according to the law , naturalized amrican citizens

Answer:

The diameter of mirror [tex] 5\times10^{-6}\ m[/tex]

Explanation:

Given that,

Wavelength = 2 μm

Resolution = 0.1

We need to calculate the diameter of mirror

Using formula of resolution

[tex]resolution=0.25\times\dfrac{wavelength}{diameter}[/tex]

[tex]diameter =0.25\times\dfrac{wavelength}{resolution}[/tex]

Put the value into the formula

[tex]diameter=0.25\times\dfrac{2\times10^{-6}}{0.1}[/tex]

[tex]diameter = 0.000005\ m[/tex]

[tex]diameter = 5\times10^{-6}\ m[/tex]

Hence, The diameter of mirror [tex] 5\times10^{-6}\ m[/tex]

Answer:

Let N = N0 where N0 is the number of atoms originally present.

In 6 days    N = N0 / 2

In 12 days   N = N0 / 4

In 18 days   N = N0 / 8    = .125 N0

So it would take 18 days.

Manganese-52 has a half-life of 6 days. a scientist has to wait 18 days for the radioactivity to be 12.5% of the starting amount

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity. This radiation is released when a nucleus undergoes radioactive decay and transforms into a different isotope that may be radioactive (unstable) or non-radioactive depending on the number of neutrons and protons in the nucleus (stable).

As given in the problem statement Manganese-52 has a half-life of 6 days. this means after 6 days Manganese-52 will reduce to its half value

similarly, after 12 days it further reduces to 50% of the previous value which would be 25 %

Similarly, after 18 days, it will reduce 50% from the previous value which comes out to be 12.5 %

Thus, The half-life of manganese-52 is 6 days. It takes 18 days for the radioactivity to drop to 12.5% of the initial level.

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Answer 24cm

Explanation:

The amplitude of vibration of the spring is "24 cm"

The periodic vibrating body's motion follows a sinusoidal path. This sinusoidal path is illustrated in the attached picture.

From the picture, it can be clearly seen that the amplitude of the periodic vibration motion is the distance from its mean position to the highest point.

Since the distance of both the highest and the lowest points from the mean position is the same. Therefore, the distance between the lowest and the highest point must be equal to two times the amplitude of the wave.

[tex]Distance\ between\ highest\ and\ lowest\ point = 2(Amplitude)\\\\Amplitude = \frac{Distance\ between\ highest\ and\ lowest\ point}{2}\\\\Amplitude = \frac{48\ cm}{2}\\\\[/tex]

Amplitude = 24 cm

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Answer:

0.2886 Kmoles

Explanation:

Number of moles is calculated by dividing mass of element/molecular mass of element

Mass of Carbon Di oxide = 5000 g or 5 kg

Molecular mass of CO2 = 12 + 16×2 = 44 g

No of moles = 5000/44 = 113.6 moles = 0.1136 Kmoles

Mass of argon = 7Kg or 7000 kg

Molecular mass of Argon(Ar) = 40g

No of moles = 7000/40 = 175 moles = 0.175 Kmoles

Total Kmoles = 0.175+0.1136=0.2886 Kmoles

Answer:

50 m/s

Explanation:

Hi.

just for little clarification, I'd explain what a tail wind is, if you don't mind.

A tail wind is a wind that moves in the direction of the aircraft. If an aircraft is moving in a direction northwards, then a tail wind is also a wind moving northwards.

Now to the question, the airplane is flying at, 150 km/h with a tail wind of 30 km/h.

The airplane's speed is then,

150 + 30 = 180 km/h

And to convert to m/s, we have

180 km/h = 180 * 1000/3600 m/s

180 km/h = 50 m/s

Answer:

The formula is kelvin = (tempature in farenheit-32) ÷ 1.8 +273.15

So it will be (-22-32) ÷ 1.8 +273.15= 243.15 kelvin

Answer:

T(K) = (T(°F) + 459.67)× 5/9

answer is 243.15

Answer:

b) the earth did not orbit the sun

Explanation:

The sun appears to move through the background stars due to parallax . Parallax is a phenomenon when the near object appears to move faster than the distant object . If we travel in a train , the near object like electric poles on rail track or trees and fields nearby appear to move faster against the distant background .

Hence when the earth moves around the sun , the sun appears to move against the background the stars which are far away . Had earth remained stationary at a place on its orbit around the sun , the sun would have appeared stationary against the background the   stars .

Answer:

Traveling with a constant velocity means you're going at the same speed in the same direction continuously. If you have a constant velocity, this means you have zero acceleration. ... If you travel with a constant acceleration, your velocity is always changing, but it's changing by a consistent amount each second.

Answer: I dont see the option choices

Explanation:

Answer:

Generally it is only possible  to compute the tangent of angle in their various unit but because 5 meter is not an angle then it is impossible  to compute the tangent of 5 meters.

Explanation:

Answer:

0.000047N

Explanation:

We know that

intensity (I) = P/ A

Where

P= power

A= Area

So lets say that the power absorbed

Will be = Intensity x Area

Which Is = 1.4 x 10^3 x(10)

So

14000 Watt = 14 kWatt

However we know that radiation pressure is equal to

time-averaged intensity all over the speed of light in free space

So

P = (1.4 x 1000)/c

But

F= P x A

So

((1.4 x 1000)/(3 x1 0^8)) x 10

Which is

=0.000046666N

To two SIG figures we have

=0.000047 N

(a) The total solar power P absorbed by the panels is 14 kW.

(b) The total force F on the panels exerted by radiation pressure from the sunlight is [tex]4.7 \times 10^{-5} \ N[/tex].

The given parameters;

The total solar power P absorbed by the panels is calculated as follows;

[tex]P = I A\\\\P = (1.4 \ kW /m^2 ) \times 10\ m^2\\\\P = 14 \ kW[/tex]

The total force F on the panels exerted by radiation pressure from the sunlight is calculated as follows;

[tex]Pressure, P = \frac{I}{c} \\\\Force, F = PA\\\\F = (\frac{I}{c} )A\\\\F = \frac{IA}{c} \\\\F = \frac{(1.4 \times 10^3) \times (10)}{3\times 10^8} \\\\F = 4.7 \times 10^{-5} \ N[/tex]

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Answer:

100 Ω

Explanation:

Given that

Open circuit voltage, V = 1 V

Short circuit current, I = 10 mA

Source resistance R, = ?

This is rather a straight forward question. Remember Ohms Law? Current being directly proportional to the voltage and inversely proportional to the resistance?

Yeah, that's the formula we'd be using.

Ohms Law states that V = IR, and thus, if we make R subject of the formula, we have

R = V / I, on substituting the values, we have

R = 1 / 10*10^-3

R = 1 / 0.01

R = 100 Ω

Answer:

a

 [tex]T  =7.7 \ s [/tex]

b

   [tex]  s = 73.3 \  m [/tex]

Explanation:

From the question we are told that

   The speed is  [tex]u =  45.2  \  m/s[/tex]

   The angle is  [tex]\theta  = 57 .0^o[/tex]    

Generally the velocity of the stone in the y-axis is mathematically evaluated as

        [tex]v_y  = v * sin(\theta )[/tex]

=>     [tex]v_y  =  45.2  * sin(57 )[/tex]

=>      [tex]v_y  = 37.9 \  m/s [/tex]

Now  the time taken for the first flight is mathematically represented as

        [tex]t =  \frac{v_y}{g}[/tex]

=>      [tex]t =  \frac{37.9}{9.8}[/tex]

=>      [tex]t = 3.87 \  s [/tex]

The time taken for the total flight is mathematically represented as

           [tex]T  =  2 * t[/tex]

               [tex]T  =  2 * 3.87[/tex]

           [tex]T  =7.7 \ s [/tex]

From the equation of kinematics we have that  

      [tex]v^2  =  v_y^2  + 2gs[/tex]

At maximum heigth v =  0

      [tex]  =  37.9 ^2  + 2 *( -9.8) * s[/tex] The  negative sign is because it is moving against gravity to attain the maximum height

So

        [tex]  s = 73.3 \  m [/tex]

The time a projectile is in the air and the maximum height reached is required.

The projectile is in the air for 7.73 s.

The maximum height reached by the projectile is 73.24 m.

u = Initial velocity = 45.2 m/s

[tex]\theta[/tex] = Angle of inclination = [tex]57^{\circ}[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Time of flight is given by

[tex]t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 45.2\sin 57^{\circ}}{9.81}\\\Rightarrow t=7.73\ \text{s}[/tex]

Maximum height is given by

[tex]h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{45.2^2\sin^257^{\circ}}{2\times 9.81}\\\Rightarrow h=73.24\ \text{m}[/tex]

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Answer:

The  value is  [tex]E =  8.9 *10^{-5} \  J[/tex]

Explanation:

From the question we are told that

   The  area is  [tex]A =  0.700 \  m^2[/tex]

   The  root mean square value  is [tex]E_{rms} =  0.0400 \  V/m[/tex]

   The time taken is [tex]t =  30.0 \  s[/tex]

Generally the energy is mathematically represented as

     [tex]E =  c *  \sepsilon_o *  A  *  t  * E_{rms}^2[/tex]

=>    [tex]E =  3.0*10^{8} *  8.85*10^{-12} *  0.700 *  30 * (0.04)^2[/tex]

=>     [tex]E =  8.9 *10^{-5} \  J[/tex]

Answer:

44 is right answer

Explanation:

Step 1 :

11+11+11+11+11

step 2:

=22+22

step 3:

=44

hope it helped you:)

Thanks!

Answer:

Explanation:

From the question we are told that

 The diameter is [tex]d = 150 \ m[/tex]

  The time taken is  [tex]t = 5 \ min = 300\ s[/tex]

Generally the circumference is mathematically represented as

     [tex]C =  d  *  \pi[/tex]

     [tex]C =  150 *  3.142[/tex]

     [tex]C =  471.3 \  m[/tex]

The average speed is mathematically represented as

      [tex]v  =  \frac{C}{ t}[/tex]

     [tex]v  =  \frac{471.3}{300}[/tex]

    [tex]v =  1.571 \  m/s[/tex]

50Kpa

Explanation:

P1V1 = P2V2

Where;

P1= 100. P2= ?

V1 = 500. V2 = 1000

100 × 500 = P2 × 1000

50000 = 1000P2

50000/1000 = P2

50 = P2

P2 = 50Kpa

Answer:

120

Work :

W = Fd (work = force x distance)

Force :

F = W/d

Distance :

d = W/F

Answer:

E = 10t^2e^-10t Joules

Explanation:

Given that the current through a 0.2-H inductor is i(t) = 10te–5t A.

The energy E stored in the inductor can be expressed as

E = 1/2Ll^2

Substitutes the inductor L and the current I into the formula

E = 1/2 × 0.2 × ( 10te^-5t )^2

E = 0.1 × 100t^2e^-10t

E = 10t^2e^-10t Joules

Therefore, the energy stored in the inductor is 10t^2e^-10t Joules

Answer:

We know that angular momentum is mvr

So that of the students initially will be

A1= mvr

and the final of the student and the merrygo round will be

A2= (1/2Mr²+mr)omega

So

Angular velocity (omega)= mvr/(1/2Mr²+mr)

This is the final angular velocity of the system so yea the student must have angular momentum before jumping on the merry-go-round

B. Because of directional changes at every edge of the Merry go round that result in changes in velocity, this results in changes in momentum too thus linear momentum is not conserved

Answer:

Speed =distance/time.

=20/4

=5m/s.

Formula: s = d/t

s = speed

d = distance

t = time

Solve using the values we are given.

s = 20/4

s = 5m/s

best of Luck!

Answer:

111.6 g or 0.112 kg

Explanation:

specific heat of liquid water = 4190 J/kg⋅K

specific heat of ice = 2100 J/kg⋅K

heat of fusion for water = 3.34*10^5 J/kg

You didn't state the mass of the beaker, so, I will be assuming that the mass is negligible.

Assuming that the mass of ice required is m kg

Then the heat gained by the ice to attain zero degree will be

= m * 22.3 * 2100

= 46830m J

The heat gained by the ice to melt

= m * 3.34*10⁵ J

= 334000m J

The heat gained by water at zero degree to warm up to 30° =

m * 4190 * 30 = 125700m J

Total heat gained = 506530m J

Note: You didn't state the mass of the water and it's temperature, so I will be assuming that the mass of water is 0.3 kg, and it's temperature was 75° C

The heat lost by hot water to cool up to 30°

= .3 * 4190 * (75 - 30)

= 1257 * 45

= 56565 J

Using the relation, Heat lost = heat gained

506530m = 56565

m = 56565 / 506530 kg

m = 0.112 kg or 111.6 g

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yes its The observation that all objects that have mass attract each other

Answer:

This question has already been answered.

Explanation:

https://brainly.com/question/13542582

Answer:

The ruler's center of mass is located on the vertical line defined by the 50 cm mark.

Explanation:

Recall that in order to have equilibrium as that described by this example, the net Torque in the ruler should be zero. which means in our case that the weight due to the right half of the ruler, should equal in absolute value of the weight of the left side of the ruler, thus defining where the ruler's center of mass is.

Since this happens at the mark 50 cm, then the center of mass of the ruler is located somewhere inside the ruler somewhere above where the pivot is located (50 cm mark)

Answer:

[tex]a=4.8m/s^2[/tex]

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

[tex]a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)[/tex]

The purpose here is derive x(t) twice as follows:

[tex]a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2[/tex]

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

Answer:

A) The value of the diameter in inches is 5.19685 × 10⁻⁹ inches

B)  There are 1,590,909,091 atoms on a 21.0cm line

Explanation:

A) To determine what its diameter is in inches

We will convert 1.32 × 10⁻¹⁰ m to inches

First convert this to centimeters (cm)

1.32 × 10⁻¹⁰m = 1.32 × 10⁻¹⁰ × 10² cm

=  1.32 × 10⁻⁸cm

Now, since 1 inch = 2.54 cm

∴ 1 cm = [tex]\frac{1}{2.54}[/tex] inches

If  1 cm = [tex]\frac{1}{2.54}[/tex] inches

Then 1.32 × 10⁻⁸ cm will be

1.32 × 10⁻⁸ × [tex]\frac{1}{2.54}[/tex] inches

= 5.19685 × 10⁻⁹ inches

This is the value of the diameter in inches

B) For the number of atoms on a 21.0cm line

The diameter of 1 atom is 1.32 × 10⁻¹⁰m

1.32 × 10⁻¹⁰m = 1.32 × 10⁻⁸cm

Hence, on a 21.0 cm line, we will have

(21.0 / 1.32 × 10⁻⁸) atoms

= 1590909091 atoms

Hence, there are 1,590,909,091 atoms on a 21.0cm line

Answer:

1.67 s

Explanation:

Since the clock is moving at relativistic speed, the period dilates. So, we use the equation

t = t₀/√[1 - (v/c)²].

Given that t = the period of the clock = 1 s and v = speed of the clock = 0.80c, substituting these values into t, we have

t = t₀/√[1 - (v/c)²]

t = 1/√[1 - (0.8c/c)²]

t = 1/√[1 - (0.8)²]

t = 1/√[1 - 0.64]

t = 1/√0.36

t = 1/0.6

t = 1.67 s

So the period of the clock when it is observed while moving with a speed of 0.8c is 1.67 s

Answer:

a. [tex]1.019 \times 10^{-7} N[/tex]

b. Repulsive force

Explanation:

The computation is shown below:

a. The magnitude of the force is

Given that

Charge = 7.52nc

Location = 1.65m

Point charge = 4.10nC

Based on the above information,

As we know that

[tex]F= \frac{kqQ}{r^2} \\\\= \frac{9\times10^{9} \times 7.52 \times 10^{-9} \times 4.1 \times 10^{-9}}{1.652} \\\\= 1.019 \times 10^{-7} N[/tex]

b. Now as it can be seen that both contains the positive charges so this represents the repulsive force and the same is to be considered