Hi there!
II. Linear momentum of the system is zero.
This is an example of a RECOIL collision. With the Law of Conservation of Momentum, momentum remains constant before and after the collision.
Thus, the total momentum would also be equivalent to zero after the collision.
Is it raining anywhere else because it is about to start pouring where I live
Current Forecast is:
Sunny with a temp of 67 deg F, as of rn there is no clouds in the sky
Location, Oklahoma USA in the NE corner
____________ is a medium-sized flat-topped hill with cliff-face sides that is taller than it is wide.
Answer:
mesa
Explanation:

A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.
What is the weight of sugar if 5% of sugar from 6g of sugar
The momentum of a system is conserved:
I. when no net external force act on the system
II. when no internal forces act on the system
III. always
Answer:
I. when no net external force act on the system
Explanation:
Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).
General kinematics problem.
"Anna is returning from vacation driving down the Sunshine Highway. She travels for a stretch (SA) at a speed of 110 km/h. Then, due to an increase in traffic, Anna is forced to reduce her speed by travelling the second part of the journey (SB) at 60 km/h. The total distance and duration of the trip are 350 km and 4.0 hours respectively.
-> Calculate the time intervals needed to travel SA and SB
-> Calculate the distances covered in the two sections SA and SB".
The results I should get by doing the exercise are in the attached picture.
If you could explain the various steps in the problem you would be doing me a huge favor. Thanks!
Explanation:
What we know:
Sa + Sb = 350 km
Ta + Tb = 4h
S = Vt
With these equations above we can write a system of equations and find Tb, as you see in the picture(s).
After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.
1. Which among the sports you stated above are you familiar with?
I am familiar with Russian Mountaineering
Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.
Answer:
Sound waves bend around the corners of various obstacles.
Explanation:
I took the test
[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,
[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]
[tex]it \: was \: helpful \: to \: you[/tex]
# be careful#
A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2. 15, 2. 05, 02. 02, 02. 7. Use the table to answer the questions. What is the fastest time trial for the first quarter checkpoint? seconds What is the slowest time trial for the first quarter checkpoint? seconds What is the range of times measured for this checkpoint? seconds.
The fastest time trial for the first quarter checkpoint is 2.02 s.
The slowest time trial for the first quarter checkpoint is 2.7 s.
The range of the times measured for the checkpoint is 0.68 s.
The given parameters;
Time for quarter checkpoint, = 2.15, 2.05, 2.02, 2.7The fastest time trial for the first quarter checkpoint is the least measured time value.
fastest time trial = least time measured
fastest time trial = 2.02 s
The slowest time trial for the first quarter checkpoint is the highest measured time value.
slowest time trial = 2.7 s
The range of the times measured for the checkpoint is difference between the fastest time and slowest time.
Range = fastest time - slowest time
Range = 2.7 - 2.02
Range = 0.68 s
Learn more about range of data here: https://brainly.com/question/24326172
Answer:
2.02, 2.15, 0.13
Explanation:
A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2.15, 2.05, 2.02, 2.07.
Use the table to answer the questions.
What is the fastest time trial for the first quarter checkpoint?
2.02
seconds
What is the slowest time trial for the first quarter checkpoint?
2.15 seconds
What is the range of times measured for this checkpoint?
0.13 seconds
40 POINTSS. Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fingertip. Note how much opposition to your push you feel. Repeat the steps, but this time push the piece of plastic or wood across a rug, carpet, or piece of fabric. If you’re using fabric, be sure to secure the fabric so it doesn’t move. How does the opposition to motion on the tabletop compare with that of the rug, carpet, or fabric? WILL MARK BRAINLIST IF RIGHT
Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.
The Earth has a mass of 6.0 x 1024 kg, and the Moon has a mass of 7.3 x 1023
kg. They are separated by a distance of about 3.84 x 105 kilometers. How
much gravitational force do the two bodies exert on one another?
0 1.0 x 1021 N
O 2.0 x 1021 N
o 3.0 x 1021 N.
O 4.0 x 1021 N
The amount of gravitational force the two bodies exert on one another is [tex]2.0 \times 10^{27} \;Newton[/tex].
Given the following data:
Mass of Moon = [tex]7.3 \times 10^{23}\; kg[/tex]Mass of Earth = [tex]6.0 \times 10^{24}\; kg[/tex]Radius = [tex]3.84 \times 10^5\; kilometers[/tex]Scientific data:
Gravitational constant = [tex]6.67\times 10^{-11}[/tex]To determine the amount of gravitational force the two bodies exert on one another, we would apply Newton's Law of Universal Gravitation:
Mathematically, Newton's Law of Universal Gravitation is given by the formula:
[tex]F = G\frac{M_1M_2}{r^2}[/tex]
Where:
F is the gravitational force.G is the gravitational constant.M is the mass of object.r is the distance between centers of the masses.Substituting the given parameters into the formula, we have;
[tex]F = 6.67\times 10^{-11} \times \frac{7.3 \times 10^{23} \; \times \;6.0 \times 10^{24}}{(3.84 \times 10^5)^2}\\\\F = 6.67\times 10^{-11} \times \frac{4.38 \times 10^{48} }{1.48 \times 10^{11} }\\\\F=\frac{2.92 \times 10^{38} }{1.48 \times 10^{11}} \\\\F= 2.0 \times 10^{27} \;Newton[/tex]
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place any object (textbook, pen, or eraser) on a floor what happens then
Answer:
The force of gravity on earth, no matter the object is approximately 9.8 m/ s2 . The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.
if a tent is touched with a finger on inner surface , when it is raining , it allows the rain water to leak through. give a reason for this observation
Explanation:
When water vapor in the air comes into contact with something cool, like the ceiling of a tent, its molecules slow down and get closer together. When that happens, the gaseous water vapor turns back into liquid water droplets. That's condensation!
What would happen to a 100N gravitational force if both masses were doubled and the radius were
doubled
The force winds up unchanged, at 100 N.
Which are the most likely products for the following reaction? Zn + CuSO4 --> ?
Answer:
It's going to be a single displacement reaction
So we'll get ZnSO4 + Cu for the following reaction Zn + CuSO4
Equation:
Zn + CuSO4 ------> Cu + ZnSO4
A student on a bicycle decided to determine his acceleration when coasting down a steep hill. The student started from a full stop and reached a velocity of 8.75 m/s in 3.8 s. What was his average acceleration? Assume that downhill is the positive direction.
Answer:
A=2.2
Explanation:
You have to lay everything out first.
You are given the:
Velocity and the time
V=8.75m/s
t=3.8s
Now you need to know what you are looking for, and that is the average acceleration.
Write down the formula (teachers like this)
A=v/t
Now calculate:
8.75/3.8= 2.3026315789473
You can now round down since the number next to the decimal is below 5
The number of significant digits will be 2 because that is the lowest number in the question. This means you will only need to display 2 numbers.
The final answer will be:
A=2.2
:)
*make sure to show your work step by step, some nice teachers give extra marks for that*
I hope this helped, goodluck! :D
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
1
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
A certain satellite is in circular orbit about the earth at an altitude of 550km. If the satellite makes a revolution in 110minutes, calculate its orbital speed
Answer:
Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].
The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:
[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].
Convert the units of both distance and time to standard units:
Orbital radius:
[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].
Orbital period:
[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].
Calculate the circumference of this orbit:
[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].
Calculate the orbital speed (tangential) of this satellite:
[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].
the impulse-momentum relationship is a direct result of
Newton's second law.
__________________
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The impulse-momentum relationship is a direct result of Newton's second law of motion.
What is the impulse-momentum?The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. It proves that the change in momentum of an object depends not only on the amount of force applied but also on the duration of force applied.
Newton's second law states that the force acting on an object is equal to the rate of change of its momentum.
This means that a force applied to an object will cause a change in its momentum. The impulse-momentum relationship describes the relationship between the force applied to an object and the resulting change in its momentum.
The impulse-momentum relationship states that the impulse acting on an object is equal to the change in its momentum.
Impulse is defined as the force applied to an object over a period of time, while momentum is the product of an object's mass and velocity. Therefore, the impulse-momentum relationship can be expressed as:
Impulse = Change in momentum
This relationship is important in understanding the behavior of objects in motion, particularly in collisions or other situations where forces act over a period of time.
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how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air
A 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?
Help!!
Answer:
500 J.
Explanation:
Work done = force * distance
= 25 * 20
= 500 Joules.
whats 10x10 PLEASE I NEED THIS
Answer:
100
Explanation:
El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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PLEASE HELP MEEEEE 80 points on the line and i need this done
Answer:
5) A 200n
F net=0n
6) B 50n
F net=0n
7) C 200n
F net= 900n, up
8) D 80n
F net=60n,left
9) E 300n
F net=60n,left
10)???
11) G 20n
F net=30n,Right
__________________________________
All the answers is hard
correct me if i'm wrong
given the formula p=mv what are the units of p
Answer:
They are kg * m/s.
The unit of the momentum p would be kg × m/s..
What is momentum?Momentum is defined as the ability or tendency of an object to continue moving.
Also momentum is the product of mass and velocity. It can be shown as follows;
p = m × v
where,
p = momentum
m = mass
v = velocity
Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.
Now the unit of the momentum p would be;
p = m × v
p = kg × m/s
Hence, the unit of the momentum p would be kg × m/s.
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A man pushes a box with a force of 75N across a 12M loading dock. How much work did he do on the box?
Once again, Have a Happy, Merry Christmas!! =)
Answer: 75n,a * (12m)
Explanation I'm trying to understand the question but this is what i got.
Happy Holidays!
We can use the following equation to calculate work done on an object.
W = F · d
Work (J) = Force (N) · displacement (m)
Plug in the given values into the equation:
W = 75 · 12 = 900 J
If you are soaking wet and the water on your clothes evaporates, you will feel cold. Explain the cooling effect in the terms of kinetic theory.
Evaporation is a type of vaporization which usually occurs in liquid when molecules of that liquid transform into the gaseous phase.
Evaporation causes cooling. This is because, when a molecule wants to evaporate, it requires heat to do so.
This heat is derived from the surface from which the molecule is about to evaporate. The emission of heat from this surface results in the cooling of the surface left behind.
Kinetic Theory and Evaporation.Liquid molecules are in constant random motion while possessing different velocities.
Molecules which are near the surface possess higher velocities and kinetic energy escape from the surface.
Since the average kinetic energy is a measure of temperature, it implies that the temperature is lowered and hence a person who is soaking wet feels cold when evaporation occurs.
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The mass of a sample of sodium bicarbonate is 2. 1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and 1 Times. 109 nanograms (ng) in 1 g. What is the mass of this sample in ng? 2. 1 Times. 103 ng 2. 1 Times. 106 ng 2. 1 Times. 109 ng 2. 1 Times. 1012 ng.
2.1 kg of sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample. Option D is correct.
Mass is the quantity of the substance in the body or object. The SI unit of mass is Kilogram.
There are other units of measure,
Milligram: 1 g is equal to the [tex]\bold {10^3 \ mg}[/tex]Micro-gram: 1 g is equal to [tex]\bold {10^{6} \ \mu g}[/tex]Nano-gram: 1 g is is equal to[tex]\bold {10^{9} \ ng}[/tex]First convert kg to gram,
Since, 1 Kg = 1000 g
2.1 kg = grams of sample
So,
Do the cross multiplication,
[tex]\rm mass\ of\ sample = \dfrac {2.1\ kg \times 1000\ g }{ 1 kg}\\\\\rm mass\ of\ sample =2100 g[/tex]
Now, convert 2100 g to nano-grams
Since, 1 g = 1 x 10⁹ ng
2100 g = ng of sample
So,
Do the cross multiplication,
[tex]\rm mass\ of\ sample = \dfrac {2100 g \times 1 \times 10^9 ng }{1\ g}\\\\\rm mass\ of\ sample = 2.1 \times 10^1^2 ng[/tex]
Therefore, 2.1 kg of sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample.
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Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?
Answer:
Density of the mixture = 855.56kgm-3
Explanation:
Density = Mass / Volume
Volume of Liquid X = 0.5m³
Density of Liquid X = 900kgm-3
Mass of Liquid X = Density × Volume
= 900kgm-3 × 0.5m³ = 450kg
Volume of Liquid Y = 0.4m³
Density of Liquid Y = 800kgm-3
Mass of Liquid Y = Density × Volume
= 800kgm-3 × 0.4m³= 320kg
As X and Y are mixed, we add their masses and volumes together:
Mass = 770kg
Volume = 0.9m³
Now we can find the density of the mixture:
Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)
Annie comes to a sudden stop to avoid hitting a deer crossing the road at night. As she hits the breaks, her speed drops from 12 m/s to zero in 1.5 seconds.(p1) How far did she travel during that time? (p2)What was her average acceleration?
Distance(p1)
9 m
8 m
10 m
13.5 m
Acceleration(p2)
6 m/s2
8 m/s2
12 m/s2
16 m/s2
Answer:
1. around 22m
Explanation:
Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².
Annie's initial speed was 12 m/s.
Her final speed was 0 m/s.
The time it took her to stop was 1.5 seconds.
Therefore, the distance she traveled during that time is:
distance = (initial speed + final speed)/2 * time
= (12 m/s + 0 m/s)/2 * 1.5 seconds
= 9 meters
Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.
In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.
The time it took for this change to occur is 1.5 seconds.
Therefore, Annie's average acceleration is:
acceleration = change in velocity / time
= -12 m/s / 1.5 seconds
= -8 m/s²
The negative sign indicates that Annie was slowing down.
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