Ana is a teacher who plays a review game with her class. The game involves writing each student's name on
an identical slip of paper and selecting students at random. Here's the makeup of her class:
Grade
9th 10th 11th
Number of students
12. 9. 7.
Suppose that Ana picks a name, replaces it, and picks a name again.
What is the probability that NEITHER of the students selected are
9th graders?
Round your answer to two decimal places.
Answers
Answer:
P(Neither 9th grade)=16/28*16/28=16/28*16/28=(16/28)^2=256/784≈0.3265
Answer:
The probability that neither of the students selected are 9th graders is about 0.33.
Step-by-step explanation:
Pls give brainliest
Probabilities are used to determine the chances of events
The probability that neither of the students is a 9th grader is 0.33
From the table, the number of students that are not 9th graders are:
[tex]N9 =9 + 7[/tex]
[tex]N9 =16[/tex]
The total number of students is:
[tex]Total =12 + 9 + 7[/tex]
[tex]Total =28[/tex]
The probability that neither of the students is a 9th grader is calculated as follows
[tex]P =P(N9) \times P(N9)[/tex]
So, we have:
[tex]P =\frac{16}{28} \times \frac{16}{28}[/tex]
Multiply
[tex]P =\frac{256}{784}[/tex]
Divide and approximate
[tex]P =0.33[/tex]
Hence, the probability that neither of the students is a 9th grader is 0.33
Read more about probabilities at:
https://brainly.com/question/7965468
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Step-by-step explanation:
Answer:
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2
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у
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Step-by-step explanation:
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Answers
Answer:
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if you like my answer, please mark me brainliest !! thanks !! <3
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..............................................................
Step-by-step explanation:
..........................................................................
..........................................................................
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Answers
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Will give brainliest!
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Answers
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Answers
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Answers
Answer:
No solution
Step-by-step explanation:
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see more at: https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-negative-number-topic/cc-6th-absolute-value/a/intro-to-absolute-value