The initial velocity of the projectile, Vo is 25√5 m/s.
What is initial velocity?
initial velocity is the velocity at time interval t=0 and it's representative as u.
It is velocity which the motion start.
Sol-as per the question
Sx=400 Vx=Vo cos 37°=4/5Vo
Sy= -100 Vy=Vo sin 37° 3/5Vo ay=-10 m/s^2
Let the time of flight be t
Sx=u^xt +1/2axt^2
=>400= 4/5Vot----------(eq1)
Sy=uyt +1/2 ay t^2
=>-100=3/5 Vot -5t^2-----(eq2)
By solving this we are get-
Vo=25√5 m/s
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WHAT IS THE ANSWER
IS IT A OR C AND PLS EXPLAIN WHY
Answer:
the answer is the options c
the coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834.
The greatest static resistance between the upper and lower block is f1max = f 1max = s m 1g = 0.6×2×10 = 12N.
According to Newton's second law of motion, an object's net force must equal the sum of its mass and the acceleration it experiences. In the direction of the net force is where acceleration is moving.
The force of action and reaction between two bodies is equal in magnitude but opposite in direction, according to Newton's third law of motion. The highest frictional force that prevents slippage on a surface is known as the limiting friction force.
The highest static resistance between the lower block and the ground is
f2max
=μ s (m 1 +m 2 )g=0.6(2+2)10
=24N
Assumedly, both blocks move to the right at the same speed.
Consequently, (m 1 + m 2 )a = T- μk (m1 + m2)g
or 4a = T - 0.4(2+2)10
or a = T-16 / 4
for upper block, f1 = 2a = T - 16 / 2
For just sliding, f1 = f1max
or T - 16 / 2 = 12
or T - 16 = 24 => T = 40N
The complete question is:
You are lowering two boxes, one on top of the other, down the ramp by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 15.0 cm/s. The coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
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an ice cube of volume 15.0 cm3 and density 917 kg/m3 is placed in ethyl alcohol of density 811 kg/m3. what is the buoyant force on the ice? will it float?
a. mass is 917 V , b. Buoyant force = 917 Vg, c. Fь= 1000Vsub g d. Vsub=0.917 V e. Volume Vsub/V=0.764
A force called the buoyant force is generated when an object is submerged in a fluid. The pressure that the fluid is applying to the object is what creates the buoyant force. The pressure at the bottom of an item is always greater than the force at the top because pressure rises with depth, leading to the net upward force.
Whether the object sinks or floats, the buoyant force is still at work. The analysis is essentially the same for a submerged object as well, but let's focus on a floating object first.
Even if a related (more difficult) analysis yields the same conclusion for objects with amusing shapes, we'll also take into account a rectangular block. On each of the object's six sides, forces are applied.
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a worker is standing on a wet concrete floor, holding an electric drill having a metallic case. the metallic case is connected through the ground wire of a three-terminal power outlet to power-system ground. the resistance of the ground wire is rg. the resistance of the worker's body is rw
The resistance of the ground wire is Rg is mathematically given as Rg=0.025Ф
This is further explained below.
What is resistance?Take into account that the amount of electricity flowing through the worker's body does not surpass 0.1 mA.
The value of the earth's resistors should be extremely low in order to ensure that the greatest possible current is carried by the earth wire and, as a result, that the worker is not shocked.
Determine the highest possible value for R g s o.
[tex]$\begin{aligned}&0.1 \mathrm{~mA}=(2)\left(\frac{R_g}{R_g+500}\right) \\&\frac{R_g+500}{R_g}=20000 \\&R_g+500=20000 R_g \\&\begin{aligned}R_g &=\frac{500}{20000-1} \\&=0.025 \Omega\end{aligned}\end{aligned} \\\\ Rg=0.025Ф[/tex]
The current that flows through the worker is less than or equal to 0.1mA.
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CQ
A worker is standing on a wet concrete floor, holding an electric drill having a metallic case. The metallic case is connected through the ground wire of a three-terminal power outlet to the power-system ground. The resistance of the ground wire is Rg. The resistance of the worker's body is Rw = 500 ?. Due to faulty insulation in the drill, a current of 2 A flows into its metallic case. The circuit diagram for this situation is shown in the figure.Find the maximum value of Rgso that the current through the worker does not exceed 0.1 mA.
can someone please help im begging
Newton’s first law states that no force is required to maintain motion in a straight line at constant speed. If Newton’s first law is true, why must you continue to pedal a bicycle on a level surface to keep moving?
The reason for the continued pedaling of the bicycle is to be able to overcome the forces of resistance and friction.
What is the Newton first law?According to the Newton first law, an object would remain at rest or continue in a state of uniform motion unless is acted upon by an external force. The external force is thus the reason for motion.
We know that a bicycle moves along a straight line. If we are to follow what is said by the Newton's law then we would know that the bicycle should just continue to move once it has started moving. There would thus be no need for the bicycle to be pedaled since it s already moving along a straight line.
But we have to consider the fact that there is friction and air resistance that tends to prevent the motion of the bicycle along the straight line and this is why we must have to keep pedaling the bicycle.
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consider a mach 4 airflow at a pressure of 4 atm. we wish to slow this flow to subsonic speed through a system of shock waves with as small a loss in total pressure as possible.
The density of the gas remains constant and the flow of gas can be characterized by momentum and energy conservation if the speed of the object is substantially slower than the gas's speed of sound.
We must examine the impact of the gas's compressibility when the object's speed approaches that of sound. As the gas is compressed by the object, its local density changes.
Entropy is constant for compressible flows with little to no flow turning, and the flow process is reversible. The isentropic relations then provide the change in flow attributes. Constant entropy is the definition of entropy. However, the flow process becomes irreversible and the entropy rises when an object travels faster than the speed of sound and the flow area suddenly decreases. There are shock waves produced. Shock waves are incredibly small areas in a gas where the gas's properties change significantly.
The static pressure, temperature, and gas density all rise almost instantly across a shock wave. The total enthalpy and the total temperature remain constant because a shock wave doesn't produce any work and there isn't any heat addition.
The total pressure downstream of the shock is, however, always lower than the total pressure upstream of the shock since the flow is non-isentropic. A shock wave is associated with a drop of overall pressure. The slide displays the total pressure ratio. We cannot apply the standard (incompressible) form of Bernoulli's equation across the shock due to variations in total pressure. Over a shock wave, the flow's speed and Mach number both fall.
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in the olympiad of 708 b.c., some athletes competing in the standing long jump used handheld weights called halteres to lengthen their jumps. the weights were swung up in front just before liftoff and then swung down and thrown backward during the flight. suppose a modern 88 kg long jumper similarly uses two 6.00 kg halteres, throwing them horizontally to the rear at his maximum height such that their horizontal velocity is zero relative to the ground. let his liftoff velocity be v with arrow
His range would increase by 0.55m yards if he used the halteres. Therefore, using halteres results in a 0.55 m improvement in range.
A speed velocity of, 9.5, was heard. Before the hotter, I last four J. meters per second. finally at the peak of the puff. Okay. The long jumper went with the bank route. Okay. Helter is also present, so we do have the long jumper. A long jumper is currently in motion at the top. So let's talk about RE X. then assisted her. Moving to the rear roof, indeed. none m/s. Okay, in the frame of the ground.
Okay, So, we're curious to know if the long jumper had the conventional distance added. Okay, so in order to properly answer this topic, we must apply the conservation of momentum at the highest point in addition to the concepts from projectile motion.
Therefore, we have 9.5 I. Without the water, speed remains the same. Thus, we might conclude that this is the V. X. The U. I. is this. We can locate a moment of light, okay. Okay hence, multiplying by two and four. Yes, there were roughly 9.8, which is equivalent to your argument. It's 1/6. The range then became hotter without us having to do anything. Then, this is V. X. multiplied by T. I guess there are 25 aches. 0.816. Let's begin. 7.76. Because. Next, we'll locate a range and figure out how to use it.
Therefore, after a long leap, the time of flights for the for the speed duration of light 0.816 seconds remain. Okay. though 1/2 T. is large and in the. 9.5. He performs it again where T is the other half. So his range would increase by 0.55m.
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a circuit maintains a constant resistance. if the current in the circuit is doubled, what is the effect on the power dissipated by the circuit? a circuit maintains a constant resistance. if the current in the circuit is doubled, what is the effect on the power dissipated by the circuit? the power dissipated is reduced by a factor of 2. the power dissipated is doubled. the power dissipated is reduced by a factor of 4. the power dissipated remains constant. the power dissipated is quadrupled.
When the circuit's current doubles, the power lost in the circuit is given by, Beginning with "begin aligned" and ending with "end aligned," P =I 0 2 R =(2 I) 2 R =4 I 2 R. The power dissipated by the circuit is quadrupled if the current in the circuit is twice.
The idea of a resistance's power loss at constant voltage. The square of the potential across the resistor over its resistance, then, represents the power dissipated or the bubble that generated at constant volume at constant voltage. From this, we might conclude that power and resistance are inversely related.
Starting with "begin aligned" and continuing with "end aligned," P =I 0 2 R =(2 I) 2 R =4 I 2 R gives the power lost in the circuit when the circuit's current doubles. If the circuit's current is doubled, the power it dissipates is multiplied by four.
Now that we know this, we may write the original power P equals are over our buddies and the power BI prime over it. We can express the power P prime equals P times are greater than our prime from this. The resistance is prime is off by double the initial help in the problem now.
As a result, the power Well will decrease by a factor of 2, and the new power P prime will therefore be P over two.
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Why is using a car not a good reason to use as a reference point
A car not a good reason to use as a reference point because it is not a fixed object relative to earth.
What is a Reference point?This is referred to as a point which is used to describe or discover the location of an object. The types of objects which are used as a good reference point are those which are fixed relative to earth.
On the other hand, cars are not fixed relative to earth such as trees, land which is therefore the reason why car is a good reason not to be used as a reference point.
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a small sphere that carries a charge q is whirled in a circle at the end of an insulating string. the angular frequency of rotation is ????. what average current does this rotating charge represent? (use the following as necessary: ???? and q.)
Electric current is defined as the total flow of electric charge through a surface over a period of time. Despite not being a vector, electric current has a sense of direction connected with it.
Electric current flows in a direction that is parallel to the motion of the positive charge and transverse to the motion of the negative charge. Ampere is the S.I. unit of electric current (A).
Every revolution, the charged particle that is rotating around the circle passes by a single point on the circle. That is, a charge of Q passes by a point on the circle over the course of evolution, and since que is provided in the question, we can simply use que in the numerator.
We do not, however, know the precise time period because omega, a related quantity, is provided in the question; therefore, we will just relate to these two quantities. T is equal to two pi radiance over Omega Radiance per second since we know that the angular velocity is equal to the circumference of the circle divided by the time it takes for a revolution to occur.
Our expression for the present is therefore cute over T, which is to buy over Omega, which only comes out to good Q over two pi. There is also our typical electric current.
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a golf ball of mass 0.045 kg is hit off the tee at a speed of 37 m/s . the golf club was in contact with the ball for 3.90×10−3 s .find the impulse imparted to the golf ball.
Impulse = change in momentum = 0.045 * 36 = 1.62 kg m/sec and Average Force = Impulse / time = 1.62 / 3.9 x 10^-3 = 415.3 Newton
Impulse forces are those that have a relatively brief duration of action. The term "impulse" refers to the result of the impulsive force and the time at which it acts. I = F dt = dM is the formula for the impulse, which is the change in momentum brought on by the impulsive force.
The momentum of an object will change when a force acts for a predetermined period of time. In other words, an uneven force always accelerates an object, either by making it go faster or slower. When a force opposes an object's motion, the object slows down. When a force is applied in the same direction as an object's motion, the object is accelerated by the force. In either case, a force will alter an object's velocity.
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A student drops a ball and it falls downward. What types of energy are involved in this energy transformation? Two answers are correct
A student drops a ball and it falls downward. Types of energy are involved in this energy transformation are kinetic and gravity potential.
What is energy?Energy is defined as the capacity of a physical system to perform work.
Types of energy are Kinetic energy and potential energy.
The energy an object has as a result of motion is known as kinetic energy. Applying force to an object will cause it to accelerate.
Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement.
A student drops a ball and it falls downward then there is kinetic energy due to motion and potential energy due to height.
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A BASE jumper jumps from rest and is in free fall for 40.0 m, then he opens his parachute and slows down at a rate of 3.00 m/s². If he
reaches the ground with a speed of 4.00 m/s, how far did he fall in total?
All falling objects experience a downward acceleration equal to the force of gravity.
He jumps 155.96 meters from the ground.
What is free fall motion ?In free fall, an item is traveling only as a result of gravity. Wind and air resistance need to be disregarded for an object to fall freely. On Earth, all falling objects experience a downward acceleration equal to the force of gravity.A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.A BASE jumper jumps from rest and is in free fall for 40.0 m,
s= 1/2 g t^2
t^2 = 2* 40/9.2
t= 2.95s
v= at = 9.2 * 2.95 =26.68 m/s
u= 26.68 when he opens his parachute and slows down at a rate of 3.00 m/s².
v= 4m/s
2as = v^2 -u^2
s= (4^2 - 2.68^2)/2*9.2
s =115.96 m
total distance = 115.96+ 40 = 155.96 m
He jumps 155.96 meters from the ground.
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Help please I need help and explanation
Answer:
Choice d
0 acceleration and velocity of 6 m/s
Explanation:
The smart way to tackle questions like these is by POE or Process of Elimination.
We can easily eliminate choices a, b and c since velocity is definitely not 0
So choice (d)
If we look at the graph we see that between 6s and 8s the graph is flat at a velocity value of 6 m/s. So the answer should be velocity of 6 m/s and since there is no increase in velocity, the acceleration is also 0
However, this can also be proved mathematically
Acceleration = change in velocity/change in time
= Δv/Δt
Δv = 6 - 6 = 0
The velocity is 6 m/s at 8 seconds and also 6 m/s at 6 seconds
Δt = 8 - 6 =2
Acceleration = 0/2 = 0 m/s²
Hence choice d
At which part a of a river would you have the best luck
growing food??
Answer:
Delta !
Explanation:
how does the current through the bulb in a single-bulb circuit compare with the current through the same bulb when it is connected in series with a second bulb?
Because the single bulb has a greater current, it is brighter. Less current is used with the second bulb since the current is split equally between the two bulbs.
The voltage drop across each bulb is 6.0 V when the light bulbs are linked in parallel, and they all glow as the current passing through them combines to generate the current flowing through the battery. Each component in a series circuit needs to be operational for the circuit to be complete.
Energy from the battery is transferred to the circuit's components by an electric current. Nothing in this procedure "uses up" any current. Negatively charged electrons that are constantly present in the circuit's wires and other components make up the majority of the moving charged particles.
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What is the mass of an object a of 77.5 N?
Answer:
Explanation:
Given:
F = 77.5 N
g = 9.8 m/s²
__________
m- ?
m = F /g = 77.5 / 9.8 ≈ 7,9 kg
The graph depicts the temperature curves for two substances labeled as substance X and Y.
Why does the temperature remain constant as heat is added to each substance in the regions labeled A to B, C to D, and A' to B', and C' to D'?
Based on the curve for either substance X or substance Y and using what you know about the particulate nature of matter, and the relationship between temperature and potential or kinetic energy, describe why adding heat leads to the step-wise change in temperature depicted in the graphs.
The heat supplied to increase the temperature of the substance is used up to transform the state of matter of that substance. Hence the temperature of the substance stays constant until the phase transition completes.
What is the phase transition?In chemistry, phase transitions or phase changes are the physical processes of transition between a state of a medium of a substance. This term is used to refer to changes in the basic states of matter such as solid, liquid, and gas.
When a substance is heated or cooled and approaches a temperature corresponding to one of its phase transitions. Further gain or loss of heat results in diminishing or enhancing intermolecular attractions, instead of changing the molecular kinetic energies.
While a substance is undergoing a change in state which is a phase transition, its temperature remains constant. The horizontal lines on the graph represent the transition between the states of the substances X and substances Y.
When adding heat leads to the temperature of a substance being increased as the kinetic energy of the molecules of the substance increases. The conduction of heat occurs when these molecules start vibrating with high energy, Hence the heat transfer from one molecule to another.
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suppose you want to move the block, but you want to push it with the least horizontal force possible to get it moving. with what horizontal force f must you be pushing the block just before the block begins to move?
For the block to just start moving the horizontal force must equal the static friction.
F⇔ ↑N↓mg
N = mg
F = [tex]m_{s} n[/tex]
= [tex]m_{s} mg[/tex]
Frictional forces act parallel to the surface. The frictional force is the force that resists the movement of an object in contact with the surface and acts parallel to the surface with which the object is in contact. When one body moves relative to another, a constant force called friction force begins to act on the sliding surface in the opposite direction of the movement. A moving object has a constant frictional force.
The magnitude of static friction is equal to the magnitude of the applied force. The supporting force F must be greater than the frictional force. The underlying object that requires less force to move is the pencil. Friction: Friction is defined as the force that opposes the motion of objects on contacting surfaces. On the other hand, if you move a large object, it becomes difficult for friction to work.
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Two airplanes leave an airport at the same time. The velocity of the first airplane is 740 m/h at a heading of 42.8°. The velocity of the second is 580 m/h at a heading of 114°.
How far apart are they after 1.6 h? Answer in units of m.
Question 2 of 6
Read the problem below and find the solution. Draw a diagram on your own
paper to help solve it.
If your teacher tells you to do questions 28 through 41 in your math book for
homework, how many questions is that?
(Do not include units in your answer.)
Answer here 14
If your teacher tells you to do questions 28 through 41 in your math book for homework, 14 questions are required, and this can be found out through general mathematical concepts such as addition and subtraction.
What are the general mathematical concepts?The general mathematical concepts can be said as the basic concepts or formulas that are taught to everybody. these include the concepts such as Addition, Subtraction, Multiplication and Division.
These are the base formulated concepts basing upon which the whole lot of other generalized equations and formulas are set up.
As per the question, we see that your teacher tells you to do questions a total of 28 through 41 in your math book for homework. Thus, we are then asked to find out the total number of questions.
Since we need to solve a total of questions 28 through 41, this means we have to solve question number 28 and 41 as well.
We already know that 28-37 would be 10 questions and then further 38-41 would be about 4 questions.
So, the total questions required = 10 +4
Total questions = 14
Thus, you just need to solve 14 questions in total to complete the homework.
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observing a spacecraft land on a distant asteroid, scientists notice that the craft is falling at a rate of 5 m/s. when it is 100 m closer to the surface of the asteroid, the craft reports a velocity of 8 m/s. according to their data, what is the approximate gravitational acceleration on this asteroid?
The gravitational acceleration on the asteroid is 0.195 m/s².
Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.
From the question above, we know that
h = 100 m
vo = 5 m/s
vt = 8 m/s
By substituting the given parameters, we get
vt² = vo² + 2a . s
vt² = vo² + 2g . h
8² = 5² + 2.g . 100
64 = 25 + 200g
g = 0.195 m/s²
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What makes a method accurate or inaccurate?
Answer:
Accuracy is how far off a measurement is from its true value. A measured value that's far from a true value is inaccurate, while a measure that is close to a true value is accurate.
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You’ve searched an area for fingerprints but haven’t found any in your initial visual examination of an area. If you are still curious if there are fingerprints, what would you need to start looking for?
The kind of finger print that could be used in this case is the latent finger print.
What are finger prints?The term finger print refers to a unique pattern that could be obtained from the fingers of an individual. The use of the finger prints have been very helpful in the science of forensics as many complex crimes have been solved by the use of this method.
The latent finger prints are the kind of finger prints that are not readily visible thus they could be used when we are dealing with very tough crimes.
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Missing parts;
You’ve searched an area for fingerprints but haven’t found any in your initial visual examination of an area. If you are still curious if there are fingerprints, what would you need to start looking for?
Plastic fingerprints
Latent fingerprints
Visible fingerprints
Abbil fingerprints
A mechanic uses a hydraulic car jack to lift the front end of a car to change the oil. The jack used exerts 8000 N of force from the larger piston. To pump the jack, 4000 N of force is exerted on the small piston, which has an area of 2 m2 . What is the area of the large piston?
Answer:
Hope the picture will help you
Can someone help me with this please
Explanation:
I think it's the last option
A pitcher throws a fastball horizontally toward home plate 18.39 meters away. If the ball is traveling at a speed of 40.0 m/s when it leaves his hand, what is the ball's acceleration if it takes 0.500s to reach home plate?
A -6.44 m/s2
B -12.9 m/s2
C 6.44 m/s2
D 12.9 m/s2
The ball's acceleration if it takes 0.500s to reach home -12.9 ms⁻².
The problem we are dealing with is related to acceleration, which is the rate of change of the velocity, Since speed could be a speed and a direction, there are as it were two ways for you to accelerate: alter your direction or change your speed—or alter both. We are given the distance of the home plate 18.39 meters, traveling with the initial velocity of 40.0 ms⁻¹ and the time taken to reach the home plate 0.500s.
Since referring to the equation of motion:
s=ut+1/2at^2
=>a=2(s-ut)/t^2
= 2(18.39-(40*0.500)/(0.500^2)
=-12.88
= -12.9 ms⁻²
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A stone hangs by a fine thread from the ceiling, and a section of the same thread dangles from the bottom of the stone. If a person gives a sharp pull on the dangling thread, where is the thread likely to break: below the stone or above it? What if the person gives a slow and steady pull? Explain your answers.
Answer: the tension in the upper string will be larger than the tension in the lower string because of the weight of the stone. So, the upper string will break first.
Explaination:
Step 1. Newton’s second law
According to Newton’s second law, the value of the force can be obtained by examining the value of the object’s acceleration and the mass. Its value is altered linearly to the value of the object’s acceleration.
Step 2. Draw a free-body diagram
Here, is the tension force in the string, is the mass of the object, is the gravitational force, and is the applied force.
Step 3. Application of Newton’s second law
When given a sharp pull, there is a sudden application of force. When a large, sudden force is applied to the bottom of the string, the bottom string will have a large tension. Because of the stone's inertia, the upper string does not experience this large force, and therefore, the bottom string breaks.
If a slow and steady pull is applied, the tension in the bottom string increases. The stone is in equilibrium until the string breaks.
The block will be in equilibrium as long as T = F + mg
Thus, the tension in the upper string will be larger than the tension in the lower string because of the weight of the stone. So, the upper string will break first.
If an object has a mass of 85g and a volume 92cm^3
The density of the object mentioned in the question when mass and volume are given is 0.924 g[tex]/cm^{3}[/tex]
According to the problem we have the following data given,
The mass of object m= 85g
The volume of object V= 92[tex]cm^{3}[/tex]
To find the density of the object we use the formula [tex]density=\frac{mass}{volume}=\frac{m}{V}[/tex]
∴density ρ [tex]=\frac{m}{V}=\frac{85}{92}=0.924g/cm^{3}[/tex]
Thus the density of the object = 0.924 g/[tex]cm^{3}[/tex]
Your question was not complete but most probably the question was if an object of mass 85g and volume 92cm^3 is given, what is its density?
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an 800 n crate is pulled up a 4m long ramp. the high end of the ramp is elevated 2 m above the ground. it takes 3200 j of work to pull the crate to the top of the ramp. find the magnitude of the friction acting on the crate.
400N magnitude of the friction acting on the crate.
work done by gravity
[tex][w=mg sin \theta \cdotS],[w=mgh=],[w=800 \cdot2=w=1600][/tex]
Then was done by friction external work - wask done by gravity
[tex][f_S \cdot S=3200-1600],[f_S \cdot4=1600],[f_S=400 N][/tex]
Thus the crate is not moving with constant speed then we can say that the value of friction Force is less then 400 N
So Friction Force is not zero but less then the 400N
The resistance present at the contact surface at the point of contact when two or more objects move over one another can be referred to as friction force. The direction of friction force is always perpendicular to the object's motion.
The amount of friction is influenced by the surface's roughness and outside pressures. The force of friction works more strongly on a surface the rougher it is. The same is true of outside factors.
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