ANSWER ASAP PLEASE AND SHOW YOUR WORK!!!!
Algebraically determine whether the following function is Even, Odd, or Neither.
f(x)= x^3-2x

Answer:

f(-x)= -f(x) so, the given function [tex]f(x)= x^3-2x[/tex] is Odd

Step-by-step explanation:

We need to determine if the function [tex]f(x)= x^3-2x[/tex] is Even, Odd, or Neither.

Determining if a function f(x) is even or not we put x=-x and check

If f(-x)=f(x) the function is even

if f(-x)= -f(x) the function is odd

So, Putting x =-x and determining if the given function [tex]f(x)= x^3-2x[/tex] is Even, Odd, or Neither.

[tex]f(x)= x^3-2x\\Put \ x=-x\\f(-x)=(-x)^3-2(-x)\\f(-x)=-x^3+2x\\f(-x)=-(x^3-2x)\\f(-x)=-f(x)[/tex]

As f(-x)= -f(x) so, the given function [tex]f(x)= x^3-2x[/tex] is Odd

PLEASE HELP ME ASAP

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Step 2: Write an equation.
Step 3: Solve your equation.Step 5: Write a summary statement explaining your solution in the context of the problem..
Step 4: Check your solution.
Step 5: Write a summary statement explaining your solution in the context of the problem..
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