The total mass of the carts is 1000 kg. The first
drop is 77.7 m. What is the speed of the coaster
at the bottom of the hill?

The maximum displacement angle of the bob is 13⁰.

The given parameters;

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m[/tex]

The maximum displacement angle is calculated as follows;

[tex]cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0[/tex]

Thus, the maximum displacement angle of the bob is 13⁰.

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Answer:

105,000km or about 65,244mi

Explanation:

If the space shuttle orbits around it 1.4 times every hour then the speed of the space shuttle in km/hour would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

Average speed = total distance /Total time

As given in the problem If the circumference of a space shuttle's orbit around Earth is 42,522 km and the space shuttle orbits around it 1.4 times every hour, then we have to find the speed of the space shuttle in km/hour

The total distance covered by the space shuttle in an hour = 42,522×1.4

                                                                                                 = 595330.8 Km

The speed of the space shuttle in meters/second = 595330.8 × 1000/3600

                                                                                   = 165369.67 m/s

Thus, the speed of the space shuttle would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.

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The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:

Given parameters

To find

The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.

In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.

y-axis

Initial instant. Before the shock.

          [tex]p_{oy}[/tex]  = M v₀₁

Final moment. After the crash

          [tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]

The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.

          [tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]          

Calculate us

           [tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]  

           vfx = 9.23 m / s

x-axis

Initial instant. Before the crash.

           p₀ₓ = m v₀₂

Final moment. After the crash.

           [tex]p_{fx}[/tex] = ​​(M + m) [tex]v_{fx}[/tex]  

The momentum is preserved.

          [tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]  

Let's find the velocity just after the collision, let's use Newton's second law,

y-axis

        N-W = 0

        N = W = (M + m) g

x-axis

       fr = (M + m) a

The friction force is the macroscopic manifestation of the interactions between the two bodies.

       fr = μ N

We substitute.

       μ  g = a

Now we can use kinematics.

        v² = v₀² - 2a d

When the vehicles stop their speed is zero.

        v₀² = 2 a x

        v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]

Let's calculate.

       v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]  

       v₀ = 14 m / s

This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.

          cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]  

          v₀ₓ = v₀ cos 25

          v₀ₓ = 14 cos 25

          v₀ₓ = 12.69 m / s

We substitute in the expression of the conservation of the momentum in the x-axis.

           m v₀₂ = (M + m) [tex]v_{fx}[/tex]  

           [tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]  

Let's calculate.

           [tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]  

           vfy = 32.99 m / s = 40 m / s

In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:

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Answer:

probably liquid cause it can be contained easily

Answer:

A Wave red

Explanation:

Answer:

Answer: Wave E

Explanation:

Why because if you put each in a strait line it would have been longer

hope it helps

Answer:

D. unsaturated fat

Explanation:

Unsaturated fats are considered the healthiest fats because they improve cholesterol, help reduce inflammation (a risk factor for heart disease), and help decrease the overall risk of developing heart disease. The main source of unsaturated fats are plant-based foods.

Answer:unsaturated fat

Explanation:

The weight of the object from the information provided in the question is  1500 N.

We know that pressure = Force/area. We have the following information from the question;

Pressure =500 Nm-2

Area = 3 m2

Hence;

Force = Pressure × area

Force = 500 Nm-2 × 3 m2

Force = 1500 N

Hence, the weight of the object is 1500 N

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Answer:

5m/s ez

Explanation:

plz make me brainliest

The largest angle for which box B will not slip​ is 16.7⁰.

The given parameters:

The frictional force between box A and box B is calculated as;

[tex]F_f_1= \mu_s_1 (mg)[/tex]

The frictional force between box B and inclined surface is calculated as;

[tex]F_f = \mu_s_2 (2mg) cos(\theta)[/tex]

The net force on the boxes that results in no movement is calculated as;

[tex](2mg) sin(\theta) - F_f= 0\\\\(2mg) sin(\theta) = F_f\\\\(2mg) sin(\theta) = \ \mu_s_2 (2mg) cos(\theta)\\\\ sin(\theta) = \mu_s_2 cos(\theta)\\\\\mu_s_2 = \frac{sin(\theta)}{cos(\theta)} \\\\\mu_s_2 = tan(\theta)\\\\\theta = tan^{-1} (\mu_s_2)\\\\\theta = tan^{-1} (0.3)\\\\\theta = 16.7 \ ^ 0[/tex]

Thus, the largest angle for which box B will not slip​ is 16.7⁰.

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The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

The impulse experienced by the ball is calculated as follows;

[tex]Ft = \Delta P[/tex]

where;

[tex]Ft[/tex] is impulse

[tex]\Delta P[/tex] is change in momentum

The time of motion of the ball is calculated as follows;

[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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Translucent objects allow some light to travel through them. The light does not pass directly through the materials. It changes direction many times and is scattered as it passes through. Therefore, we cannot see clearly through them and objects on the other side of a translucent object appear fuzzy and unclear.

Answer:

No

Explanation:

It doesn't depend on the density

Answer:No. If you take all your masses and and squeeze them into a tiny volume,

The 4th state of matter would make an acceptable force field.

The 4th state of matter which is plasma would make an acceptable force field because this fourth state of matter is present in ionized form which has two charges on it i.e. cation which is a positive charge and anion which is a negative charge.

We know that charges attract as well repel other objects if they are strong enough. Positive charge repel positive charge but attract negative charge so we can conclude that 4th state of matter would make an acceptable force field.

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Answer:

jogging

Explanation:

Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.

Answer:

magnesium (Mg), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table, and the lightest structural metal. Its compounds are widely used in construction and medicine, and magnesium is one of the elements essential to all cellular life.

Explanation:

hope it helps

The car accelerates 60 mph in 6.3 seconds. Thus, the acceleration is [tex]\frac{60}{6.3}[/tex]. [tex]f=ma[/tex], so [tex]4106 = m(\frac{60}{6.3})[/tex], so [tex]m=431.13[/tex].

Answer:

C

Explanation:

don't worry Tama yan base sa pagkakaintindi ko

The frequency of a photon of red light with wavelength 4.50 x 10−7m is 6.67 x 1014Hz.

Answer:

4.3 m/s^2

Explanation:

a = vf - vi / t

26 - 20 / 1.4

= 4.28 ( round your numbers)

Answer:

the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

Explanation:

The potential energy of the car when it let go is 20,000 J.

The speed of the car at the bottom of the ramp is 20 m/s.

The given parameters;

The potential energy of the car is calculated as follows;

P.E = mgh

P.E = 100 x 10 x 20

P.E = 20,000 J

The speed of the car at the bottom of the ramp is calculated as follows;

[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s[/tex]

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Answer: when free energy is extensive property that means its magnitude depends on the amount  of a substance.

Explanation:

srry if im wrong :( .

Answer:

state of the system

Explanation:

Answer:

a smooth

b less smooth

c faster

d faster than fast c

e to fast for fast

Explanation:

Answer:

a-

V= IR

9V = I ×( 12+6)

I = 9/ 18 A = 0.5 A

b

V=IR

240 = 6 A ×( 20 + R)

40 = 20 + R

R = 20 ohm

c

resultant resistance of the 2 parallel resistances= Ro

1/Ro = 1/ 5 + 1/ 20

1/Ro =( 20+5)/100

= 1/Ro = 1/4

Ro= 4 ohm

V=IR

V = 2A × ( 1+ 4 OHM)

V = 10V

d

equivalent resistance = Ro

1/Ro = 1/(2+8) + 1/(5+5)

1/Ro = 1/10 +1/10

2/10 = 1/ Ro

Ro= 10/2 = 5 ohm

V = IR

12V = I × 5Ohm

I=2.4 A

To move maximum height the friction force can be assumed to be

negligible.

Reasons:

The component of the weight acting on the incline, w = m·g·sin(θ)

Length of the ramp = 15 m

Potential energy of the box = 15 × sin(θ) ×20 = 300·sin(θ)

F × 15 = 300·sin(θ)

F = 20·sin(θ)

Work done by net force = Potential energy gained by the box

Work done by net force = (40 - 20·sin(θ)) × 15 = 300·sin(θ)

40 = 20·sin(θ) + 20·sin(θ) = 40·sin(θ)

sin(θ) = 1

θ = arcsin(1) = 90°

The ramp is at an inclination of 90°, therefore, the ramp is oriented vertically

The height of the ramp = The length of the ramp = 15 m

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Answer:

*Disclaimer you can't actually do that, or at least not yet because the nearest black hole is at least 1,000 light years away. But if we could...

His journy would be pretty fast and horrific. For him, he would slowly be streched apart or spegetified into a string of atoms as he nears the event horizoin. But for an outside observer he would apear to go slower and slower and would never actualy reach the event horizion. This is becuase of einstines general relativity, massive objects slow time down. He would also apear to become red as the lights wavelength is streched out due to the entense gravity of the black hole.