Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.
A spiral spring of natural length 20.00cm has a scale
pan hanging on its lower end while the other end is
fixed firmly to a support.When an object of mass 50g
is placed in the pan, the length of the spring becomes
22.00 cm.When another object of mass 70g is placed in
The pan, the length becomes 22.25cm Calculate the
mass of the scale pan. (g = 10m/s]
The mass of the scale pan : 0.11 kg
Further explanationGiven
A spiral spring's length = 20 cm
mass 50 g ⇒ the length = 22 cm
mass 70 g ⇒ the length = 22.25 cm
Required
the mass of the scale pan
Solution
Hooke's Law :
[tex]\tt F=k.\Delta x[/tex]
The spring constant (k) :
[tex]\tt k=\dfrac{\Delta F}{\Delta x}=\dfrac{g.(70-50)}{22.25-22}=\dfrac{g.20}{0.25}=g.80~g/cm=10~m/s^2\times 8~kg/m=80~N/m[/tex]
mass of the scale pan=m(for 50 g mass) :
[tex]\tt (m+0.05).g=80\times (0.22-0.20)\\\\m=0.11~kg[/tex]
A ball is released out a window that is 13 m above the ground. How fast will the ball be traveling when it reaches the ground?
A. 32 m/s
B. 0.26 km/s
C. 0 m/s
D. 16 m/s
Answer:
Option D. 16 m/s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Height (h) = 13 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
We can determine how fast (i.e final velocity) the ball is traveling when it reaches the ground as illustrated below:
v² = u² – 2gh
v² = 0² – (2 × 9.8 × 13)
v² = 0 – 254.8
v² = 254.8
Take the square root of both side.
v = √254.8
v = 15.96
v ≈ 16 m/s
Thus, the ball is travelling with a velocity of 16 m/s when it reaches the ground
A body weighing 108N moves with speed of 5m/s in a horizontal
circular of radius 5m.Calculate the magnitude of the:
(i)centripetal acceleration (ii) Centripetal force (iii) centrifugal
force
Answer:
i) 5 [tex]m[/tex]/[tex]s^{2}[/tex] ii) 54 [tex]N[/tex] iii) 54 [tex]N[/tex]
Explanation:
i) [tex]a = \frac{v^{2}}{r}[/tex] ⇒ [tex]a[/tex] = 5² ÷ 5 = 5 [tex]m/s^{2}[/tex]
ii) [tex]m = \frac{W}{g}[/tex] ⇒ [tex]m[/tex] = 108 ÷ 10 = 10.8 [tex]kg[/tex] , [tex]F = ma[/tex] ⇒ [tex]F =[/tex] 10.8 × 5 = 54 [tex]N[/tex]
iii) F1 = F2 = 54 [tex]N[/tex]
How do the summer monsoons of India affect the hydrosphere, geosphere, and biosphere?
Answer:
Explanation:
The monsoon rains are the main source of water for 55 percent of the country’s arable land. This means the rains are crucial — not only for India’s farmers, but for its economy as a whole. Now, that’s a good thing when the monsoon arrives on time and brings the right amount of rain. But when it’s late or weak, it leads to drought.
Which of the following is an example of electrical energy being changed to thermal energy?
HAIR DRYER
CAMP FIRE
Answer:
Hair dryer
Explanation:
The electrical energy from the outlet is converted to heat to dry hair. In a fair chemical energy is converted to heat instead.
An illustration of a ball sitting at the top of a hill of height labeled h Subscript 1 Baseline = 2 m. A the the bottom of the hill it levels off and the leveled surface is at a height labeled h Subscript 2 Baseline = .5 m. A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth. m/s
Answer:
5.5 m/s
Explanation:
Right on Edge
The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.
What is RNA polymerase?RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.
Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.
Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.
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An exoplanet with one half of Earth's mass and 50% of Earth's radius is discovered.
What would a space cadet who weighs 800 N on Earth weigh on the exoplanet?
Answer:
The space cadet that weighs 800 N on Earth will weigh 1,600 N on the exoplanet
Explanation:
The given parameters are;
The mass of the exoplanet = 1/2×The mass of the Earth, M = 1/2 × M
The radius of the exoplanet = 50% of the radius of the Earth = 1/2 × The Earth's radius, R = 50/100 × R = 1/2 × R
The weight of the cadet on Earth = 800 N
[tex]The \ weight, W =G\dfrac{M \times m}{R^{2}} = 800 \ N[/tex]
Therefore, for the weight of the cadet on the exoplanet, W₁, we have;
[tex]W_1 =G\dfrac{\dfrac{M}{2} \times m}{ \left ( \dfrac{R}{2} \right ) ^{2}} = G\dfrac{\dfrac{M}{2} \times m \times 4}{ R ^{2}} = 2 \times G \times \dfrac{M \times m}{R^{2}} = 2 \times 800 \, N = 1,600 \, N[/tex]
The weight of a space cadet on the exoplanet, that weighs 800 N on Earth = 1,600 N.
explain the difference between reversible and irreversible
Answer:
The difference between reversible and irreversible is reversible can be changed but irreversible can not.
Birdman is flying horizontally at a
speed of 40 m/s and a height of 58
m. Birdman releases a turd directly
above the start of the field. How far
from the start of the field should the
robot hold the bucket to catch the
turd?
Answer:
The robot should hold the bucket at 137.6 m from the start of the field
Explanation:
Horizontal Motion
When an object is launched horizontally with a speed v from a height h, it describes a curved path exclusively ruled by gravity until it eventually hits the ground.
The range or maximum horizontal distance d traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
Birdman flies horizontally at a speed of v=40 m/s and a height of h=58 m. He releases a turd above the start of the field. If the robot was exactly down Birdman, then it won't catch the turd with the bucket because it would land farther away by a distance equal to the range. Thus:
[tex]\displaystyle d=40\cdot\sqrt{\frac {2*58}{9.8}}[/tex]
[tex]\displaystyle d=40\cdot\sqrt{11.84}[/tex]
d = 137.6 m
The robot should hold the bucket at 137.6 m from the start of the field
the diagram shows the apparent motion of the sun across the sky?
Answer:
The earth rotates west to east
Explanation:
Considering that the sun doesn't really move and the earth is rotating around the sun, and it is moving from east to west with us (the earth) facing it in which means the earth rotates around the sun west to east!
Cannon ball of mass 3.5kg is fired at a speed of 22m/s2
Answer:
77N
Explanation:
Since we are not told what to find, we can as well look for the net force acting on the ball.
According Newton's second law;
F = mass × acceleration
Given
Mass = 3.5kg
Acceleration = 22m/s²
Net force F = 3.5×22
F = 35/10×22
F = 7/2×22
F = 7×11
F =77N
Hence the magnitude of force required is 77N
because of friction? A. energy is not always conserved
B. not all potential energy is converted to kinetic energy
C.all an object's kinetic energy turns into potential energy
D all of an object's potential energy turns into kinetic energy
Answer:
i think its B.NOT all potential energy is converted to kinetic energy
Answer:
Maybe, B. Not all potential energy is converted to kinetic energy.
Explanation:
Even if air resistance slows down the ball, the potential energy is the same. But if air resistance is in the way, not all of the potential energy can be converted to kinetic energy. Some of the energy has to be used to push the air molecules out of the way.
WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?
Answer:
372Explanation:(40.0)×(9.8)=392
764N-392=372
Please help!
A stone of mass 50 g is placed in a measuring
cylinder which contains some water.
The reading of the water level increases from
30 cm to 40 cm
What is the density of the stone?
Answer:
Answer:
3 g/cm
Explanation:
Mass of stone = 30 g
Initial volume of cylinder = 50 cm
Increased volume = 60 cm
Volume = 60-50
= 10 cm
Density of stone = Mass/Volume
= 30/10
= 3 g/ml as 1 ml = 1 cm
= 3 g/ml
Explanation:
How does an executive order differ from a statue?
Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.
Explanation: learned it last week
True or false: " The rotation of the earth and revolution of the earth mean essentially the same thing."
Answer:
FALSE
Explanation:
Rotation is spinning on its axis
Revolution is spinning around the sun
According to Kepler's second law of planetary motion,
O a. planets maintain constant speed around the Sun.
Ob. the area swept out by the orbit per time unit keeps changing.
O c. the speed of a planet is greatest when it is closest to the Sun.
O d. planets maintain constant acceleration around the Sun.
Answer:
c. the speed of a planet is greatest when it is closest to the Sun.
Explanation:
Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).
The three (3) laws published by Kepler include;
I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.
II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.
Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.
III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.
Answer:
A planet moves faster when it is closer to the Sun.
Explanation:
Kepler law!
Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero
Answer:
The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.
explain the universal law of gravity and it's calculate from as well as the value of g
Answer:
According to the Newton's law of gravitational every object in the universe attracts every other objects with a force which is called gravitational force.This gravitational force is (i) directly proportional to the product of their masses and (ii) inversely proportional to the square of the distance between their centres.
Explanation:
Newton's law of gravitational is called the universal law because it is applicable to all the bodies either terrestrial or celestial having any shape,size,mass or at any distance apart with any medium between them,at any time(past,present or future).
1. Photosynthesis is a chemical reaction that occurs inside green plant cells. Which sentence describes
one important energy conversion that occurs as a result of photosynthesis?
A. Light is converted to chemical energy.
B. Carbon dioxide is converted to light energy.
C. Oxygen is converted to chemical energy.
D. Chlorophyll is converted to light energy.
Answer:oxygen is converted to chemical energy
Explanation:
I got it right
Es muy común que cuando se viaja hacia un río o lago se juegue "ranita", el cual consiste en lanzar una piedra horizontalmente hacia adelante para que cuando ésta toque la superficie del agua haga varios "saltos" sobre el agua. Durante un juego de estos, un desocupado nota que una de las piedras que arroja se demora 0,4 s en tocar la superficie del agua y la toca a 2,5 m de la orilla del lago, desde donde fue lanzada. Encuentre: a) La altura de la que fue lanzada la piedra. b) La velocidad con la que fue lanzada.
Answer:
a) La piedra es lanzada desde una altura de 0,785 metros.
b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.
Explanation:
a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:
[tex]y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)
Donde:
[tex]y[/tex] - Altura final, medida en metros.
[tex]y_{o}[/tex] - Altura inicial, medida en metros.
[tex]v_{o,y}[/tex] - Componente vertical de la velocidad inicial, medida en metros por segundo.
[tex]t[/tex] - Tiempo, medido en segundos.
[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo cuadrado.
Si sabemos que [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex], [tex]t = 0,4\,s[/tex] y [tex]g = -9,807\,\frac{m}{s^{2}}[/tex], entonces la altura inicial de la piedra es:
[tex]y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}[/tex]
[tex]y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}[/tex]
[tex]y_{o} = 0,785\,m[/tex]
La piedra es lanzada desde una altura de 0,785 metros.
b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:
[tex]v_{o,x} = \frac{x-x_{o}}{t}[/tex] (2)
Donde:
[tex]x_{o}[/tex], [tex]x[/tex] - Posiciones horizontales iniciales y finales, medidas en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
Si tenemos que [tex]x_{o} = 0\,m[/tex], [tex]x = 2,5\,m[/tex] y [tex]t = 0,4\,s[/tex], entonces el componente horizontal de la velocidad inicial es:
[tex]v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}[/tex]
[tex]v_{o,x} = 6,25\,\frac{m}{s}[/tex]
La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.
Studying energy involves determining the amount of energy an object has. This energy can be kinetic or potential, or it could be a combination of both. Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls toward the ground. Think about the amounts kinetic energy the bowling ball has as it falls, select the when the ball would have the most kinetic energy from the choices given.
Answer: the answer is a
Explanation: I got it correct on test
Answer:
as it is halfway through the fall and it has reached a speed of 19.8 meters per second
Explanation:
Studying energy involves determining the amount of energy an object has. This energy can be kinetic or potential, or it could be a combination of both. Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls toward the ground. Think about the amounts kinetic energy the bowling ball has as it falls, select the when the ball would have the most kinetic energy from the choices given.
A loudspeaker produces a sound wave of frequency 50hz.
The amplitude of sound wave is increased.
What is heard?
A) a louder sound of higher pitch.
B) a louder sound of the same pitch.
C) a sound of higher pitch but the same loudness.
D) a sound of the same pitch and loudness as before
Answer:
B) a louder sound of the same pitch.
Explanation:
Given that the loudspeaker produces a sound wave of frequency 50hz and the amplitude of the sound wave is increased.
As loudness of the sound depends on the amplitude of the sound while pitch depends on the frequency of the sound.
On increasing the amplitude of the sound there is no effect on the frequency of the sound, so, the loudness of the sound will increase while the pitch remains unchanged.
Therefore, on increasing the amplitude of the soundwave a louder sound of the same pitch is heard.
Hence, option (B) is correct.
A friend is coming to Tim’s house to study after school. What directions would Tim give for reaching his house from the entrance of the school?
(I WILL GIVE BRAINLIEST)
Answer:
go up the street as you exit the house and make a right and keep going up for 3 blocks and you should see the school
A force of 150 kg x m/s (Newtons) acts on a 0.5kg object. What rate of acceleration will result?
Answer:
300m/s/s
Explanation:
a=f/m
f=150N
m=.5kg
150/.5=300
5. Rashmi is watching her favourite TV show. Her grandmother asks her to look for her senga
which has fallen on the ground. Rashmi bringshermagnet and searches the neede
(a) Which property of magnet do you think helped Rashmi find the needle?
(b) Which value is displayed by Rashmi ?
Answer:
a) Magnet attracts to ferromagnetic substances like Iron.
b) Scientific thinking (critical thinking)
As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
What muscle movement do we use to close a joint.
Answer: Your using your skeletal muscle
Explanation:
How does an increase in thermal energy affect the state of matter?
Answer:
When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation). ... When the pressure exerted on a substance increases, it can cause the substance to condense.
Explanation:
Hope it will help use
a 5500-kg freight trunk accelerates from 4.2 m/s to 7.8 m/s in 15.0 s by the application of a constant force a) what change in momentum occurs
b) how large of a force is exerted?
(a) The change in momentum of the trunk is 19800 kgm/s,
(b) The force exerted on the trunk is 3960 N
Change in momentum:The can be defined as the product of the mass of a body and its change in velocity. The S.I unit of change in momentum is kgm/s
(a) To calculate the change in momentum of the trunk, we use the formula below.
Formula:
ΔM = m(v-u)............... Equation 1Whee:
ΔM = change in momentum of the trunkm = mass of the trunkv = final velocity of the trunku = initial velocity of the trunk.From the question,
Given:
m = 5500 kgv = 7.8 m/su = 4.2 m/sSubstitute these values into equation 1
ΔM = 5500(7.8-4.2)ΔM = 5500(3.6)ΔM = 19800 kgm/s.(b) To calculate how large is the force was exerted on the trunk, we use the formula below.
Formula:
F = ΔM/t................. Equation 2Where:
F = Force exerted on the trunkt = time.From the question,
Given:
t = 15.0 s.Substitute into equation 2
F = 19800/5F = 3960 N.
Hence, (a) The change in momentum of the trunk is 19800 kgm/s, (b) The force exerted on the trunk is 3960 N
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