A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5 °F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.

Write an expression to represent the water temperature after the submarine’s final dive. Then simplify the expression to find the temperature.

Answers

Answer 1

Answer:

At the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°F

Step-by-step explanation:

At 502.5 feet below the sea level temperature of the water is 63\frac{1}{4}°F

When submarine dives down 115 feet deeper, water temperature drops by 2\frac{1}{5}°F

Elevation after the submarine dove = -502.5 - 115 = -617.5 feet

This negative sign represents the elevation below the sea level.

And the temperature will be = 63\frac{1}{4}-2\frac{1}{5}

                                              = \frac{253}{4}-\frac{11}{5}

                                              = \frac{1265-44}{20}

                                              = \frac{1221}{20}

                                              = 61\frac{1}{20}°F

Therefore, at the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°F

Answer 2

The required expression is y = 0.01x +  58.2. Where, x = level of sea and y = temperature. At 115 feet deeper temperature is 61 1/4°F.


A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F.

What are functions?

It is the relationship between sets of values. e g y=f(x),

Here, assume that relation ship between temperature and sea level is linear. So the expression can be calculated as  y = - 0.01x +  58.2.
Since at 115 feet deeper from 502.5 temperature-
total sea level; = 502.5+115
                      = 617.5
Put it in expression
y = -0.01 * 617.5 + 68.2
y = 61.25
y = 61 1/4 °F

Thus, the required expression is y = 0.01x +  58.2. Where, x = level of sea and y = temperature. At 115 feet deeper temperature is 61 1/4°F.

 

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