a proton follows the path shown in (figure 1). its initial speed is v0 = 2.6×106 m/s.

Answers

Answer 1

The speed of the proton at point P is determined as 2.67 x 10⁶ m/s.

The speed of the proton at point P is determined by applying the principle of conservation of energy as shown below.

Total energy of the proton at the initial position = total energy of the proton at the final position

Ui + K.Ei = Uf + K.Ef

where;

U is potential energy

K.E is the kinetic energy

= kq₁q₂/r₁  +  ¹/₂mv₁² = kq₁q₂/r₂  +  ¹/₂mv₂²

= kq₁q₂/r₁  +  ¹/₂mv₁² - kq₁q₂/r₂ = ¹/₂mv₂²

= kq₁q₂(1/r₁  - 1/r₂)  + ¹/₂mv₁² = ¹/₂mv₂²

= ¹/₂mv₂²  = kq₁q₂ (1/r₁  - 1/r₂)  + ¹/₂mv₁²

= v₂² = 2/m [kq₁q₂ (1/r₁  - 1/r₂)  + ¹/₂mv₁² ]

where;

m is mass of the proton

k is coulomb's constant

q₁ is the magnitude of the charge

q₂ is charge of proton

r₁ is the initial position of the proton

r₂ is the final position of the proton = 5 mm (from Pythagoras theorem)

= v₂² = 2/(1.67 x 10⁻²⁷) [9 x 10⁹ x 10 x 10⁻⁹ x 1.6 x 10⁻¹⁹ (1/0.003  - 1/0.005)  + ¹/₂(1.67 x 10⁻²⁷)(2.2 x 10⁶)² ]

= v₂² = 7.14 x 10¹²

= v₂ = √ (1.44 x 10²³)

= v₂ = 2.67 x 10⁶ m/s

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The complete question is below:

a proton follows the path shown in (figure 1). its initial speed is v0 = 2.2×106 m/s. find the speed of the proton at point P?


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The light emitted by hydrogen atoms appears red because the most intense line in its spectrum, at 656 nm, is in the red section of the visible spectrum.

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Answer:

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a man seeking to set a world record wants to tow a 118,000-kg airplane along a runway by pulling horizontally on a cable attached to the airplane. the mass of the man is 93 kg, and the coefficient of static friction between his shoes and the runway is 0.79. what is the greatest acceleration the man can give the airplane? assume that the airplane is on wheels that turn without any frictional resistance.

Answers

The greatest acceleration the man can give the airplane is 6.102*10^-3 m/s^2

What is a frictional force ?

The force produced when two surfaces slide past one another and make contact is known as frictional force. The surface texture of these forces and the amount of force pressing them together have the biggest impact.

Mass of the person

m1 = 93kg

Mass of the air plane

m2 = 118000 kg

Coefficient of static friction between the shoes of the person and floor

μs=0.79

Acceleration due to gravity

g=9.8m/s^2

The maximum force the person can apply on the floor is equal to his weight

F = w = m1∗g

         = 93∗9.8=911.4 N

The maximum frictional force he can get from the floor is the product of coefficient of static friction and normal reaction

Ff = μs∗N

   = μs∗W

   = 0.79 ∗ 911.4 = 720 N

Let's assume that the individual is able to use or apply the entire frictional force in pushing the airplane.

Following that, the relationship can be used to determine the acceleration an air plane created.

Ff = m2 * a

a = Ff/m2

  = 720/118000

  = 6.102*10^-3 m/s^2

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in the double-slit experiment with electrons, suppose that the observer uses a detector to determine through which slit the electron actually passes. does this affect the outcome of the experiment, and why or why not?

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Answers

Answer:

Driver 1

Explanation:

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the equivalent capacitance is a. 9 μf b. 6 μf c. 3 μf d. 2 μf e. 1 μf

Answers

The equivalent capacitance is  21 μF.

In electrical engineering, equivalent capacitance often abbreviated as C eq—is a measurement of the total combined electric charge held in two or more capacitors connected in series or parallel. A capacitor is an electrical device that stores electrical energy into the electric field. Typically, a capacitor has two electrical leads that are separated by a dielectric or other insulating substance.

We are given that,

capacitance =c₁ =9  μF

capacitance = c₂ =6  μF

capacitance = c₃ = 3  μF

capacitance = c₄ =2  μF

capacitance = c₅ = 1  μF

Thus If the capacitor is connected in parallel the equivalent capacitance, cₐ can be calculated by the equation,

cₐ= c₁+c₂+c₃+c₄+c₅

cₐ = 9 +6 +3 +2+1 μF

cₐ = 21 μF

Therefore , The equivalent capacitance would be  21 μF.

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a 3 * 10 to the power -3 kg copper penny drops a distance of 50 m to the ground. if 65 percent of the initial potentia energy goes into increasing the internal energy of the penny, determine the megnitude of that increase.

can some genius explain this to me please?

Answers

Explanation:

The magnitude of the increase is 0.9555J

Explanation

Potential Energy (PE) = mgh mass(m) = 3 * 10 ^ - 3 * kg

, acceleration due to gravity (g) = 9.8m / (s ^ 2) distance(h) = 50m PE = 3 * 10 ^ - 3 * 9.8 * 50 = 1.47J Increase in internal energy = 65% of 1.47J = 0.65 × 1.47J

= 0.9555J

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the plate area of a parallel-plate capacitor of capacitance c is doubled and the distance between the plates is halved, so that the volume of the dielectric remains the same. the new capacitance of the capacitor is

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The new capacitance of the capacitor is Cf = 4Ci is the correct answer.

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Using the Capacitance theorem

Given:

Capacitance of Parallel Plate Capacitor = C

Area = 2A

Distance = 1/2d

Volume of the dielectric remains the same.

New Capacitance =?

1.  Initial Capacitance can be written as:

Ci = A ∈0 / d

2.  After putting the desired values of area and distance.

Cf = 2A ∈0 / (d/2)

Cf = 4A ∈0 / d

Cf = 4Ci

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What type of metamorphosis do hive beetles undergo?a. completeb. incompletec. mesocomplete

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When you are playing pool and a moving ball hits a stationary ball and the moving ball stops what happens to the momentum of the moving ball?

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When a moving pool ball hits a stationary ball, some kinetic energy from the moving pool ball is transferred to the stationary ball and it attains momentum.

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               mₐ₁× vₐ₁ = mₐ₂×vₐ₂ + m₂ v₂

                 

                     mₐ₁× vₐ₁ is the momentum of ball A before the collision

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                     m₂ v₂    is the momentum of ball B after  collision.

So the stationary ball begins to move after the collision due to increased kinetic energy and attains some momentum. The total momentum of the system remains the same.

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Answer:

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A ball of mass M is on a horizontal surface with negligible friction. One end of a string is attached to the ball so that it is spun in a horizontal circle of radius R at a tangential speed vo, as shown in Figure 1. A free-body diagram for the ball at an instant in time is shown in Figure 2. The magnitude of the tension force is also indicated in Figure 2. Which of the following equations represents the centripetal acceleration of the ball if its tangential speed is increased to 2vo ?

Answers

The centripetal acceleration of the ball if its tangential speed is increased to 2 v₀ is (4 M v₀²)/R.

The centripetal force equation that we are aware of is

F = (m* v²)/r ----(1)

where,

m is the of the ball

v is the velocity

r is the radius

We are aware that F = m* a ----(2)

Equating (1) and (2), we have,

m* a = (m* v²)/r

a = v²/r -----(3)

where, a is centripetal acceleration

In this problem, it is said that, the tangential speed is increased to 2 v₀, then the centripetal acceleration

So, v = 2 v₀, r = R

Substituting the values in (3), we have,

ac = (2 v₀)²/R = 4 v₀²/R

Thus, the required centripetal acceleration is 4 v₀²/R.

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Classify the measurements as having English units or metric units. English units Metric units Answer Bank 2.50 lb 2. 20 kg 335 ml. 33.21 oz 12.2 26.9 mm Now, classify the units of the measurements as units of length, mass or volume.

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It will decompose to 1/100 of its initial mass in 53.4 days.

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The deterioration rate is expressed as a percentage. The decimal equivalent can be obtained by simply reducing the percentage and multiplying it by 100. Therefore, it is possible to determine the decay factor b = 1-r. For instance, the exponential function's decay rate is 25% if the rate of decay is 0.25 and b = 1- 0.25 = 0.75 for the decay factor.

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What is the line segment formula?

Answers

Formula of

Line segment

is AB =

[tex]\sqrt{(x_{2} -x_{1} )^{2} } +\sqrt{(y_{2} -y_{1} )^{2} }[/tex]

                                                                             

Line segment

is a part of line with definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

.

            A ______________________ B    

        (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as [tex]\frac{}{AB} /\frac{}{BA}[/tex]. In other word we can say line segment is

subset

of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by

ruler

. A bar (-) is always on top of its notation {[tex]\frac{}{AB}[/tex]}.

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Line segment

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Formula of Line segment is AB =  [tex]\sqrt{(x_{2}-x_{1})^{2} } +\sqrt{(y_{2}-y_{1})^{2} }[/tex]

                                       

Line segment

is a part of line with a definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

        A ______________________ B    

       (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as[tex]\overline{AB}/\overline{BA}[/tex] . In other word we can say line segment is subset of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by ruler A bar (-) is always on top of its notation {[tex]\overline{AB}/\overline{BA}[/tex]}.

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What is the approximate wavelength range of thermal radiation Mcq?

Answers

Thermal radiation has a wavelength range of 7700A to 4106A.A emission if electromagnetic waves by all stuff with a temperature greater that absolute zero is known as thermal radiation.

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Thermal electromagnetic radiation is radiation with wavelengths between 0.1 and 100 m that is emitted by all matter that is not at absolute zero.All of the infrared and visible spectrums, as well as some ultraviolet (UV), are included (IR).

What is the heat source's radiative energy's approximate wavelength?

Thermal radiation, or radiation heat transfer, is defined as radiation having wavelengths between 0.1 and 100 m.The entire visible, infrared, and some ultraviolet spectrums are all included in thermal radiation.

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Problem 5: Consider the circuit diagram depicted in the figure 0.5 Ω R2 2.5 Ω /2 R 1.5Ω 0.5 Ω 50% Part (a) what equation do you get when you apply the loop rule to the loop abcdergha, in terms of the variables in the figure? Grade= 100% Correct Answer Student Final Submission Feedback Correct! 012 R2+ 112 T3 R3 +32-62 0- 1-(Ti +R2) I2+(R3r2)13 2 Grade Summary Deduction for Final Submissi Deductions for Incorrect Submissions, Hints and Feedback [?] Student Grade-100-0-0-100% 0% 0% on Submission History All Date times are displayed in Central Standard Time Red submission date times indicate late work. Date Time 9:25 PM Answer Hints Feedback 1 Oct 29,2018 0- 1-(Ti +R2) I2+(R3r2)13 2 50% Part (b) If the current through the top branch is 12-0.505 A, what is the current through the bottom, 13, in amps?

Answers

Part(a) The equation for the loop is 0 −1−(R1 +R2)I2+(R3+R2)I3=0

Part(b) The current through the bottom branch 13 is 0.75 A.

(a) This equation is found by applying the loop rule, which states that the sum of voltage drops around a loop is equal to zero. To find the equation, we start at the point, and move clockwise around the loop. At each point, we add the voltage drop of the component connected between that point and the previous point. We then substitute the component values into the equation.

For example, the voltage drop across R1 is equal to I2 * R1. In this equation, I2 and I3 are the currents through R2 and R3 respectively.

(b) To calculate this, we need to use Ohm's Law, which states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance.

First, we need to calculate the total resistance of the circuit.

       R total = R_1 + (1/2)*R_2 + R_3

                    = 0.5 + (1/2)*2.5 + 0.5

                    = 2.5 Ω

Now, we can use Ohm's Law to calculate the current through the bottom branch.

             I 13 = V/R

                     = (12-0.5)/2.5

                     = 0.75 A

Therefore, the current through the bottom branch 13 is 0.75 A.

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1. How did the rock of the Great Plains and Rocky Mountains form?Choose the claim you can eliminate. ResponsesThey formed as one rock formation, and then something separated them.They formed as one rock formation, and then something separated them.One rock formation formed before the other. Then, the minerals from the older rock became part of the younger rock.One rock formation formed before the other. Then, the minerals from the older rock became part of the younger rock.3What do we still need to know in order to determine why the two rock formations have such similar minerals?Evidence Card E: Rocky Mountains. Photo of the Rocky Mountains. Observations: The large mountains have jagged tops. The chunks of rock vary in size. The rock appears to be light and dark gray. There is a forest at base of the mountains.Evidence Card C: Rock from the Rocky Mountains. Photo of a rose-colored rock with dark veins. Observations: The rock contains visible pink, dark gray, and light brown grains. The grains fit together. The grains have sharp edges. There are no bubbles or fossils in this sample.2Why can we eliminate the claim you selected?

Answers

Rocky Mountains and Great Plains rock came together to form one rock formation, but then something tore it apart. The first claim is true while the second claim needs to be eliminated

What are rocky mountains?

It should be remembered that the Rocky Mountains and the Great Plains are two separate rock formations that did not form simultaneously. The older rock's minerals were not incorporated into the younger rock as a result.

After combining the rock from the Rocky Mountains and the Great Plains to form one formation, something tore it apart. As a result, the second claim must be rejected because it is false.

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