. A scientist placed a sample of lithium into a container of water. The scientist observed the lithium floating and making a buzzing sound as gas bubbles were forming around it. Which conclusion is BEST supported by this observation

5) B

6) C

7) B newland, law of octaves

8) A)

Answer:

CH2O and C6H12O6

Explanation:

To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.

Answer:

It is a halogen element

Explanation:

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An alpha particle emission causes the atomic number of a nuclide to decrease by 2 and its mass number to decrease by 4.

Nuclear Emission explains the release of energy stored in the nucleus of an atom in the form of particles like alpha particles, beta particles, gamma ray etc.

When a nucleus emits an alpha particle, it loses 2 protons and 2 neutrons, so its atomic number decreases by 2 and its mass number decreases by 4.

Hence, option 1 is correct.

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Answer:

HNO3

Explanation:

i have the test

Therefore, decrease in PH can be achieved by adding acidic substance.

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Answer:

No because it's located inside the nucleus of the atom

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Explanation:

Answer:

The final volume is 6.4 L.

Explanation:

Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

In this case:

Replacing:

8 M* 2 L= 2.5 M* Vf

Solving:

[tex]Vf=\frac{8 M* 2 L}{2.5 M}[/tex]

Vf=6.4 L

The final volume is 6.4 L.

Answer:

10.35= 4 sig figs but change it to 2 since it's 2.3 is the lowest number

10.

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Explanation:

Explanation:

moles= number of particle or atom / 6.02×10^23

so

[tex] \frac{1.1 \times {10}^{20 } }{6.02 \times {10}^{23} } [/tex]

gives u 1.83×10^-4 moles

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Answer:

1.7 * 10^-4 moles

Explanation:

According to Avogadro, one mole of a substance contains 6.02 * 10^23 number of atoms, molecules, ions etc.

Hence;

1 mole of Na contains 6.02 * 10^23 atoms

x moles of Na contains  1.0x10^20 atoms

x = 1.0x10^20 * 1/6.02 * 10^23

x = 1.7 * 10^-4 moles

Answer: There are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole of every substance.

Hence, moles present in [tex]9.12 \times 10^{23}[/tex] atoms are calculated as follows.

[tex]Moles = \frac{9.12 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.51 mol[/tex]

Thus, we can conclude that there are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

Answer:

The required volume is 0.84 L

Explanation:

Given,

Mass of O2 gas = 1.20 g

We know,

At STP, molar volume of all gases is 22.4 L

and Molar mass of O2 gas is 32 g

Now,

Number of moles = mass/molar mass

                              = 1.20/32

                              = 0.0375

Again,

At STP,

Number of moles = Volume/Molar volume

or, Volume = Number of moles X Molar Volume

or Volume = 0.0375 X 22.4

∴ Volume = 0.84 L

So, the required volume is 0.84 L

Answer:

I did it in steps in the picture I just hope it helps you to understand:)

Answer:

0.603J/g°C is the specific heat of the metal object

Explanation:

To solve this question we must know the heat given by the metal is equal to the heat absorbed by the water. The change in heat follows the equation:

Q = m*S*ΔT

Where Q is heat in Joules, m is the mass of the substance, S its specific heat and ΔT change in temperature

The equation to solve the problem is:

m(Object)*S(Object)*ΔT(Object) = m(Water)*S(Water)*ΔT(Water)

Where:

m(Object) = 29.0g

S(Object) = ??

ΔT(Object) = (97.0°C - 23.7°C = 73.3°C)

m(Water) = 95.8g

S(Water) = 4.184J/g°C

ΔT(Water) = (23.7°C - 20.5°C = 3.2°C)

29.0g*S(Object)*73.3°C = 95.8g*4.184J/g°C*3.2°C

S (Object) * 2125.7g°C = 1282.6J

S(Object) = 0.603J/g°C is the specific heat of the metal object

Answer:

(C) pollen from flowers is blown by the wind.

I think this is the correct answer friend

The coefficients in a balanced equation can be used as molar ratios, which can act as conversion factors to relate the reactants to the products. These conversion factors state the ratio of reactants that react but do not tell exactly how much of each substance is actually involved in the reaction.

Answer:

First Choice

it produces offspring with a large amount of genetic variation

Answer: i think this is correct.

Explanation: it occurs in simple organisms, such as bacteria, but not in multicellular organism such as plants and animals

Answer:

A.

Cu Zn K is are metals which form ionic bond with oxygen

ig The right answer is -Give the reaction more time.

Answer:

2H2 in products

Explanation:

she should have added another 2 in H2

The edited equation does not balance the number of hydrogens. The correct balanced equation for the given reaction is written as follows:

[tex]\rm 2H_{2}O \rightarrow 2H_{2} +O_{2}[/tex].

The balanced chemical equation of a reaction represents the perfect stochiometric coefficients of all the reactants and products. Thus, each elements in the reaction have to be equal in both side.

According the mass conservation law, the total mass of the reactants is equal to the total mass of the products. Thus, all elements have to balanced on each side.

When water dissociates into hydrogen and oxygen molecules, 2moles of water undergoes dissociation to give two moles of H2 and one mole of O2. Thus the balanced equation is:

[tex]\rm 2H_{2}O \rightarrow 2H_{2} +O_{2}[/tex]

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Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

Answer:

because of heat and pressure

Answer:

molar mass (molar weight)

Explanation:

Answer:

Negative 5

Explanation:

I am not 100% sure btw

Answer:

Maritime tropical air mass

Continental polar air mass

Answer: Electrolysis

Explanation: ‍♀️

Explanation:

A geological process where materials of Earth are transported from one place to another by natural forces like wind or water is called erosion.

When materials of Earth are deposited over a certain landmark due to transportation by natural forces then this process is called deposition.

The four major causes of erosion and deposition are as follows.

Gravity - Force that is responsible for attracting an object towards the center of Earth.

Running water - Water present in the rivers, oceans or lakes is moving from one place to another. Also, along with it carries pebbles or other materials.

Wind Waves - This is basically air and it keeps on moving from one place to another all the time. Wind waves tend to carry dust particles or other materials along with it.

Glaciers - When a mass of ice that is formed by accumulation and compaction of snow over mountains or around the poles tends to move slowly is called glaciers.

Answer:

They equal the same

Explanation:

Because A ton of feathers and A ton of bricks. They both equal A ton.

Answer:

Br

Explanation:

Answer:

T = 3206.89 K

Explanation:

Given that,

Number of moles, n = 1.9 moles

Pressure, P = 5 atm

Volume, V = 100 L

We need to find the temperature of the gas. Let the temperature is T. We know that,

PV = nRT

Where

R is gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

[tex]T=\dfrac{PV}{nR}\\\\T=\dfrac{5\times 100}{1.9\times 0.08206 }\\\\T=3206.89\ K[/tex]

So, the temperature of the gas is 3206.89 K.