Chua Chang & Wu Inc. is planning its operations for next year, and the CEO wants you to forecast the firm's additional funds needed (AFN). Data for use in your forecast are shown below. Based on the AFN equation, what is the AFN for the coming year?

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1500\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500e^{0.07\cdot 6}\implies A=1500e^{0.42}\implies A\approx 2282.94[/tex]

Answer: aₙ = -11 + 7(n - 1)

Step-by-step explanation: The equation of an arithmetic sequence is

aₙ = a₁ + d(n - 1).

a₁ is the first term.

d is the common difference.

Let's consider the relationship between the circumference and the radius:

 ⇒ first, consider the equation for finding the circumference

      [tex]Circumference = 2\pi *radius[/tex]

Let's consider the known information

Let's plug the known information to find the radius:

  [tex]Circumference = 2\pi *radius\\36\pi =2\pi *radius\\radius = 18[/tex]

Thus the radius is 18 cm

Answer: 18 cm

Hope that helps!

Answer:

Step-by-step explanation:

Formula:

Lateral surface area = perimeter of the base × height

………………………………………………………………

perimeter of the base = 2×(1.5+3) = 9

height = 4.

then

Lateral surface area = 9 × 4 = 36

Area of two bigger rectangles

Area of two smaller rectangles

LSA

Answer:

4m/9

Step-by-step explanation:

Answer: 7

Step-by-step explanation:

By the angle bisector theorem,

[tex]\frac{21}{14}=\frac{3x-12}{6}\\21(6)=14(3x-12)\\126=14(3x-12)\\9=3x-12\\21=3x\\x=\boxed{7}[/tex]

Answer:

Answer = 25 miles

Step-by-step explanation:

We can make an equation based off of this information in the form of 4.25x+4=110.25. When we solve for x we find that it equals 25.

Hope that helps! :)

Answer:

we need a pic of the graph to be able. to work this out.

THANK YOU

Answer:

It's 5.

Step-by-step explanation:

8-3= 5

The correct option that defines repeating decimals correctly is Option B;

a decimal that has a recurring sequence of numbers that follow a pattern.

A repeating decimal is also called a recurring decimal and it is a decimal representation of a number whose digits are periodic and the infinitely repeated portion is not zero.

From the above definition, it means that the correct option that defines repeating decimals correctly is Option B.

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Answer:

A. [tex]y\leq \frac{1}{2}x+2[/tex]

Step-by-step explanation:

First, let's find the slope of the line, so we can eliminate some answers.

From point (0,2) we can go up 1 and over to the right 2 to the point of (2,3). Slope is rise over run so 1 over 2.

This eliminates C and D.

The last part is to recognize that y being less than the equation will result in the shaded region being below the line. If y was greater than the equation then the shaded region would be above the line.

Therefore, the correct answer would be A. [tex]y\leq \frac{1}{2}x+2[/tex].

Hope this helps! If you have questions about my work please let me know down in the comments!

Answer:

[tex]y\leq \frac{1}{2}x+2[/tex]

Step-by-step explanation:

The first part of finding our answer is finding the slope of the line. The image attached shows this.

[tex]\frac{rise}{run} = \boxed{\frac{1}{2}}[/tex]

This means the slope is [tex]\frac{1}{2}[/tex], removing the bottom 2 answer choices.

Now we have to choose between the [tex]\leq[/tex] and [tex]\geq[/tex] sign. Since the shaded area is below the line, it will be the [tex]\leq[/tex]. (If it was the [tex]\geq[/tex] sign, the shaded area would be above the line.) This marks the first answer as the correct answer.

Answer:

a) 8

Step-by-step explanation:

The prime factors for 24 are 2, 2, 2, 3 -> The greatest is 3

The prime factors for 35 are 5, 7 -> The smallest is 5

So the sum is 3+5=8

#1

Volume

#2

Radius=10/2=5cm

Volume

#3

Volume

#4

#5

radius=8/2=4

Volume

Answer:

1)  314 cm³

2)  523.33 cm³

3)  87.92 in³

4)  11 cm

5)  502.4 cm³

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 5^2 \cdot 4\\& = 3.14 \cdot 25 \cdot 4\\& = 3.14 \cdot 100\\& = 314 \: \sf cm^3\end{aligned}[/tex]

[tex]\textsf{Volume of a sphere}=\sf \dfrac43 \pi r^3\quad\textsf{(where r is the radius)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =\dfrac{4}{3} \cdot 3.14 \cdot 5^3 \\& =\dfrac{4}{3} \cdot 3.14 \cdot 125 \\& =\dfrac{500}{3} \cdot 3.14 \\& = 523.33\: \sf cm^3\:(2\:dp)\end{aligned}[/tex]

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 2^2 \cdot 7\\& = 3.14 \cdot 4 \cdot 7\\& = 3.14 \cdot 28\\& = 87.92\: \sf in^3\end{aligned}[/tex]

[tex]\textsf{Volume of a square pyramid}=\sf \dfrac{1}{3} a^2h \quad\textsf{(where a is the base edge and h is the height)}[/tex][tex]\textsf{Area of base of square pyramid}=\sf a^2 \quad\textsf{(where a is the base edge)}[/tex]

Given:

[tex]\implies 81=a^2[/tex]

[tex]\implies a=\sqrt{81}[/tex]

[tex]\implies a=9\: \sf cm[/tex]

Substitute the given values into the formula and solve for h:

[tex]\begin{aligned}\implies \textsf{297} & =\dfrac{1}{3} \cdot 9^2 \cdot h\\\\297 & =\dfrac{81}{3} h\\\\891 & =81 h\\\\h & = 11 \: \sf cm\end{aligned}[/tex]

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 4^2 \cdot 10\\& = 3.14 \cdot 16 \cdot 10\\& = 3.14 \cdot 160\\& = 502.4\: \sf cm^3\end{aligned}[/tex]

The equation of the line parallel to y=-2x-5 and passing through the point (-1,3) is y = -2x + 1.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given that:-

The equation of the new line will be:-

y - y₁ = m ( x - x₁ )

Since the line is parallel to the line y = -2x - 5 so slope will be same m = -2 now the coordinates are ( -1, 3).

y - ( 3) = -2 [( x - (-1) ]

y - 3 = -2x - 2

y = -2x + 3 -2

Y = -2x + 1

Therefore the equation of the line parallel to y=-2x-5 and passing through the point (-1,3) is y = -2x + 1.

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The point R is the point which is not coplanar with points C, D and E.

We need to find the point which is not coplanar with points C, D and E.

The points that lie on the same plane are called coplanar points.

In the given figure there are five planes which are as follows:

BCUD, BRAE, BRAC, BTDE, ACUDE

Now, points C,D and E lie in plane ACUDE.

In the plane ACUDE points A, C, U, D, E and S lies.

From the options point, R is not lining in the same plane as C, D and E lies.

Therefore, the point R is the point which is not coplanar with points C, D and E.

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Answer: some perfect cubes are

8 (2^3)

27 (3^3)

64 (4^3)

there are many perfect cubes

maybe there is more to this question?

Step-by-step explanation:

A perfect cube of a number is a number that is equal to the number, multiplied by itself, three times. If x is a perfect cube of y, then x = y3. Therefore, if we take the cube root of a perfect cube, we get a natural number and not a fraction. Hence, 3√x = y. For example, 8 is a perfect cube because 3√8 = 2.

Answer:

C. interquartile range

Step-by-step explanation:

using this to show im right

"The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest."

Hope This Helped

Using it's formula, considering a loan of $10,000, the regular monthly payments required to pay off the loan will be of $221.3.

It is given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

In which:

In this problem, we have that the parameters are given as follows:

P = 10,000, r = 0.0299, n = 4 x 12 = 48.

Then:

r/12 = 0.0299/12 = 0.00249167.

Hence, the monthly payment will be given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

[tex]A = 10000\frac{0.00249167(1+0.00249167)^{48}}{(1+0.00249167)^{48} - 1}[/tex]

A = 221.3.

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Answer:

B

Step-by-step explanation:

look at the graph. y is negative from x>2, so interval is 2<x<infinity.

in other case y=0 for x=2, y<0 for infinity<x<2

Answer:

The intervel that describes where the graph is negative is C :)

I hope this helps you!

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

b^5 + 2b^3 + 7

Here,

degrees are 5 and 3.

The degree of the polynomial is the highest / greatest number in the degree.

Out of 3 and 5

5 is the highest / greatest number.

Hence,

the degree of the given polynomial is 5.

Answer:

wouldn't it be -7 and 5? I'm pretty sure that you switch the signs around.

Step-by-step explanation:

set y=0 and solve. -7 + 7 = 0 and 5 - 5 = 0. my teacher told me to switch the signs for each factored term. hope this helps.

Answer:

x = -7

x = 5

Step-by-step explanation:

Hello!

We can use the Zero Product Property to solve for the Zeroes.

The zero product property stars by factoring a quadratic. You then set each of the factors to zero, and solve for the variable in the factor.

Factored form: y = a(x - h)(x - k)

Now, let's call each factor, A and B. To get to 0, either A, B, or both have to be 0. We prefer to solve for both.

The zeroes of the Quadratic is -7 and 5.

Why do we replace it with 0?

Zeroes means the x-intercepts, or the roots of a quadratic. An x-intercet is when y is equal to 0. So we replace y with 0, and solve for x.

Answer:

6 + 7/10x + 2/y

Step-by-step explanation:

Hope this helps :)

Equations can be used to find the dimensions of the picture frame:

Length = 2 +1/2w

and, 2(l+b)=40

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Perimeter = 40 inches.

let the width be w

length= 1/2w+2

So.

Perimeter of rectangle

40= 2 (l+b)

40= 2(0.5w+2+w)

20=1.5w+2

18=1.5w

w= 12

length= 8

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Answer:

76.5in²

Step-by-step explanation:

First we will find the area of the square. This is done by multiplying the side length (9in) by itself.

[tex]9 * 9 = \boxed{81}[/tex]

The area of the square is 81in².

Next we will find the area of the triangular hole. We can use the formula [tex]\frac{1}{2}bh[/tex], where b is the base of the triangle (3) and h is the height of the triangle (3).

[tex]\frac{1}{2}bh\\\frac{1}{2}(3)(3)\\\frac{9}{2}\\\boxed{4.5}[/tex]

The area of the triangle is 4.5in².

Now we can find the area of the figure by subtracting the area of the square and the area of the triangular hole.

[tex]81 - 4.5 = \boxed{76.5}[/tex]

The area of the figure is 76.5in².

That is the answer

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Answer:

The formation of the equation is odd, but I assume it's supposed to be:
4k - 10k = -8k

-6k = -8k
-6k + 8k = -8k + 8k
2k = 0
[tex]\frac{2k}{2}[/tex] = [tex]\frac{0}{2}[/tex]
k = 0

Answer:

By proportional method

[tex] \frac{4}{6} = \frac{5}{x} [/tex]

4x= 30

x= 7.5

Based on the graph that Aaron made, we can infer that the inequality he solved is | x + 2 | < 3.

The value of x in the graphed inequality is:

-5 < x < 1

If 2 was added to both sides, the least value would be - 3 and the highest value would be 3.

The inequality then becomes:

-3 < x < 3

This in line with the first option which is that when 2 is added to any value of x, it will be less than 3.

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Answer:

your answer will be 85 1/3ins

Step-by-step explanation:

16x 5 1/3 = 85.3333333333

then I took the 85 and the 1/3

and just put em together

To factorize something:

 ⇒ need to simplify the equation to its most basic form

Let's solve:

  [tex]2x^2+6x=2(x^2+3x)=2x(x+3)[/tex]

Thus the factorized form is ⇒ [tex]2x(x+3)[/tex]

Answer: 2x(x+3)

Hope that helps!

Answer:

Solution:

→ 2x(x + 3)

Step-by-step explanation:

Method:

→ Common factor

→ Rewrite in factored form