A summer camp cookout is planned for the campers and their families. There is room for 200 people. Each adult costs $4, and each camper costs $3. There is a maximum budget of $750. Write the system of inequalities to represent this real-world scenario, where x is the number of adults and y is the number of campers. x + y ≤ 200 4x + 3y ≤ 750 x + y ≤ 750 4x + 3y ≤ 200 x + y ≤ 200 3x + 4y ≤ 750 x + y ≤ 750 3x + 4y ≤ 200

Answer:

I think its A

Step-by-step explanation:

The required system of inequalities is x + y ≤ 200 and 4x + 3y ≤ 750. Hence, the first option is the correct choice.

Inequality is a non-equal relation between two expressions involving variables and constants.

The sign of the inequality can be, less than (<), greater than (>), less than or equal to (≤), or greater than or equal to (≥).

In the question, we are asked to write the system of inequalities to represent the given scenario,  where x is the number of adults and y is the number of campers.

We are informed that there is a room for 200 people.

Thus, the total number of people, that is, the number of adults + the number of campers, or, x + y should be less than or equal to 200.

This gives us an inequality:

x + y ≤ 200.

We are informed that the cost of an adult is $4 and the cost for a camper is $3, and the total budget is $750.

Thus, the total cost, that is, the cost of all adults + the cost of all campers, or, 4x + 3y should be less than or equal to 750.

This gives us an inequality:

4x + 3y ≤ 750.

Thus, the required system of inequalities is x + y ≤ 200 and 4x + 3y ≤ 750. Hence, the first option is the correct choice.

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