A 2 kg wagon is being pulled by a kid with a force of 0.1 N to the right. Determine the acceleration of the wagon

Answer:

e = k q / r² then,

e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C

hope this helps ❤.

Answer:

Earth

Explanation:

The sun and the moon come together and they seem like one bonded.

Answer:

Explanation:

Power is the rate at which work is done and can be found by using the formula

[tex]p = \frac{w}{t} \\ [/tex]

p is the power in Watts (W)

w is the workdone in joules

t is time in s

but workdone = force × distance

From the question

force = 780 N

distance = 2 m

workdone = 780 × 2 = 1560 N

Since we now have the value of workdone we can find the power

We have

[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.

A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.

The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.

Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.

The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.

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Answer:   biogeochemical process

Explanation:

Force = mass x acceleration:

5N = 1kg x acceleration

Acceleration = 5N / 1 kg

Acceleration  = 5 m/s^2

Acceleration is a positive value so it is speeding up

Answer:

it is B

Explanation:

Answer:

CO and H20

Explanation:

Answer:

Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:

S = Vt + S0

With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).

From this you can calculate t, if that's what you want.

Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

The time for the projectile to hit the ground from the given position is 1.5 s.

The given parameters:

The time for the projectile to hit the ground is calculated as follows:

when the projectile hits the ground, the final velocity = 0

[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]

Thus, the time for the projectile to hit the ground from the given position is 1.5 s.

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D)

Explanation:

Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

The speed at which the arrow would be launched is 133.42 m/s

The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.

The equation for the work-energy theorem can be computed as:

[tex]\mathbf{W =\Delta K.E}[/tex]

[tex]\mathbf{F\Delta x =\dfrac{1}{2} mv^2}[/tex]

where;

From the above equation, let make speed(v) the subject of the formula:

∴

[tex]\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }[/tex]

[tex]\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }[/tex]

v = 133.42 m/s

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Answer:

The density of the substance is

[tex]0.85\: \: g \: \: \: {cm}^{ - 3}[/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

[tex]\boxed {\boxed {\sf 4 \ Newtons}}}[/tex]

Explanation:

Work is energy transferred when an object is moved. It is the product of force and distance.

[tex]W= F*d[/tex]

John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.

Substitute the values into the formula.

[tex]3.2 \ N *m = F * 0.8 \ m[/tex]

We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.

[tex]\frac {3.2 \ N*m}{0.8 \ m}= \frac{ F* 0.8 \ m}{0.8 \ m}[/tex]

The units of meters cancel.

[tex]\frac {3.2 \ N}{0.8 }=F[/tex]

[tex]4 \ N = F[/tex]

John must exert 4 Newtons of force.

Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.

Answer:

Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.

The number of variations the dealership have is 40 cars.

Data given;

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

[tex]4*2*5=40[/tex]

From the above calculation, we can say that the variations the dealership offers is 40

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Answer:

C

Explanation:

because the concave mirror is always inverted

d )  when object is between focus and mirror , image formed is always virtual and erect

A concave mirror has a reflective surface that is curved inward and away from the light source .

a) Incorrect because image can be equal to , smaller then , and bigger then the object

b) and c)  Incorrect when object is between focus and mirror , image formed is virtual and erect

d ) Correct option  when object is between focus and mirror , image formed is always virtual and erect

e) Incorrect except one case in all other cases nature is real and inverted

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[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]

Or

[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]

Answer:

[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.

Explanation:

The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].

If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.

The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].

The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:

[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].

(The new velocity of the log is negative because the log would be moving away from the beaver.)

The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].

Answer:

Explanation:

Centrifugal force Fc = m x v2 / r

Weight  = mg

As required by the question

Fc = W

v2 /r = g

given radius r = 22 m

v2 /22 = 9.8

Solve for v

required speed v = √(22 * 9.8)

= 14.35 m/s

v=15 m/s

this may help you

The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.

The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.

The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:

[tex]{\displaystyle F=m\omega ^{2}r}[/tex]

Given, the radius of the curve, r = 22m

The acceleration, a = v²/r

The weight of the box, W = mg

We know that, F = ma

mg = m(v²/r)

v = √gr

[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]

v = 14.68 m/s

Therefore, you should drive at a speed of 14.68 m/s

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Answer:

1 N

Explanation:

1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.

Ftot = |F1 - F2| = 6N - 5N = 1N

2)The direction will be the same as the greater force's direction.

Answer:

acid rain corrodes a monument. d.

Explanation:it only makes sense because its doing something to a physical object.and the other ones aren't.

Sorry your tired, ill try to make it worth reading.

One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.

Answer:

$2140

Explanation:$2000 missing plus 7 percent of 2000 is 140 so 2000+140=2140. Each month she would pay $268 approx.

The Thrust on the rocket is 1.434 MN.

To calculate the thrust of a rocket, we use the formula below

Thrust: This is the force that moves an aircraft through the air.

⇒Formula

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, the Thrust on the rocket is 1.434 MN.

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Answer:

Explanation:

There are only two forces causing motion involved. They oppose each other. You know this because there is no acceleration of the sled: you see only a velocity.

The formula when friction is involved is

Fnet = T - mu*Normal

mu is the frictional coefficient

The normal is the downward force caused by the mass of the sled being pulled down by the gravitational constant.

The tension is brought about by the dog pulling in the opposite direction to the frictional force.

The frictional force, oddly, acts in a horizontal direction even though the normal is vertical. It does this because friction always opposes motion.

Since there is no acceleration, the net force = 0

N= m * a_g

m = 1.2 kg

a_g = 9.8

N = 1.2 * 9.8

N = 11.76

The frictional force = mu*Normal Force.

Ff = N * mu

N = 11.76

mu = 0.2

Ff = 0.2 * 11.76

Ff = 2.35

As stated The frictional force and the Tension are equal but in opposite directions

T = 2.35