A playground merry-go-round with a radius of 2.0 m and a rotational inertia of 100 kg m2 is rotating at 3.0 rad/s. A child with a mass of 22 kg jumps onto the edge of the merry-go-round, traveling radially inward. What is the new angular speed of the merry-go-round

Answers

Answer 1

Answer:

The new angular speed of the merry-go-round = [tex]1.6rad/sec[/tex]

Explanation:

From angular momentum conservation

[tex]Iw_1 = (I + mr^2)w_2\\\\3*100 = (100 + 22*2^2)w_2\\\\300 = (100 + 88)w_2\\\\w_2 = \frac{300}{188}\\\\w_2 = 1.6rad/sec[/tex]

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Related Questions

What is the acceleration of a bicycle that goes from 3 m/s to 1 m/s in 2 seconds?
0.5 m/s2
1.0 m/s2
1.5 m/s2
-1.0 m/s2

Answers

Answer:

a=vf - vi/t

vf=final velocity

vi= initial velocity

t=time period

Now The bicycle went from 3ms to 1ms...

1.. It decelerated

2... Since it went from 3 to 1... 1 is the final velocity while 3 is the initial Velocity

Applying the Formula

a= 1-3/2

= -2/2

a= -1ms-²

Option D

A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev/s. What is its angular velocity (in rev/s) after a 22.0 kg child gets onto it by grabbing its outer edge

Answers

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

[tex]I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\[/tex]

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

What is the answer to this problem

Answers

Answer:

Material that allow the electrons to move freely in order to produce a current

Please mark as brainliest if answer is right

Have a great day, be safe and healthy  

Thank u  

XD  

material that allow the electrons to move, it is B

You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Your spring is to give the satellite a maximum acceleration of 5.00g. The spring's mass, the recoil kinetic energy of the shuttle, and changes in gravitational potential energy will all be negligible.
(a) What must the force constant of the spring be?
(b) What distance must the spring be compressed?

Answers

Answer:

[tex]380697.33\ \text{N/m}[/tex]

[tex]0.138\ \text{m}[/tex]

Explanation:

m = Mass rocket = 1070 kg

v = Velocity of rocket = 3.75 m/s

a = Acceleration of rocket = 5g

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The energy balance of the system is given by

[tex]\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}[/tex]

The force balance of the system is given by

[tex]ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}[/tex]

The distance the spring must be compressed is [tex]0.138\ \text{m}[/tex]

[tex]k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}[/tex]

The force constant of the spring is [tex]380697.33\ \text{N/m}[/tex].

If a magnet can cut into a small piece , each piece will remain a magnet ? Explain this phenomenon

Answers

yes ,each piece will remain a magnet because the small pieces will cut into north and south

A bicycle possesses 1000 units of momentum. what would be the bicycle's momentum if,
A.its velocity is doubled
B. its mass is tripled

Answers

the answer is A. it’s velocity’s doubled

A flat circular coil of wire having 400 turns and diameter 6.0 cm carries a current of 7.0 A. It is placed in a magnetic field of with the plane of the coil making an angle of 30° with the magnetic field. What is the magnitude of the magnetic torque on the coil?​

Answers

Answer:

6.8 N.m

Explanation:

The computation of the magnitude of the magnetic torque on the coil is given below:

Given that

n = 400

d =  6.0 cm

Current  is I = 7.0 A

Angle is [tex]\theta[/tex] = 30 degree

Now

We know that

the magnitude of the magnetic torque is

= nIABsin[tex]\theta[/tex]

= (400) (7.0) π ÷ 4 (0.06m)^2 sin(90° - 30°)

As

[tex]\theta[/tex] = (90° - Ф)

=  (400) (7.0) π ÷ 4 (0.06m)^2 sin 60°

= 6.8 N.m

Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five seconds.​

Answers

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

[tex]Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W[/tex]

Now, the energy supply can be calculated as follows:

[tex]E = Pt[/tex]

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

E = 75 J

how does light travel across the universe to earth?

Answers

Light travels at the speed of 186,000 miles per second. If you were to travel around the earth it would be 7.5 times in a second

Please please help me please please help

Answers

Answer:

Materials like air, water, and clear glass are called transparent. When light encounters transparent materials, almost all of it passes directly through them. ... When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials.

Explanation:

The chart lists the masses of four planets.
Planetary Masses
Planet
Mass
Neptune
1.02 x 1026
Uranus
8.68 x 1025
Mars
6.42 x 1023
Venus
4.87 X 1024
According to evidence that supports Einstein's general
theory of relativity, which list shows the planets that
would cause curvature in space-time from the least
amount of curvature to the greatest?
O Mars, Venus, Uranus, Neptune
O Neptune, Uranus, Venus, Mars
O Neptune, Uranus, Mars, Venus
O Venus, Mars, Uranus, Neptune

Answers

Answer:

I think it's A

Explanation:

It's definitely not B on edge

The correct option for the given question about Einstein's general

theory of relativity is Option A) Mars, Venus, Uranus, Neptune.

What is the Einstein's general theory of relativity?Albert Einstein established that the rules of physics apply to all non-accelerating observers in his theory of special relativity.He also demonstrated that the speed of light in a vacuum remains constant regardless of the velocity of an observer.The theory may be used to anticipate everything and describes how objects behave in space and time. For instance: that if there are black holes or not, if Gravity can causes light to bend, The way Mercury behaves when it is in orbit and many more interesting things.

As a Conclusion, we can state that the planets who would cause curvature in space time from the least amount of curvature to the greatest will be in order Mars, Venus, Uranus, Neptune.

Learn more about Einstein's general theory of relativity here:

https://brainly.com/question/13311063

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What is the correct calculation for voltage if the resistance is 3 ohms and the current is 4 amps?
3 x 4 = 12 volts
3 + 4 = 7 volts
4= 3 = 1.33 volts
4-3 = 1 volt

Answers

Answer:

iek

Explanation:

Answer:

the answer to your questions above is 3 x 4 = 12 volts

Explanation:

Voltage =  Current × Resistance

two 0.5 kg carts, one red and one green, sit about half a meter apart on a low friction track, you push on the red one with the constant force of 4N for 0.17m and then remove your hand. the cart moves 0.33 m on the track and then strikes the green cart. what is the work done by you on the two cart system?​

Answers

Answer:

The work done by you on the two cart system is 2 N-m

Explanation:

Work done is the product of force and displacement.

W = F * D

Substituting the given values we get -

W =

[tex]4 * (0.17+0.33)\\= 2[/tex]

The work done by you on the two cart system is 2 N-m

Why does one side of the Moon’s surface always remain much colder than the other side?
A) The colder side of the Moon has a cloud cover over it.
B) The colder side of the Moon is entirely covered with ice.
C) The colder side of the Moon always faces away from the Sun.
D) The colder side of the Moon has many high-altitude mountains.

Answers

Answer:

it's C

Explanation:

The colder side of the Moon always faces away from the Sun.

A force is described as?

Answers

Explanation:

A push or pull of an objecr

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

A force is described as push or pull on an object.

ThanksHope it helps.

HELP PLEASEEEEEEEEEEEE

Answers

the answer would be a

4. A girl sits on a tire that is attached to a tree limb by a rope 2.10 m in length. The girl's father pushes her with a tangential speed of 2.50 m/s. If the magnitude of the force that maintains her is 88.0 N, What is the girl's mass? Predictions On JOT 自 DLL Fa F11​

Answers

Answer:

the answer is M=29.6kg

Explanation:

your welcome:)

Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where low frequency sound is originating from. (a) Suppose a low-frequency sound source is placed to the right of a person, whose ears are approximately 18 cm apart, and the speed of sound generated is 340 m/s. How long is the interval between when the sound arrives at the right ear and the sound arrives at the left ear

Answers

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

[tex]\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}[/tex]

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

[tex]\Delta t = \frac{0.18\ m}{340\ m/s}[/tex]

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.10 m2 and whose thickness is 8 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 11 m2 and 0.15 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window

Answers

Answer:

the percentage of heat lost by the window is 93.18%

Explanation:

Given the data in the question;

Area of glass [tex]A_{glass[/tex] = 0.10 m²

Thickness of glass [tex]t_{glass[/tex] = 8 mm = 0.008 m

Area of Styrofoam [tex]A_{styrofoam[/tex] = 11 m²

Thickness of Styrofoam [tex]t_{styrofoam[/tex] = 0.15 m

we know that;

Thermal conductivity of glass [tex]k_{glass[/tex] =  0.80 J/smC°

Thermal conductivity of Styrofoam  [tex]k_{styrofoam[/tex] =  0.010 J/smC°

Now, temperature difference between outside and inside the walls and window is ΔT

So, In time t, heat lost due to conduction in the window will be;

[tex]Q_{glass[/tex] = [[tex]k_{glass[/tex] × [tex]A_{glass[/tex]  × ΔTt] / [tex]t_{glass[/tex]

we substitute

[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008

[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008  

[tex]Q_{glass[/tex] = 10(ΔT)t J

Also, the heat lost due to conduction in the wall be;

[tex]Q_{styrofoam[/tex] =  [[tex]k_{styrofoam[/tex] × [tex]A_{styrofoam[/tex] × ΔTt] / [tex]t_{styrofoam[/tex]

we substitute

[tex]Q_{styrofoam[/tex] =  [ 0.010 × 11 × ΔTt] / 0.15

[tex]Q_{styrofoam[/tex] =  0.7333(ΔT)t J

Now, Net heat lost in the wall and window is;

Q = [tex]Q_{glass[/tex] + [tex]Q_{styrofoam[/tex]

Q = 10(ΔT)t J + 0.7333(ΔT)t J

Q = 10.7333(ΔT)t J

So, the percentage of heat lost by the windows will be;

% of heat lost = [tex]Q_{glass[/tex] / Q

= 10(ΔT)t J / 10.7333(ΔT)t J

= 0.93167

= ( 0.93167 × 100 )%

= 93.18%

Therefore, the percentage of heat lost by the window is 93.18%

A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant force of magnitude 38.0 N in the same direction as the ball's motion. Over what distance must her foot be in contact with the ball to increase the ball's speed to 6.00m/s?

Answers

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

Thus, the distance is 0.187 m

What is the length of a string with a mass of 2.5 kg, with a
tension of 20 N, if the speed of wave on the string is 2 m/s?
a 0.8 m
b 0.4 m
C 0.5 m
d 1.0 m
e 0.1 m

Answers

B 0.4 m should be correct if not it is A

P Flag question
Matt, shown below, is able to move
the large truck because

Answers

Answer:

he has more pushing force than the truck there for pushing it forword.

Explanation:

What happens when sulfur reacts with potassium?
O A. Electrons move from the sulfur atoms to the potassium atoms.
B. Electrons become delocalized among the atoms.
O C. Electrons are shared between the potassium atoms and the sulfur
atoms.
O D. Electrons move from the potassium atoms to the sulfur atoms.

Answers

Answer: Electrons move from the potassium atoms to the sulfur atoms.

Explanation:  2 K + S ⇒ 2 K^+ + S^2-   . Usually metals donor electrons to non-metals

The plank you are going to walk has a length of 8.76 m and a mass of 16.35 kg. The plank is not bolted down but is to be placed so that 3.17 m of the plank are actually in contact with the boat. The rest of the board overhangs the jelly fish infested waters. You have a mass of 60.3 kg. What is the minimum mass you must put on the end of the board that is still on the ship so that you can successfully walk to the end of the plank without have the board rotate you into the water

Answers

Answer:

Explanation:

The center of gravity  will act at the middle point that is at 4.38 m from the end of the plank that is on boat . 16.35 x 9.8 N will act at this point .

The plank will turn around a point at 3.17 m from the end of plank that is on boat .

Suppose the weight required be W . It will be placed at the end of the plank that is on boat . The position of man is on the extreme end of the plank that is over water . So its distance from turning point will be 8.76 - 3.17 = 5.59 m .

Taking torque about turning point of all the forces like , weight of plank , weight of the person walking and force due to W

W   x 3.17 =  16.35 x ( 4.38 - 3.17 ) + 60.3 x ( 8.76 - 3.17 )

W   x 3.17 =  19.78  + 337.07 = 356.85

W = 112.57 kg .

Please help!!!!!! Motion and Forces​

Answers

157.5J
KE=1/2 mv^2
KE= 1/2(35kg)(3m/s)^2
KE=(17.5kg)(9m^2/s^2)
KE= 157.5J

P Flag question
Matt, shown below, is able to move
the large truck because

Answers

Can we please get the picture

180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?

Answers

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

What is the answer to question 4

Answers

In order to make it all the way from the opening to the detector, a wave has to travel through air, glass, water, plastic, and vacuum.

-- The siren and the tuning fork are sounds.

-- Sound cannot travel through vacuum.

-- That knocks out choices B, C, and D.

The answer is A.

Note:  Making a big exception here.  We don't do test questions on Brainly. That would be cheating. Don't let me catch you doing it again.

What is the light speed formula?

Answers

If ' c ' is the speed of light, then the formula for it is . . .

c = 299,792,458 meters per second

Please help I’ll mark you brainliest

Answers

Answer:

Percentage:

Rr = 50% because it's 2/4 (for both or 25% each since you have them separate)

rr = also 50%, because it's also 2/4.

Phenotype:

Rr = heterozygous

rr = "hozygous" recessive

In addition, RR is "hozygous" dominant

Explanation:

They said the hozygous is a swearword LOL.

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The 2020 accounting records of Novak Corp. reveal these transactions and events.Payment of interest $10,000 Collection of accounts receivable $190,100 Cash sales 50,800 Payment of salaries and wages 57,100 Receipt of dividend revenue 18,800 Depreciation expense 16,300 Payment of income taxes 16,900 Proceeds from sale of vehicles 12,100 Net income 38,400 Purchase of equipment for cash 22,800 Payment of accounts payable Loss on sale of vehicles 2,900 for merchandise 115,600 Payment of dividends 14,200 Payment for land 73,300 Payment of operating expenses 28,300 Required:Prepare the cash flows from operating activities section using the direct method. Greta has $6 in a savings account. The interest rate is 5%, compounded annually.To the nearest cent, how much interest will she earn in 2 years? I have a question When dose season 2 of owl house come out hey ill give brainliest please help True or False: Charles Wallace suggests that Calvin and Meg turn to IT if they are in the need ofa father.True False What are the characteristics of a good leader ? Why do you think those traits or characteristics are important? How did FW de Klerk influence democratic reforms in South Africa Patricia owns a dog. The dog shows signs of Inflamed skin, itching, and hair loss. Her veterinarian tells her that her dog has a noninfectiousdisorder. 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