Christian buys a two-gallon bottle of juice for $28.16. What is the unit rate of the cost of the juice per fluid ounce?

Answers

Answer 1

Answer:

$0.22

Step-by-step explanation:

128 oz in a gallon

2 gallons is 256oz

28.16*2=56.32

56.32/256=0.22


Related Questions

the company installs the new windows for $3150. the total cost for buying them and having them installed is $5769.00. if ray hills pay $145.50 per widow how many windows did they buy?

Answers

Answer:  18

====================================================

Work Shown:

x = number of windows purchased

The cost expression is 145.50x+3150 because the "145.50x" portion represents the $145.50 per window charge, then we tack on the fixed fee of $3150. Set this cost expression equal to the total charge ($5769) and solve for x.

[tex]145.50x+3150 = 5769\\\\145.50x = 5769-3150\\\\145.50x = 2619\\\\x = 2619/(145.50)\\\\x = 18\\\\[/tex]

They bought 18 windows.

How do I simplify the ratio of

42 : 28 : 21

Answers

Answer:

6:4:3

Step-by-step explanation:

each can be divided by 7

Answer:

6 4 3

Step-by-step explanation:

Please help with this question !!

Answers

Answer:

c) i^337 is equivalent to the expression i^137

Which of the following are steps in practical problem solving?

Answers

Answer:

Assign an identifying variable to the quantity to be found. Write a sentence stating conditions placed on the quantity. Solve the sentence for the variable.

Step-by-step explanation:

can you mark me as brainlist

Veronica made 960 cookies to sell. She wants to package the cookies in boxes of 16. Her goal is to make $630 from selling her cookies.

Answers

Answer: She should charge $10.50 for each box

Step-by-step explanation:

Total cookies = 960

Each box has 16 cookies

Her goal is $630

First, you want to find out how many boxes she made

960÷ 16 = 60

She made 60 boxes

Now you want to find the price for each box

630 ÷ 60 = 10.5

She should charge $10.50 for each box

I hope this helps!!!

The verticles of a triangle are the points R(3,c),Q(9,2) and R(3c,11) where c is constant. Given that angle PQR is 90​

Answers

Answer:

Step-by-step explanation:

Find c if ∠PQR = 90°?

I will ASSUME you mean point P is at (3. c)

slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6

slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)

perpendicular lines have negative reciprocal slopes.

(2 - c) / 6 = -1(3c - 9)/9

9(2 - c) = -6(3c - 9)

18 - 9c = -18c + 54

       9c = 36

         c = 4

Help help help help math math

Answers

Answer:

<4 = 67 degrees

Step-by-step explanation:

Find <3

30+37+x=180

subtract 37 and 30

x = 180 - 30 - 37

x = 150 - 37

x= 113

Find <4

180 - 113

67

67 degrees im not completely sure tho but this is probably the answer

Though it just opened last month, the Mash Mobile food truck has been doing well; they're now serving an average of 200 mashed potato creations every day. If there are 8 ounces of potatoes in each dish, how many 50-pound bags of potatoes does the food truck use every day?

Answers

Answer:

2 50-pound bags

Step-by-step explanation:

[Conversions] 50-pound bags -> 800-ounce bags

[Total potatoes used] 200 mashed potato creations * 8 ounces of potatoes in each dish = 1,600 ounces of potatoes

[Bags used] 1,600 / 800 = 2 bags

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

index notation simplify 4^9 x 4^3

Answers

Answer:

[tex]4^{12}[/tex]

Step-by-step explanation:

Using the rule of exponents

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex] , then

[tex]4^{9}[/tex] × [tex]4^{3}[/tex] = [tex]4^{(9+3)}[/tex] = [tex]4^{12}[/tex]

How to do this problem

Answers

Answer: a. y=3      slope = 0

b. x=-4 slope does not exist

Step-by-step explanation:

#13) Mrs. Frye says that the following triangles are congruent. Is she correct? Why or why not? ​

Answers

Answer: The following triangles are congruent.

Can someone help me please?

Answers

Answer:

put your equation into fractions and then see what or which 1mathces with the image

Step-by-step explanation:

A group of pigs and ducks has a total of 40 feet. There are twice as many ducks as pigs. How many of each animal are there?

Answers

The question relates to the total number of pairs of feet ducks and a pigs

are known to have.

There are 5 pigs and 10 ducks

Reasons:

The length of the group of ducks and pigs = 40 feet

Number of ducks = Twice the number of pigs

Each duck has 2 feet.Each pig has 4 feet.

Let x represent the number of pigs, and let y represent the number of ducks, we have;

y = 2 × x

4·x + 2·y = 40

Which gives;

4·x + 2 × (2·x) = 40

8·x = 40

x = 40 ÷ 8 = 5

The number of pigs, x = 5

y = 2 × x

Therefore;

y = 2 × 5 = 10

The number of ducks, y = 10

Learn more about solving word problems in mathematics here:

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What will $82,000 grow to be in 11 years if it is invested today at 8% and the interest rate is compounded monthly

Answers

Answer:

Well the answer would be 865,920. Hope this helped! this is the way i learned it so if its wrong i'm super sorry!

Step-by-step explanation:

I = p x r x t

I = 82,000 x 8 x 11yrs

BUT WAIT! this is MONTHLY, so convert 11 x 12 = 132 and then move 8 back 2 spaces = 0.08 so the correct equation is

I = 82,000 x 0.08 x 132

I = 865,920

A self-storage center has many storage rooms that are 6 feet wide, 10 feet deep, and 12 feet high. What is the volume of the room?

Answers

Answer:

720 ft^3

Step-by-step explanation:

6 * 10 *12

v = l * w * h

6 * 10 * 12 =  720

Volume is a three-dimensional scalar quantity. The volume of the self-storage centre room is 720 ft³.

What is volume?

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of a room or box that is the shape of a rectangular prism is calculated by multiplying the length, width, and height of the prism.

Volume = Length × Width × Height

Given that the self-storage centre room's are 6 feet wide, 10 feet deep, and 12 feet high. Therefore, the dimension of the room can be written as,

Length = 10 ft

Width = 6 ft

Height = 12 ft

Now, the volume of the room can be written as,

Volume of the room = 10ft × 6ft × 12ft

                                  = 720 ft³

Hence, the volume of the self-storage centre room is 720 ft³.

Learn more about Volume:

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#SPJ5

a prisms base has a perimeter of 12cm and a height of 2 cm. the area of the base was 5cm. what is the surface area of the prism.

Answers

[tex]\text{Surface Area of Prism} = (2 \times \text{Base Area}) + (\text{Base perimeter} \times \text{height})\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(2 \times 5)+(12\times 2)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=10+24\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=34~~ \text{cm}^2[/tex]

The function v(t) is the velocity in m/sec of a particle moving along the x-axis. Use analytic methods to do each of the following: (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particle's displacement for the given time interval. If s(0) = 3, what is the particle's final position? (c) Find the total distance traveled by the particle. v(t) = 5 (sint)^2(cost); 0 ≤ t ≤ 2π

Answers

Answer:

(a) The particle is moving to the right in the interval  [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].

(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].

(c)  The total distance traveled by the particle is 9.67 (2 d.p.)

Step-by-step explanation:

(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).

Situation 1: When the particle stops.

[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].

Situation 2: When the particle moves to the right.

[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]

Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .  

*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.

Situation 3: When the particle moves to the left.

[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]

Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or  [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].

(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.

[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]

To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where

[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].

[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]

Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].

The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].

(c)

[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]

[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]

[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].

The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].

Factorize the expressions
px2 + qx

Answers

Answer:

SOLUTION

HERE,

=X(P.2+Q)

=X(2P+Q)

Answer:

x(px+q) ( I took x as a common and the remaining are some

The equation \sqrt{6-y^2}=x
6−y
2


=x is a function of yy."

Answers

Equations are used to represent functions, and vice versa.

The equation of y as a function of x is [tex]y=\sqrt{6 - x^2[/tex]

The function is given as:

[tex]\sqrt{6-y^2}=x[/tex]

Square both sides

[tex]6-y^2=x^2[/tex]

Subtract 6 from both sides

[tex]-y^2=x^2 - 6[/tex]

Multiply both sides by -1

[tex]y^2=6 - x^2[/tex]

Take square root of both sides

[tex]y=\sqrt{6 - x^2[/tex]

Express as a function

[tex]f(x) = \sqrt{6- x^2[/tex]

Hence, the equation of y as a function of x is [tex]y=\sqrt{6 - x^2[/tex]

Read more about functions and equations at:

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What dose f(-2)=3 mean?

Answers

function!

Step-by-step explanation:

this was a function that the answer (y) is equal to 3

and the X is equal to (-2)

Answer:

This is about a function evaluated at a particular point.  You don't get a formula for the function, but there is enough information to say that the ordered pair (-2, 3) is part of the function.

The function's name is f.

The -2 in parentheses is a value for the independent variable ("input"), often designated by the variable  x.

The 3 is the corresponding value of the dependent variable ("output"), often designated by  the variable y.

The expression can be read as:

"f of negative two is equal to 3"

"the value of f at -2 is 3"

Given 2 angles that measure 50 and 80 and a side that measure 4 feet how many triangles if any can be condctuted

Answers

Answer:

The number of unique triangles that can be constructed from the given values is; Only one triangle

Step-by-step explanation:

We are given the 2 angles of a triangle as;  

∠1 = 50°  

∠2 = 80°  

Now, we know that sum of angles in a triangle is 180°. This means that if the third angle is denoted as ∠3, then we have;  

∠1 + ∠2 + ∠3 = 180°  

Thus;  

∠3 = 180 - (∠1 + ∠2)  

∠3 = 180 - (50 + 80)  

∠3 = 180 - 130  

∠3 = 50°  

Thus; ∠1 = ∠3 = 50°  

A triangle with two equal angles is called an isosceles triangle. Which means that it will also have 2 of its' sides to be equal.  

Thus, in conclusion, only one unique triangle can be drawn.

How do you add fractions with a whole number? Please explain the rules of it too! To be marked as brainliest

Answers

Hello this is how you do it!<3

9/4 = 21/4 therefore, 9/4 = 21/4

24/10 try to reduce the numerator and denominator by a common denominator 24/10 divided 2/2 = 12/5

16/2 divided 2/2 = 8/1 = 8

I hoped that help!<3

You buy candy bars at 85 cents each plus one newspaper for 60 cents. You can spend no more than $4. How many candy bars can you buy? answer

Answers

Answer:

4

Step-by-step explanation:

Well first you want to take 0.60 from the total amount which is $4 leaving you with $3.40

then you want to divide the remaining amount of money by the cost of a candy bar ($0.85)

So you do 3.40/0.85 which is equal to 4

14. What's the least common denominator of 3/4, 4/5, and 2/3?
A. 60
B. 20
C. 15
D. 12

Answers

im pretty sure it's 60

The area of each square tile is square feet and the area of each triangular tile is square foot.

We will pour sand into each frame to a depth of foot.

image placeholder
ft
Complete the sentence with the amount of sand we will need for each tile.​

We will need

ft of sand for each square tile, and

ft of sand for each triangular tile.

Answers

Answer

hi

Step-by-step explanation:

ok

sin(83)cos(7) + cos(83)sin(7)

Answers

Answer:

1

Step-by-step explanation:

correct on edge

sin(83 radians) * cos(7 radians)) + (cos(83 radians) * sin(7 radians)) =

0.893996664

Answer:

hope it helps

A line has a slope of and passes through the point (4, 7). What is its equation in
slope-intercept form?

Answers

Answer:

y = (7/4)x + 0

Step-by-step explanation:

yeah-ya....... right?

find the derivitive of f(x)=(x+9)/(x+1)

Answers

[tex]\dfrac{d}{dx} \left(\dfrac{x+9}{x+1}\right)\\\\\\=\dfrac{(x+1)\dfrac{d}{dx}(x+9) - (x+9) \dfrac{d}{dx}(x+1)}{(x+1)^2}\\\\\\=\dfrac{(x+1) - (x+9)}{(x+1)^2}\\\\\\=\dfrac{x+1-x-9}{(x+1)^2}\\\\\\=-\dfrac{8}{(x+1)^2}[/tex]

Help me out please ???????

Answers

Answer:

I think it's 33.

Hope that helps you.

Step-by-step explanation:

it will be 33 because the interquartile we give it by Q3 - q1

Q3 median of 84 plus 90 divided by 2 equal 87

q1 equal 54

Which of the following is equal to 2,952 ÷ 24?
A.
(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)
B.
(2,400 + 24) ÷ (480 + 24) ÷ (72 + 24)
C.
(2,400 + 24) + (480 + 24) + (72 + 24)
D.
(2,400 ÷ 24) - (480 ÷ 24) - (72 ÷ 24)

Answers

Answer:

A

Step-by-step explanation:

After doing long division we then know that 2,952 ÷24 = 123

We 1st follow pemdas knowing this we solve the equations in parenthesis 1st

(2,400 ÷ 24) + (480 ÷ 24) + (72 ÷ 24)

2,400 ÷ 24 = 100

480 ÷ 24 = 20

72 ÷ 24 = 3

We can then rewrite the equation as

100 + 20 + 3   We then solve left to right

100 + 20 = 120

120 + 3 = 123

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