A school allots £1500 to spend on a trip to the theatre.
Theatre tickets have a regular cost of £25 each and are on offer for 1/5 off.
A train ticket for the day will cost £15 each.
If 2 teachers and the maximum number of students attend, how many students go on the trip?

Answers

Answer 1

Answer:

40 students

Step-by-step explanation:

If the tickets are 1/5 that means they cost 4/5

25 * 4/5 = 20

The tickets cost 20 and the train costs 15 so the total per person is 35

Teachers: 2 at 35 = 70

1500 -70 = 1430

Take 1430 / 35 =40.85714286

We can send 40 students

Answer 2

Answer:

40

Step-by-step explanation:

since the school allots £1500 to spend on a trip to the theatre.  Theatre tickets have a regular cost of £35 each and are on offer for 1/5 off

therefore 4/5*35 = 28 for the tickets

:

A train ticket for the day will cost £15 each.

therefore total cost for each: 28 + 15 = 43 pounds each

:

If 2 teachers and the maximum number of students attend, how much money will the school have left over?

:

let s = no. of students

43(s+2) =< 1500

43s + 86 =< 1500

43s =< 1500 - 86

43s =< 1414

s =< 1414/43

s =< 32.88, 32 students max

:

find how much left over. plus 2 teachers = 34 people

1500 - 43(34) =

1500 - 1462 = 38 pounds left over


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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

Answer:

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Answers

Answer: you can use show the multiples of 5 and 8

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Over the course of the past 4 months, Victor’s family spent a total of $360 on their satellite television bill. Based on this rate, how much does their satellite service cost in a year?

Answers

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Answers

A for sure because it can be

Rational numbers are terminating or repeating numbers. Therefore, option C is the correct answer.

We need to check from the options which expression best defines a rational number.

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Rational numbers: Rational numbers are in the form of p/q, where p and q can be any integer and q ≠ 0. This means that rational numbers include natural numbers, whole numbers, integers, fractions of integers, and decimals (terminating decimals and recurring decimals).

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answer:

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Answer:

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Step-by-step explanation:

Answer:

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Answer:

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Answer:

Concept: Graph Analysis

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Step-by-step explanation:

Problem 1.

Start at (0, -2). Go up 5 and right 2. That is a slope of 5/2.

First choice.

Problem 2.

The y-intercept is (0, -2), so b = -2.

Start at (0, -2). Go down 5 and right 2. That is a slope of -5/2.

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Answer:

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Step-by-step explanation:

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

Answer:

add 2536 to how many tickets you have left.

Step-by-step explanation:

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Answers

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Answer:

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Question options:

Answers

Answer: The last line is the answer

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New inequality: x > -2

Step-by-step explanation:

The correct option is d. The solution to the linear  inequality 12 - 4x ≤ 20 is x ≥ -2 by solving the inequality.

To solve this inequality,  to isolate the variable x.

Step 1

subtract 12 from both sides of the inequality:

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Step 2 :

Divide both sides of the inequality by -4. However, when  divide by a negative number, the direction of the inequality sign must be flipped. So   x ≥ -2, indicating that x is greater than or equal to -2.

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Answers

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Step-by-step explanation:

Answer:

1. D 1/5 divided by 950.

Step-by-step explanation:

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Answers

Answer:

120

Step-by-step explanation:

The answer 140° you just have to subtract the given measure from 180° hope this helps :)

WILL MARK BRAINLIEST!!
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Answers

Answer:

75%

Step-by-step explanation:

Answer:

43%

Step-by-step explanation:

if the answer to a system of equations is x = 4 y = 0, if you were to graph the solution at what point(X,Y) would you expect to see the two lines intersecting. Explain your answer.

Answers

Answer:

Step-by-step explanation:

We can find the solution to a system of equations by graphing the equations. Let's do this with the following systems of equations:

\goldD{y=\dfrac{1}{2}x+3}y=  

2

1

​  

x+3start color #e07d10, y, equals, start fraction, 1, divided by, 2, end fraction, x, plus, 3, end color #e07d10

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First, let's graph the first equation \goldD{y=\dfrac{1}{2}x+3}y=  

2

1

​  

x+3start color #e07d10, y, equals, start fraction, 1, divided by, 2, end fraction, x, plus, 3, end color #e07d10. Notice that the equation is already in yyy-intercept form so we can graph it by starting at the yyy-intercept of 333, and then going up 111 and to the right 222 from there.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Next, let's graph the second equation \greenE{y=x+1}y=x+1start color #0d923f, y, equals, x, plus, 1, end color #0d923f as well.

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