A smoke jumper jumps from a plane that is 1900 ft above the ground. The function h=-16t+1900 gives the​ jumper's height h in feet during the free fall at t seconds. a. How long is the jumper in free fall if the parachute opens at 1000​ ft? b. How long is the jumper in free fall if the parachute opens at ​ft? c. What is a reasonable domain and range for the function​ h? a. The jumper is in free fall for nothing s if the parachute opens at 1000 ft

Answers

Answer 1

Answer:

a) The jumper opens the parachute in 7.5 seconds.

b) The jumper opens the parachute in approximately 7.706 seconds.

c) There are two possible choices for the function:

Case a): [tex]Dom\{h(t)\} = [0\,s,7.5\,s][/tex], [tex]Ran\{h(t)\}=[1000\,ft,1900\,ft][/tex]

Case b): [tex]Dom\{h(t)\} = [0\,s,7.706\,s][/tex], [tex]Ran\{h(t)\}=[950\,ft,1900\,ft][/tex]

Step-by-step explanation:

Note: The equation presented in statement is incorrect. The correct formula for free fall is:

[tex]h(t)=-16\cdot t^{2}+1900[/tex] (1)

Where:

[tex]t[/tex] - Time, measured in seconds.

[tex]h[/tex] - Height above the ground, measured in feet.

a) If we know that [tex]h(t) = 1000\,ft[/tex], then the final instant of the free fall stage is:

[tex]-16\cdot t^{2}+1900 = 1000[/tex]

[tex]16\cdot t^{2} = 900[/tex]

[tex]t = 7.5\,s[/tex]

The jumper opens the parachute in 7.5 seconds.

b) How long is the jumper in free fall if the parachute opens at 950 ​ft?

If we know that [tex]h(t) = 950\,ft[/tex], then the final instant of the free fall stage is:

[tex]-16\cdot t^{2}+1900 = 950[/tex]

[tex]16\cdot t^{2} = 950[/tex]

[tex]t \approx 7.706\,s[/tex]

The jumper opens the parachute in approximately 7.706 seconds.

c) There are two possible choices for the function:

Case a): [tex]Dom\{h(t)\} = [0\,s,7.5\,s][/tex], [tex]Ran\{h(t)\}=[1000\,ft,1900\,ft][/tex]

Case b): [tex]Dom\{h(t)\} = [0\,s,7.706\,s][/tex], [tex]Ran\{h(t)\}=[950\,ft,1900\,ft][/tex]


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answer:

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