The question is incomplete, the complete question is;
Assume that your empty crucible weighs 15.98 g, and the crucible plus the sodium bicarbonate sample weighs 18.56 g. After the first heating, your crucible and contents weighs 17.51 g. After the second heating, your crucible and contents weighs 17.50 g.
What is the theoretical yield of sodium carbonate?
What is the experimental yield of sodium carbonate?
What is the percent yield for sodium carbonate?
Which errors could cause your percent yield to be falsely high, or even over 100%?
Answer:
See Explanation
Explanation:
We have to note that water is driven away after the second heating hence we are concerned with the weight of the pure dry product.
Hence;
From the reaction;
2 NaHCO3 → Na2CO3(s) + H2O(l) + CO2(g)
Number of moles of sodium bicarbonate = 18.56 - 15.98 = 2.58 g/87 g/mol
= 0.0297 moles
2 moles of sodium bicarbonate yields 1 mole of sodium carbonate
0.0297 moles of 0.015 moles sodium bicarbonate yields 0.0297 * 1/2 = 0.015 moles
Theoretical yield of sodium carbonate = 0.015 moles * 106 g/mol = 1.59 g
Experimental yield of sodium bicarbonate = 17.50 g - 15.98 g = 1.52 g
% yield = experimental yield/Theoretical yield * 100
% yield = 1.52/1.59 * 100
% yield = 96%
The percent yield may exceed 100% if the water and CO2 are not removed from the system by heating the solid product to a constant mass.
How does percolation filter water?
Answer:
Explanation:
Percolation is a natural process in which surface water is gradually filtered through the soil into aquifers. When groundwater is depleted, recycled water can be introduced into aquifers by letting it gradually filter through the soil When you hear the word “percolation,” making coffee probably comes to mind.
Is this equation balanced or unbalanced?
C+02=CO2
How many ML of 1.2 52 M KOH would be required to completely neutralize 9.55 ML of 0.114 HF
Answer:
0.871 mL
Explanation:
Step 1: Write the balanced neutralization reaction
KOH + HF ⇒ KF + H₂O
Step 2: Calculate the reacting moles of HF
9.55 mL of 0.114 M HF react.
9.55 × 10⁻³ L × 0.114 mol/L = 1.09 × 10⁻³ mol
Step 3: Calculate the moles of KOH needed to react with 1.09 × 10⁻³ moles of HF
The molar ratio of KOH to HF is 1:1. The moles of KOH needed are 1/1 × 1.09 × 10⁻³ mol = 1.09 × 10⁻³ mol.
Step 4: Calculate the volume of KOH solution that contains 1.09 × 10⁻³ moles of KOH
An unknown volume of 1.252 M KOH solution contains 1.09 × 10⁻³ moles of KOH.
1.09 × 10⁻³ mol × 1 L/1.252 mol = 8.71 × 10⁻⁴ L = 0.871 mL
When a mixture of oxygen and hydrogen is ignited in a test tube, the
reaction shown occurs. What happens to the total mass of the contents of
the test tube?
Answer:
follow me and pm and I answer your question
Which type of molecule is shown below?
A. Cyclic alkene
B. Alkene
C. Alkyne
D. Cyclic alkane
Answer:
D. Cyclic alkane
Explanation: there is no double or triple bond
The type of molecule that is shown below in the picture is a cyclic alkane. The correct option is D.
What is the cyclic alkane?This is the compound that contain hydrogen and carbon bond. They are mono cyclic saturated hydrocarbons.
These are the atoms that replace the hydrogen atom in an organic compound.
Thus, the correct option is D. Cyclic alkane.
Learn more about cyclic alkane
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How many hydrogen atoms are in 709 grams of water? Answer in units of atoms.
Answer:
26 Hydrogen atoms
Explanation:
H2O
Each hydrogen atom: 2+16 = 18g
Hence,
1 atom -> 18g
x atoms -> 709g
709/18 = 39 atoms
Therefore, 39 atoms give 709g
Hence, 26 Hydrogen atoms are used
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HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start with 155,8 grams of
iron (Fe), how many grams of copper (Cu) will be produced?
2Fe + 3CuCl2 à 2FeCl3 + 3Cu
Answer: 30.978
Explanation:
From the equation 2 moles of Fe will result in 3 moles copper
so .325 moles Fe will result in .4875 moles Cu
Cu weights 63.546 gm per mole
.4875 moles * 63.546 gm / mole = 30.978 gm of Cu
What is the volume of a brick with a Length of 5cm, height of 1cm, and a
width of 2cm. *
O 8cm
O 10cm
15cm
O 12cm
all answer are cubed. I just couldn't add the cube symbol to the answer choices
Answer:
The answer is 10cm^3
Explanation:
5x1x2=10
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meaning of alchol in one word
Identify the true statement(s). There may be one answer or more than one answer.FADH2 is a reducing agent. FADH2 is an oxidizing agent. NADH is an oxidizing agent. NADPH is a reducing agent. FAD is an oxidizing agent.
Answer:
FADH2 is a reducing agent.
FAD is an oxidizing agent.
Explanation:
The full form of FAD is flavin adenine dinucleotide. It is mainly a redox-active coenzyme which is associated with the different proteins and is involved with the enzymatic reactions in the metabolism.
FAD is obtained by donating or accepting electrons.
In the citric acid cycle,
succinate + FAD → fumarate + [tex]$FADH_2$[/tex]
Thus we see that FAD is an oxidizing agent while [tex]$FADH_2$[/tex] is a reducing agent.
write the manufacturing process of oxygen gas from liquid air
Answer:
Production of liquid oxygen from air Oxygen is generated by liquefaction of atmospheric air in the air separation unit (ASU). Cryogenic technique is the most commonly used for producing liquid oxygen for industrial and medical applications .
Explanation:
An air separation unit (ASU) uses continuous cryogenic distillation to continuously liquefy ambient air and separate the oxygen gas.
What is oxygen?Oxygen is the second largest abundant element in the atmosphere comprising 20.8% by volume. Despite being mostly used as a gas, oxygen is frequently stored as a liquid. Compared to high-pressure gaseous storage with a similar capacity, liquid storage is less expensive and bulkier.
A cryogenic storage tank, one or more vaporizers, and a pressure control system make up a typical storage system. The cryogenic tank is built similarly to a vacuum bottle.
The primary air compressor is where the ASU manufacturing process starts, and the product storage tanks' output is where it concludes. Moisture, carbon dioxide, and hydrocarbons are taken out of the air after it has been compressed and put through a purification system.
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. When is separation of substances necessary ?Name four methods used to separate solid substances ?
the one of 2 who send correct answer will get the brainliest and 40 points
When an acid reacts with a strong base which product always forms
Answer:طيزي
Explanation:
Water moves on, above or under the surface of the Earth true or false
above because its above
You want to decaffeinate your coffee by extracting the caffeine outwith dichloromethane. It's too late to extract the caffeinefrom the coffee beans because you've already brewed yourself a 200mL cup of coffee. Your particular brand of coffee contains100 mg of caffeine in that 200mL cup. The partitioncoefficient of caffeine in dichloromethane/water is 9.0.
How much caffeine would still be in your 200 mL if you did:
A. One extraction using 200 mL o fdichloro methane
B. Two extractions using 100 mL of dichloro methane each.
Solution :
The partition coefficient
[tex]$k_d= \frac{\text{(mass of caffeine in }CH_2Cl_2 / \text{volume of }CH_2Cl_2)}{\text{(mass of caffeine in water/ volume of water)}}$[/tex]
= 9.0
A). 1 x 200 mL extraction
Let m be the mass of caffeine in water
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m
∴ [tex]$\frac{(100-m)/200}{m/200}=9$[/tex]
[tex]$\frac{100-m}{m}=9$[/tex]
[tex]$10 \ m = 100$[/tex]
[tex]$m=\frac{100}{10}$[/tex]
= 10
Therefore, the mass remaining in the coffee is m = 10 mg
B). 2 x 100 mL extraction
First extraction :
Let [tex]$m_1$[/tex] be the mass of the caffeine in water.
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m
∴ [tex]$\frac{(100-m_1)/100}{m_1/200}=9$[/tex]
[tex]$\frac{100-m_1}{m_1}=9$[/tex]
[tex]$5.5 \ m_1 = 100$[/tex]
[tex]$m_1=\frac{100}{5.5}$[/tex]
= 18.18
Mass remaining in the coffee after the 1st extraction [tex]$m_1$[/tex] = 18.18 mg
Second extraction:
Let [tex]$m_2$[/tex] be the mass of the caffeine in water.
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 18.18 - [tex]$m_2$[/tex]
∴ [tex]$\frac{(18.18-m_2)/100}{m_2/200}=9$[/tex]
[tex]$\frac{18.18-m_2}{m_2}=9$[/tex]
[tex]$5.5 \ m_2 = 18.18$[/tex]
[tex]$m_1=\frac{18.18}{5.5}$[/tex]
= 3.3
Mass remaining in the coffee after the 1st extraction [tex]$m_2$[/tex] = 3.3 mg
OH- of a solution that has a pH of 8.57
Answer:
I think its -8.75
Explanation:
Hope this helps!11
Which compound is an isomer of CH3CH2OH?
A) CH3OCH3
B) CH3COOH
C) CH3COCH3
D) CH3CH2CH3
identify and name the functional
present in (i) C₂ H₂ (ii). CH₃ CH₂OH.
Answer:
I)Acetylene
II)2-Methyl-1-butanol
Explanation:
I)appears as a colorless gas with a faint garlic-like odor. Easily ignited and burns with a sooty flame. Gas is lighter than air.
A plot of binding energy per nucleon (Eb/ A) versus the mass number (A) shows that nuclei with a small mass number have a small binding energy per nucleon, as the mass number increases the binding energy per nucleon increases, and the value for the binding energy per nucleon has a maximum value for nuclei with a mass number around 60. Verify that this is the case by determining the binding energy per nucleon for each of the following four nuclei. (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of 2H be 2.0141 u, the mass of 7Li be 7.0160 u, the mass of 62Ni be 61.9283 u, and the mass of 110Cd be 109.9030 u.
a. 2H
b. 7Li
c. 62Ni
d. 110Cd
Answer:
a) 1.12 MeV / nucleon
b) 5.62 MeV / nucleon
c) 8.80 MeV / nucleon
d) 8.56 MeV / nucleon
we can conclude that the binding energy has a maximum value for nuclei with a mass around 60
Explanation:
Binding energy = ( Δm * 931.5 ) MeV
Binding energy per nucleon = Binding energy in / Number of nucleon
a) ²H = 1 neutron , 1 proton = 2 nucleons
Given that the theoretical mass = 2.0141 u
Actual mass = 1.0078 u + 1.0087 u = 2.0165 u
Δm = 2.0165 u - 2.0141 u = 2.4 * 10^-3 u
∴ Binding energy per nucleon = ( 2.4 * 10^-3 * 931.5 ) MeV / 2 nucleons
= 1.12 MeV / nucleon
b) ⁷Li = 3 protons , 4 neutrons = 7 nucleons
theoretical mass = 7.0160 u
Actual mass = ( 3 * 1.0078 ) + ( 4 * 1.0087 ) = 7.0582 u
Δm = ( 7.0582 u - 7.0160 u ) = 0.0422 u
∴ Binding energy per nucleon = ( 0.0422 * 931.5 ) / 7
= 5.62 MeV / nucleon
C) ⁶²Ni = 28 protons , 34 neutrons = 62 nucleons
Theoretical mass = 61.9283 u
Actual mass = ( 28 * 1.0078 ) u + ( 34 * 1.0087 ) u
= 62.5142 u
Δm = 0.5859 u
∴ Binding energy per nucleon = ( 0.5859 * 931.5 ) / 62
= 8.80 MeV / nucleon
D) ¹¹⁰Cd = 48 protons , 62 neutrons = 110 nucleons
Theoretical mass = 109.9030 u
Actual mass = ( 48 * 1.0078 ) + ( 62 * 1.0087 )
= 110.9138 u
Δm = ( 110.9138 - 109.9030 ) = 1.0108 u
∴ Binding energy per nucleon = ( 1.0108 * 931.5 ) / 110
= 8.56 MeV / nucleon
hence we can conclude that the binding energy has a maximum value for nuclei with a mass around 60
1. Rearrange the letters to form a word.
1. OOTPSIL
2. BCDEROK
3. UHMSU
4. AOML
5. LCYA
science po ito
1- Topsoil
2- Bedrock
3- Humus
4- Loam
5- Acyl, Clay, or Lacy
Well that was fun :)
Answer:
Explanation:
1. TOPSOIL
2. BEDROCK
Predict the effect of an eightfold pressUre increase on the equillbrium composition of the reaction 3 Nalg) + H2lg) 2 NaHlg)
Answer:
See explanation
Explanation:
Given the reaction;
3N2(g) + H2(g) = 2N3H(g).
We know that when a constraint is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.
In this case, when the pressure is increased eightfold, the equilibrium position will shift towards the direction where there is the least total volumes.
In this particular reaction, the forward reaction has the least total volumes and is favoured by an eightfold increase in pressure.
Hence, when the pressure is increased eightfold, more N3H(g) is obtained.
Calculate the mass of 100.0 mL of a substance whose density is 19.32 kg/L. Express your answer in kilograms using the correct number of significant figures. Do not enter your answer using scientific notation.
Answer:
1.932 kg
Explanation:
First we convert 100.0 mL to L:
100.0 mL / 1000 = 0.1000 LThen we calculate the mass of the substance, using the definition of density:
Density = mass / volumemass = density * volume19.32 kg/L * 0.1000 L = 1.932 kgAs the multiplication involves two numbers of 4 significant figures each, the answer needs to have 4 significants figures as well.
what is the name of the functional group of pentanoic acid
Answer:
organic acid
Explanation:
Answer:
Hey mate.....
Explanation:
This is ur answer.....
Alkyl carboxylic acid
Valeric acid (pentanoic acid) is a straight-chain alkyl carboxylic acid with a very unpleasant odor. It is found naturally in the perennial flowering plant valerian (Valeriana officinalis), from which it gets its name.
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Calculate the volume occupied
at s.t.p by 6.89
gas [H = 10, N = 14
Answer:
9.07 L
Explanation:
Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0].
Step 1: Given and required data
Mass of NH₃ (m): 6.89 gMolar mass of NH₃ (M): 17.0 g/molStep 2: Calculate the moles (n) of NH₃
We will use the following epxression.
n = m / M
n = 6.89 g / (17.0 g/mol) = 0.405 mol
Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP
At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).
0.405 mol × 22.4 L/1 mol = 9.07 L
. Describe the movement of the Earth, The moon and the sun?
Answer:
Explanation:
It orbits
HELP ME OMG
A sample of xenon gas collected at a pressure of 1.15 atm and a temperature of 279 K is found to
occupy a volume of 786 milliliters. How many moles of Xe gas are in the sample?
mol
n = 0.0395 mol Xe
Explanation:
Use the ideal gas law:
PV = nRT
n = PV/RT
= (1.15 atm)(0.786 L)/(0.08205 L-atm/mol-K)(279K)
= 0.0395 mol Xe
The shapes of the drops relate to the attractive forces between molecules in a compound. Based on their shapes, how does the attractive force between the water molecules compare with the attractive force between the oil molecules?
Answer:
Water molecule has hydrogen bonding and surface tension
Explanation:
Intermolecular behavior of water is different from that of the intermolecular force of oil because water molecule is polar in nature while oil molecule is non polar. Dur to polar nature, water molecule has high surface tension which keep its atoms intact. Also the water molecule being polar also exhibit hydrogen bonding between hydrogen (+ive) and oxygen atom (-ive)
Calculate the density of a solid substance if a cube measuring 2.54 cm on one side has a mass of 108 g/cm3
Answer:
6.59 g/cm³
Explanation:
Step 1: Given data
Side of the cube (s): 2.54 cmMass of the cube (m): 108 gStep 2: Calculate the volume of the cube
We will use the following expression.
V = s³ = (2.54 cm)³ = 16.4 cm³
Step 3: Calculate the density of the solid
Density is an intrinsic property, equal to the quotient between the mass and the volume.
ρ = m/V
ρ = 108 g / 16.4 cm³ = 6.59 g/cm³
1.State two uses of water at home.
2. State two uses of water in industries.
3. What is water conservation?
4. What are some methods of water conservation?
Helppppp!!!!!!
Answer:
1. Washing dishes and cooking
2. Water is used as a solvent in the manufacture of beverages and it is also largely used in agriculture.
3. Water conservation is the action of using water wisely and not wasting it.
4. i) Wash dishes in a tub of water instead of under a running tap.
ii) Use a pail of water to wash the car instead of spraying water from a hose.
iii) Make sure that there are no leaking or broken taps and pipes.
Answer:
Washing dishes and cooking
2. Water is used as a solvent in the manufacture of beverages and it is also largely used in agriculture.
3. Water conservation is the action of using water wisely and not wasting it.
4. i) Wash dishes in a tub of water instead of under a running tap.
ii) Use a pail of water to wash the car instead of spraying water from a hose.
iii) Make sure that there are no leaking or broken taps and pipes.
Explanation:
Use the chart above to help you answer the following questions.
2Na + 2HCI →
2 NaCl
+ H
(s)
(aq)
(aq) 2(g)
? What are the reactants in the chemical reaction shown above?
Answer:
2Na and 2HCl
Explanation:
The equation for the above chemical reaction is as follows:
2Na + 2HCI → 2NaCl + H2
In a reaction, the reactants are said to be those that combine together to form products. In this case, sodium (Na) and hydrochloric acid (HCl) are the reactants of this reaction