Consider the equation A(aq) 2B(aq) 3C(aq) 2D(aq). In one experiment, 45.0 mL of 0.050 M A is mixed with 25.0 mL 0.100 M B. At equilibrium the concentration of C is 0.0410 M. Calculate K. g

Answers

Answer 1

Answer:

K = 0.0396

Explanation:

Based on the reaction:

A + 2B ⇄ 3C + 2D

Where equilibrium constant, K, is:

K = [C]³[D]² / [A] [B]²

The initial concentrations of A and B are:

[A]₀ = 0.050M * (45.0mL / 70.0mL) = 0.0321M

[B]₀ = 0.100M * (25.0mL / 70.0mL) = 0.0357M

As [C] = 0.0410M, the molar concentration of D is:

0.0410M * (2mol D / 3mol C) = 0.0273M = [D]

And the concentration of A and B that reacted was:

0.0410M * (2mol B / 3mol C) = 0.0273M B

0.0410M * (1mol A / 3mol C) = 0.0137M A

Equilibrium concentration B and A:

0.0357M - 0.0273M = 0.0084M = [B]

0.0321M - 0.0137M = 0.0184M = [A]

And K is:

K = [0.0410M]³[0.0273M]² / [0.0184M] [0.0084M]²

K = 0.0396


Related Questions

. When is separation of substances necessary ?Name four methods used to separate solid substances ?

the one of 2 who send correct answer will get the brainliest and 40 points​

Answers

1.) when components are needed to be used in different ways

2.) sublimation, filtration, evaporation, and distillation

Use the chart above to help you answer the following questions.
2Na + 2HCI →
2 NaCl
+ H
(s)
(aq)
(aq) 2(g)
? What are the reactants in the chemical reaction shown above?

Answers

Answer:

2Na and 2HCl

Explanation:

The equation for the above chemical reaction is as follows:

2Na + 2HCI → 2NaCl + H2

In a reaction, the reactants are said to be those that combine together to form products. In this case, sodium (Na) and hydrochloric acid (HCl) are the reactants of this reaction

Calculate the density of a solid substance if a cube measuring 2.54 cm on one side has a mass of 108 g/cm3​

Answers

Answer:

6.59 g/cm³

Explanation:

Step 1: Given data

Side of the cube (s): 2.54 cmMass of the cube (m): 108 g

Step 2: Calculate the volume of the cube

We will use the following expression.

V = s³ = (2.54 cm)³ = 16.4 cm³

Step 3: Calculate the density of the solid

Density is an intrinsic property, equal to the quotient between the mass and the volume.

ρ = m/V

ρ = 108 g / 16.4 cm³ = 6.59 g/cm³

meaning of alchol in one word​

Answers

Liquid, harmful, addicting, flammable, drink

a. acidic
b. basic
; neutral
d. will not be affected
Find the molarity of 10% NaOH.[MOE 2003
a. 1.5
b! 2.5
c. 4
d. 0.4
10 ml of 2.5 N NaOH is mixed with 20 ml of
N HCI. The mixture is diluted to 100 ml. WI
is the nature of mixture?
IMOF 20​

Answers

1. You didn't post the question to Number 1.

2.

10% means There's 10g in 100ml of this solution.

This is the weight/volume(w/v) expression of concentration.

So

We have Mass =10g

volume =100ml

Molarity = Moles of solute/volume of solution(in LITRES)

Moles=Mass/Molar mass

Molar mass of NaOH=40g/mol

Mole=10/40

=0.25mole

Volume =100ml =0.1Litres

MOLARITY=0.25/0.1 =

=2.5M

OPTION B.

3. NOTE: THE MOLARITY AND NORMALITY OF NAOH AND HCL ARE THE SAME(This doesn't happen for all compounds tho)

So We can take 2.5N(Normality) of NaOH to be 2.5M(Molarity) NaOH

I think you forgot to write the Normality of the second one. I'll take it to be 1N. Maybe you can then Input supposed value when you're solving on your own

So

1N HCl is same as 1M HCL

We were given their respective volumes

2.5M NaOH can also be written as 2.5mole/volume(in Liters)

The volume of NaOH =10ml or 0.01L

Moles = 2.5mole/L x 0.01L

You notice that Liters on top and bottom cancels out... leaving the moles

So

Mole=0.01x2.5 = 0.025moles of NaOH

we're gonna do the same for 1N HCl in 20ml(0.02L)

So

Mole = 1 x 0.02 =0.02moles

Total Mole = 0.02 + 0.025 =0.045moles

The Final Volume is 100ml as stated in the question. It was diluted to 100ml or 0.1L

So

Final Concentration In Molarity

= Total Moles/Volume in L

=0.045/0.1

=0.45M.

1. Phosphorous reacts with bromine to form phosphorous tribromide. If 35.0 grams of bromine
reacted and 27.9 grams of phosphorous tribromide are actually formed.
what is the percent yield of phosphorous tribromide (PBr3)?
2 P + 3 Br2 ---> 2 PBr3
(Note that the molar masses: P=30.97g, Br = 79.90g) Show your steps
*
Please help me

Answers

Answer:

70.6 %

Explanation:

First step, we define the reaction:

2P + 3Br₂  →  2PBr₃

We determine the moles of reactant:

35 g . 1mol / 159.8 g = 0.219 moles

We assume, the P is in excess, so the bromine is the limiting reagent.

3 moles of Br₂ can produce 2 moles of phophorous tribromide

Then, 0.219 moles may produce (0.219 . 2) /3 = 0.146 moles of PBr₃

We convert moles to mass:

0.146 mol .  270.67 g /mol = 39.5 g

That's the 100 % yield reaction, also called theoretical yield. The way to determine the % yield is:

(Yield produced / Thoeretical yield) . 100

(27.9 / 39.5) . 100 = 70.6 %

Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.

Answers

Answer:

Suppose you added some solid NaCl to a saturated solution of NaCl at 20℃ and warmed the mixture to 40℃. What would happen to the added NaCl?

Explanation:

can you help with this one

HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start with 155,8 grams of
iron (Fe), how many grams of copper (Cu) will be produced?
2Fe + 3CuCl2 à 2FeCl3 + 3Cu

Answers

Answer: 30.978

Explanation:

From the equation 2 moles of Fe will result in 3 moles copper

so .325 moles Fe will result in .4875 moles Cu

Cu weights 63.546 gm per mole

.4875 moles * 63.546 gm / mole = 30.978 gm of Cu

are either positively charged or negatively charged species in which the number of protons and electrons are not equal. ____________ bonds are chemical bonds that results from the sharing of electrons. ____________ are positively charged ions with more ____________ than ____________ . ____________ ion is an example of a polyatomic anion. ____________ is the system of assigning an unambiguous name to a compound.

Answers

Answer:

1. Ions are either negatively or positively charged species in which the number of electrons and protons are not equal.

2. The chemical bond that arises due to the sharing of electrons is termed a covalent bond.

3. The positively charged ions are called cations, which comprise more protons than electrons.

4. An example of a polyatomic anion is the hydroxide anion.

5. The system of assigning an unambiguous name to a compound is called nomenclature.

1.State two uses of water at home.
2. State two uses of water in industries.
3. What is water conservation?
4. What are some methods of water conservation?​
Helppppp!!!!!!

Answers

Answer:

1. Washing dishes and cooking

2. Water is used as a solvent in the manufacture of beverages and it is also largely used in agriculture.

3. Water conservation is the action of using water wisely and not wasting it.

4. i) Wash dishes in a tub of water instead of under a running tap.

ii) Use a pail of water to wash the car instead of spraying water from a hose.

iii) Make sure that there are no leaking or broken taps and pipes.

Answer:

Washing dishes and cooking

2. Water is used as a solvent in the manufacture of beverages and it is also largely used in agriculture.

3. Water conservation is the action of using water wisely and not wasting it.

4. i) Wash dishes in a tub of water instead of under a running tap.

ii) Use a pail of water to wash the car instead of spraying water from a hose.

iii) Make sure that there are no leaking or broken taps and pipes.

Explanation:

When a mixture of oxygen and hydrogen is ignited in a test tube, the
reaction shown occurs. What happens to the total mass of the contents of
the test tube?

Answers

Answer:

follow me and pm and I answer your question

identify and name the functional
present in (i) C₂ H₂ (ii). CH₃ CH₂OH.

Answers

Answer:

I)Acetylene

II)2-Methyl-1-butanol

Explanation:

I)appears as a colorless gas with a faint garlic-like odor. Easily ignited and burns with a sooty flame. Gas is lighter than air.

How many ML of 1.2 52 M KOH would be required to completely neutralize 9.55 ML of 0.114 HF

Answers

Answer:

0.871 mL

Explanation:

Step 1: Write the balanced neutralization reaction

KOH + HF ⇒ KF + H₂O

Step 2: Calculate the reacting moles of HF

9.55 mL of 0.114 M HF react.

9.55 × 10⁻³ L × 0.114 mol/L = 1.09 × 10⁻³ mol

Step 3: Calculate the moles of KOH needed to react with 1.09 × 10⁻³ moles of HF

The molar ratio of KOH to HF is 1:1. The moles of KOH needed are 1/1 × 1.09 × 10⁻³ mol = 1.09 × 10⁻³ mol.

Step 4: Calculate the volume of KOH solution that contains 1.09 × 10⁻³ moles of KOH

An unknown volume of 1.252 M KOH solution contains 1.09 × 10⁻³ moles of KOH.

1.09 × 10⁻³ mol × 1 L/1.252 mol = 8.71 × 10⁻⁴ L = 0.871 mL

Balance the following equation by LCM method.Mg + H2O = Mg(OH)2 + H2​

Answers

Answer:

Mg + 2H₂O —> Mg(OH)₂ + H₂

Explanation:

Mg + H₂O —> Mg(OH)₂ + H₂

The above equation can be balance as illustrated below:

Mg + H₂O —> Mg(OH)₂ + H₂

There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

Mg + 2H₂O —> Mg(OH)₂ + H₂

Now, the equation is balanced

****Check***

Element >>>>> Reactant >>>> Product

Mg >>>>>>>>>> 1 >>>>>>>>>>> 1

H >>>>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>>>> 2 >>>>>>>>>>> 2

The balanced equation of Mg + H2O = Mg(OH)2 + H2​ is given as

Mg + 2H₂O —> Mg(OH)₂ + H₂

What is the balance equation?

Generally, the equation for the Chemical equation  is mathematically given as

Mg + H₂O —> Mg(OH)₂ + H₂

Therefore, We se that  we have on the LHS

Mg=1

H=2

O=1

and on The RHS

Mg=1

H=4

O=2

Therefore to balance, we add 2 to H and 1 to O giving

Mg + 2H₂O —> Mg(OH)₂ + H₂

Read more on Chemical equation

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Is this equation balanced or unbalanced?
C+02=CO2

Answers

This equation is balanced

OH- of a solution that has a pH of 8.57

Answers

Answer:

I think its -8.75

Explanation:

Hope this helps!11


HELP ME OMG
A sample of xenon gas collected at a pressure of 1.15 atm and a temperature of 279 K is found to
occupy a volume of 786 milliliters. How many moles of Xe gas are in the sample?
mol

Answers

n = 0.0395 mol Xe

Explanation:

Use the ideal gas law:

PV = nRT

n = PV/RT

= (1.15 atm)(0.786 L)/(0.08205 L-atm/mol-K)(279K)

= 0.0395 mol Xe

You want to decaffeinate your coffee by extracting the caffeine outwith dichloromethane. It's too late to extract the caffeinefrom the coffee beans because you've already brewed yourself a 200mL cup of coffee. Your particular brand of coffee contains100 mg of caffeine in that 200mL cup. The partitioncoefficient of caffeine in dichloromethane/water is 9.0.
How much caffeine would still be in your 200 mL if you did:
A. One extraction using 200 mL o fdichloro methane
B. Two extractions using 100 mL of dichloro methane each.

Answers

Solution :

The partition coefficient

[tex]$k_d= \frac{\text{(mass of caffeine in }CH_2Cl_2 / \text{volume of }CH_2Cl_2)}{\text{(mass of caffeine in water/ volume of water)}}$[/tex]

   = 9.0

A). 1 x 200 mL extraction

Let m be the mass of caffeine in water

Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m

∴ [tex]$\frac{(100-m)/200}{m/200}=9$[/tex]

  [tex]$\frac{100-m}{m}=9$[/tex]

  [tex]$10 \ m = 100$[/tex]

[tex]$m=\frac{100}{10}$[/tex]

     = 10

Therefore, the mass remaining in the coffee is m = 10 mg

B). 2 x 100 mL extraction

First extraction :

Let [tex]$m_1$[/tex] be the mass of the caffeine in water.

Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m

∴ [tex]$\frac{(100-m_1)/100}{m_1/200}=9$[/tex]

  [tex]$\frac{100-m_1}{m_1}=9$[/tex]

  [tex]$5.5 \ m_1 = 100$[/tex]

[tex]$m_1=\frac{100}{5.5}$[/tex]

     = 18.18

Mass remaining in the coffee after the 1st extraction [tex]$m_1$[/tex] = 18.18 mg

Second extraction:

Let [tex]$m_2$[/tex] be the mass of the caffeine in water.

Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 18.18 - [tex]$m_2$[/tex]

∴ [tex]$\frac{(18.18-m_2)/100}{m_2/200}=9$[/tex]

  [tex]$\frac{18.18-m_2}{m_2}=9$[/tex]

  [tex]$5.5 \ m_2 = 18.18$[/tex]

[tex]$m_1=\frac{18.18}{5.5}$[/tex]

     = 3.3

Mass remaining in the coffee after the 1st extraction [tex]$m_2$[/tex] = 3.3 mg

A plot of binding energy per nucleon (Eb/ A) versus the mass number (A) shows that nuclei with a small mass number have a small binding energy per nucleon, as the mass number increases the binding energy per nucleon increases, and the value for the binding energy per nucleon has a maximum value for nuclei with a mass number around 60. Verify that this is the case by determining the binding energy per nucleon for each of the following four nuclei. (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of 2H be 2.0141 u, the mass of 7Li be 7.0160 u, the mass of 62Ni be 61.9283 u, and the mass of 110Cd be 109.9030 u.

a. 2H
b. 7Li
c. 62Ni
d. 110Cd

Answers

Answer:

a)   1.12 MeV / nucleon

b)   5.62 MeV / nucleon

c)  8.80 MeV / nucleon

d) 8.56 MeV / nucleon

we can conclude that the binding energy has a maximum value for nuclei with a mass around 60

Explanation:

Binding energy = ( Δm * 931.5 ) MeV

Binding energy per nucleon = Binding energy in / Number of nucleon

a) ²H = 1 neutron , 1 proton = 2 nucleons

Given that the theoretical mass = 2.0141 u

Actual mass = 1.0078 u + 1.0087 u = 2.0165 u

Δm  = 2.0165 u - 2.0141 u = 2.4 * 10^-3 u

∴ Binding energy per nucleon = ( 2.4 * 10^-3  * 931.5 ) MeV / 2 nucleons

                                                  = 1.12 MeV / nucleon

b) ⁷Li = 3 protons , 4 neutrons = 7 nucleons

theoretical mass = 7.0160 u

Actual mass = ( 3 * 1.0078 ) + ( 4 * 1.0087 )  = 7.0582 u  

Δm  = ( 7.0582 u  - 7.0160 u  ) = 0.0422 u

∴ Binding energy per nucleon = ( 0.0422 * 931.5 ) / 7

                                                  = 5.62 MeV / nucleon

C) ⁶²Ni = 28 protons , 34 neutrons = 62 nucleons

Theoretical mass = 61.9283 u

Actual mass = ( 28 * 1.0078 ) u + ( 34 * 1.0087 ) u

                    = 62.5142 u

Δm = 0.5859 u  

∴ Binding energy per nucleon = ( 0.5859 * 931.5 ) / 62

                                                  = 8.80 MeV / nucleon

D) ¹¹⁰Cd = 48 protons , 62 neutrons = 110 nucleons

Theoretical mass = 109.9030 u

Actual mass = ( 48 * 1.0078 ) + ( 62 * 1.0087 )

                    = 110.9138 u

Δm  = ( 110.9138 - 109.9030 ) = 1.0108 u

∴ Binding energy per nucleon = ( 1.0108 * 931.5 ) / 110

                                                  = 8.56 MeV / nucleon

hence we can conclude that the binding energy has a maximum value for nuclei with a mass around 60

When an acid reacts with a strong base which product always forms

Answers

Answer:طيزي

Explanation:

The shapes of the drops relate to the attractive forces between molecules in a compound. Based on their shapes, how does the attractive force between the water molecules compare with the attractive force between the oil molecules?

Answers

Answer:

Water molecule has hydrogen bonding and surface tension

Explanation:

Intermolecular behavior of water is different from that of the intermolecular force of oil because water molecule is polar in nature while oil molecule is non polar. Dur to polar nature, water molecule has high surface tension which keep its atoms intact. Also the water molecule being polar also exhibit hydrogen bonding between hydrogen (+ive) and oxygen atom (-ive)

1. Rearrange the letters to form a word.
1. OOTPSIL
2. BCDEROK
3. UHMSU
4. AOML
5. LCYA
science po ito

Answers

1- Topsoil

2- Bedrock

3- Humus

4- Loam

5- Acyl, Clay, or Lacy

Well that was fun :)

Answer:

Explanation:

1. TOPSOIL

2. BEDROCK

The solubility of an ionic compound can be expressed as the number of moles of the compound that will dissolve per liter of solution (molarity). The saturated solution has approximately____(a) sodium ions dissolved in it (give an estimate of the average value.) The solution (not the solid) contains approximately_____(b) moles of sodium ions.

Answers

Answer:

Number of moles  of sodium dissolved =  6.0 *10^23

Explanation:

The image for the question is attached

Solution

a) Total 181 ions of Na are dissolved

b)

The number of moles of sodium dissolved = 181/6.023 *10^23

Number of moles  of sodium dissolved = 5.987 * 10^23

Number of moles  of sodium dissolved =  6.0 *10^23

write the manufacturing process of oxygen gas from liquid air​

Answers

Answer:

Production of liquid oxygen from air Oxygen is generated by liquefaction of atmospheric air in the air separation unit (ASU). Cryogenic technique is the most commonly used for producing liquid oxygen for industrial and medical applications .

Explanation:

An air separation unit (ASU) uses continuous cryogenic distillation to continuously liquefy ambient air and separate the oxygen gas.

What is oxygen?

Oxygen is the second largest abundant element in the atmosphere comprising 20.8% by volume. Despite being mostly used as a gas, oxygen is frequently stored as a liquid. Compared to high-pressure gaseous storage with a similar capacity, liquid storage is less expensive and bulkier.

A cryogenic storage tank, one or more vaporizers, and a pressure control system make up a typical storage system. The cryogenic tank is built similarly to a vacuum bottle.

The primary air compressor is where the ASU manufacturing process starts, and the product storage tanks' output is where it concludes. Moisture, carbon dioxide, and hydrocarbons are taken out of the air after it has been compressed and put through a purification system.

To find more on oxygen manufacturing, refer here:

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Water moves on, above or under the surface of the Earth true or false ​

Answers

above because its above

This is true ! Hope it helps

. Describe the movement of the Earth, The moon and the sun?

Answers

Answer:

Explanation:

It orbits


The moon orbits the earth, the earth orbits the sun, thats is the movement and ao does other planets

Predict the effect of an eightfold pressUre increase on the equillbrium composition of the reaction 3 Nalg) + H2lg) 2 NaHlg)​

Answers

Answer:

See explanation

Explanation:

Given the reaction;

3N2(g) + H2(g) = 2N3H(g).

We know that when a constraint is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

In this case, when the pressure is increased eightfold, the equilibrium position will shift towards the direction where there is the least total volumes.

In this particular reaction, the forward reaction has the least total volumes and is favoured by an eightfold increase in pressure.

Hence, when the pressure is increased eightfold, more N3H(g) is obtained.

What is the volume of a brick with a Length of 5cm, height of 1cm, and a
width of 2cm. *
O 8cm
O 10cm
15cm
O 12cm
all answer are cubed. I just couldn't add the cube symbol to the answer choices

Answers

Answer:

The answer is 10cm^3

Explanation:

5x1x2=10

Mind marking me brainliest? :)

a buffer solution contain 0.1 mole per litres of acetic acid and 0.001 moles perlitre of sodium acetate.what will be its pH?(k=1.8×10-5)

Answers

Answer: The pH of the solution is 2.74.

Explanation:

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

[tex]pH=pK_a+\log (\frac{\text{[conjugate base]}}{\text{[acid]}})[/tex]         .......(1)

The power of the acid dissociation constant is the negative logarithm of the acid dissociation constant. The equation for it is:

[tex]pK_a=-log K_a[/tex]        ......(2)

The chemical equation for the reaction of acetic acid and NaOH follows:

[tex]CH_3COOH+NaOH\rightleftharpoons CH_3COONa+H-2O[/tex]

Given values:

[tex]K_a=1.8\times 10^{-5}[/tex]

Putting values in equation 2:

[tex]pK_a=-log (1.8\times 10^{-5})\\\\pK_a=4.74[/tex]

We are given:

[tex]CH_3COOH[/tex] = 0.1 M

[tex]CH_3COONa[/tex] = 0.001 M

Plugging values in equation 1:

[tex]pH=4.74+\log (\frac{0.001}{0.1})\\\\pH=4.74-2\\\\pH=2.74[/tex]

Hence, the pH of the solution is 2.74.

How many hydrogen atoms are in 709 grams of water? Answer in units of atoms.

Answers

Answer:

26 Hydrogen atoms

Explanation:

H2O

Each hydrogen atom: 2+16 = 18g

Hence,

1 atom -> 18g

x atoms -> 709g

709/18 = 39 atoms

Therefore, 39 atoms give 709g

Hence, 26 Hydrogen atoms are used

Feel free to mark it as brainliest :D

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Would you say this was a well-designed network please help ASAPITS 14 points What is the GCF of 11ab + 32ab ? Find the volume.A. 103 ydB. 54 ydC. 74 ydD. 84 yd Read the Greek myth "Midas" retold by Thomas Bulfinch and answer the question.[1] Bacchus, on a certain occasion, found his old schoolmaster and foster-father, Silenus, missing. The old man had been drinking, and in that state wandered away, and was found by some peasants, who carried him to their king, Midas. Midas recognized him, and treated him hospitably, entertaining him for ten days and nights with an unceasing round of jollity.[2] On the eleventh day he brought Silenus back, and restored him in safety to his pupil. Whereupon Bacchus offered Midas his choice of a reward, whatever he might wish. He asked that whatever he might touch should be changed into gold. Bacchus consented, though sorry that he had not made a better choice.[3] Midas went his way, rejoicing in his new-acquired power, which he hastened to put to the test. He could scarce believe his eyes when he found a twig of an oak, which he plucked from the branch, become gold in his hand. He took up a stone; it changed to gold. He touched a sod; it did the same. He took up an apple from the tree; you would have thought he had robbed the garden of the Hesperides. His joy knew no bounds, and as soon as he got home, he ordered the servants to set a splendid repast on the table. Then he found to his dismay that whether he touched bread, it hardened in his hand; or put a morsel to his lip, it defied his teeth. He took a glass of wine, but it flowed down his throat like melted gold.[4] In consternation at the unprecedented affliction, he strove to divest himself of his power; he hated the gift he had lately coveted. But all in vain; starvation seemed to await him. He raised his arms, all shining with gold, in prayer to Bacchus, begging to be delivered from his glittering destruction. Bacchus, merciful deity, heard and consented. "Go," said he, "to River Pactolus, trace its fountain-head, there plunge yourself and body in, and wash away your fault and its punishment." He did so, and scarce had he touched the waters before the gold-creating power passed into them, and the river sands became changed into gold, as they remain to this day.Select a possible theme of the myth. Gold is a symbol of wealth and authority in many cultures. People who expect a reward for good deeds are selfish. Money does not bring as much happiness as friendship. Wishes are sometimes better when they don't come true. answer asap! thank uu 3 x 5 x 5 x5 x5 x 5 x5 x5 In line 15, the phrase, "But mine is all as hungry as the sea," contains:A. hyperbole.B. metaphor.C. synecdoche.D. onomatopoeia.O E. internal rhyme.