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Answer:

[tex]T_1=-91.18\°C[/tex]

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

[tex]\frac{T_1}{V_1}= \frac{T_2}{V_2}[/tex]

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

[tex]T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C[/tex]

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Answer: Whats the question?

Answer:

[tex]n_{O_2}=343.75molO_2[/tex]

Explanation:

Hello there!

In this case, according to the combustion of octane:

[tex]2C_8H_1_8+25O_2\rightarrow 16CO_2+18H_2O[/tex]

We can see there is a 2:25 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:

[tex]n_{O_2}=27.5molC_8H_1_8*\frac{25molO_2}{2molC_8H_1_8} \\\\n_{O_2}=343.75molO_2[/tex]

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Answer:

1.099

Explanation:

Hope this helps

Answer:

1.09944660051578e-23

Explanation:

Answer:

chloroplast

Explanation:

Answer:

chloroplasts

Explanation:

Answer:

The pressure is = 897 torr

Explanation:

We use Gay Lussac's Law.

Answer:

1.1) Covalent bonding

Explanation:

All of the above are intermolecular forces except covalent, which is intramolecular.

Answer:

A.

Explanation:

In an endothermic reaction heat is applied.

In an endothermic process, heat is transferred from the surroundings to the system.

What are endothermic and exothermic processes?

An exothermic process is one that gives off heat. This heat is transferred to the surroundings. An endothermic process is one in which heat has to be supplied to the system from the surroundings.

The endothermic process is a term that describes a reaction where the system absorbs the energy from its surrounding in the form of heat. A few examples of the endothermic process are photosynthesis, evaporating liquids, melting ice, etc.

The exothermic reaction is the opposite of an endothermic reaction. It releases energy by light or heat to its surrounding. A few examples are neutralization, burning of a substance, reactions of fuels, etc.

Hence, option A is the correct answer.

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Answer:

they can become smaller or start fall apart or aroud

Explanation:

Answer:

5.97 mol

Explanation:

To find the number of moles when given the mass of a substance, we divide the mass of the sample by its molar mass.

so, we get,

nN203 = 454 g / 76.01 g /mol

= 5.97 mol

Answer:

4.5M

Explanation:

The solution was diluted from 2.0L to 3.0L, the dilution factor was:

3.0L / 2.0L = 1.5.

That means the solution was diluted 1.5 times.

As the final molarity of the diluted solution is 3.0M, the initial molarity of the solution was:

3.0M * 1.5 =

Answer:

6

Explanation:

Answer:

NH3 ------dipole - dipole forces

CH3OH ------ dipole - dipole forces

AlBr3 ------- ion - dipole forces

AlCl3 ------- ion - dipole forces

Explanation:

Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.

Similarly, CH3OH  possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.

As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.

Answer:

Ammonia [tex]NH_3[/tex]

Aluminium Chloride [tex]AlCl[/tex]

Methanol [tex]CH_3OH[/tex]

Aluminium bromide [tex]AlBr_3[/tex]

Explanation:

Because water is not in ionic form it can only forms dipole forces which are strongest. Methanol, Ammonia and AlCl are also dipoles not ions . Thus dipole dipole forces exist.

On the other hand, aluminium bromide are ionic and it can forms ion dipole bonds with water.

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Answer:

36 atoms

Explanation:

The reactants are in the left side of the equation. First we determine how many atoms are there in the C₆H₁₂O₆ molecule:

There are two atoms in a O₂ molecule, and there are 6 O₂ molecules in the equation:

The total number of atoms in the reactants is

[tex]V = \text{133 mL}[/tex]

[tex]\rho = \text{0.789 g/mL}[/tex]

[tex]m[/tex]

[tex]\rho = \frac{m}{V}[/tex]

[tex]m = \rho V[/tex]

[tex]m = (\text{0.789 g/mL})(\text{133 mL})[/tex]

[tex]\boxed{m = \text{105 g}}[/tex]

Ethanol is a common laboratory solvent and has a density of 0.789 g/mL.  105g is the mass, in grams, of 133 mL of ethanol.

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the force that is applied. The change caused by a force applied is smaller the more mass a body has.

The kilogram, which would be specified as equivalent to 6.62× 10³⁴ joule second in terms of Planck's constant, is the unit of mass inside the International Units System (SI).

density = mass / volume

mass =density× volume

         = 0.78× 1.33

         =105g

Therefore, 105g is the mass.

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Answer:

9.7 g

Explanation:

From the question,

Note: The molar volume of all gas at stp is 22.4 dm³ or 22.4 L

1 mol of  oxygen gas (O₂) at stp = 22.4 dm³

X mole of oxygen gas (O₂) at stp = 6.8 L

X = (1 mol×6.8 L)/22.4 L

X = 0.3036 mol.

But,

Number of mole (n) = mass (m)/molar mass (m')

n = m/m'

m = n×m'.................. Equation 2

Where n = 0.3036 mol, m' = 32 g/mol

Substitute into equation 2

m = 0.3036×32

m = 9.7 g

Answer:

Well, there is no photo...

Explanation:

Answer:

from the chromosome..l dont know

Answer:

10.5 got it!!!!

Answer:

how many liters of 0.150 m hcl would be required to react completely with 8.00 grams of magnesium hydroxide

Explanation:

please give me brainlist and follow

Answer:

B

Explanation:

if it releases energy it becomes a solid(Solid)

if it absorbs energy it becomes a gas(Water Vapor)

Answer:

1. 23.3 g

2. 82 g

3. 0.402 mol

4. 0.506 mol

Explanation:

We can convert moles (n) to mass (m) using the following expressions that include the molar mass (M).

n = m/M

m = n × M

1. The molar mass of NH₄Cl is 53.49 g/mol.

m = 0.436 mol × 53.49 g/mol = 23.3 g

2. The molar mass of Ca(NO₃)₂ is 164.09 g/mol.

m = 0.50 mol × 164.09 g/mol = 82 g

3. The molar mass of NaCl is 58.44 g/mol.

n = 23.5 g/(58.44 g/mol) = 0.402 mol

4. The molar mass of KMnO₄ is 158.03 g/mol.

n = 79.9 g/(158.03 g/mol) = 0.506 mol

Answer:

1.59%

Explanation:

First, we convert 0.1606 g of AgCl into moles, using its molar mass:

Then we convert the calculated moles of Cl (equal to AgCl moles) into moles of DDT:

Now we convert 2.24x10⁻⁴ moles of DDT into grams, using its molar mass:

Finally we calculate the percentage of DDT in the sample:

Answer:

If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises.

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Answer: Balanced molecular equation :

[tex]2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)[/tex]

Total ionic equation:

[tex]6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)[/tex]  

The net ionic equation:

[tex]2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)[/tex]

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

[tex]2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)[/tex]

The total ionic equation in separated aqueous solution will be,

[tex]6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)[/tex]

In this equation, and  are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)[/tex]