Answer:
1. and 2. I belive are true sorry if wrong
Step-by-step explanation:
can i get an owa owa ?????
owa owa???
owa owa??
OWA OWA??
OWA OWA??
OWA OWA?Show that if U is open in X, and A is closed in X, then UA is open in X, and A\U is closed in X.
The intersection of N(x) and N'(x), denoted by N(x)∩N'(x), is an open neighborhood of x. Since N(x)∩N'(x) ⊆ N(x) ⊆ U and N(x)∩N'(x) ⊆ N'(x) ⊆ X\U, we can conclude that N(x)∩N'(x) ⊆ UA.
Since N(x)∩A is a non-empty set contained in A\U, we have shown that every point in (A\U)' has a neighborhood contained in A\U. Therefore, (A\U)' is open in X, which implies that A\U is closed in X.
To show that if U is open in X and A is closed in X, then UA is open in X and A\U is closed in X, we need to prove two statements:
UA is open in X.A\U is closed in X.Let's prove these statements one by one:
To show that UA is open in X, we need to prove that for every point x in UA, there exists an open neighborhood around x that is completely contained within UA.Let x be an arbitrary point in UA. Since x is in UA, it must belong to U as well as A. Since U is open in X, there exists an open neighborhood N(x) of x that is completely contained within U. Now, since x is in A, it is also in X\U (complement of U in X). As A is closed in X, X\U is closed in X, which means its complement, U, is open in X. Therefore, there exists an open neighborhood N'(x) of x that is completely contained within X\U.
Now, consider the intersection of N(x) and N'(x), denoted by N(x)∩N'(x). This intersection is an open neighborhood of x. Since N(x)∩N'(x) ⊆ N(x) ⊆ U and N(x)∩N'(x) ⊆ N'(x) ⊆ X\U, we can conclude that N(x)∩N'(x) ⊆ UA.
Since N(x)∩N'(x) is an open neighborhood of x completely contained within UA, we have shown that UA is open in X.
To show that A\U is closed in X, we need to prove that its complement, (A\U)', is open in X.Let x be an arbitrary point in (A\U)'. Since x is not in A\U, it means that x must either be in A or in U (or both). If x is in A, then x is not in A\U. Therefore, x is in U.
Since x is in U and U is open in X, there exists an open neighborhood N(x) of x that is completely contained within U. Now, consider the intersection of N(x) and A. Since x is in A, N(x)∩A is a non-empty set. Let y be any point in N(x)∩A.
We know that N(x)∩A ⊆ U∩A ⊆ A\U, because if y was in U, it would contradict the assumption that y is in A. Therefore, N(x)∩A is a subset of A\U.
Since N(x)∩A is a non-empty set contained in A\U, we have shown that every point in (A\U)' has a neighborhood contained in A\U. Therefore, (A\U)' is open in X, which implies that A\U is closed in X.
Hence, we have shown that if U is open in X and A is closed in X, then UA is open in X, and A\U is closed in X.
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select the correct answer. which expression is equivalent to x 3x2−2x−3÷x2 2x−3x 1 if no denominator equals zero? a. 1x2−2x−3 b. 1x2−4x 3 c. 1x2 2x−3 d. x 3x 1
The correct answer is option c. 1/(x² + 2x - 3). To determine which expression is equivalent to the given expression, let's simplify it step by step:
The given expression is (x³ - 2x - 3) ÷ (x² + 2x - 3).
Option a. 1/(x² - 2x - 3):
This option is not equivalent to the given expression because it represents the reciprocal of the quadratic denominator, which is different from the given expression.
Option b. 1/(x² - 4x + 3):
This option is not equivalent to the given expression because the signs of the quadratic terms are different. The given expression has a positive quadratic term, while this option has a negative quadratic term.
Option c. 1/(x² + 2x - 3):
This option is equivalent to the given expression because it represents the reciprocal of the quadratic denominator with the same signs for the quadratic terms.
Option d. x/(3x - 1):
This option is not equivalent to the given expression because it lacks the term x³ in the numerator.
Therefore, the correct answer is option c. 1/(x² + 2x - 3).
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2.1. let a be the event that 2 consecutive flips both yield heads and let b be the event that the first or last flip yields tails. prove or disprove that events a and b are independent.
The events A and B are not independent. The occurrence of event B affects the probability of event A.
To determine whether events A and B are independent,
we need to check if the probability of event A occurring is affected by the occurrence of event B, and vice versa.
Probability of event A: Since we are flipping two coins,
the probability of getting heads on each flip is 1/2.
Therefore, the probability of getting two consecutive heads is
[tex](1/2) \times (1/2) = 1/4[/tex]
Probability of event B: The first or last flip yielding tails means there are two possibilities:
either the first flip is tails and the second flip is any outcome,
or the first flip is any outcome and the second flip is tails.
Each of these individual possibilities has a probability of
[tex](1/2) \times (1/2) = 1/4[/tex]
Hence, theprobability of event B is 1/4 + 1/4 = 1/2.
Since the probability of event A is 1/4 and the probability of event B is 1/2, and 1/4 ≠ 1/2,
we can conclude that events A and B are not independent.
The occurrence of event B (first or last flip yielding tails) affects the probability of event A (two consecutive flips yielding heads).
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THIS WILL HELP A LOT OF PPL PLZ HLP!!!!!!
Determine the interval where the graph of the function is negative.
ANSWER CHOICES AND GRAPH IN IMAGES
Answer:
If I'm correct I think its answer B
Step-by-step explanation:
I'm not sure but i hope this help
Answer:
second option
-∞ < x < 1
Step-by-step explanation:
please someone answer fast!!! I'm so confused and this is due today
Answer:
From greatest to least it would be 3.66666,[tex]\sqrt{11}[/tex],2(1/4),-2.5,-3.97621
Step-by-step explanation:
Just type in a calc
Answer:
[tex]\sqrt{11}=3.31[/tex], -2.5, [tex]2\frac{1}{2}= 2.25[/tex], 3.6, -3.97621...
Step-by-step explanation:
Greatest to least would be:
3.6, [tex]\sqrt{11}[/tex], [tex]2\frac{1}{4}[/tex], -2.5, -3.97621...
Least to greatest would be:
-3.97621, -2.5, [tex]2\frac{1}{4}[/tex], [tex]\sqrt{11}[/tex], 3.6
Hopefully, that helps.
1. Identify the Parent function related to the given function. Choose the correct answer from the choices below:
f(x)=1/2x-9 4/5
Linear Function
Not a Function
Absolute Value Function
Quadratic Function
Could someone please help me with this !
And also show work
Answer: C. K= 2.5
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
[tex]\Huge\boxed{k=2.5}[/tex]
Step-by-step explanation:
Given -2.1k + 13 + 6.5k = 24 we need to isolate the variable using inverse operations
step 1 combine any like terms
sometimes there are not like terms but in this case there are. When there are like terms (must be on the same side of the = ) you add them together
-2.1k + 6.5k = 4.4k
now we have
4.4k + 13 = 24
Now we want to get rid of the 13
To do so we subtract 13 from each side
13 - 13 cancels out
24 - 13 = 11
now we have 4.4k=11
now we want to get rid of the 4.4
To do so we divide each side by 4.4
4.4k/4=k
11/4.4=2.5
we're left with k - 2.5
Find the flux of the given vector field F across the upper hemisphere x^2 + y^2 + z^2 = a^2, z >= 0. Orient the hemisphere with an upward-pointing normal.
19. F= yj
20. F = yi - xj
21. F= -yi+xj-k
22. F = x^2i + xyj+xzk
6πa² is the flux of F across the upper hemisphere.
The problem requires us to compute the flux of the given vector field F across the upper hemisphere x² + y² + z² = a², z ≥ 0. We are to orient the hemisphere with an upward-pointing normal. The four vector fields are:
F = yj
F = yi - xj
F = -yi + xj - kz
F = x²i + xyj + xzk
To begin with, we'll make use of the Divergence Theorem, which states that the flux of a vector field F across a closed surface S is equivalent to the volume integral of the divergence of the vector field over the region enclosed by the surface, V, that is:
F · n dS = ∭V (div F) dV
where n is the outward pointing normal unit vector at each point of the surface S, and div F is the divergence of F.
We'll need to write the vector fields in terms of i, j, and k before we can compute their divergence. Let's start with the first vector field:
F = yj
We can rewrite this as:
F = 0i + yj + 0k
Then, we compute the divergence of F:
div F = d/dx (0) + d/dy (y) + d/dz (0)
= 0 + 0 + 0 = 0
So, the flux of F across the upper hemisphere is 0. Now, let's move onto the second vector field:
F = yi - xj
We can rewrite this as:
F = xi + (-xj) + 0k
Then, we compute the divergence of F:
div F = d/dx (x) + d/dy (-x) + d/dz (0)
= 1 - 1 + 0 = 0
So, the flux of F across the upper hemisphere is 0. Let's move onto the third vector field:
F = -yi + xj - kz
We can rewrite this as:
F = xi + y(-1j) + (-1)k
Then, we compute the divergence of F:
div F = d/dx (x) + d/dy (y(-1)) + d/dz (-1)
= 1 - 1 + 0 = 0
So, the flux of F across the upper hemisphere is 0. Lastly, let's consider the fourth vector field:
F = x²i + xyj + xzk
We can compute the divergence of F directly:
div F = d/dx (x²) + d/dy (xy) + d/dz (xz)
= 2x + x + 0 = 3x
Then, we express the surface as a function of spherical coordinates:
r = a, 0 ≤ θ ≤ 2π, 0 ≤ φ ≤ π/2
Note that the upper hemisphere corresponds to 0 ≤ φ ≤ π/2.
We can compute the flux of F over the hemisphere by computing the volume integral of the divergence of F over the region V that is enclosed by the surface:
r² sin φ dr dφ dθ
= ∫[0,2π] ∫[0,π/2] ∫[0,a] 3r cos φ dr dφ dθ
= ∫[0,2π] ∫[0,π/2] (3a²/2) sin φ dφ dθ
= (3a²/2) ∫[0,2π] ∫[0,π/2] sin φ dφ dθ
= (3a²/2) [2π] [2] = 6πa²
Therefore, the flux of F across the upper hemisphere is 6πa².
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Solve the following initial value problem. cos2x sin x dy + (cos?x)y = 5, 7(7/3) = 4 dx
The solution to the given initial value problem [tex]cos2x sin x dy + (cos?x)y = 5, 7(7/3) = 4 dx[/tex] is [tex]y(x) = (5/6) * (cos^2(x) - 1) + (28/9) * sin(x) + (40/9) * cos(x)[/tex].
To solve the initial value problem, we can use the method of integrating factors. The integrating factor is found by taking the exponential of the integral of the coefficient of y with respect to x. In this case, the coefficient is cos(x). So, the integrating factor is [tex]e^(^\int ^{ cos(x)} \, ^d^x^) = e^s^i^n^(^x^))[/tex].
Multiplying the given differential equation by the integrating factor, we obtain:
[tex]e^{sin(x)} * [cos^{2x} sin(x) dy + cos(x) y] = 5e^{sin(x)} dx[/tex]
By using the product rule and simplifying, we have:
[tex]d/dx [e^{sin(x)} * y * cos^{2x}] = 5e^{sin(x)}[/tex]
Integrating both sides with respect to x, we get:
[tex]e^{sin(x)} * y * cos^{2(x)} = \int {5e^{sin(x)}} \, dx = 5e^{sin(x)} + C,[/tex]
where C is the constant of integration.
Simplifying and solving for y, we obtain:
[tex]y(x) = [(5/6) * (cos^{2x} - 1) + (28/9) * sin(x) + (40/9) * cos(x)] / (e^{sin(x)} * cos^{2(x)} + Ce^{-sin(x)},[/tex]
where C is the constant of integration.
To find the value of C, we can use the initial condition y(7/3) = 4. Substituting this into the equation and solving for C, we can determine the specific solution.
In conclusion, the solution to the given initial value problem is [tex]y(x) = (5/6) * (cos^{2x} - 1) + (28/9) * sin(x) + (40/9) * cos(x)[/tex], subject to the specified initial condition.
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How many permutations of S9, have cycle strucrure 3^3?
There is only 1 permutation in S9 with a cycle structure of [tex]3^3[/tex].
To find the number of permutations of S9 with a cycle structure of [tex]3^3[/tex], we can use the concept of cycle index.
In a permutation with a cycle structure of[tex]3^3[/tex], we have three cycles of length 3. The cycle index of S9 with respect to cycles of length 3 can be determined using the Polya enumeration theorem.
The cycle index of S9 with respect to cycles of length 3 is given by:
[tex]Z(S9, t1, t2, t3) = (t1^3 + t3^3)^3[/tex]
Expanding this expression, we get:
[tex]Z(S9, t1, t2, t3) = (t1^3 + t3^3)^3\\\= (t1^9 + 3t1^6t3^3 + 3t1^3t3^6 + t3^9)[/tex]
To count the number of permutations with the desired cycle structure, we need to find the coefficient of the term [tex]t1^9t3^9[/tex].
From the expanded form, we see that the coefficient [tex]t1^9t3^9[/tex] is 1.
Therefore, there is only one permutation in S9 with a cycle structure of [tex]3^3[/tex]
In summary, there is 1 permutation of S9 that has a cycle structure of [tex]3^3[/tex].
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how do you get the value of x7+8x+3-1+7
Answer:
first add the numbers that have the same variable s x7+8x=15x
then the numbers first add and then you subtract
1+7=8
3-8= -5
15x-5
Answer:
8x+x7+9
Step-by-step explanation:
subtracted one term from another
subtracted 1 from 3 to get 2
x7=+8x+2+7
add two terms together
add 2 and 7 toget 9
x7+8x+9
IM GIVING BRAINLIEST!!PLEASE HELP!!
Answer: c
Step-by-step explanation:
Suppose that 5 people should be randomly selected from a group of 20 forming couples by 10. What is the probability that the 5 unrelated chosen from related persons (that is, no chosen person be a couple)?
The probability that none of the 5 randomly selected individuals are part of a couple is 0.016.
What is the probability that none of the 5 randomly selected individuals are part of a couple?A probability means the branch of math which deals with finding out the likelihood of the occurrence of an event. Its measures the chance of an event happening.
We will know total number of possible outcomes when selecting 5 individuals from a group of 20. This can be calculated using the combination formula:
C(20, 5) = 20! / (5! * (20 - 5)!)
C(20, 5) = 15,504
We know that when we select an individual, we are removing their corresponding partner from the pool of available choices. This means that for each individual we choose, the number of available choices decreases by 1.
The number of favorable outcomes can be calculated as follows:
= 20 * 18 * 16 * 14 * 12
= 967,680
The probability will be:
= Outcomes / Favorable outcomes
= 15,504 / 967,680
= 0.01602182539
= 0.016.
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What correction does Petri need to make? BRAINLIEST I WILL CROWN
A solid object has the right triangle with vertices (0, 0), (3, 0), and (0, 4) as its base.
a) Any cross section of the solid, taken parallel to the y-axis and perpendicular to the x-axis, is a square. Find the volume of the solid.
b) Any cross section of the solid, taken parallel to the y-axis and perpendicular to the x -axis, is a smi-circle. Find the volume of the solid.
a. The volume of the solid is 24 cubic units.
b. The volume of the solid is 4π cubic units.
How to calculate tie valuea. Volume = Area of Base * Height
The base is a right triangle with base length of 3 units and height of 4 units. The area of the base can be calculated as:
Area of Base = (1/2) * base * height
= (1/2) * 3 * 4
= 6 square units
The height of the solid is 4 units.
Volume = Area of Base * Height
= 6 * 4
= 24 cubic units
b) Any cross section of the solid, taken parallel to the y-axis and perpendicular to the x-axis, is a semicircle.
Volume = (1/2) * π * radius² × height
Volume = (1/2) * (1/2) * π * 2² * 4
= (1/4) * π * 4 * 4
= π * 4
Therefore, the volume of the solid is 4π cubic units.
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Select all the figures that are shaded to represent 60% of the whole. Whoever answers correctly and first will be marked as brainliest!!!!
Answer:
the first one
Step-by-step explanation:
What is the lyrics for its good to be alive by among us?
Answer:
HEHEHEHEHEH
I've been waiting for this moment
Feels good to be alive right about now
Good, good, good, good to be alive right about now
Good, good, good, good to be alive right about now
Hallelujah, let that bass line move ya, say hey
Step-by-step explanation:
Have fun
Please help me I need to answer this question
Answer:
.........
it is -7
I need help on the circled problem please
Answer:
There would be infinite solutions because the equations are exactly the same.
I hope this answered your question
Write a quadratic equation in standard form with [tex]\frac{3}{4}[/tex] an -5 as its roots
Knowing the roots first write the equation in factored form:
(X - 3/4)(x +5) = 0
Now use the FOIL method ( multiply each term in one set of parentheses by each term the other set:
X•x + x•5 -3/4•x -3/4•5
Simplify:
X^2 + 5x -3/4x -3 3/4
Combine like terms:
X^2+ 4 1/4x - 3 3/4
help with questions 10-13 plz!!
Answer:
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NOLINKS ..................
Answer:
The answer is in the link
Step-by-step explanation:
quntyfcjb/crown!.com :))))
PLEASE HELP ASAP
Find the surface area and volume of the figure below:
Answer:
What I think it might be is 62.3
A medical team randomly selects people in an area, until he finds a person who has a corona virus, Let p is the probability that he succeeds in finding such a person, is 0.2 and X denote the number of people asked until the first success. (i) What is the probability that the team must select 4 people until he finds one who has a corona virus? (ii) What is the probability that the team must select more than 6 people before finding one who who has a corona virus?
Answer : i) The probability of finding the first case in 4 trials is 0.1024 ii) The probability that the team must select more than 6 people before finding one who has a corona virus is 0.4095.
Explanation : Given information:Let p is the probability that he succeeds in finding such a person, is 0.2 and X denote the number of people asked until the first success.
(i) What is the probability that the team must select 4 people until he finds one who has a corona virus?
The number of trials required until the first success follows geometric distribution.
The probability of finding the first case in 4 trials is: P(X = 4) = q^3p, where q = 1 - p. We have p = 0.2 and q = 0.8. So, P(X = 4) = 0.8^3 × 0.2 = 0.1024
(ii) What is the probability that the team must select more than 6 people before finding one who who has a corona virus? P(X > 6) = 1 - P(X ≤ 6) The probability of finding the first case in the first 6 trials is:P(X ≤ 6) = 1 - q^6p= 1 - 0.8^6 × 0.2= 0.59049P(X > 6) = 1 - P(X ≤ 6)= 1 - 0.59049= 0.4095 Therefore, the probability that the team must select more than 6 people before finding one who has a corona virus is 0.4095.
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Find all possible trigonometric ratios given the following:
tan θ = -7/24 and cos θ > 0
The given information allows us to find the values of trigonometric ratios involving angle θ. Given that tan θ = -7/24 and cos θ > 0, we can determine the following trigonometric ratios: sin θ, csc θ, sec θ, and cot θ
We are given that tan θ = -7/24. Using this information, we can determine the values of sin θ and csc θ.
Since tan θ = sin θ / cos θ, we can write -7/24 = sin θ / cos θ. Rearranging the equation, sin θ = -7 and cos θ = 24.
Now, we can find the values of csc θ, sec θ, and cot θ.
csc θ is the reciprocal of sin θ, so csc θ = 1 / sin θ = 1 / (-7) = -1/7.
To find sec θ, we use the fact that sec θ = 1 / cos θ. So, sec θ = 1 / (24) = 1/24.
Lastly, to calculate cot θ, we know that cot θ = 1 / tan θ. Thus, cot θ = 1 / (-7/24) = -24/7.
In summary, given tan θ = -7/24 and cos θ > 0, we have sin θ = -7, csc θ = -1/7, sec θ = 1/24, and cot θ = -24/7.
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who are these bots giving us links i’m literally gonna fail now
Answer:
Fr. It’s annoying. My mom yells at me for not passing lolz.
Step-by-step explanation:
Answer:
Ignore them and re-upload the questions. The links are very bad.
Step-by-step explanation:
Which golf ball went higher, and how many feet? (Desmos!)
Answer:
1. 36
2. Second
Step-by-step explanation:
- For the first ball, we can see the given function:
[tex]f(x)=-16(t^{2}-3t )[/tex]
[tex]=-16[t^{2} -3t+(3/2)^{2}-(3/2)^{2} ][/tex]
[tex]=-16(t-\frac{3}{2} )^{2} +(-\frac{3}{2} )^{2} *(-16)[/tex]
[tex]-16(t-\frac{3}{2} )^{2} +36[/tex]
So the vertex is ([tex]\frac{3}{2}[/tex], 36), it means when the ball was hit by the [tex]\frac{3}{2}[/tex] seconds, it arrived at the highest height of 36 feet.
- For the second ball, we can see the given graph: the vertex is (2,64), it means when the ball was hit by the 2 seconds, it arrived at the highest height of 64 feet.
- Compare to the two heights, 36 (first ball) is less than 64 (second ball), so the second ball went higher.
[tex]\left \{ {{x=3} \atop {y+1=0}} \right.[/tex] solve graphically this linear system of equations
Answer:
The solution is the point (3, -1)
Step-by-step explanation:
We have the system of equations:
x = 3
y + 1 = 0
To solve this graphically, we need to graph these two lines and see in which point the lines intersect.
To graph the line x = 3, we need to draw a vertical line that passes through x = 3.
To graph y + 1 = 0
First we should isolate y.
y = -1
This is graphed as a horizontal line that passes through y = -1
The graph of these two lines can be seen in the image below.
Where the green line is x = 3, and the blue line is y = -1
Now, looking at the graph we can see that the lines do intersect in the point (3, -1)
Then the solution of the system is the point (3, -1)
Find the distance between the points (7,
–
9) and (
–
2,
–
4).
Answer:
7.07106781187
Step-by-step explanation:
Let us use the distance formula:
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]
x2=2
x1=7
y2=4
y1=9
[tex]d = \sqrt{(2 - 7)^{2} + (4-9)^2}[/tex]
[tex]d = \sqrt{(-5)^2 + (-5)^2}[/tex]
[tex]d = \sqrt{25 + 25}[/tex]
[tex]d = \sqrt{50}[/tex]
d=7.07106781187 (round to whatever digit neccesary)
Hope this helps!!