can someone explain please?​

Can Someone Explain Please?

Answers

Answer 1

Hi there!

We can begin by solving for the velocity in which the ball was thrown at using the following:

[tex]v_f^2 = v_i^2 + 2ad[/tex]

At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:

[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]

'a' = acceleration due to gravity and 'd' is the max height, so:

[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]

Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).

[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]

[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]


Related Questions

Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340

Answers

The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?

[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]

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Answer:

6.983 km/hr

Explanation:

The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr

Mejor yo por favor

Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30

Answers

Answer:

here's your answer below

Explanation:

sorry something went wrong

.

define nuclear energy​

Answers

Answer:

Nuclear energy is the energy stored in atoms that can produce electricity.

Hope that helps. x

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)

0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle

Answers

Answer:

0.60N along the line tangent to the circle

Answer:

A is the answer

Explanation:

Just got finished with the quiz! Hope this helps <3

why does polishing the surface of a metal extend fatigue life

Answers

Answer:

they are machined with shape characteristics which maximize the fatigue life of a metal.

Explanation:

they are highly polished to provide the surface characteristics which enable the best fatigue life.

how do you think the liquid density affects the buoyancy of objects placed in the liquid?

Answers

Answer:

density can be written as:

d = F / V  (weight density) or M / V (mass density)

Since F in the first equation can be written as

B = d V where B is the buoyant force and is proportional to the

weight of the liquid displaced

For a given volume the weight of the liquid displaced is proportional to the density and hence the buoyant force

calculate the resultant force acting on the object and state its direction

Answers

[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]

[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]

[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]

Direction is east.

With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Answers

initial velocity=u=20km/h=5.5m/sAcceleration=a=8m/s^2Time=t=10s

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

☆ Correct and rewrite the following statements:
_____
e). electroplating is based on magnetic effect of electricity.

f). an electric bulb glows due to the chemical effect of electricity.
_______________________

#No spam
#No Internet answers, please #Explanation needed​

Answers

Answer:

e)Question:-Electroplating is based on magnetic effect of electricity.Answer:-It's incorrect sentence As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.

So correct sentence is:

Electroplating is based of chemical effect of electricity.

f)Question:-An electric bulb glows due to the chemical effect of electricity.Answer:-It's incorrect sentence As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.

So correct sentence is:

An electric bulb glows due to the heating effect of electricity.

4) What process produces carbon dioxide?
a) photosynthesis
b) replication
c) mutation
d) respiration

5) What happens during cytokinesis?
a) a spindle forms
b) chloroplasts release energy
c) the cytoplasm divides
d) chromosomes

plz answer asap

Answers

Answer:

d and c are the answers :)

The weak nuclear force causes:
(A). Lightning
(B). Combustion
(C). Radiation
D). Protons and neutrons to form the nuclear of atoms

Answers

Answer:

(C) Radiation

Explanation:

The weak nuclear forces causes radiation to form.

what is the theory relativity by Einstein? ​

Answers

:MAIN ANSWER:

determined that the laws of physics are the same for all non-accelerating observers

Explanation:

Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.

HOPE IT HELPS

#CARRY ON LEARNING

HAPPY HOLIDAYS DEC 2021

Assume ideal behavior. How many moles of are needed to fill a 2000L weather balloon at 210K and 1atm pressure? Round your answer to the nearest mole (use R = 0.082057 L atm mol-1K-1)

Answers

Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case, you know:

P= 1 atmV=2000 Ln= ?R= 0.082057 [tex]\frac{atmL}{molK}[/tex]T= 210 K

Replacing in the ideal gas law:

1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K

Solving:

[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]

n=116.06 moles

Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

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SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.

Answers

Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21

Answers

First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,

3x10^30. 5x10 to the 19 power

_______.

6x10^10

The answer is c

If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.

What is speed?

Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit  time . Thus, mathematically it is the ratio of distance to the time.

If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.

Here the spaceship travels  6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:

1 year   -    6 × 10¹⁰ km

  ?           -  3 × 10³⁰ km

Cross multiply them we get, 3 × 10³⁰ km/  6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.

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what is the prmary source of energy inside of the earth

Answers

The correct answer is the energy of the sun
The primary source would be the sun

BRAINLIST!!!
Two metallic balls A and B carry the charges QA= 16×10^-9C and QB=-8×10^-9C.
We fixed balls A and B 5cm apart. Given e=1.6×10^-9C and k=9×10^9 S.I unit.
1) identify the ball that has excess of electrons.
2) calculate the number of deficit and excess of electrons on both balls.
3) calculate the force exerted by A on B.

Answers

QB=-8×10^-9C.QB=-8×10^-9C.We fixed balls A and B 5cm apart. Given e=1.6×10^-9C and k=9×10^9 S.I unit.

how to put in velocity into a graphing calculator

Answers

Answer:

You need a graphing calculator that implemented vectors. I don't know any that have it. Sorry.

Answer:

Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps:

Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds ,

Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .

Explanation:

What are the three different social perspectives on sport

Answers

Answer:

functionalist theory,feminist theory. discipline of sociology

Please HELP
6. A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed
of 10.0-m/s.


a.
If the rope can only tolerate 400-N of force, what is the maximum speed the bucket can
experience before the rope snaps? {Hint: Let the centripetal force be 400-N and solve for the speed)

Answers

Answer:

Explanation:

hope this helps

The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

What is force?

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the bucket, m = 3.4 kg,

The length of the rope, r = 1 m,

The speed of the bucket, v = 10 m / s,

The force of the rope, F = 400 N,

Calculate the maximum speed by the formula given below,

[tex]F_c = mv^2 / r[/tex]

400 = 3.4 v² / 1

v² = 400 / 3.4

v² = 117.6

v = 10.85 m / s

Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

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which is the correct relationship among pressure, flow, and resistance?

Answers

Answer:

Flow is proportional to change in pressure and inversely proportional to resistance.

An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground

Answers

Answer:

20 ft/sec / 32 ft/sec^2 = .625     to reach top

2 * .625 = 1.25

It will be on the ground at t = 0 and t = 1.25

You can also solve the equation:

H = 0 = V0 t - 1/2 g t^2

Obviously, at t=0 h = 0

V0 = 1/2 g t    is a solution

t = 20 * 2 / 32 = 1.25 sec

A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?​

Answers

By Newton's second law, the car slows down with an average acceleration a such that

-7100 N = (1500 kg) a   ⇒   a ≈ -4.7 m/s²

If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that

0² - (25 m/s)² = 2a ∆x   ⇒   ∆x ≈ 66 m

The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The acceleration is found as;

F=ma

-7100 N = (1500 kg) a

a= -4.7 m/s²

If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;

v²=u²+2as

v²-u²=2as

0² - (25 m/s)² =2×(-4.7) s  

s=66 m

Hence,the car slide before it comes to rest will be 66 m.

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what are the three elements that can be used to make a magnet?

Answers

Answer:

Iron, cobalt, and nickel are the only three naturally occurring elements that are magnetic. 

Explanation:

hope it helps

correct me if I'm wrong thank you

brainliest please

Answer:

The three elements that can be used to make a magnet are :

Aluminum, nickel and cobalt

When the mass of the cylinder increased from 3. 0 kg to 6. 0 kg, what happened to the amount of heat generated in the system? It decreased by a factor of 3. It decreased by a factor of 2. It increased by a factor of 2. It increased by a factor of 3.

Answers

When the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

The given parameters:

Initial mass of the cylinder, m₁ = 3.0 kgFinal mass of the cylinder, m₂ = 6.0 kg

The amount of heat generated in the system is calculated as follows;

Q = mcΔT

where;

m is the massc is the specific heat capacityΔT is the change in temperature

If we keep every other parameters constant and change the mass from 3.0 kg to 6.0 kg, the increase in the heat generated is calculated as follows;

[tex]Q_1 = 3c \Delta T\\\\Q_2 = 6c\Delta T\\\\Q_2 = 2(3c \Delta T)\\\\Q_2 = 2Q_1[/tex]

Thus, when the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

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why does rhododendron not grow well in the terai region of nepal give reason

Answers

Answer:

Tge Rhododendrob is the national flower of Nepal. The hills and mountain sides ranges of Nepal are decorated with diff colours and shapes

How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?

Answers

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.

Answers

Hi there!

To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.

Recall:

[tex]\large\boxed{F_D = \mu N}}[/tex]

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]

We can plug in the known values to solve for one part of the normal force:

N = (1)(9.8)(cos30)  + F(.5) = 8.49  + .5F

Now, we can plug this into the equation for the dynamic friction force:

Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F

For a block to move with constant speed, the summation of forces must be equivalent to 0 N.

If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:

Fcosθ = 1.697 + .1F

Solve for F:

Fcos(30) - .1F = 1.697

F(cos(30) - .1) = 1.697

F = 2.216 N

the gravitational force acts on all objects in proportion to their mass. neglecting air resistance, why don’t heavy objects fall faster than light ones?

Answers

Answer:

Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.

A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s

Answers

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated  from Newton' second law of motion. That is,

M( g + a) = m(g - a)

1(9.8 + a) = 3( 9.8 - a)

9.8 +a = 29.4 - 3a

collect the like terms

4a = 19.6

a = 19.6/4

a = 4.9 m/[tex]s^{2}[/tex]

Therefore, the cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

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