Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
A student on a bicycle decided to determine his acceleration when coasting down a steep hill. The student started from a full stop and reached a velocity of 8.75 m/s in 3.8 s. What was his average acceleration? Assume that downhill is the positive direction.
Answer:
A=2.2
Explanation:
You have to lay everything out first.
You are given the:
Velocity and the time
V=8.75m/s
t=3.8s
Now you need to know what you are looking for, and that is the average acceleration.
Write down the formula (teachers like this)
A=v/t
Now calculate:
8.75/3.8= 2.3026315789473
You can now round down since the number next to the decimal is below 5
The number of significant digits will be 2 because that is the lowest number in the question. This means you will only need to display 2 numbers.
The final answer will be:
A=2.2
:)
*make sure to show your work step by step, some nice teachers give extra marks for that*
I hope this helped, goodluck! :D
It takes a car 4 seconds to slow down from 22 m/s to 6 m/s , what was its acceleration?
To Find The Acceleration of A Car Slowing Down:
The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.
whats 10x10 PLEASE I NEED THIS
Answer:
100
Explanation:
A man pushes a box with a force of 75N across a 12M loading dock. How much work did he do on the box?
Once again, Have a Happy, Merry Christmas!! =)
Answer: 75n,a * (12m)
Explanation I'm trying to understand the question but this is what i got.
Happy Holidays!
We can use the following equation to calculate work done on an object.
W = F · d
Work (J) = Force (N) · displacement (m)
Plug in the given values into the equation:
W = 75 · 12 = 900 J
1. Which among the sports you stated above are you familiar with?
I am familiar with Russian Mountaineering
Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?
This question involves the concepts of the equations of motion in vertical direction.
The height of the bridge is "116.8 m".
We will use the second equation of motion in vertical direction to find out the height of the bridge.
[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]
where,
h = hieght = ?
vi = initial speed = 0 m/s
t = time taken = 4.88 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]
h = 116.8 m
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how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air
Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
Magnitude of the vector = 350 NPosition of the vector = 30⁰ South eastThe vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
The length of the arrow represents the magnitude of the vector which is 350 N. The direction of the arrow indicated by the arrow head represents the position of the vector.The position of the vector is 30 degrees South of East.Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
Learn more about vector representation here: https://brainly.com/question/14204873
Porque la densidad de un solido es alta?
[tex] \large \sf{hola \: amigo ♡ }[/tex]
Porque, las partículas en los sólidos están muy juntas. Están empaquetados herméticamente, dando a los sólidos altas densidades.
espero que ayude ♡♡
Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?
Answer:
Density of the mixture = 855.56kgm-3
Explanation:
Density = Mass / Volume
Volume of Liquid X = 0.5m³
Density of Liquid X = 900kgm-3
Mass of Liquid X = Density × Volume
= 900kgm-3 × 0.5m³ = 450kg
Volume of Liquid Y = 0.4m³
Density of Liquid Y = 800kgm-3
Mass of Liquid Y = Density × Volume
= 800kgm-3 × 0.4m³= 320kg
As X and Y are mixed, we add their masses and volumes together:
Mass = 770kg
Volume = 0.9m³
Now we can find the density of the mixture:
Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)
Annie comes to a sudden stop to avoid hitting a deer crossing the road at night. As she hits the breaks, her speed drops from 12 m/s to zero in 1.5 seconds.(p1) How far did she travel during that time? (p2)What was her average acceleration?
Distance(p1)
9 m
8 m
10 m
13.5 m
Acceleration(p2)
6 m/s2
8 m/s2
12 m/s2
16 m/s2
Answer:
1. around 22m
Explanation:
Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².
Annie's initial speed was 12 m/s.
Her final speed was 0 m/s.
The time it took her to stop was 1.5 seconds.
Therefore, the distance she traveled during that time is:
distance = (initial speed + final speed)/2 * time
= (12 m/s + 0 m/s)/2 * 1.5 seconds
= 9 meters
Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.
In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.
The time it took for this change to occur is 1.5 seconds.
Therefore, Annie's average acceleration is:
acceleration = change in velocity / time
= -12 m/s / 1.5 seconds
= -8 m/s²
The negative sign indicates that Annie was slowing down.
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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,
[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]
[tex]it \: was \: helpful \: to \: you[/tex]
# be careful#
A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
why is creavity important inn constructing scientific methods
1) A creative method can save money when you have limited resources
2) A scientific experiment is always very boring
3) There is only one experiment that can test each hypothesis
4) There is no creativity in the scientific community.
Answer:
The answer is C
Explanation:
Scientists use creativity to determine which smaller questions are likely to yield results, imagine possible answers to their questions, and devise ways to test those answers.
Creativity is the key to make the scientific experiments more efficient and and economic and hence, a creative method can save money when you have limited resources.
What is a scientific method?A scientific method is constituted by a set of stages and instructions to conduct a scientific experiment to attain a possible solution for a problem. Scientific methods have to be reproducible and effective to bring a valid solution for a hypothesis based on an observation.
Creative thinking is always paramount significance because it leads more ways and identifies the pitfalls in the available scientific methods. Creativity improves the way of designing a scientific experiments and to gather informations also.
Therefore, creative method can save money when you have limited resources is a true statement regarding a scientific method.
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A 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?
Help!!
Answer:
500 J.
Explanation:
Work done = force * distance
= 25 * 20
= 500 Joules.
explain why an astronaut on moon seems to be attracted only to the moon
Answer: the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.
Explanation:
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
1
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.
Part A
How much work does the rope do on the wagon if you pull the wagon 200 m at a constant speed?
Answer:
2000 J
Hope you could get an idea from here.
Doubt clarification - use comment section.
S O L U T I O N:
Here we've been provided with the information i.e
Force (F) = 20N Distance (s) = 200m Angle (θ) = 60°Ans we have given to find out what is work done (W) = ?
The standard formula to calculate work done is given by,
[tex]:\implies\sf{w = f \times s \times cos \theta}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times cos60}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times \frac{1}{2} }[/tex]
[tex]:\implies\sf{w = 20 \times 100 \times 1}[/tex]
[tex]:\implies\sf{w = 2000J}[/tex]
Total work done done by rope is 2000J.A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2. 15, 2. 05, 02. 02, 02. 7. Use the table to answer the questions. What is the fastest time trial for the first quarter checkpoint? seconds What is the slowest time trial for the first quarter checkpoint? seconds What is the range of times measured for this checkpoint? seconds.
The fastest time trial for the first quarter checkpoint is 2.02 s.
The slowest time trial for the first quarter checkpoint is 2.7 s.
The range of the times measured for the checkpoint is 0.68 s.
The given parameters;
Time for quarter checkpoint, = 2.15, 2.05, 2.02, 2.7The fastest time trial for the first quarter checkpoint is the least measured time value.
fastest time trial = least time measured
fastest time trial = 2.02 s
The slowest time trial for the first quarter checkpoint is the highest measured time value.
slowest time trial = 2.7 s
The range of the times measured for the checkpoint is difference between the fastest time and slowest time.
Range = fastest time - slowest time
Range = 2.7 - 2.02
Range = 0.68 s
Learn more about range of data here: https://brainly.com/question/24326172
Answer:
2.02, 2.15, 0.13
Explanation:
A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2.15, 2.05, 2.02, 2.07.
Use the table to answer the questions.
What is the fastest time trial for the first quarter checkpoint?
2.02
seconds
What is the slowest time trial for the first quarter checkpoint?
2.15 seconds
What is the range of times measured for this checkpoint?
0.13 seconds
ii. Which of these has a heating element with a low melting point?
a, electric bell
c. electric iron
b. fuse
d. all of these
why is water soaked cloth used on forehead during fever?please can you tell me answer
This is because the cloth soaked in water can absorb and evaporate the heat from your forehead.
Explanation:This technique is used to cool down your fever, and to help you feel better.
stella is driving down a steep hill. she should keep her car __________ to help _________.
Answer:
Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.
Explanation:
what is value of 2.37 in sl units
A pitcher throws a softball
Answer:
Did you forget the answers
Explanation:
if so leave in comments and i will try to figure out
Answer:
what is the question and the answers??
El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies.
a) Express the initial velocity of the package as a vector. What
observer on the ground.
b) How long will it take for the package to reach the ground?
c) How fast will it be going as it lands? Express your answer as
a vector.
d) Describe the path of the package as seen by a stationary
assumptions have you made about the frame of reference?
e) Describe the path of the package as seen by someone in the
aeroplane.
The motion of the package can be described as the motion of a projectile,
given that it has an horizontal velocity and it is acted on by gravity.
a) [tex]\vec{v}[/tex] = 70·ib) The package will reach ground in approximately 12.77 seconds.c) The speed of the package as it lands is approximately 145.51 m/s.d) The path of the package based on a stationary frame of reference is parabolice) The path of the package as seen from the plane is directly vertical downwards
Reasons:
Velocity of the aircraft = 70 m/s
Direction of flight of the aircraft = Eastward
Height from which the aircraft drops the package, h = 800 m
a) The initial velocity of the package, [tex]\vec{v}[/tex] = 70·i
b) The time it will take the package to reach the ground, t, is given by the formula;
[tex]\displaystyle h = \mathbf{\frac{1}{2} \cdot g \cdot t^2}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]\displaystyle t = \mathbf{\sqrt{ \frac{2 \cdot h}{g} }}[/tex]
Which gives;
[tex]\displaystyle t = \sqrt{ \frac{2 \times 800}{9.81} } \approx \mathbf{12.77}[/tex]
The time it will take the package to reach the ground, t ≈ 12.77 seconds
c) The vertical velocity just before the package reaches the ground, [tex]v_y[/tex], is given as follows;
[tex]v_y^2[/tex] = 2·g·h
Therefore;
[tex]v_y[/tex] = √(2·g·h)
Which gives;
[tex]v_y[/tex] = √(2 × 9.81 × 800) ≈ 125.28
[tex]v_y[/tex] ≈ 125.28 m/s
Which gives; [tex]\vec{v}[/tex] = 70·i - 125.28·j
Therefore, |v| = √(70² + (-125.28)²) ≈ 143.51
The speed of the package as it lands, |v| ≈ 143.51 m/s
d) The motion of the package that includes both horizontal and vertical motion is a projectile motion.
Therefore;
The path of the package is the path of a projectile, which is a parabolic shape.
e) As seen by someone on the aeroplane, the horizontal velocity will be
zero, therefore, the package will appear as accelerating directly vertical
downwards.
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What would happen to a 100N gravitational force if both masses were doubled and the radius were
doubled
The force winds up unchanged, at 100 N.
The Earth has a mass of 6.0 x 1024 kg, and the Moon has a mass of 7.3 x 1023
kg. They are separated by a distance of about 3.84 x 105 kilometers. How
much gravitational force do the two bodies exert on one another?
0 1.0 x 1021 N
O 2.0 x 1021 N
o 3.0 x 1021 N.
O 4.0 x 1021 N
The amount of gravitational force the two bodies exert on one another is [tex]2.0 \times 10^{27} \;Newton[/tex].
Given the following data:
Mass of Moon = [tex]7.3 \times 10^{23}\; kg[/tex]Mass of Earth = [tex]6.0 \times 10^{24}\; kg[/tex]Radius = [tex]3.84 \times 10^5\; kilometers[/tex]Scientific data:
Gravitational constant = [tex]6.67\times 10^{-11}[/tex]To determine the amount of gravitational force the two bodies exert on one another, we would apply Newton's Law of Universal Gravitation:
Mathematically, Newton's Law of Universal Gravitation is given by the formula:
[tex]F = G\frac{M_1M_2}{r^2}[/tex]
Where:
F is the gravitational force.G is the gravitational constant.M is the mass of object.r is the distance between centers of the masses.Substituting the given parameters into the formula, we have;
[tex]F = 6.67\times 10^{-11} \times \frac{7.3 \times 10^{23} \; \times \;6.0 \times 10^{24}}{(3.84 \times 10^5)^2}\\\\F = 6.67\times 10^{-11} \times \frac{4.38 \times 10^{48} }{1.48 \times 10^{11} }\\\\F=\frac{2.92 \times 10^{38} }{1.48 \times 10^{11}} \\\\F= 2.0 \times 10^{27} \;Newton[/tex]
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1) A plane takes off from an O'Hare runway heading due west with a speed of 210.1 m/s. Once in the air, it encounters a north wind (blowing south) with a speed of 55.0 m/s. What is the magnitude of its velocity relative to the ground?
2) What is the direction of the resulting velocity (relative to its initial direction)?