Carbon dioxide and oxygen are both ___ found in the air.

Answer:

Both

compounds in left hand side of the equation is called reactants.

compounds in right hand side of the equation is called products.

so ans is both water and carbon di oxide

Explanation:

Answer:

The last one

Explanation:

I have done this before

Answer:

Earth's plates moving & colliding against one another.

Answer:

Explanation:

I did the lab

Thermal energy is represented in the units joules J. It is the energy needed to raise the temperature by one degree celsius.Per gram this energy is called as specific heat capacity with the unit J/°Cmol.

Heat capacity of a substance is the heat energy required to raise the temperature of the substance by one degree celsius.

If the heat capacity is measure per one mole of a substance it is called specific heat capacity. It is an intensive property whereas heat capacity is an extensive property.

The given passage can be completed as follows:

The unit often used in chemistry and physics to measure energy, such as for work or electrical current, is Joule (J). We can also use this unit, as we did in this lab, for measuring  heat capacity.  

This is a property that is quantified by the energy needed per one gram of material to raise the temperature by one degree celsius.The unit for this measure is therefore J/°Cg.

To find more about heat capacity, refer the link below:

https://brainly.com/question/28921175

#SPJ2

These are structural formulas of constitutional isomers of hexene, an alkene.

Both are acyclic, six-carbon chains, and they differ only in the position of the double bond. As constitutional isomers, both structures have the same molecular formula.

The first structure is of hex-1-ene (or 1-hexene).

The second structure is of (3E)-hex-3-ene [or (3E)-3-hexene].

Both structures have the molecular formula C₆H₁₂.

I hope I answered your question. Please feel free to let me know otherwise.

Answer:

it is a chemical change because it can't be change back to it normal position when it gets burnt

Answer:

grams NH3 is equal to 0.058718113128665 mole.

Explanation:

Answer:

3 moles

Explanation:

Use the mole = mass/mr equation

so, mole = 51/17 = 3 moles

Answer:

wave amplitude is the answer

Answer:

[tex]a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction[/tex]

Explanation:

Ferrous Sulphate[tex](FeSO4)[/tex] is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide [tex](SO_3)[/tex], Sulphur Dioxide [tex](SO_2)[/tex]  as well as Ferric Oxide [tex](Fe_2O_3)[/tex].

We can hence, frame a skeletal equation of this reaction and try to balance it.

Hence,

[tex]FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3[/tex]

Now,

a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of steps:

1. First, lets compare the number of  Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside [tex]FeSO_4[/tex].

2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:

Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :

[tex]2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3[/tex]

b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds decompose into smaller elements and compounds. Here, as Ferrous Sulphate decomposes into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is Decomposition Reaction.

Answer:

[tex]\boxed {\boxed {\sf PCl_3}}[/tex]

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

Use the molar masses as ratios and multiply by the number of grams. [tex]22.5 \ g \ P * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P[/tex]

[tex]77.5 \ g \ Cl * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl[/tex]

Divide both of the moles by the smallest number of moles to find the mole ratio.

[tex]\frac {0.7264157035} {0.7264157035} = 1[/tex]

[tex]\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3[/tex]

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as: PCl₃