Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life periods

Answers

Answer 1

The number of hours required : 37.2 hours

Further explanation

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

[tex]\tt 3\times 12.4=37.2~hours[/tex]

Based On Table N Of The Reference Tables What Is The Number Of Hours Required For 42k (potassium -42)

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Answers

Answer: The concentration of the resulting solution is 0.025 M

Explanation:

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[tex]V_1[/tex] = volume of concentrated [tex]NaOH[/tex] solution = 50 ml

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The concentration of a solution can be calculated by using the following formula:

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1 × 50 = C2 × 2000

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C2 = 0.025M

Therefore, the concentration of the resulting solution if 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L is 0.025M.

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