad \longrightarrow \sf a_{i}=(v,{\phi}_{i})}[/tex]

Then Bessel's inequality give us:

[tex]{\boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}[/tex]

Proof :- We assume the following equation is true

[tex]{\quad \qquad \longrightarrow \displaystyle \sf v_{n}=\sum_{i=1}^{n}a_{i}{\phi}_{i}}[/tex]

So that, [tex]{\bf v_n}[/tex] is projection of [tex]{\bf v}[/tex] onto the surface by the first [tex]{\bf n}[/tex] of the [tex]{\bf \phi_{i}}[/tex] . For any event, [tex]{\sf (v-v_{n})\perp v_{n}}[/tex]

Now, by Pythagoras theorem:

[tex]{:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}[/tex]

[tex]{:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}[/tex]

Now, we can deduce that from the above equation that;

[tex]{:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i} \vert^{2}\leqslant \Vert v\Vert^{2}}[/tex]

For [tex]{\sf n\to \infty}[/tex], we have

[tex]{:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}[/tex]

Hence, Proved

An increase in the concentration of sugar in a solution leads to the increase in boiling point of the solution.

Boiling point of a solution is that pressure exerted on a liquid by its surrounding is equal to the vapour pressure of the liquid.

When there is an increase in concentration of solute, more space will be occupied in the fluid leading to an increase in the boiling point of the fluid.

Therefore, An increase in the concentration of sugar in a solution leads to the increase in boiling point of the solution.

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The average velocity of the lizard for the whole journey is 0.26 m/s Down.

The term average velocity has to do with the velocity of the lizard for the whole journey. We can see that the downward displacement is greater than the upward displacement.

Thus;

Velocity = displacement / time = 23.7 m - 15.5 m/31.5s = 0.26 m/s Down.

Thus, the average velocity of the lizard for the whole journey is 0.26 m/s Down.

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The current density of the copper wire is determined as (7.059 x 10⁸ A/m²)/L

The current density of the copper wire is calculated as follows;

J =1/ρ(E) = 1/ρ(V/L)

where;

J =1/ρ(E) = 1/ρ(V/L)

J = (1/1.7 x 10⁻⁸) x (12)/L

J = (7.059 x 10⁸ A/m²)/L

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One parameter of the system that is held constant that can be considered is the mass of the water.

In science, the constant is a type of unmodified variable that remains equal along with the experimental procedure.

The constants of a particular system must be considered and they cannot change in experiments or observations.

In conclusion, one parameter of the system that is held constant that can be considered is the mass of the water.

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Answer:

proton in a material all spin in the opposite direction

The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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Answer:

Area under force time graph gives ‘impulse ‘

The resultant force of both forces is 15.62 N.

The Resultant of forces is a single force obtained when two or more forces are combined.

To calculate the resultant of the force, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the resultant force of both forces is 15.62 N.

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Using the parallelogram law of vectors to obtain the resultant, we have the value 16 N.

The resultant force is that force that has the same effect in magnitude and direction as two forces acting together. In this case, we have two forces , 8 N and 10 N inclined at an angle of 120 degrees

Using the parallelogram law of vectors to obtain the resultant;

R = √([8²+10²)-2×8×10cos120°]

R = √164 +80

R = 16 N

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Answer:

it would depend on which element u would be considering

Explanation:

as helium , oxygen , carbon ,sodium and other would be easier while plutonium , americium and other very radioactive elements would be harder

Answer:

~ 20 half lives

Explanation:

(1/2) ^n   = 1/1,000,000     n = number of half-lives

                                        LOG both sides to get

n LOG 1/2 = -6

n = -6/(LOG (1/2)) = 19.931    or approx  20 half lives

Answer:

26.562

Explanation:

1+25= 26

0.362+0.2= 0.562

26+0.562= 26.562

or just use a calculator

The words best describe the archer's results are  The correct option is A.

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Given is an archer's targets on the target board.

Accuracy compares the experimental value to the theoretical value (desired target)

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is A.

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The changes that would increase the total energy of a system is an addition of 500 J of kinetic energy and a loss of 450 J of thermal energy.

The term conservation of energy means that energy can not be created nor destroyed.

In this case, the changes that would increase the total energy of a system is an addition of 500 J of kinetic energy and a loss of 450 J of thermal energy.

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By using Displacement method we can find volume of irregular object like marble.

In displacement method,  

First , we measuring the volume of water displaced by an object which tell us the volume of the object.

Secondly We can use the physical balance to determine its mass.

Lastly , calculate the density by dividing the mass by the volume.

Procedure to find the Volume of irregular object i.e. marble

step 1 - Fill the graduated cylinder about half full and measure the initial volume of water.

step 2 - Drop the marble in the graduated cylinder.

step 3 -Now measure the final level of water.

Step 4 - Subtract both the values.

Here , comes the Volume of Irregular Object.

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The average speed traveled by car is [tex]35m/s[/tex].

[tex]1^{st}[/tex] case

       Distance [tex]=[/tex] [tex]speed*time= 50*20=1000m[/tex]

[tex]2^{nd}[/tex] case

       Distance[tex]=30*30=900m[/tex]

[tex]3^{rd}[/tex] case

       Distance[tex]=20*10=200m[/tex]

Now, The total distance[tex]=(1000+900+200)m=2100m[/tex]

        Total time[tex]=(20+30+10)s=60s[/tex]

       Average distance [tex]=\frac{total distance}{total time} = \frac{2100}{60}=35m/s[/tex]

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Answer:

Electron groups could be considered as  Lone pair electrons and bonded pairs of electrons.

Answer: Option D & B

Explanation:

The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.

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Answer:

Using two to three sentences, summarize what you investigated and observed in this lab. I investigated that Most of my planets and moons had the element carbon in them. I observed that Different elements absorb different wavelengths of light.

Astronomers use a wide variety of technology to explore space and the electromagnetic spectrum; why do you believe it is essential to use many types of equipment when studying space?

It is essential to use a number of telescopes sensitive to different parts of the electromagnetic spectrum to study objects in space. Even though all light is fundamentally the same thing, the way that astronomers observe light depends on the portion of the spectrum they wish to study. Tools are useful, such as detectors that help see the different wavelengths of light. Not all light can get through the Earth's atmosphere, so for some wavelengths we have to use telescopes aboard satellites.

If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to Earth?  Explain why. (Hint: Think about the carbon cycle.)

The missing element that would make moons and other planets similar to earth is oxygen. The two make carbon dioxide.

We know that the electromagnetic spectrum uses wavelengths and frequencies to determine a lot about outer space. How does it help us find out the make-up of stars?  

electromagnetic radiation Explanation, astronomers observe the wavelengths by putting telescopes on mountain tops and take results of what they are seeing

Why might it be useful to determine the elements that a planet or moon is made up of?

It might be useful so we can make new discoveries of life or even plants on other planets and moons. And discover maybe even more moons one other planets.

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Explanation:

Answer:

Claim: Lunar eclipses occur when Earth passes between the Sun and the Moon, blocking the sunlight falling on it.

Evidence: A lunar eclipse is caused by Earth blocking sunlight from reaching the moon and casting a shadow across its surface. A lunar eclipse occurs when the Moon and Sun are on opposite sides of Earth. Sun-blocking Earth casts two shadows on the moon: The umbra is a full, dark shadow, and the penumbra is a partial shadow. Lunar eclipses can be divided into two types: total and partial. A total lunar eclipse occurs when the Moon and Sun are on opposite sides of Earth. A partial lunar eclipse happens when only part of Earth's shadow covers the Moon.

Reasoning:  The Moon moves into the shadow of the Earth during a lunar eclipse. This can occur only when the Sun, Earth, and Moon are exactly or very closely aligned (in syzygy) with Earth between the other two, which can happen only on the night of a full moon when the moon is near either lunar node.

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Answer:

Claim: Lunar eclipses occur when Earth passes between the Sun and the Moon, blocking the sunlight falling on it.

Evidence: A lunar eclipse is caused by Earth blocking sunlight from reaching the moon and casting a shadow across its surface. A lunar eclipse occurs when the Moon and Sun are on opposite sides of Earth. Sun-blocking Earth casts two shadows on the moon: The umbra is a full, dark shadow, and the penumbra is a partial shadow. Lunar eclipses can be divided into two types: total and partial. A total lunar eclipse occurs when the Moon and Sun are on opposite sides of Earth. A partial lunar eclipse happens when only part of Earth's shadow covers the Moon.

Reasoning:  The Moon moves into the shadow of the Earth during a lunar eclipse. This can occur only when the Sun, Earth, and Moon are exactly or very closely aligned (in syzygy) with Earth between the other two, which can happen only on the night of a full moon when the moon is near either lunar node.

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Answer:

Approximately [tex]111\; {\rm \Omega}[/tex].

Explanation:

It is given that [tex]R_{1} = 200\; {\Omega}[/tex] and [tex]R_{2} = 250\; {\Omega}[/tex] are connected in a circuit in parallel.

Assume that this circuit is powered with a direct current power supply of voltage [tex]V[/tex].

Since [tex]R_{1}[/tex] and [tex]R_{2}[/tex] are connected in parallel, the voltage across the two resistors would both be [tex]V[/tex]. Thus, the current going through the two resistors would be [tex](V / R_{1})[/tex] and [tex](V / R_{2})[/tex], respectively.

Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor: [tex]I = (V / R_{1}) + (V / R_{2})[/tex].

In other words, if the voltage across this circuit is [tex]V[/tex], the total current in this circuit would be [tex]I = (V / R_{1}) + (V / R_{2})[/tex]. The (equivalent) resistance [tex]R[/tex] of this circuit would be:

[tex]\begin{aligned} R &= \frac{V}{I} \\ &= \frac{V}{(V / R_{1}) + (V / R_{2})} \\ &= \frac{1}{(1/R_{1}) + (1 / R_{2})}\end{aligned}[/tex].

Given that [tex]R_{1} = 200\; {\Omega}[/tex] and [tex]R_{2} = 250\; {\Omega}[/tex]:

[tex]\begin{aligned} R &= \frac{1}{(1/R_{1}) + (1 / R_{2})} \\ &= \frac{1}{(1/(200\: {\rm \Omega})) + (1/(250\; {\rm \Omega}))} \\ &\approx 111\; {\rm \Omega}\end{aligned}[/tex].

Answer:

24 mph

Explanation:

Speed = Distance / Time

Speed = 20 ÷ 5/6

Speed = 24 mph

NOTE: 5/6 is a fraction in this case and is equivalent to 50/60 and 60 minutes = 1 hour of course.

Hope this helped!

Answer:

[tex]\textsf {speed = 24 mph}[/tex]

Explanation:

[tex]\textsf {Formula used :}\\\implies \textsf {speed = distance/time}[/tex]

[tex]\mathsf {Given :}[/tex]

[tex]\implies \textsf {distance = 20 miles}[/tex]

[tex]\implies \textsf {time = 50 minutes = 5/6 hour}[/tex]

[tex]\textsf {Solving :}[/tex]

[tex]\implies \mathsf {speed = 20 \div 5/6 }[/tex]

[tex]\implies \mathsf {speed = 20 \times 6/5}[/tex]

[tex]\implies \mathsf {speed = 4 \times 6}[/tex]

[tex]\implies \textsf {speed = 24 mph}[/tex]

KE

For nitrogen n=5

So

The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

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The speed of the cart after 3 seconds of Low fan speed is 55 cm/s.

The speed of the cart after 5 seconds of Medium fan speed is 120 cm/s.

The speed of the cart after 2 seconds of High fan speed is 63 cm/s.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.

The graph in the attachment may be used to estimate the cart speed for various fan speeds.

Blue letters indicate the low fan speed. When the line drawn from x hits the blue line, the elapsed time is indicated on the x-axis cart speed after three seconds.

This is equivalent to 55 cm/s.Yellow markings indicate the medium fan speed. After 5 seconds, the line drawn from the point marked 5 on the x-axis crosses the yellow line, marking the time that has passed.

The intersection of the yellow line with the line drawn from the point marked 5 on the x-axis indicates the cart speed five seconds later. The y-axis measurement is roughly 120 cm/s.

Green markings indicate the high fan speed. On the x-axis is the elapsed time. Cart speed at the place where the green line and the line drawn from the x-point axis 2 connect. The y-axis reading is roughly 63 cm/s.

Hence, after the specified seconds, the cart's estimated speeds at low, medium, and high speeds are 55 cm/s, 120 cm/s, and 63 cm/s, respectively.

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Explanation:

Snell's Law of refraction:

Refraction of light obeys the following its two laws which's snell's law.

[tex] \rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

This is known as the refractive index of the second medium with respect to the first medium. Mu is given as:

[tex] \rm\mu = \cfrac{Speed \; of \; light \; in\; the\; first \; medium}{Speed \; of \; light \; in\; the\; second \; medium}[/tex]

Let's take an example.

If a ray light travels from air to water,then mu = sin i/sin r is the refractive index of water with air.

[tex]\rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

Ex.1:Ray light from air to water

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} \: m \: s {}^{1} }{2.25 \times 10 {}^{8} \: m \: s {}^{ - 1} } = \cfrac{4}{3} = \boxed{ 1.33}[/tex]

Ex.2: Ray light from Air to glass:

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} m \: s {}^{ - 1} }{2 \times {10}^{8 \: } m \: s {}^{ - 1} } = \cfrac{3}{2} = \boxed {1.5}[/tex]

[tex] \rule{225pt}{2pt}[/tex]